Transcription & Translation — Transcription and translation (prokaryotic framing) - Microbiology

SECTION 1

Historical Context & Motivation

The story of how genetic information flows from DNA to RNA to protein is one of the most consequential narratives in modern biology. Before the molecular details were elucidated, geneticists understood that genes specified traits, but the biochemical mechanism linking a nucleotide sequence to a polypeptide chain remained profoundly mysterious. The resolution of this mystery—particularly through experiments conducted in prokaryotic model organisms such as Escherichia coli—laid the groundwork for the central dogma of molecular biology, a framework that continues to guide research in microbial genetics, synthetic biology, and biotechnology.

1958 • The Central Dogma

Francis Crick articulated the central dogma, proposing that information flows from DNA → RNA → protein, establishing the conceptual scaffold for understanding gene expression.

1960 • Discovery of mRNA

François Jacob and Jacques Monod hypothesized the existence of messenger RNA (mRNA) as a transient intermediate carrying genetic instructions from DNA to the ribosome. Sydney Brenner and colleagues provided experimental confirmation in E. coli.

1961 • The Genetic Code Cracked

Marshall Nirenberg and Heinrich Matthaei used cell-free E. coli extracts to demonstrate that poly-U RNA encodes polyphenylalanine, breaking the first codon of the genetic code.

1961 • The Lac Operon Model

Jacob and Monod described the operon model of gene regulation in E. coli, demonstrating how prokaryotes coordinate transcription of functionally related genes as a single polycistronic unit.

1966 • Complete Codon Table

The entire 64-codon table was resolved through the combined efforts of Nirenberg, Har Gobind Khorana, and Robert Holley, enabling researchers to predict protein sequences from DNA and mRNA.

These discoveries converged on a central question that remains at the heart of microbial genetics: how does a prokaryotic cell, lacking a nucleus and the elaborate RNA-processing machinery of eukaryotes, efficiently and accurately convert its genetic blueprint into functional proteins? The answer lies in the elegant coupling of transcription and translation—two processes that occur simultaneously in the bacterial cytoplasm, a feature with profound implications for gene regulation, antibiotic targeting, and evolutionary adaptation.

SECTION 2

Core Principles of Prokaryotic Gene Expression

Prokaryotic gene expression operates under a set of organizing principles that distinguish it sharply from the eukaryotic paradigm. The absence of a nuclear envelope is not merely a structural detail—it fundamentally shapes how bacteria manage information flow. Because DNA, ribosomes, and translation factors all coexist in the same compartment, a nascent mRNA transcript can be engaged by ribosomes before transcription is even complete. This coupled transcription-translation is a defining hallmark of prokaryotic biology, enabling rapid responses to environmental change and underpinning regulatory mechanisms such as attenuation.

No Nuclear Compartmentalization

Prokaryotes lack a nuclear membrane, so transcription and translation occur in the same cytoplasmic space. Ribosomes can bind the 5′ end of an mRNA while RNA polymerase is still extending its 3′ end.

Polycistronic mRNA

Many prokaryotic mRNAs encode multiple open reading frames (ORFs) organized in operons. A single transcription event produces a polycistronic transcript that is translated into several distinct proteins.

No Extensive mRNA Processing

Prokaryotic mRNA does not undergo 5′ capping, 3′ polyadenylation, or splicing. The primary transcript is the functional message—translation-ready as it emerges from RNA polymerase.

Sigma Factor Promoter Recognition

Transcription initiation depends on a dissociable sigma (σ) factor that directs the RNA polymerase core enzyme to specific promoter sequences, particularly at the −10 and −35 elements.

Shine-Dalgarno Sequence

Translation initiation in prokaryotes relies on the Shine-Dalgarno (SD) sequence in the 5′ UTR, which base-pairs with the anti-SD sequence on the 16S rRNA of the 30S ribosomal subunit to position the start codon.

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KEY TAKEAWAY

Think of prokaryotic gene expression as a factory floor where the blueprint printer (RNA polymerase) and the assembly line (ribosomes) operate side by side with no walls between them. In a eukaryotic cell, the blueprint is first printed in a private office (the nucleus), edited and stamped for approval (RNA processing), and then sent to the factory floor (cytoplasm) for assembly. In bacteria, workers on the assembly line can read the blueprint as it is being printed, producing finished goods with remarkable speed. This spatial coupling makes bacterial gene expression faster but also creates unique opportunities for regulation—and unique vulnerabilities that antibiotics exploit.

