Organic Chemistry 1 • Alkene and Alkyne Addition Reactions

Ozonolysis and Oxidative Cleavage of Alkenes

Breaking carbon–carbon double bonds to reveal the structural identity of unknown alkenes through controlled oxidation.

A molecular ring with laboratory flask and atom symbols for organic chemistry.
Inside this lesson 10 sections 5 questions 4 figures

SECTION 1

Historical Context & Motivation

In the late nineteenth century, organic chemists faced a profound challenge: determining the position of carbon–carbon double bonds within complex molecules. Without modern spectroscopic methods such as NMR or mass spectrometry, structural determination relied on chemical degradation—systematically breaking molecules apart and identifying the fragments. Ozonolysis emerged as one of the most powerful tools in this arsenal, allowing chemists to cleave double bonds with surgical precision and deduce structure from the resulting carbonyl fragments. The reaction's elegance lies in its predictability: the two carbonyl products obtained directly map back to the two ends of the original alkene, making it an indispensable analytical and synthetic tool.

1840 • Discovery of Ozone

Christian Friedrich Schönbein first identifies ozone (O₃) as a distinct allotrope of oxygen, noting its characteristic pungent odor during electrolysis experiments. The name derives from the Greek word "ozein," meaning "to smell."

1855 • Ozone Reacts with Organic Compounds

Early studies reveal that ozone reacts vigorously with unsaturated organic compounds, though the mechanism and products remain poorly understood at this stage.

1905 • Harries Develops Ozonolysis

Carl Dietrich Harries systematically investigates the reaction of ozone with alkenes, developing ozonolysis as a reliable method for determining the position of double bonds. He applies the technique to elucidate the structure of natural rubber.

1953 • Criegee Mechanism Proposed

Rudolf Criegee proposes the accepted mechanism for ozonolysis, involving a 1,3-dipolar cycloaddition to form a molozonide, followed by retro-[3+2] fragmentation and recombination to give the ozonide. This mechanism remains the foundation of our understanding today.

1970s–Present • Modern Synthetic Applications

Ozonolysis becomes a workhorse reaction in organic synthesis and total synthesis campaigns, with reductive (Me₂S, PPh₃, Zn) and oxidative (H₂O₂) workup procedures providing selective access to aldehydes, ketones, or carboxylic acids.

The central question that ozonolysis addresses is deceptively simple: Where is the double bond located, and what fragments result from its cleavage? Understanding this reaction equips you not only with a powerful synthetic transformation but also with a conceptual framework for reasoning backward from products to starting material—a critical skill in retrosynthetic analysis.

SECTION 2

Core Principles & Definitions

Ozonolysis belongs to a broader class of reactions known as oxidative cleavage reactions, in which the π bond and σ bond of a carbon–carbon double bond are both broken, generating two separate carbonyl-containing fragments. The identity of these carbonyl products—whether aldehydes, ketones, or carboxylic acids—depends on both the substitution pattern of the original alkene and the specific workup conditions employed. To master ozonolysis, you must internalize several foundational principles that govern the reaction's selectivity and utility.

1

Ozone as a 1,3-Dipole

Ozone (O₃) is a powerful electrophilic 1,3-dipolar species. Its bent geometry and resonance structures generate both nucleophilic and electrophilic character at the terminal oxygens, enabling concerted [3+2] cycloaddition with the electron-rich π bond of an alkene.
2

Reductive vs. Oxidative Workup

After ozonide formation, the workup determines the product oxidation state. Reductive workup (Me₂S or Zn/AcOH) yields aldehydes and ketones. Oxidative workup (H₂O₂) converts any aldehyde fragments to carboxylic acids, while ketones remain unchanged.
3

Substitution Pattern Dictates Products

Each carbon of the original C=C becomes a carbonyl carbon. A disubstituted carbon yields a ketone (R₂C=O), while a monosubstituted or unsubstituted carbon yields an aldehyde (RCHO or H₂C=O) under reductive workup.
4

Regioselectivity and Predictability

Ozonolysis is perfectly regioselective: the cleavage occurs exclusively at the C=C double bond. No rearrangements occur, meaning the products directly reveal the connectivity of the starting alkene, making it an ideal structural probe.
5

Complementary Oxidative Cleavage Reagents

KMnO₄ (hot, concentrated or acidic) and HIO₄/OsO₄ (Lemieux–Johnson) also cleave alkenes oxidatively. KMnO₄ produces carboxylic acids from non-terminal positions and CO₂ from terminal =CH₂ groups, providing complementary information.
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KEY TAKEAWAY

Think of ozonolysis like cutting a rope at a specific knot: the double bond is the knot, and the resulting rope fragments (carbonyl products) tell you exactly what was attached on each side. Reductive workup preserves the fragments as they are (aldehydes/ketones), while oxidative workup further processes any loose ends (converting aldehydes to carboxylic acids). Knowing which workup was used is essential for correctly predicting the products.

