SECTION 1
Historical Context & Motivation
Alkanes are among the least reactive organic molecules, earning them the historical name "paraffins" — from the Latin parum affinis, meaning "little affinity." Their strong, nonpolar C−H bonds resist most reagents that attack polar functional groups. Yet chemists in the nineteenth century observed that exposing methane or other simple hydrocarbons to chlorine gas under ultraviolet light produced hydrogen chloride and chlorinated products. This observation raised a fundamental question: how does a thermodynamically stable C−H bond break, and why do some C−H bonds react faster than others? The study of radical halogenation developed to answer these questions and became a cornerstone of free-radical chemistry.
1834 • Dumas Discovers Chlorination of Methane
1900s • Rise of Free-Radical Theory
1935 • Rice & Herzfeld Propose Chain Mechanisms
1947 • Hammond Postulate & Selectivity Rationalized
1970s • Bond Dissociation Energies & Modern Selectivity Data
The central question this lesson addresses is twofold: what is the step-by-step mechanism by which a halogen atom replaces a hydrogen on an alkane, and how can we predict which hydrogen will be replaced when multiple types of C−H bonds are present? The answers lie in bond dissociation energies, radical stability, and transition-state theory.
SECTION 2
Core Principles & Definitions
Radical halogenation converts an alkane R−H into an alkyl halide R−X (where X = Cl or Br) through a free-radical chain mechanism. The reaction requires an energy input — typically ultraviolet light (hν) or heat (Δ) — to generate the initial radical species. Understanding the mechanism and its selectivity depends on several interlocking concepts that form the intellectual backbone of radical chemistry.
Homolytic Bond Cleavage
Bond Dissociation Energy (BDE)
Radical Stability Order
Chain Mechanism Phases
Selectivity vs. Reactivity
KEY TAKEAWAY
SECTION 3
The Radical Chain Mechanism — Visual Overview
The following diagram illustrates the complete radical chain mechanism for the chlorination of methane, the simplest case. Each phase — initiation, propagation, and termination — is shown with the relevant bond-breaking and bond-forming events. Note the use of fishhook arrows (single-barbed) to indicate the movement of single electrons, as opposed to the double-barbed curved arrows used in ionic mechanisms.
Several features of this mechanism deserve emphasis. First, notice that the chlorine radical consumed in propagation step 1 is regenerated in propagation step 2 — this is the defining characteristic of a chain reaction. A single initiation event can trigger thousands of propagation cycles before a termination event occurs. Second, the overall reaction enthalpy is obtained by summing the ΔH° values of the two propagation steps, not the initiation step (which is thermodynamically "paid back" during propagation). Third, the rate-determining step for selectivity purposes is propagation step 1 — the hydrogen-abstraction step — because this is where the halogen radical discriminates among different C−H bonds.
SECTION 4
Thermodynamic Analysis & the Hammond Postulate
The selectivity of radical halogenation is governed by the enthalpy of the hydrogen-abstraction step (propagation step 1). To calculate ΔH° for this step, we apply the relationship between bond dissociation energies: ΔH° = Σ(BDEs of bonds broken) − Σ(BDEs of bonds formed). Since only one bond breaks and one bond forms in this step, the equation simplifies considerably.
ENTHALPY OF HYDROGEN ABSTRACTION
R−H = the C−H bond being broken; H−X = the H−Cl or H−Br bond being formed. When ΔH° is negative, the step is exothermic; when positive, endothermic.
| Bond | BDE (kJ/mol) | Radical Type Formed |
|---|---|---|
| CH₃−H (methyl) | 439 | Methyl radical (•CH₃) |
| RCH₂−H (1°) | 423 | Primary radical |
| R₂CH−H (2°) | 413 | Secondary radical |
| R₃C−H (3°) | 400 | Tertiary radical |
| H−Cl | 431 | — |
| H−Br | 366 | — |
Key Bond Dissociation Energies for Radical Halogenation
For chlorination, the hydrogen-abstraction step is slightly endothermic for a 1° C−H bond: ΔH° = 423 − 431 = −8 kJ/mol (actually mildly exothermic) and more exothermic for 3° C−H bonds: ΔH° = 400 − 431 = −31 kJ/mol. The energy differences between these ΔH° values are small (about 23 kJ/mol spread across all types), so the transition-state energies are closely spaced, and chlorine shows only modest selectivity.
For bromination, the hydrogen-abstraction step is significantly endothermic: ΔH° = 423 − 366 = +57 kJ/mol (1° C−H) versus +34 kJ/mol (3° C−H). The Hammond postulate tells us that for an endothermic step, the transition state resembles the products (the carbon radical). Since 3° radicals are substantially more stable than 1° radicals, the transition state leading to a 3° radical is significantly lower in energy. This large energy gap between transition states gives bromine its extraordinary selectivity for tertiary C−H bonds.