SECTION 3

Coupled Transcription-Translation: A Visual Overview

This diagram illustrates the simultaneous occurrence of transcription and translation in a prokaryotic cell. RNA polymerase (purple) moves along the DNA template strand, synthesizing the nascent mRNA (cyan). Multiple ribosomes attach to the 5′ end of the mRNA even before transcription is finished, forming a polysome (polyribosome). Each ribosome independently translates the message, with leading ribosomes producing longer polypeptides than those that attached more recently.

The diagram above captures the essential spatial logic of prokaryotic gene expression. Because no nuclear membrane separates the chromosome from the translation machinery, the 5′ end of the mRNA emerges from RNA polymerase directly into a ribosome-rich cytoplasm. Within seconds, the 30S ribosomal subunit identifies the Shine-Dalgarno sequence and recruits the 50S subunit to form a functional 70S ribosome. Additional ribosomes load onto the mRNA in succession, creating a polysome that maximizes protein output per transcript. This arrangement is not merely efficient—it is regulatory. For example, in the trp operon, the relative speed of the lead ribosome versus RNA polymerase determines whether a transcriptional terminator hairpin can form, a process called attenuation.

SECTION 4

Mechanism of Prokaryotic Transcription

The Prokaryotic RNA Polymerase Holoenzyme

The bacterial RNA polymerase (RNAP) is a multi-subunit enzyme with the core composition α₂ββ′ω. The core enzyme is catalytically competent for RNA synthesis but cannot recognize promoters on its own. Promoter recognition requires association with a sigma (σ) factor, yielding the holoenzyme (α₂ββ′ωσ). In E. coli, the primary sigma factor is σ⁷⁰ (RpoD), which recognizes the canonical −10 (TATAAT, the Pribnow box) and −35 (TTGACA) promoter elements. Alternative sigma factors such as σ³² (heat shock) or σ⁵⁴ (nitrogen limitation) redirect RNAP to specialized promoters, constituting a powerful mechanism of global gene regulation.

Three Phases of Transcription

Prokaryotic transcription proceeds through three phases: initiation, elongation, and termination. During initiation, the holoenzyme binds the promoter to form a closed complex, then melts approximately 12–14 base pairs of DNA around the −10 element to generate the open complex (transcription bubble). RNAP synthesizes short abortive transcripts (2–9 nt) before clearing the promoter. Upon promoter clearance, the sigma factor dissociates, and the core enzyme enters the elongation phase, adding ribonucleotides in the 5′ → 3′ direction at a rate of approximately 40–80 nucleotides per second. The enzyme reads the template strand 3′ → 5′, so the mRNA product is complementary and antiparallel to the template.

TRANSCRIPTION ELONGATION

(NMP)ₙ + NTP → (NMP)ₙ₊₁ + PPᵢ

Each nucleotide monophosphate (NMP) is added to the 3′-OH of the growing RNA chain using a nucleoside triphosphate (NTP) substrate. The release of pyrophosphate (PP_i) drives the reaction forward upon its subsequent hydrolysis by pyrophosphatase, making the reaction effectively irreversible (ΔG << 0).

Termination Mechanisms

Prokaryotes employ two principal termination strategies. Intrinsic (Rho-independent) termination relies on a GC-rich palindromic sequence in the nascent RNA that forms a stable stem-loop (hairpin) structure, followed by a run of uridine residues. The hairpin destabilizes the elongation complex, and the weak rU:dA base pairs facilitate RNA release. Rho-dependent termination involves the Rho (ρ) protein, an ATP-dependent RNA translocase that binds rut (Rho utilization) sites on the mRNA and translocates 5′ → 3′ toward the paused RNAP, unwinding the RNA–DNA hybrid within the transcription bubble and causing transcript release.

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Clinical Connection

Rifampicin, a cornerstone antibiotic for tuberculosis treatment, inhibits bacterial transcription by binding the β subunit of RNAP within the RNA exit channel. This blocks elongation after the first 2–3 nucleotides are incorporated. Because the human RNA polymerase II is structurally distinct, rifampicin achieves selective toxicity—a principle central to antimicrobial pharmacology.

SECTION 5

Prokaryotic Translation in Detail

Translation is the process by which the nucleotide sequence of mRNA is decoded into a polypeptide chain. In prokaryotes, the machinery is the 70S ribosome, composed of a small 30S subunit (16S rRNA + 21 proteins) and a large 50S subunit (23S rRNA, 5S rRNA + 31 proteins). The ribosome possesses three functional tRNA-binding sites: the A site (aminoacyl), the P site (peptidyl), and the E site (exit). Translation proceeds through initiation, elongation, and termination.

