Light as Electromagnetic Radiation (4D)
MCAT · Flashcards · Application
MCAT · FLASHCARDS
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QUESTION
What is the photon energy in eV for
λ
=
620
nm
\lambda = 620\ \text{nm}
λ
=
620
nm
using
h
c
=
1240
eV
⋅
nm
hc=1240\ \text{eV}\cdot\text{nm}
h
c
=
1240
eV
⋅
nm
?
QUESTION
A photon has energy
4.0
eV
4.0\ \text{eV}
4.0
eV
. What is its wavelength in nm using
h
c
=
1240
eV
⋅
nm
hc=1240\ \text{eV}\cdot\text{nm}
h
c
=
1240
eV
⋅
nm
?
QUESTION
Light goes from air
n
1
=
1.00
n_1=1.00
n
1
=
1.00
into glass
n
2
=
1.50
n_2=1.50
n
2
=
1.50
. What is the speed in glass using
c
=
3.0
×
10
8
m/s
c=3.0\times 10^8\ \text{m/s}
c
=
3.0
×
1
0
8
m/s
?
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ANSWER
v
=
2.0
×
10
8
m/s
v = 2.0\times 10^8\ \text{m/s}
v
=
2.0
×
1
0
8
m/s
. Speed in the medium is vacuum speed divided by the refractive index of glass, yielding the given velocity.
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