HAMMOND POSTULATE (QUALITATIVE)
TS = transition state. For exothermic (or thermoneutral) steps, the TS resembles reactants, and radical stability matters less. This is why Cl• (exothermic abstraction) is less selective than Br• (endothermic abstraction).
Why Not Fluorine or Iodine?
SECTION 5
Selectivity Factors & Product Prediction
Predicting the product distribution in radical halogenation requires two pieces of information: the number of each type of hydrogen and the relative reactivity (selectivity factor) of each hydrogen type toward the halogen radical. By convention, the reactivity of a primary C−H bond is set to 1.0, and the reactivities of secondary and tertiary C−H bonds are expressed relative to that baseline. The commonly accepted selectivity factors at 25 °C are as follows.
| C−H Type | Chlorination (relative rate) | Bromination (relative rate) |
|---|---|---|
| Primary (1°) | 1.0 | 1 |
| Secondary (2°) | 3.9 | 82 |
| Tertiary (3°) | 5.2 | 1600 |
Relative Reactivity per Hydrogen at ~25 °C
The product ratio is calculated by multiplying the number of hydrogens of each type by its relative reactivity factor. The general formula is:
PRODUCT RATIO CALCULATION
nₐ = number of equivalent H atoms at site A; rₐ = relative reactivity of that H type; Σ(nᵢ × rᵢ) sums over all distinct hydrogen types in the molecule.
The strikingly different selectivity factors for chlorination and bromination emerge directly from these energy diagrams. In chlorination, the three transition-state energies for 1°, 2°, and 3° C−H abstraction are clustered closely together — hence selectivity factors of only 1.0 : 3.9 : 5.2. In bromination, the same transition states are spread far apart — giving selectivity factors of 1 : 82 : 1600. The practical consequence is that bromination is the reagent of choice when you want a single constitutional isomer from a substrate that has a tertiary C−H bond.
SECTION 6
Worked Example: Monochlorination of 2-Methylbutane
Let us predict the product distribution for the radical monochlorination of 2-methylbutane (isopentane, C₅H₁₂) at 25 °C. This molecule has four distinct types of C−H bonds, making it an excellent test of the selectivity-factor method.
Monochlorination of 2-Methylbutane: Product Distribution
- 1
Step 1 — Draw the Structure and Classify All Hydrogens
2-Methylbutane is CH₃CH(CH₃)CH₂CH₃. Identify each unique hydrogen type. Position a: the two equivalent CH₃ groups attached to C2 → 6 primary (1°) H's. Position b: the single H on C2 (the tertiary carbon) → 1 tertiary (3°) H. Position c: the CH₂ group at C3 → 2 secondary (2°) H's. Position d: the terminal CH₃ at C4 → 3 primary (1°) H's.6 × 1° H (a), 1 × 3° H (b), 2 × 2° H (c), 3 × 1° H (d) = 12 total H atoms - 2
Step 2 — Apply the Selectivity Factors for Chlorination
Using the relative reactivity values: 1° = 1.0, 2° = 3.9, 3° = 5.2. Calculate the weighted reactivity for each site. Site a: 6 × 1.0 = 6.0. Site b: 1 × 5.2 = 5.2. Site c: 2 × 3.9 = 7.8. Site d: 3 × 1.0 = 3.0.Weighted reactivities: a = 6.0, b = 5.2, c = 7.8, d = 3.0; Total = 22.0 - 3
Step 3 — Calculate the Percentage of Each Product
Divide each site's weighted reactivity by the total (22.0) and multiply by 100%. Site a (1-chloro-2-methylbutane, on the gem-dimethyl CH₃ groups): (6.0/22.0) × 100% = 27.3%. Site b (2-chloro-2-methylbutane, the 3° product): (5.2/22.0) × 100% = 23.6%. Site c (3-chloro-2-methylbutane, the 2° product): (7.8/22.0) × 100% = 35.5%. Site d (1-chloro-3-methylbutane, on the terminal CH₃): (3.0/22.0) × 100% = 13.6%.Product distribution: 27% (a), 24% (b), 35% (c), 14% (d) — a complex mixture - 4
Step 4 — Interpret the Result
No single product dominates. Despite the tertiary C−H being the most reactive per hydrogen, there is only one such hydrogen, so the 3° product constitutes only about 24% of the mixture. The 2° product (site c) is actually the largest fraction because 2 hydrogens × 3.9 = 7.8 gives the highest weighted reactivity. This illustrates the critical point: selectivity depends on both the number of hydrogens AND their relative reactivity.Chlorination gives a mixture of four constitutional isomers — poor for synthesis. - 5
Step 5 — Compare with Bromination (for perspective)
Using bromination selectivity factors (1° = 1, 2° = 82, 3° = 1600): Site a: 6 × 1 = 6. Site b: 1 × 1600 = 1600. Site c: 2 × 82 = 164. Site d: 3 × 1 = 3. Total = 1773. Site b: (1600/1773) × 100% = 90.2%. The tertiary product overwhelmingly dominates.Bromination gives ~90% 2-bromo-2-methylbutane — excellent selectivity for the 3° product
SECTION 7
Chlorination vs. Bromination — Strengths and Limitations
Chlorination and bromination each have distinct advantages and disadvantages in synthetic planning. The choice between them depends on the substrate structure and the desired outcome. The following comparison highlights the practical trade-offs a chemist must consider when designing a radical halogenation procedure.