The 70S ribosome is shown straddling the mRNA with tRNAs occupying the P site and A site. The growing polypeptide chain extends from the P-site tRNA. The Shine-Dalgarno (SD) sequence upstream of the AUG start codon positions the ribosome correctly during initiation. The peptidyl transferase center in the 23S rRNA of the 50S subunit catalyzes peptide bond formation—making the ribosome fundamentally a ribozyme.

Initiation: A Prokaryote-Specific Process

Prokaryotic translation initiation is mechanistically distinct from the eukaryotic process. Three initiation factors (IF1, IF2, IF3) orchestrate assembly of the 30S initiation complex. IF3 prevents premature association of the 30S and 50S subunits and assists in start codon selection. IF2 is a GTPase that escorts the specialized initiator tRNA, fMet-tRNA^fMet, to the P site. Unlike eukaryotes that use unmodified methionyl-tRNA, bacteria formylate the amino group of the initiator methionine—producing N-formylmethionine (fMet). IF1 occupies the A site to prevent premature tRNA binding. Once the 30S initiation complex is assembled on the mRNA with fMet-tRNA^fMet positioned at the AUG codon, the 50S subunit joins, GTP is hydrolyzed, and all three IFs are released, yielding a functional 70S initiation complex.

Elongation and Termination

Elongation is a cyclical process involving three steps. First, an aminoacyl-tRNA is delivered to the A site in a ternary complex with EF-Tu and GTP. Codon–anticodon recognition triggers GTP hydrolysis, and EF-Tu dissociates; the aminoacyl-tRNA is accommodated in the A site. Second, the peptidyl transferase activity of the 23S rRNA catalyzes peptide bond formation, transferring the peptide from the P-site tRNA to the amino acid on the A-site tRNA. Third, EF-G•GTP drives translocation: the ribosome advances one codon along the mRNA, moving the deacylated tRNA from P to E and the peptidyl-tRNA from A to P. This cycle repeats at a rate of approximately 15–20 amino acids per second in E. coli. Termination occurs when a stop codon (UAA, UAG, or UGA) enters the A site. Release factors RF1 (recognizes UAA and UAG) or RF2 (recognizes UAA and UGA) bind the A site, stimulating hydrolysis of the ester bond between the polypeptide and the P-site tRNA. RF3•GTP then facilitates release of RF1/RF2. Ribosome recycling factor (RRF) and EF-G dissociate the 70S ribosome into its subunits for the next round.

SECTION 6

Worked Example: From Gene to Protein

Let us trace the expression of a hypothetical prokaryotic gene from its DNA template strand through transcription and translation. Consider the following segment of the coding (non-template) strand of a gene within an operon:

CODING STRAND (5′ → 3′)

5′-ATGCGUAAUCCGUGAUAA-3′

Note: This represents DNA, so uracil (U) should be thymine (T). Written here with standard DNA bases: 5′-ATGCGTAATCCGTGATAA-3′

Tracing Gene Expression: DNA → mRNA → Polypeptide

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Step 1 — Identify the Template Strand

The coding (sense) strand is given as: 5′-ATGCGTAATCCGTGATAA-3′. RNA polymerase reads the template (antisense) strand in the 3′ → 5′ direction. We derive the template strand by writing the complementary antiparallel sequence:

Template strand: 3′-TACGCATTAGGCACTAT T-5′
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Step 2 — Transcribe to mRNA

mRNA is synthesized 5′ → 3′ and is complementary to the template strand (and therefore identical to the coding strand, except that thymine is replaced by uracil). Reading the template strand 3′ → 5′, the mRNA sequence is:

mRNA: 5′-AUGCGUAAUCCGUGAUAA-3′
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Step 3 — Identify Codons

Starting from the AUG start codon, we read the mRNA in triplets: AUG | CGU | AAU | CCG | UGA | UAA. Note that UGA is a stop codon.

Codons: AUG – CGU – AAU – CCG – UGA(stop)
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Step 4 — Translate Using the Genetic Code

Using the standard genetic code table: AUG = fMet (in prokaryotes, the initiator is N-formylmethionine), CGU = Arg, AAU = Asn, CCG = Pro. Translation terminates at UGA. The formyl group on Met is typically removed post-translationally, and in many cases the Met itself is cleaved.