SECTION 3

The Criegee Mechanism Visualized

The Criegee mechanism for ozonolysis proceeds through three key stages. First, ozone undergoes a [3+2] cycloaddition with the alkene π bond to form an unstable molozonide (a 1,2,3-trioxolane). This five-membered ring intermediate rapidly undergoes retro-[3+2] fragmentation to generate a carbonyl fragment and a carbonyl oxide (Criegee zwitterion). These two fragments then recombine in a second [3+2] cycloaddition to form the more stable ozonide (a 1,2,4-trioxolane), which is subsequently cleaved during the workup step.

Criegee Mechanism of OzonolysisAlkeneR₁R₂CCR₃R₄π bond+ O₃MolozonideC—O—O—O—C(1,2,3-trioxolane)Unstable!retro-[3+2]FragmentationR₁R₂C=O+R₃R₄C=O(carbonyl oxide)CarbonylCriegee Zwitt.[3+2]OzonideC—O—O—C \O/(1,2,4-trioxolane)Workup StepReductive WorkupMe₂S, Zn/AcOH, or PPh₃Products:Aldehydes + KetonesR₂C=O and/or RCHO(preserves oxidation state)Oxidative WorkupH₂O₂ or mCPBAProducts:Carboxylic Acids + KetonesR₂C=O and/or RCOOH(aldehydes → carboxylic acids)
The Criegee mechanism: ozone attacks the alkene π bond via [3+2] cycloaddition to form the molozonide, which fragments and recombines to give the ozonide. The workup step (reductive or oxidative) then determines the final carbonyl products.

As shown in the diagram, the critical decision point comes at the workup stage. The reductive workup uses a mild reducing agent such as dimethyl sulfide (Me₂S) to cleave the ozonide and reduce any peroxide intermediates, yielding aldehydes and ketones without further oxidation. The oxidative workup uses hydrogen peroxide (H₂O₂), which pushes any aldehyde products to the carboxylic acid oxidation level. Ketones, lacking the C–H bond required for further oxidation, remain unchanged in both protocols. This distinction is the single most important detail that students must track when predicting ozonolysis products.

SECTION 4

Mechanistic Details & Reaction Energetics

The ozonolysis mechanism is a showcase of pericyclic reaction logic. Each key step is a concerted, orbital-symmetry-allowed process. The initial [3+2] cycloaddition between the ozone 1,3-dipole and the alkene π system is suprafacial on both components, consistent with the Woodward–Hoffmann rules for a thermally allowed (4π + 2π) process. The resulting molozonide is a strained 1,2,3-trioxolane whose O–O bond weakness drives a rapid retro-[3+2] fragmentation at temperatures as low as −78 °C. The two fragments—a carbonyl compound and a carbonyl oxide (Criegee intermediate)—recombine in a second [3+2] cycloaddition to form the thermodynamically more stable 1,2,4-trioxolane (ozonide).

Step 1: 1,3-Dipolar Cycloaddition

Ozone acts as a 1,3-dipole with the HOMO localized on the terminal oxygens. It attacks the alkene LUMO (π*) in a concerted, synchronous fashion, forming two new C–O bonds and one O–O bond simultaneously. The reaction is highly exothermic (ΔH ≈ −50 kcal/mol) and proceeds with a low activation barrier because both components are electronically well-matched. Electron-rich alkenes react faster due to their higher-energy HOMOs, which overlap more effectively with the ozone LUMO.

Step 2: Retro-[3+2] Fragmentation

The molozonide fragments in the reverse of a [3+2] cycloaddition, cleaving the C–C bond and one O–O bond simultaneously to produce a carbonyl fragment (aldehyde or ketone) and a carbonyl oxide. This step is driven by the relief of ring strain in the five-membered trioxolane and the formation of the strong C=O π bond. The carbonyl oxide is a 1,3-dipolar zwitterion with substantial charge separation, making it highly reactive.

