Organic Chemistry 1 • Alkene and Alkyne Addition Reactions

Addition to Alkynes and Partial Reductions

Mastering the selective transformation of triple bonds into alkenes and alkanes through controlled addition and reduction strategies.

A molecular ring with laboratory flask and atom symbols for organic chemistry.
Inside this lesson 10 sections 5 questions 5 figures

SECTION 1

Historical Context & Motivation

The chemistry of alkynes has occupied a central position in organic synthesis since the mid-nineteenth century, when chemists first began to appreciate the distinctive reactivity conferred by the carbon–carbon triple bond. Unlike alkenes, which undergo a single addition to form saturated products, alkynes present two π bonds available for reaction, enabling sequential transformations that can be halted at the alkene stage or driven to completion. This dual reactivity posed both a challenge and an opportunity: chemists needed methods to control whether one or both equivalents of a reagent would add across the triple bond. The development of selective catalysts and reagents to achieve this control ranks among the most impactful achievements in synthetic organic chemistry.

1862 • Berthelot Synthesizes Acetylene

Marcellin Berthelot prepared acetylene (C₂H₂) from carbon and hydrogen at high temperature, establishing the simplest alkyne as a building block for organic synthesis and industrial chemistry.

1912 • Sabatier's Catalytic Hydrogenation

Paul Sabatier received the Nobel Prize for his work on heterogeneous catalysis, demonstrating that metals like nickel and platinum could catalyze the full hydrogenation of unsaturated compounds, including alkynes to alkanes.

1941 • Lindlar Catalyst Developed

Herbert Lindlar introduced a poisoned palladium catalyst (Pd/CaCO₃, quinoline, Pb(OAc)₂) that selectively reduces alkynes to cis-alkenes, halting hydrogenation at the alkene stage—a landmark in partial reduction methodology.

1960s • Dissolving Metal Reductions Refined

Birch and others systematically explored sodium or lithium in liquid ammonia for alkyne reduction, establishing the dissolving metal method as the route to trans-alkenes via radical anion intermediates.

2000s–Present • Modern Selectivity and Green Chemistry

Contemporary research focuses on semi-hydrogenation catalysts with improved selectivity and atom economy, including nanostructured palladium, copper catalysts, and transfer hydrogenation methods that minimize over-reduction.

The overarching question that drove this historical progression remains the central theme of this lesson: How can we selectively add reagents to a triple bond and, in particular, control whether the product is a cis-alkene, a trans-alkene, or a fully saturated alkane? Understanding the mechanistic basis for each transformation empowers the organic chemist to select the right reagent for any synthetic target.

SECTION 2

Core Principles of Alkyne Reactivity

Alkynes are characterized by a triple bond consisting of one σ bond and two mutually perpendicular π bonds. The sp-hybridized carbons hold their electrons more tightly than sp²-hybridized alkene carbons, resulting in a shorter, stronger bond (bond dissociation energy ≈ 839 kJ/mol for C≡C versus ≈ 614 kJ/mol for C=C). Despite this greater bond strength, the increased electron density of two π bonds makes alkynes excellent nucleophiles in electrophilic addition reactions. The cylindrical symmetry of the two π clouds also means that electrophiles can approach from any direction perpendicular to the bond axis, a factor that influences the stereochemistry of addition products. Crucially, because two equivalents of reagent can add, the chemist must understand when and how to stop after a single addition to obtain a vinyl halide, vinyl borane, or alkene rather than the fully saturated product.

1

Two π Bonds = Two Additions

Alkynes can undergo two sequential addition reactions. The first addition yields a substituted alkene (vinyl intermediate), and the second produces a saturated compound. Controlling the stoichiometry and catalyst is the key to selectivity.
2

Electrophilic Addition Follows Markovnikov's Rule

When HX or other protic electrophiles add to an unsymmetrical alkyne, the proton adds to the terminal carbon and the nucleophile to the internal carbon, following Markovnikov regiochemistry and forming the more stable carbocation or vinyl cation intermediate.
3

Syn vs. Anti Addition Controls Stereochemistry

Catalytic hydrogenation delivers both hydrogens from the same face (syn addition), yielding a cis-alkene. Dissolving metal reductions proceed through an anti pathway via radical anion intermediates, producing the trans-alkene.
4