Polypeptide: fMet-Arg-Asn-Pro (tetrapeptide before processing)
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Step 5 — Consider the Biological Context

In a living E. coli cell, RF2 would recognize the UGA stop codon in the A site and trigger polypeptide release. Note that UAA follows UGA in this sequence—tandem stop codons are sometimes used to ensure efficient termination. The released polypeptide would undergo deformylation by peptide deformylase and potentially N-terminal methionine cleavage by methionine aminopeptidase if the second amino acid (Arg, in this case) does not block the enzyme.

Final mature peptide (after processing): Met-Arg-Asn-Pro or Arg-Asn-Pro

SECTION 7

Prokaryotic vs. Eukaryotic Gene Expression

Understanding the distinctive features of prokaryotic gene expression is most effectively accomplished by comparing it with the eukaryotic system. These differences are not merely academic curiosities—they underpin the selective toxicity of numerous antibiotics and define the experimental advantages that made bacteria the premier model systems for molecular biology.

Feature	Prokaryotes	Eukaryotes
Compartmentalization	No nucleus; transcription and translation occur in the cytoplasm simultaneously	Transcription in nucleus; translation in cytoplasm after mRNA export
mRNA structure	Polycistronic; no 5′ cap or 3′ poly-A tail; Shine-Dalgarno sequence for ribosome binding	Monocistronic; 5′ m⁷G cap and 3′ poly-A tail; Kozak sequence for initiation
RNA processing	Minimal; no splicing of mRNA (group I/II introns are rare exceptions)	Extensive; 5′ capping, splicing, 3′ polyadenylation
RNA Polymerase	Single RNAP (α₂ββ′ω) with interchangeable σ factors	Three RNAPs (I, II, III) with distinct promoter specificities
Ribosome	70S (30S + 50S); initiator tRNA carries fMet	80S (40S + 60S); initiator tRNA carries Met (no formylation)
Coupled transcription-translation	Yes—ribosomes translate nascent mRNA co-transcriptionally	No—spatial and temporal separation due to nuclear envelope
Antibiotic targets	Rifampicin (β subunit), chloramphenicol (50S), tetracycline (30S), erythromycin (50S exit tunnel)	α-Amanitin (Pol II); cycloheximide (60S); not clinical antibiotics

Key differences between prokaryotic and eukaryotic gene expression

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WHY IT MATTERS

The structural and mechanistic differences between prokaryotic and eukaryotic gene expression are the biochemical basis for selective antibiotic toxicity. Chloramphenicol inhibits the peptidyl transferase center of the bacterial 50S subunit but has negligible affinity for the human 60S subunit. Tetracycline blocks aminoacyl-tRNA binding to the bacterial 30S A site but does not effectively penetrate eukaryotic ribosomes. These differences allow clinicians to kill or inhibit bacterial pathogens while minimizing harm to the host—a principle analogous to a locksmith who can pick a specific lock because its mechanism is fundamentally different from every other lock in the building.

SECTION 8

Connection to Gene Regulation & Advanced Concepts

The basic framework of prokaryotic transcription and translation serves as the foundation for understanding more sophisticated regulatory phenomena. Because the two processes are physically coupled, bacteria have evolved regulatory strategies that exploit this coupling in ways that are impossible in eukaryotes. Three particularly important advanced topics build directly on the material covered here: operons and regulons, transcriptional attenuation, and riboswitch-mediated regulation.

Concept	Foundation from This Lesson	Advanced Extension
Operon regulation	Polycistronic mRNA; single promoter controls multiple genes	Repressors, activators, and two-component systems modulate transcription initiation at operon promoters
Attenuation (trp operon)	Coupled transcription-translation; ribosome follows RNAP	Ribosome stalling at Trp codons alters mRNA secondary structure, determining terminator vs. antiterminator formation
Riboswitches	5′ UTR of mRNA; untranslated leader sequences	Metabolite binding to structured mRNA elements in the 5′ UTR controls transcription termination or translation initiation without protein factors
Small regulatory RNAs (sRNAs)	Shine-Dalgarno sequence is essential for translation initiation	sRNAs base-pair with or near the SD sequence, blocking 30S binding and inhibiting translation; Hfq chaperone facilitates pairing
CRISPR-Cas systems	Transcription of CRISPR arrays; translation of Cas proteins	Adaptive immunity in prokaryotes; crRNA-guided nucleases target foreign DNA—the basis for genome editing technology

From basic gene expression to advanced regulatory concepts

Looking forward, the principles of prokaryotic transcription and translation are not only essential for understanding natural bacterial physiology but also for the rapidly growing field of synthetic biology. Engineered promoters, ribosome binding sites, and codon-optimized sequences are the building blocks of genetic circuits constructed in bacteria. Mastery of the molecular details of prokaryotic gene expression—the sigma factors, the Shine-Dalgarno interaction, the elongation factor cycle—provides the mechanistic vocabulary required to design, troubleshoot, and optimize these synthetic systems.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

Explain why coupled transcription-translation is possible in prokaryotes but not in eukaryotes. What structural feature of the eukaryotic cell prevents this coupling, and what are two consequences of this spatial separation for eukaryotic gene expression?