Step 3: Recombination to Ozonide

The carbonyl oxide undergoes a second [3+2] cycloaddition with the carbonyl fragment, but with reversed regiochemistry—the central oxygen of the original ozone now bridges the two carbons in a 1,2,4-trioxolane arrangement. This isomeric five-membered ring is more stable than the molozonide because the O–O bonds are positioned with less torsional strain. The ozonide can be isolated at low temperatures but is typically treated directly with a reducing or oxidizing agent in the workup step.

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Safety Note

Ozonides are potentially explosive peroxidic compounds. In practice, ozonolysis is performed at −78 °C in dilute solution (typically CH₂Cl₂ or MeOH), and the ozonide is never isolated on large scale. The workup reagent is added directly to the reaction mixture to decompose the ozonide safely.

SECTION 5

Predicting Products by Substitution Pattern

The power of ozonolysis as a structural tool lies in the direct correspondence between the substitution pattern of the alkene and the carbonyl products formed. Each vinylic carbon of the original C=C bond becomes the carbonyl carbon of a product. Learning to map substitution patterns to products—and vice versa—is the essential skill for both exam problems and retrosynthetic reasoning.

Ozonolysis Product Map: Substitution Pattern → Products(Reductive workup: O₃ then Me₂S)Terminal Monosubstituted (RCH=CH₂)RCH=CH₂ → RCHO + H₂C=OOne aldehyde + formaldehydeRCHO+ CH₂ODisubstituted — cis or trans (RCH=CHR')RCH=CHR' → RCHO + R'CHOTwo aldehydes (may be same if symmetric)RCHO+ R'CHODisubstituted — geminal (R₂C=CH₂)R₂C=CH₂ → R₂C=O + H₂C=OOne ketone + formaldehydeR₂C=O+ CH₂OTrisubstituted (R₂C=CHR')R₂C=CHR' → R₂C=O + R'CHOOne ketone + one aldehydeR₂C=O+ R'CHOQuick Rules• =CH₂ → CH₂O• =CHR → RCHO• =CR₂ → R₂C=OEach vinylic C becomesa carbonyl C (C=O).With H₂O₂ workup:• RCHO → RCOOH• CH₂O → CO₂ + H₂O• R₂C=O → R₂C=O(ketones unchanged)Tetrasubstituted:R₂C=CR₂' → two ketones
Product map showing how each type of alkene substitution pattern maps to specific ozonolysis products under reductive workup (Me₂S). The "Quick Rules" panel summarizes the correspondence: =CH₂ gives formaldehyde, =CHR gives an aldehyde, and =CR₂ gives a ketone.

An important point that frequently appears on exams concerns cyclic alkenes. When the double bond is embedded within a ring, ozonolysis does not produce two separate fragments. Instead, the ring opens to yield a single dicarbonyl compound—a dialdehyde, diketone, or keto-aldehyde depending on the substitution. For example, cyclohexene (a disubstituted cyclic alkene) treated with O₃ followed by Me₂S yields a six-carbon dialdehyde: OHC–(CH₂)₄–CHO (hexanedial). Recognizing whether a substrate is cyclic is therefore essential for drawing the correct product.

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Cyclic Alkene Tip

For cyclic alkenes, mentally "cut" the double bond and replace each C=C carbon with a C=O. Since both carbons are connected through the ring backbone, the product is a single open-chain dicarbonyl compound rather than two separate fragments.

SECTION 6

Worked Example: Ozonolysis of 2-Methylbut-2-ene

Let us work through a complete ozonolysis problem from start to finish, predicting products for both reductive and oxidative workup conditions.