Catalyst Poisoning Enables Partial Reduction

The Lindlar catalyst uses lead(II) acetate and quinoline to deactivate ("poison") palladium, reducing its catalytic activity enough to halt hydrogenation at the alkene stage and prevent over-reduction to the alkane.
5

Hydroboration–Oxidation Gives Anti-Markovnikov Products

Hydroboration of alkynes with a hindered borane such as disiamylborane (Sia₂BH) adds boron to the less substituted carbon, and subsequent oxidation yields an enol that tautomerizes to an aldehyde (from terminal alkynes) or ketone.
✦

KEY TAKEAWAY

Think of the alkyne triple bond as a two-story parking garage with two levels (π bonds) available for incoming reagent "cars." A normal catalyst opens both levels simultaneously, filling them completely (full reduction to alkane). A poisoned catalyst, like Lindlar's, blocks the ramp to the second level after the first is full—parking only one equivalent of H₂ and leaving you with a cis-alkene. Dissolving metal reduction, by contrast, uses a completely different entrance that forces the substituents apart, yielding a trans-alkene.

SECTION 3

Visual Overview: Alkyne Reaction Map

R—C≡C—R'Internal Alkynecis-AlkeneH₂ / Lindlar cat.trans-AlkeneNa / NH₃(l)AlkaneH₂ (excess) / Pt or PdVinyl Halide1 eq HX(Markovnikov)Enol → Aldehyde/Ketone1) Sia₂BH 2) H₂O₂/NaOH(anti-Markovnikov)Geminal Dihalide2 eq HX(Markovnikov, double)
The central alkyne can be steered to six distinct product classes by varying the reagent and conditions. Upward arrows represent partial reductions (to cis- or trans-alkenes) and full reduction (to the alkane). Downward arrows illustrate electrophilic additions (HX) and hydroboration–oxidation pathways. Regiochemistry and stereochemistry are controlled by reagent choice.

The diagram above provides a roadmap that you should internalize: from a single alkyne starting material, six fundamentally different products can be obtained. The upper portion of the map highlights the three reduction pathways that differ only in stereochemistry and degree of reduction. Moving to the left, hydrogenation with the Lindlar catalyst provides the cis-alkene via syn delivery of H₂, while dissolving metal conditions (Na in liquid NH₃) yield the trans-alkene through an anti addition mechanism involving radical anion intermediates. Excess H₂ over Pt, Pd, or Ni drives the reduction all the way to the alkane. The lower portion shows electrophilic and hydroboration additions, where stoichiometry and borane choice govern whether a vinyl halide, a geminal dihalide, or a carbonyl compound is obtained.

SECTION 4

Mechanistic Details of Alkyne Additions

Electrophilic Addition of HX (One and Two Equivalents)

The addition of one equivalent of hydrogen halide (HBr, HCl) to an alkyne proceeds through an electrophilic addition mechanism analogous to that of alkenes but with important distinctions. The proton acts as the electrophile and adds to the triple bond to generate a vinyl cation intermediate. For terminal alkynes, Markovnikov's rule predicts that the proton adds to the terminal carbon (the less substituted end), placing the positive charge on the internal carbon where it is stabilized by adjacent alkyl groups. The halide ion then attacks from either face, yielding a vinyl halide as a mixture of E and Z isomers (though anti addition often predominates). Adding a second equivalent of HX to the vinyl halide follows Markovnikov's rule again—the proton adds to the carbon bearing the fewer substituents (the one without halogen), placing the second halide on the same carbon as the first, generating a geminal dihalide.

Catalytic Hydrogenation: Full vs. Partial

Catalytic hydrogenation of alkynes uses molecular hydrogen (H₂) adsorbed onto a metal surface. When Pd, Pt, or Ni catalysts are employed without modification, both π bonds are reduced, and the product is the fully saturated alkane. The mechanism involves simultaneous delivery of both hydrogen atoms from the catalyst surface to the same face of the π system (syn addition). To stop at the alkene stage, the Lindlar catalyst deactivates palladium by coating it on calcium carbonate and treating with lead(II) acetate and quinoline. The "poisoned" surface binds the alkyne but releases the resulting cis-alkene before it can be re-adsorbed and reduced further, because the less π-electron-dense alkene binds more weakly to the deactivated surface.