Show answer

Prokaryotes lack a nuclear envelope, so DNA, RNA polymerase, and ribosomes all occupy the same cytoplasmic compartment. This allows ribosomes to bind the 5′ end of a nascent mRNA while RNA polymerase is still transcribing the 3′ end, enabling coupled transcription-translation. In eukaryotes, the nuclear envelope physically separates the site of transcription (nucleus) from the site of translation (cytoplasm). Two key consequences of this spatial separation are: (1) eukaryotic pre-mRNA must undergo extensive processing—5′ capping, splicing, and 3′ polyadenylation—before export to the cytoplasm, adding layers of post-transcriptional regulation absent in prokaryotes; and (2) regulatory mechanisms that depend on coupling, such as transcriptional attenuation in the trp operon, are not available to eukaryotes, which instead rely on alternative regulatory strategies such as alternative splicing and miRNA-mediated translational repression.

Question 2: BASIC CALCULATION

A prokaryotic gene is 3,000 base pairs long. If RNA polymerase transcribes at a rate of 60 nucleotides per second and ribosomes translate at 15 amino acids per second, calculate: (a) the time to complete transcription of this gene, and (b) the time required for translation of the resulting mRNA (assume the entire ORF is 3,000 nt, beginning with AUG and ending with a stop codon).

Show answer

(a) Transcription time = 3,000 nt ÷ 60 nt/s = 50 seconds. (b) The mRNA encodes 3,000 ÷ 3 = 1,000 codons. Subtracting the stop codon, the polypeptide is 999 amino acids long. Translation time = 999 aa ÷ 15 aa/s ≈ 66.6 seconds. Note that due to coupled transcription-translation, the ribosome begins translating before transcription finishes. The ribosome consumes 3 nucleotides per amino acid, equivalent to 15 × 3 = 45 nucleotides per second of mRNA—slower than the 60 nt/s transcription rate. Therefore, RNAP stays ahead of the ribosome, and the total time from initiation of transcription to completion of translation of the first polypeptide is approximately 50 s (transcription finishes) plus the remaining translation time for the last portion of mRNA that RNAP produced in the final seconds.

Question 3: INTERMEDIATE

A microbiologist isolates a mutant strain of E. coli in which the anti-Shine-Dalgarno sequence at the 3′ end of the 16S rRNA has been partially deleted. Predict the effect of this mutation on (a) transcription, (b) translation initiation, and (c) growth rate of the bacterium. Justify each prediction.

Show answer

(a) Transcription would be unaffected because the anti-Shine-Dalgarno sequence is part of the ribosomal RNA, not the RNA polymerase machinery. Promoter recognition, elongation, and termination proceed normally. (b) Translation initiation would be severely impaired. The Shine-Dalgarno (SD) sequence on the mRNA base-pairs with the anti-SD sequence on the 16S rRNA to position the AUG start codon correctly in the P site. Deletion of the anti-SD sequence would prevent or weaken this critical interaction, leading to reduced ribosome recruitment and impaired start codon recognition. Some mRNAs with strong SD complementarity to the remaining sequence may still be translated at reduced efficiency, while those with weaker SD sequences would be disproportionately affected. (c) Growth rate would be dramatically reduced because global protein synthesis rates depend on efficient translation initiation. The mutant would likely exhibit slow growth, potentially lethal depending on the extent of the deletion, since the cell cannot produce essential proteins at sufficient rates.

Question 4: APPLIED

You are designing a recombinant gene for expression in E. coli. The gene encodes a human protein. List four specific sequence elements you must engineer into the construct to ensure efficient transcription and translation in the bacterial host. For each element, explain why it is necessary and what would happen if it were absent or suboptimal.