Ozonolysis of 2-Methylbut-2-ene

  1. 1

    Step 1 — Draw the Starting Alkene and Identify the Double Bond

    2-Methylbut-2-ene has the structure CH₃–C(CH₃)=CH–CH₃. The double bond is between C2 and C3. Identify the substituents: C2 bears two methyl groups (trisubstituted at that carbon), while C3 bears one methyl group and one hydrogen (monosubstituted at that carbon). Overall, this is a trisubstituted alkene.
    C2 = disubstituted (two CH₃ groups); C3 = monosubstituted (one CH₃ and one H)
  2. 2

    Step 2 — Apply the Cleavage Rule

    Replace the C=C with two C=O groups. C2 (bearing two R groups) becomes a ketone: (CH₃)₂C=O (acetone). C3 (bearing one R group and one H) becomes an aldehyde: CH₃CHO (acetaldehyde). Each vinylic carbon retains its substituents, but the π bond and the C–C σ bond between them are replaced by C=O bonds.
    C2 → (CH₃)₂C=O (acetone); C3 → CH₃CHO (acetaldehyde)
  3. 3

    Step 3 — Determine Products Under Reductive Workup (O₃, then Me₂S)

    Under reductive workup, both fragments are preserved at their initial oxidation level. The ketone (acetone) and aldehyde (acetaldehyde) are both obtained as the final products.
    Reductive workup products: (CH₃)₂C=O + CH₃CHO
  4. 4

    Step 4 — Determine Products Under Oxidative Workup (O₃, then H₂O₂)

    Under oxidative workup, the aldehyde (acetaldehyde, CH₃CHO) is further oxidized to a carboxylic acid: CH₃COOH (acetic acid). The ketone (acetone) is unchanged because it lacks an oxidizable C–H bond at the carbonyl carbon.
    Oxidative workup products: (CH₃)₂C=O + CH₃COOH
  5. 5

    Step 5 — Verify by Retrosynthetic Reconstruction

    To check your answer, mentally reverse the ozonolysis: join the two carbonyl carbons with a double bond, removing the oxygens. (CH₃)₂C=O + CH₃CHO → (CH₃)₂C=CH–CH₃, which is 2-methylbut-2-ene. This confirms the products are consistent with the starting material.
    Reconstruction confirmed: products map back to 2-methylbut-2-ene ✓

SECTION 7

Comparing Oxidative Cleavage Methods

Ozonolysis is not the only method for oxidatively cleaving alkenes. Two other reagent systems—hot KMnO₄ and the Lemieux–Johnson oxidation (OsO₄/NaIO₄)—also achieve C=C cleavage, each with characteristic product patterns. Understanding the distinctions among these methods is critical for choosing the right reagent in synthesis and for predicting products on exams.

FeatureO₃ / Me₂S (Reductive)O₃ / H₂O₂ (Oxidative)KMnO₄ (hot, conc.)
=CH₂ givesCH₂O (formaldehyde)CO₂ + H₂OCO₂ + H₂O
=CHR givesRCHO (aldehyde)RCOOH (carboxylic acid)RCOOH (carboxylic acid)
=CR₂ givesR₂C=O (ketone)R₂C=O (ketone)R₂C=O (ketone)
SelectivityHigh — only C=C cleavedModerate — aldehydes over-oxidizedLow — can oxidize allylic/benzylic C–H
Unique advantageProduces aldehydes — not possible with KMnO₄One-pot procedure for acidsNo special equipment needed

Comparison of oxidative cleavage methods for alkenes

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KEY TAKEAWAY

Only ozonolysis with reductive workup can produce aldehydes from oxidative cleavage. This is its principal synthetic advantage over KMnO₄ or oxidative ozonolysis, both of which push aldehydes to the carboxylic acid oxidation level. Think of it as a "gentle scissors" versus a "blowtorch"—ozonolysis/Me₂S cuts the double bond cleanly, while KMnO₄ cuts and burns the exposed ends.

SECTION 8

Connections to Advanced Topics

Ozonolysis connects to several advanced topics that you will encounter later in your organic chemistry studies and beyond. In retrosynthetic analysis, ozonolysis serves as a strategic disconnection: given a target aldehyde or ketone, you can envision an alkene precursor by mentally joining two carbonyl carbons with a double bond. This "reverse ozonolysis" approach is a staple of synthetic planning. Additionally, the Criegee mechanism provides an accessible introduction to pericyclic reaction theory, as the [3+2] cycloadditions and retro-[3+2] fragmentations obey the Woodward–Hoffmann rules. Furthermore, understanding the fate of ozonides connects to the broader chemistry of peroxides and radical intermediates in advanced mechanistic organic chemistry.

