Population Genetics and Hardy–Weinberg (1C)
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QUESTION
If
q
2
=
0.09
q^2 = 0.09
q
2
=
0.09
for an autosomal recessive disease in Hardy–Weinberg, what is
q
q
q
?
QUESTION
If
q
2
=
0.09
q^2 = 0.09
q
2
=
0.09
in Hardy–Weinberg, what is the carrier frequency
2
p
q
2pq
2
pq
?
QUESTION
If
p
=
0.80
p = 0.80
p
=
0.80
under Hardy–Weinberg, what are the expected frequencies of
A
A
AA
AA
and
a
a
aa
aa
?
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ANSWER
A
A
:
p
2
=
0.64
AA: p^2 = 0.64
AA
:
p
2
=
0.64
;
a
a
:
q
2
=
0.04
aa: q^2 = 0.04
aa
:
q
2
=
0.04
. Homozygous frequencies are squares of their respective allele frequencies in equilibrium.
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