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(1) A strong σ⁷⁰ promoter (e.g., Ptac, PT7): Necessary because E. coli RNA polymerase requires recognizable −35 and −10 elements for transcription initiation. Without a functional promoter, RNAP cannot bind and no mRNA is produced. (2) A Shine-Dalgarno sequence positioned 5–10 nt upstream of the AUG start codon: Required for 30S ribosomal subunit recruitment. Human genes lack SD sequences because eukaryotic translation uses cap-dependent scanning. Without an engineered SD sequence, the E. coli ribosome cannot efficiently locate the start codon, and protein yield will be negligible. (3) Codon optimization for E. coli codon usage: Human genes may contain codons rarely used in E. coli, corresponding to low-abundance tRNAs. Rare codons cause ribosome stalling, premature termination, and reduced protein yield. Replacing rare codons with synonymous high-usage E. coli codons ensures smooth translation elongation. (4) A transcription terminator downstream of the stop codon (e.g., rrnB T1T2 terminators): Without a terminator, RNAP reads through into downstream sequences, potentially generating antisense transcripts or destabilizing the plasmid. An efficient terminator ensures defined mRNA 3′ ends and prevents interference with other genetic elements on the vector.

Question 5: CRITICAL THINKING

The antibiotic chloramphenicol inhibits peptidyl transferase activity on bacterial 50S subunits, while rifampicin inhibits bacterial RNA polymerase. Predict the molecular consequences of treating an actively growing E. coli culture with (a) chloramphenicol alone, (b) rifampicin alone, and (c) both antibiotics simultaneously. Specifically, consider what happens to ongoing transcription, ongoing translation, polysome structure, and mRNA levels in each scenario.

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(a) Chloramphenicol alone: Translation elongation halts because peptide bond formation is blocked; ribosomes freeze on mRNA, stabilizing polysomes in a 'frozen' state. Transcription continues unimpeded because chloramphenicol does not affect RNA polymerase. However, a subtle consequence of the coupling mechanism arises: without translating ribosomes keeping pace with RNAP, the nascent mRNA may form secondary structures or be accessible to Rho factor, potentially increasing Rho-dependent termination at some loci. New mRNA accumulates initially but is rapidly degraded by RNases (bacterial mRNA has a short half-life of ~2–5 min). (b) Rifampicin alone: New transcription initiation is blocked because rifampicin traps RNAP after the first 2–3 phosphodiester bonds are formed. However, RNAP molecules that have already entered elongation are not affected (rifampicin only blocks the RNA exit channel during early initiation). Therefore, existing transcription elongation complexes complete their transcripts, and existing polysomes continue translating until their mRNAs are degraded. Over minutes, mRNA levels decline as existing transcripts are degraded and no new ones are made. Polysomes progressively run off and disassemble. (c) Both antibiotics simultaneously: Transcription initiation is blocked (rifampicin), and translation elongation is frozen (chloramphenicol). The combined effect is a rapid cessation of all new gene expression. Existing polysomes are frozen in place by chloramphenicol and cannot complete translation, while elongating RNAP molecules may finish their transcripts but no new mRNAs are initiated. The net result is a comprehensive shutdown of both processes, which is why this combination is bacteriostatic rather than synergistic—chloramphenicol's bacteriostatic effect can actually antagonize bactericidal agents by preventing the active cellular processes that some cidal drugs require to exert lethal damage.

SUMMARY

Lesson Summary

Summary

Prokaryotic gene expression is distinguished by the coupled transcription-translation made possible by the absence of a nuclear envelope. Transcription is carried out by a single RNA polymerase holoenzyme (α₂ββ′ωσ) that recognizes promoters via interchangeable sigma factors and proceeds through initiation (open complex formation, abortive cycling, promoter clearance), elongation (5′→3′ RNA synthesis at ~40–80 nt/s), and termination (intrinsic hairpin-dependent or Rho-dependent mechanisms). The resulting mRNA is often polycistronic and requires no capping, splicing, or polyadenylation before it can be translated.

Translation on the 70S ribosome (30S + 50S) initiates when the Shine-Dalgarno sequence on the mRNA pairs with the anti-SD on 16S rRNA, positioning the AUG start codon in the P site for binding by fMet-tRNA. Elongation involves a cyclical process of aminoacyl-tRNA delivery (EF-Tu), peptide bond formation (by the 23S rRNA ribozyme), and translocation (EF-G) at ~15–20 amino acids per second. Termination is triggered by release factors (RF1, RF2) at stop codons. Multiple ribosomes form polysomes on a single mRNA, maximizing protein output. The structural differences between bacterial and eukaryotic transcription and translation machinery provide the molecular basis for antibiotic selective toxicity and form the foundation for understanding operon regulation, attenuation, riboswitches, and synthetic biology applications.