Photoelectric Effect and Line Spectra (4E) - Chem & Physics

  1. State the formula for photon energy emitted or absorbed for a hydrogen transition ni→nfn_i\to n_f.
    ΔE=13.6 eV(1nf2−1ni2)\Delta E=13.6\ \text{eV}\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right). Energy difference between levels determines photon energy in transitions, positive for emission when ni>nfn_i>n_f.
  2. Which quantity must exceed the work function ϕ\phi for photoemission to occur?
    Photon energy hfhf must be ≥ϕ\geq \phi. Photoemission requires photon energy at least equal to work function to overcome electron binding energy.
  3. Which hydrogen series corresponds to transitions ending at nf=1n_f=1?
    Lyman series. Lyman series involves transitions to ground state, producing UV lines.
  4. Which hydrogen series corresponds to transitions ending at nf=3n_f=3?
    Paschen series. Paschen series involves transitions to n=3, producing infrared lines.
  5. Which direction of transition produces emission: ni>nfn_i>n_f or ni<nfn_i<n_f?
    Emission occurs for ni>nfn_i>n_f. Electron dropping to lower energy level releases photon energy equal to level difference.
  6. What is the Bohr energy formula for hydrogen energy level nn?
    En=−13.6 eVn2E_n=-\frac{13.6\ \text{eV}}{n^2}. Bohr model quantizes hydrogen electron energies, negative due to bound states relative to ionization.
  7. What is the physical meaning of the stopping potential VsV_s in a photoelectric experiment?
    Retarding voltage that reduces photocurrent to zero. Stopping potential opposes kinetic energy of fastest photoelectrons, halting them at collector.
  8. What is the physical meaning of the work function ϕ\phi in the photoelectric effect?
    Minimum energy required to eject an electron from a metal. Work function represents binding energy of least-bound electrons in metal surface.
  9. What is the threshold frequency f0f_0 in terms of work function ϕ\phi?
    f0=ϕhf_0=\frac{\phi}{h}. Threshold frequency is work function divided by Planck's constant, where photon energy just equals ϕ\phi.
  10. What is the photoelectric equation relating Kmax⁡K_{\max}, hfhf, and work function ϕ\phi?
    Kmax⁡=hf−ϕK_{\max}=hf-\phi. Maximum kinetic energy of photoelectrons equals photon energy minus work function, per Einstein's explanation.
  11. What is the slope and xx-intercept of a plot of stopping potential VsV_s versus ff?
    Slope he\frac{h}{e}; xx-intercept f0=ϕhf_0=\frac{\phi}{h}. From Vs=hef−ϕeV_s=\frac{h}{e}f - \frac{\phi}{e}, slope is h/eh/e and x-intercept is threshold frequency.
  12. Which direction of transition produces absorption: ni>nfn_i>n_f or ni<nfn_i<n_f?
    Absorption occurs for ni<nfn_i<n_f. Electron jumping to higher energy level requires absorbing photon energy matching level difference.
  13. What is the formula for photon energy in terms of frequency ff?
    E=hfE=hf. Photon energy equals Planck's constant times frequency, linking wave and particle properties of light.
  14. What is the stopping potential relation between Kmax⁡K_{\max} and VsV_s for an electron?
    Kmax⁡=eVsK_{\max}=eV_s. Maximum kinetic energy equals electron charge times stopping potential, converting KE to potential energy.
  15. What is the threshold wavelength λ0\lambda_0 in terms of work function ϕ\phi?
    λ0=hcϕ\lambda_0=\frac{hc}{\phi}. Threshold wavelength is Planck's constant times speed of light divided by work function, longest λ\lambda for emission.
  16. What is the formula for VsV_s in terms of hfhf and ϕ\phi?
    Vs=hf−ϕeV_s=\frac{hf-\phi}{e}. Stopping potential equals photon energy minus work function divided by electron charge, from Kmax⁡=eVsK_{\max}=eV_s.
  17. Identify the photon with higher energy: one with λ=400 nm\lambda=400\ \text{nm} or λ=800 nm\lambda=800\ \text{nm}.
    λ=400 nm\lambda=400\ \text{nm} photon has higher energy. Photon energy inversely proportional to wavelength, so shorter λ\lambda has higher energy.
  18. Identify what changes when light intensity increases at fixed f>f0f>f_0 in the photoelectric effect.
    Photoelectron number (current) increases; Kmax⁡K_{\max} unchanged. Higher intensity provides more photons, ejecting more electrons and increasing current, but photon energy fixes Kmax⁡K_{\max}.
  19. Identify what changes when frequency ff increases at fixed intensity in the photoelectric effect.
    Kmax⁡K_{\max} and VsV_s increase; emission requires f≥f0f\geq f_0. Higher frequency increases photon energy, raising Kmax⁡K_{\max} and VsV_s if above threshold for emission.
  20. Which graph is linear for photoelectric data: Kmax⁡K_{\max} vs ff or Kmax⁡K_{\max} vs intensity?
    Kmax⁡K_{\max} vs ff is linear with slope hh. Kmax⁡K_{\max} increases linearly with frequency per photoelectric equation, unlike independence from intensity.
  21. What is the formula for the speed of light in terms of λ\lambda and ff?
    c=λfc=\lambda f. Speed of light equals wavelength times frequency for electromagnetic waves in vacuum.
  22. Which hydrogen series corresponds to transitions ending at nf=2n_f=2 (visible region)?
    Balmer series. Balmer series involves transitions to n=2, yielding visible wavelengths.
  23. What is the Rydberg formula for the wavelength of a hydrogen spectral line?
    1λ=R(1nf2−1ni2)\frac{1}{\lambda}=R\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right). Rydberg formula derives from Bohr energy differences, with RR as constant for hydrogen spectral lines.
  24. What is the slope and yy-intercept of a plot of Kmax⁡K_{\max} versus ff?
    Slope hh; intercept −ϕ-\phi. From Kmax⁡=hf−ϕK_{\max}=hf-\phi, slope is Planck's constant and y-intercept is negative work function.
  25. What is the formula for photon energy in terms of wavelength λ\lambda?
    E=hcλE=\frac{hc}{\lambda}. Photon energy is Planck's constant times speed of light divided by wavelength, derived from E=hfE=hf and c=λfc=\lambda f.

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