Dissolving Metal Reduction

Dissolving metal reduction employs an alkali metal such as sodium or lithium dissolved in liquid ammonia (−33 °C). The metal donates a single electron to one of the π* antibonding orbitals of the alkyne, generating a radical anion that adopts a trans configuration to minimize electron–electron repulsion between the lone pair and the radical. This radical anion is then protonated by NH₃ (acting as a weak acid) to give a vinyl radical, which accepts a second electron from another sodium atom to form a vinyl anion, and a final protonation yields the trans-alkene. The four-step sequence (electron, proton, electron, proton) is the hallmark of this mechanism and explains why the anti stereochemistry is consistently obtained.

Dissolving Metal Reduction MechanismAlkyneR—C≡C—R'+e⁻(Na)Radical Anion[R—C=C—R']⁻•trans geometry+H⁺(NH₃)Vinyl RadicalR—CH=C•—R'+e⁻(Na)Vinyl AnionR—CH=C⁻—R'+H⁺trans-AlkeneStep 1: Electron transferStep 2: ProtonationStep 3: Electron transferStep 4: Protonation
The dissolving metal reduction proceeds through four discrete steps: (1) single-electron transfer from Na to the alkyne π* orbital forms a radical anion in the trans configuration, (2) NH₃ protonates the anion to produce a vinyl radical, (3) a second electron from Na gives a vinyl anion, and (4) final protonation by NH₃ yields the trans-alkene product.

Hydroboration–Oxidation of Alkynes

Hydroboration of a terminal alkyne with a bulky borane such as disiamylborane (Sia₂BH) or catecholborane adds the B–H bond in a syn, anti-Markovnikov fashion, placing boron on the terminal carbon. The steric bulk of Sia₂BH prevents a second hydroboration, arresting the reaction at the vinyl borane stage. Oxidation with H₂O₂/NaOH replaces the boron with an OH group, yielding an enol that rapidly tautomerizes to the corresponding aldehyde (from terminal alkynes) or ketone (from internal alkynes). This reaction is complementary to acid-catalyzed hydration (which follows Markovnikov's rule to give ketones from terminal alkynes), providing the synthetic chemist with access to either regiochemical outcome.

SECTION 5

Classifying Alkyne Addition Reactions

To systematically organize the many reactions of alkynes, it is helpful to classify them by the type of bond that forms and by the stereochemical and regiochemical outcome. The table below provides a comprehensive reference, grouping reactions into reductions, electrophilic additions, and hydration/hydroboration pathways. Understanding the pattern across these categories is more valuable than memorizing each reaction in isolation.

ReactionReagents / ConditionsProductStereo / Regiochemistry
Partial hydrogenation (syn)H₂, Lindlar catalyst (Pd/CaCO₃/Pb(OAc)₂/quinoline)cis-AlkeneSyn addition (both H from same face)
Dissolving metal reductionNa (or Li) / NH₃(l), −33 °Ctrans-AlkeneAnti addition via radical anion
Full catalytic hydrogenationH₂ (excess), Pd/C or Pt or NiAlkaneSyn addition (both stages)
HX addition (1 eq)1 eq HBr or HClVinyl halideMarkovnikov; mixture of E/Z
HX addition (2 eq)2 eq HBr or HClGeminal dihalideMarkovnikov (both additions)
Halogenation (1 eq X₂)1 eq Br₂ or Cl₂trans-DihaloalkeneAnti addition via halonium ion
Acid-catalyzed hydrationH₂O, H₂SO₄, HgSO₄Ketone (Markovnikov enol)Markovnikov; enol tautomerizes
Hydroboration–oxidation1) Sia₂BH 2) H₂O₂, NaOHAldehyde (from terminal)Anti-Markovnikov; syn addition of B–H

Comprehensive classification of alkyne addition reactions by reagent, product, and stereochemical outcome.

💡

Regiochemistry Tip

For terminal alkynes, remember that acid-catalyzed hydration (HgSO₄/H₂SO₄/H₂O) gives the Markovnikov product (a methyl ketone), while hydroboration–oxidation (Sia₂BH, then H₂O₂/NaOH) gives the anti-Markovnikov product (an aldehyde). These two hydration methods are complementary—know both to solve synthesis problems involving carbonyl targets from alkynes.