Concept in This LessonAdvanced Extension
Criegee mechanism ([3+2] cycloadditions)Pericyclic reactions: Diels–Alder, 1,3-dipolar cycloadditions, Woodward–Hoffmann rules, frontier molecular orbital theory
Reductive vs. oxidative workupChemoselective reductions: selectivity in complex molecule synthesis, protecting group strategies
Product prediction from substitutionRetrosynthetic analysis (Corey): strategic disconnections at C=C bonds, synthon identification
Ozonolysis of alkynesAlkynes undergo ozonolysis to give carboxylic acids (both carbons fully oxidized), used in Organic Chemistry 2 for structure determination
Oxidative cleavage of diols (glycol cleavage)Periodic acid (HIO₄) cleavage of 1,2-diols; a two-step sequence (OsO₄ then HIO₄) achieves the same result as ozonolysis

Connections between ozonolysis and advanced organic chemistry topics

Looking forward, you should recognize that ozonolysis is just one member of a larger family of C=C cleavage reactions. The two-step dihydroxylation/periodate cleavage sequence (OsO₄ then NaIO₄) achieves the same net transformation under milder conditions and avoids ozone, which requires a generator and careful handling. In total synthesis, the choice between these methods often depends on functional group compatibility, scale, and the desired oxidation state of the products.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

Explain why ozonolysis with reductive workup (Me₂S) produces aldehydes, whereas ozonolysis with oxidative workup (H₂O₂) converts those same fragments to carboxylic acids. Why are ketone products unaffected by the choice of workup?
Show answer
During reductive workup, Me₂S acts as a mild reducing agent that decomposes the ozonide by reducing the O–O bonds without further oxidizing the carbonyl products, preserving aldehydes in their native oxidation state. In oxidative workup, H₂O₂ provides additional oxidizing equivalents that convert the aldehyde C–H bond to a C–OH bond, ultimately yielding a carboxylic acid (RCHO → RCOOH). Ketones lack a hydrogen on the carbonyl carbon (R₂C=O), so there is no C–H bond available for oxidation, and they remain unchanged regardless of workup conditions. This difference in reactivity is fundamentally rooted in the greater ease of oxidizing a primary oxidation-state carbon (aldehyde) compared to a secondary one (ketone).

Question 2: BASIC CALCULATION

Predict the products of ozonolysis of 1-methylcyclohexene treated with (a) O₃ followed by Me₂S, and (b) O₃ followed by H₂O₂.
Show answer
1-Methylcyclohexene has a trisubstituted double bond within a six-membered ring (C1 bears two substituents including the methyl, C2 bears one substituent and one H). Since the alkene is cyclic, ozonolysis does not produce two separate fragments but instead opens the ring to give a single dicarbonyl compound. Under reductive workup (a): the C1 end becomes a ketone (it bore two carbon substituents) and the C2 end becomes an aldehyde, giving 6-oxoheptanal: CH₃CO(CH₂)₄CHO. Under oxidative workup (b): the aldehyde end is further oxidized to a carboxylic acid, yielding 6-oxoheptanoic acid: CH₃CO(CH₂)₄COOH. Note that the methyl ketone is preserved in both cases.

Question 3: INTERMEDIATE

Ozonolysis of an unknown alkene (molecular formula C₈H₁₆) with reductive workup gives two equivalents of butanal (CH₃CH₂CH₂CHO). Determine the structure of the unknown alkene, including its stereochemical possibilities.
Show answer
Since the ozonolysis produces two identical aldehyde fragments (butanal), we perform a reverse ozonolysis by joining the two carbonyl carbons with a double bond: CH₃CH₂CH₂CHO + OHCCH₂CH₂CH₃ → CH₃CH₂CH₂CH=CHCH₂CH₂CH₃, which is oct-4-ene. The molecular formula C₈H₁₆ corresponds to one degree of unsaturation, consistent with a single C=C bond. Because oct-4-ene is a symmetrically 1,2-disubstituted alkene, it can exist as either (E)-oct-4-ene or (Z)-oct-4-ene. Ozonolysis destroys the double bond geometry, so both geometric isomers would yield the same products. Without additional information (such as physical properties or spectroscopic data), both (E)- and (Z)-oct-4-ene are valid structural answers.