| Property | Chlorination (Cl₂ / hν) | Bromination (Br₂ / hν) |
|---|---|---|
| Selectivity | Low (1° : 2° : 3° ≈ 1 : 3.9 : 5.2) | Very high (1° : 2° : 3° ≈ 1 : 82 : 1600) |
| Reactivity | High — reacts with virtually any alkane | Moderate — may not react well with 1° C−H only substrates |
| ΔH° of H-abstraction (3° C−H) | −31 kJ/mol (exothermic) | +34 kJ/mol (endothermic) |
| TS character (Hammond) | Reactant-like — does not reflect radical stability well | Product-like — strongly reflects radical stability |
| Synthetic utility | Useful only for methane or symmetrical alkanes (single product) | Excellent for substrates with 3° C−H; gives predominant single product |
| Polyhalogenation risk | Higher — product R−Cl is still reactive toward Cl• | Lower — high selectivity limits over-reaction |
Comparison of Chlorination and Bromination in Radical Halogenation
KEY TAKEAWAY
SECTION 8
Connection to Advanced Radical Chemistry
The principles learned in radical halogenation form the foundation for understanding far more sophisticated radical reactions encountered in advanced organic chemistry. The same chain-mechanism framework, selectivity principles, and thermodynamic reasoning apply to a range of transformations that exploit radical intermediates for strategic bond formation.
| Concept in This Lesson | Advanced Extension |
|---|---|
| Radical chain mechanism (initiation / propagation / termination) | Radical polymerization — chains grow by repeated radical additions to alkenes (e.g., polyethylene, polystyrene) |
| Selectivity via BDE and Hammond postulate | Barton reaction — remote C−H functionalization using alkoxy radicals, guided by geometric selectivity and BDE considerations |
| Radical stability (3° > 2° > 1°) | Allylic and benzylic bromination (NBS reactions) — stabilized radicals direct selectivity at allylic/benzylic positions |
| Anti-Markovnikov addition excluded here | Radical addition of HBr to alkenes — peroxide-initiated anti-Markovnikov hydrobromination follows the same chain mechanism |
| Termination by radical coupling | Persistent radical effect and TEMPO-mediated oxidation — controlled radical reactions that exploit selective termination |
From Radical Halogenation to Advanced Radical Chemistry
Perhaps the most exciting modern extension is the renaissance of radical-mediated C−H functionalization in synthetic methodology. Chemists now use photoredox catalysis, hydrogen-atom transfer (HAT) catalysts, and metal-mediated radical generation to achieve selective C−H bond transformations under mild conditions — reactions that would have seemed miraculous to the pioneers of radical halogenation. Yet at their core, these modern methods rely on the same interplay of bond strengths, radical stability, and transition-state theory that govern the simple halogenation of an alkane.
SECTION 9
Practice Problems
Question 1: CONCEPTUAL
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Question 2: BASIC CALCULATION
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Question 3: INTERMEDIATE
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Question 4: APPLIED
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Question 5: CRITICAL THINKING
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SUMMARY
Lesson Summary
Summary
Radical halogenation converts alkanes (R−H) into alkyl halides (R−X) through a free-radical chain mechanism consisting of three phases: initiation (homolysis of X₂ by UV light or heat), propagation (hydrogen abstraction followed by halogen abstraction in a self-sustaining cycle), and termination (coupling of any two radicals). The thermodynamics of each propagation step are calculated using bond dissociation energies (BDE): ΔH° = BDE(broken) − BDE(formed).
Selectivity in radical halogenation depends on two factors: the number of each type of hydrogen and its relative reactivity toward the halogen radical. Chlorine is reactive but unselective (1° : 2° : 3° = 1 : 3.9 : 5.2) because its exothermic H-abstraction step has a reactant-like transition state. Bromine is less reactive but highly selective (1 : 82 : 1600) because its endothermic H-abstraction step has a product-like transition state that strongly reflects radical stability (3° > 2° > 1°), as predicted by the Hammond postulate. Product ratios are predicted using the formula: % product = (n × r) / Σ(nᵢ × rᵢ) × 100%.