SECTION 6

Worked Example: Synthesis of cis-3-Hexene

Suppose you need to synthesize cis-3-hexene from 3-hexyne. This is a classic application of Lindlar hydrogenation. The following worked example demonstrates how to analyze the problem retrosynthetically, choose the correct reagent, and predict the product stereochemistry.

From 3-Hexyne to cis-3-Hexene

  1. 1

    Step 1 — Identify the Target and Starting Material

    The target is cis-3-hexene (CH₃CH₂CH=CHCH₂CH₃, Z configuration). The starting material is 3-hexyne (CH₃CH₂C≡CCH₂CH₃), an internal alkyne with identical substituents on each side of the triple bond. We need a partial reduction that converts the triple bond into a cis double bond.
    Target: cis-3-hexene; Starting material: 3-hexyne.
  2. 2

    Step 2 — Choose the Correct Reagent

    A cis-alkene from an alkyne requires syn delivery of H₂. The Lindlar catalyst (Pd on CaCO₃ poisoned with Pb(OAc)₂ and quinoline) accomplishes exactly this: it permits the addition of one equivalent of H₂ across the triple bond and releases the product before the second equivalent can add. If we used Pd/C or Pt without poisoning, both equivalents of H₂ would add, giving hexane instead.
    Reagent: H₂, Lindlar catalyst.
  3. 3

    Step 3 — Predict Stereochemistry

    Both hydrogen atoms are delivered from the metal surface to the same face of the triple bond (syn addition). This ensures that the two ethyl groups end up on the same side of the resulting double bond, giving the Z (cis) isomer. No E isomer is formed in this reaction.
    Product: (Z)-3-hexene (cis-3-hexene).
  4. 4

    Step 4 — Verify by Considering the Alternative

    If instead the problem asked for trans-3-hexene, we would use Na in liquid NH₃ (dissolving metal reduction). The radical anion mechanism delivers hydrogen atoms from opposite faces (anti addition), yielding the E isomer. The ability to select cis or trans from the same alkyne starting material by merely changing the reducing conditions is one of the most powerful features of alkyne chemistry.
    Confirmation: Lindlar → cis; Na/NH₃ → trans.

SECTION 7

Comparing Alkyne Reduction Methods

Choosing among the available alkyne reduction methods requires careful consideration of the desired product stereochemistry, functional group tolerance, and practical convenience. The table below presents a side-by-side comparison of the three principal reduction approaches, highlighting their strengths and limitations in a synthetic context.

FeatureLindlar HydrogenationDissolving Metal (Na/NH₃)Full Hydrogenation (Pd/C, Pt)
Productcis-Alkene (Z)trans-Alkene (E)Alkane
StereochemistrySyn additionAnti additionSyn addition (both steps)
MechanismHeterogeneous catalysis on poisoned Pd surfaceRadical anion (e⁻, H⁺, e⁻, H⁺ sequence)Heterogeneous catalysis on active metal surface
StrengthsHigh cis-selectivity; mild conditions (room temperature, 1 atm H₂)Exclusive trans-selectivity; no catalyst needed (stoichiometric Na)Complete, reliable reduction; very simple setup
LimitationsRisk of over-reduction if catalyst quality varies; quinoline may complicate purificationRequires liquid NH₃ (−33 °C, hazardous); reactive Na is pyrophoricNo stereochemical control—always goes to alkane; incompatible if alkene is desired
FG ToleranceMay reduce other alkenes or alkynes present; halides generally toleratedIncompatible with protic groups that react with Na; aromatic rings may undergo Birch reductionReduces all C=C and C≡C bonds; may cleave C–X bonds (hydrogenolysis)

Comparison of three major alkyne reduction methods by stereochemistry, mechanism, and practical considerations.

✦

KEY TAKEAWAY

Selecting a reduction method for an alkyne is analogous to choosing a tool in a machine shop: a fine-grit polisher (Lindlar catalyst) smoothly brings the triple bond down to a cis-alkene without going further, a specialized reverse-threading tool (Na/NH₃) twists the geometry into a trans-alkene, and a heavy-duty grinder (Pd/C with excess H₂) removes all unsaturation entirely. Matching the tool to the desired output—cis-alkene, trans-alkene, or alkane—is the essence of strategic synthetic planning with alkynes.