Question 4: APPLIED

A natural product chemist isolates an unknown terpene (C₁₀H₁₆, two degrees of unsaturation). Treatment with excess O₃ followed by reductive workup (Me₂S) gives formaldehyde (CH₂O), acetone ((CH₃)₂C=O), and 4-oxopentanal (OHC–CH₂–CH₂–CO–CH₃). Propose a structure for the terpene and explain how each fragment arises.
Show answer
Two degrees of unsaturation with a molecular formula C₁₀H₁₆ and three ozonolysis fragments indicate two C=C double bonds (no rings, since three fragments arise from two cleavages of an acyclic compound). Working backward: the formaldehyde (CH₂O) comes from a terminal =CH₂ group; the acetone ((CH₃)₂C=O) comes from a =C(CH₃)₂ group; and the 4-oxopentanal (OHC–CH₂–CH₂–CO–CH₃) is a five-carbon fragment with aldehyde and ketone termini, meaning both ends of this fragment were connected to double bonds. Reconstructing: connect the formaldehyde carbon to one end of the 4-oxopentanal, and the acetone carbon to the other end, replacing each C=O with half of a C=C. This gives CH₂=CHCH₂CH₂C(=CH₂)CH₃... Wait—more carefully, the fragment OHC–CH₂–CH₂–CO–CH₃ has an aldehyde end (originally =CHR) and a ketone end (originally =CR₂). Joining the aldehyde end to the CH₂O gives CH₂=CH–CH₂–CH₂–, and joining the ketone end to (CH₃)₂C=O gives –C(CH₃)=C(CH₃)₂. The full structure is: CH₂=CH–CH₂–CH₂–C(CH₃)=C(CH₃)₂, which is myrcene (7-methyl-3-methyleneocta-1,6-diene, a well-known acyclic monoterpene). Formaldehyde arises from the terminal =CH₂ of C1, the ketoaldehyde fragment from the internal C2–C6 chain connecting the two double bonds, and acetone from the trisubstituted terminal isopropylidene group.

Question 5: CRITICAL THINKING

Consider two experimental approaches to determine the structure of an unknown alkene: (i) ozonolysis with reductive workup (O₃/Me₂S), and (ii) dihydroxylation followed by periodate cleavage (OsO₄ cat./NMO, then NaIO₄). Under what circumstances might these two methods give different observable outcomes, even though they formally achieve the same net transformation? Discuss at least two scenarios involving substrate structure or functional group compatibility.
Show answer
Although both methods formally cleave C=C to give the same carbonyl products, several scenarios distinguish them. First, if the substrate contains other oxidizable functional groups such as a thioether (R–S–R), ozone will oxidize it to a sulfoxide or sulfone as a side reaction, potentially complicating product analysis. OsO₄/NaIO₄ would leave the thioether intact. Second, if the molecule contains multiple double bonds of different reactivity, the two-step OsO₄/NaIO₄ sequence may be more selective—OsO₄ preferentially dihydroxylates more electron-rich or less sterically hindered double bonds, whereas ozone can react with all C=C bonds simultaneously, requiring careful stoichiometric control. Third, if the substrate contains a 1,2-diol already present in the molecule, NaIO₄ would cleave that diol as well (giving additional carbonyl fragments not arising from alkene cleavage), whereas ozone would leave the diol untouched. Fourth, for substrates sensitive to strongly electrophilic reagents, ozone might cause undesired epoxidation or Baeyer–Villiger-type side reactions, while the milder OsO₄ conditions would avoid these. Thus, the choice between these reagent systems must account for the full functional group inventory of the substrate.

SUMMARY

Lesson Summary

Summary

Ozonolysis is the reaction of an alkene with ozone (O₃) followed by a workup step that cleaves the C=C double bond to yield carbonyl compounds. The Criegee mechanism proceeds through a [3+2] cycloaddition to form a molozonide, which fragments into a carbonyl and a carbonyl oxide, then recombines to form the ozonide. The workup step controls the product oxidation state: reductive workup (Me₂S) yields aldehydes and ketones, while oxidative workup (H₂O₂) converts aldehydes to carboxylic acids.

Product prediction follows simple rules: each vinylic carbon becomes a carbonyl carbon—=CH₂ → CH₂O, =CHR → RCHO, and =CR₂ → R₂C=O. Cyclic alkenes yield a single dicarbonyl product rather than two fragments. Compared to KMnO₄ cleavage, only ozonolysis with reductive workup can produce aldehydes, making it uniquely valuable in synthesis and structure determination.

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