SECTION 8

Connections to Advanced Alkyne Chemistry

The addition and reduction reactions covered in this lesson form the foundational layer upon which more advanced alkyne transformations are built. In Organic Chemistry 2 and beyond, you will encounter reactions that exploit the terminal alkyne C–H acidity (pKa ≈ 25) to form acetylide anions (RC≡C⁻), which serve as powerful carbon nucleophiles in SN2 reactions and additions to carbonyls. The ability to first extend a carbon chain using an acetylide and then selectively reduce the resulting internal alkyne to a cis- or trans-alkene is a strategy that appears repeatedly in total synthesis.

Concept (This Lesson)Advanced Extension
Lindlar hydrogenation → cis-alkeneUsed in synthesis of Z-configured pheromones and fatty acids (e.g., bombykol synthesis)
Na/NH₃ → trans-alkeneKey step in E-configured natural product synthesis and Birch reduction methodology
Hydroboration → aldehydeGateway to oxidation state manipulation; connects to Suzuki coupling via vinyl boranes
HX addition → vinyl halideVinyl halides are substrates for cross-coupling reactions (Heck, Stille, Negishi)
Markovnikov vs. anti-Markovnikov hydrationControls aldehyde vs. ketone selectivity in retrosynthetic disconnections

How the concepts in this lesson connect to advanced organic chemistry topics.

Looking forward, the principles of stereochemical control that you practice with alkyne reductions will recur in asymmetric catalysis, where chiral catalysts achieve enantioselective transformations. Modern semi-hydrogenation catalysts—including P-2 nickel boride, Rosenmund conditions, and transfer hydrogenation systems—represent active areas of research that extend the Lindlar paradigm into greener, more selective territory. Mastering the fundamentals covered here equips you to evaluate and apply these advanced methods.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

Explain why the Lindlar catalyst stops hydrogenation at the alkene stage rather than continuing to the alkane. What role do lead(II) acetate and quinoline play in modifying the catalyst's behavior?
Show answer
The Lindlar catalyst is palladium deposited on calcium carbonate and treated with lead(II) acetate and quinoline, which partially deactivate ("poison") the catalyst surface. Alkynes bind more strongly to metal surfaces than alkenes do because of their greater π-electron density. On the poisoned surface, the alkyne adsorbs, accepts one equivalent of H₂ via syn addition, and the resulting alkene—binding more weakly to the deactivated surface—desorbs before a second equivalent of H₂ can add. Without the lead and quinoline poisons, the palladium surface would remain active enough to retain the alkene and reduce it further to the alkane.

Question 2: BASIC CALCULATION

Predict the major product of the reaction of 1-butyne with one equivalent of HBr. Clearly indicate the regiochemistry and any E/Z stereochemistry considerations.
Show answer
Adding one equivalent of HBr to 1-butyne (CH₃CH₂C≡CH) follows Markovnikov's rule: the proton adds to the terminal carbon (C-1), and the bromide adds to the internal carbon (C-2). This generates 2-bromo-1-butene (CH₃CH₂CBr=CH₂), a vinyl bromide. Because C-1 bears two identical substituents (two H atoms), there is no E/Z isomerism at this carbon—the product is the Markovnikov vinyl bromide. If two equivalents of HBr were used, both bromines would add to C-2, yielding 2,2-dibromobutane (a geminal dibromide).

Question 3: INTERMEDIATE

Starting from 2-pentyne, show how you would prepare: (a) cis-2-pentene, (b) trans-2-pentene, and (c) pentane. Specify the reagents and conditions for each transformation.
Show answer
(a) To obtain cis-2-pentene (Z-2-pentene), treat 2-pentyne with H₂ and the Lindlar catalyst (Pd/CaCO₃, Pb(OAc)₂, quinoline). The syn addition of H₂ across the triple bond places both hydrogen atoms on the same face, yielding the Z isomer. (b) For trans-2-pentene (E-2-pentene), dissolve sodium metal in liquid ammonia at −33 °C and add 2-pentyne. The dissolving metal reduction proceeds via the radical anion mechanism, delivering hydrogens from opposite faces (anti addition) to give the E isomer. (c) For pentane, treat 2-pentyne with excess H₂ over an active catalyst such as Pd/C or Pt. Both π bonds are reduced in two sequential syn addition steps to afford the fully saturated alkane.

Question 4: APPLIED

A synthetic chemist needs to convert 1-hexyne into hexanal (CH₃(CH₂)₃CH₂CHO) in a single reaction sequence. Which reagent combination should be used, and why is the alternative hydration method (H₂O/H₂SO₄/HgSO₄) unsuitable for this target?
Show answer
The chemist should use hydroboration–oxidation: treat 1-hexyne with disiamylborane (Sia₂BH), which adds boron to the terminal carbon (C-1) in an anti-Markovnikov fashion, followed by oxidation with H₂O₂/NaOH. The resulting enol at C-1 tautomerizes to hexanal (an aldehyde). The bulky Sia₂BH is essential to prevent double hydroboration. The alternative acid-catalyzed hydration (H₂O/H₂SO₄/HgSO₄) follows Markovnikov's rule, placing the OH on the internal carbon (C-2) to give an enol that tautomerizes to 2-hexanone (a methyl ketone), not the desired aldehyde. Thus the regiochemistry of the two methods is complementary, and only the hydroboration route delivers the aldehyde from a terminal alkyne.

Question 5: CRITICAL THINKING

Propose a multi-step synthesis of (E)-3-heptene starting from acetylene (ethyne) and any necessary alkyl halides. Your synthesis should include carbon–carbon bond formation and a stereoselective reduction step. Justify each reagent choice.
Show answer
Step 1: Deprotonate acetylene with NaNH₂ in liquid NH₃ to form the sodium acetylide (HC≡C⁻ Na⁺). Step 2: Alkylate with 1-bromopentane via an Sₙ2 reaction to form 1-heptyne (CH₃(CH₂)₃C≡CH). Note: use a primary alkyl halide to favor Sₙ2 over elimination. Step 3: Deprotonate 1-heptyne again with NaNH₂ to form the lithium or sodium salt, then alkylate with iodomethane—but this gives 2-octyne, not 3-heptyne. Instead, modify the plan: in Step 2, alkylate with 1-bromobutane to give 1-hexyne, then deprotonate with NaNH₂ and alkylate with 1-bromopropane to yield 4-heptyne—but we need 3-heptyne. Correct route: form propynyl anion (CH₃C≡C⁻) by deprotonating propyne with NaNH₂, then alkylate with 1-bromobutane to give 3-heptyne (an internal alkyne). Step 4: Reduce 3-heptyne with Na in liquid NH₃ (dissolving metal reduction). The radical anion mechanism produces exclusively the trans (E) alkene. This yields (E)-3-heptene. Each step is justified: NaNH₂ is required for acetylide formation (pKₐ of terminal C–H ≈ 25), primary alkyl halides ensure Sₙ2 alkylation, and Na/NH₃ is the only standard method that reliably gives the trans-alkene.

SUMMARY

Lesson Summary

Summary

Alkynes undergo a rich set of addition reactions because their two π bonds can each react with an electrophilic or reducing agent. Partial reduction with the Lindlar catalyst (H₂, Pd/CaCO₃/Pb(OAc)₂/quinoline) delivers cis-alkenes via syn addition, while dissolving metal reduction (Na/NH₃) proceeds through a radical anion mechanism to give trans-alkenes via anti addition. Full catalytic hydrogenation with excess H₂ over Pd/C or Pt reduces alkynes completely to alkanes.

Electrophilic additions of HX follow Markovnikov's rule, producing vinyl halides with one equivalent and geminal dihalides with two. Acid-catalyzed hydration (HgSO₄/H₂SO₄) of terminal alkynes yields methyl ketones (Markovnikov), while hydroboration–oxidation (Sia₂BH, then H₂O₂/NaOH) provides aldehydes (anti-Markovnikov). Mastery of these transformations—and the ability to select the appropriate reagent for a desired stereochemical and regiochemical outcome—is essential for retrosynthetic analysis and multi-step synthesis planning in organic chemistry.

Varsity Tutors • Organic Chemistry 1 • Addition to Alkynes and Partial Reductions