Light as Electromagnetic Radiation (4D) - Chem & Physics

  1. Which option correctly orders electromagnetic radiation from lowest to highest frequency?
    Radio < microwave < IR < visible < UV < X-ray < gamma. The electromagnetic spectrum is ordered by increasing frequency, which corresponds to increasing energy and decreasing wavelength.
  2. What is the relationship between wavelength, frequency, and wave speed for light in vacuum?
    c=λfc = \lambda f. The wave speed in vacuum equals the product of wavelength and frequency for electromagnetic radiation.
  3. State the formula for photon energy in terms of wavelength.
    E=hcλE = \frac{hc}{\lambda}. Derived from E=hfE=hf and c=lambdafc=lambda f, photon energy is inversely proportional to wavelength.
  4. When light enters a medium with higher refractive index, what changes: speed, frequency, wavelength?
    Speed decreases; frequency stays constant; wavelength decreases. Upon entering a denser medium, light speed decreases while frequency remains constant, resulting in shorter wavelength.
  5. What is the condition for total internal reflection in terms of indices of refraction?
    Light must go from higher to lower nn: n1>n2n_1 > n_2. Total internal reflection requires light traveling from a medium of higher refractive index to one of lower index.
  6. What is Planck's constant to two significant figures for MCAT use?
    h≈6.6×10−34 J⋅sh \approx 6.6 \times 10^{-34}\ \text{J}\cdot\text{s}. This approximate value of Planck's constant is used in quantum mechanics calculations for energy-frequency relations.
  7. Light goes from air n1=1.00n_1=1.00 into glass n2=1.50n_2=1.50. What is the speed in glass using c=3.0×108 m/sc=3.0\times 10^8\ \text{m/s}?
    v=2.0×108 m/sv = 2.0\times 10^8\ \text{m/s}. Speed in the medium is vacuum speed divided by the refractive index of glass, yielding the given velocity.
  8. State Einstein's photoelectric equation for maximum kinetic energy of emitted electrons.
    Kmax⁡=hf−ϕK_{\max} = hf - \phi. In the photoelectric effect, maximum kinetic energy is incident photon energy minus the work function.
  9. A photon has energy 4.0 eV4.0\ \text{eV}. What is its wavelength in nm using hc=1240 eV⋅nmhc=1240\ \text{eV}\cdot\text{nm}?
    λ=310 nm\lambda = 310\ \text{nm}. Wavelength in nm is found by dividing hchc by energy in eV, producing the indicated wavelength.
  10. What is the approximate speed of light in vacuum used for MCAT calculations?
    c≈3.0×108 m/sc \approx 3.0 \times 10^8\ \text{m/s}. This value represents the constant speed at which light travels in vacuum, fundamental for wave calculations.
  11. What is the index of refraction in terms of light speeds in vacuum and in a medium?
    n=cvn = \frac{c}{v}. Refractive index quantifies the reduction in light speed within a medium relative to vacuum.
  12. What is the photon energy in eV for λ=620 nm\lambda = 620\ \text{nm} using hc=1240 eV⋅nmhc=1240\ \text{eV}\cdot\text{nm}?
    E=2.0 eVE = 2.0\ \text{eV}. Photon energy in eV is obtained by dividing hchc by wavelength in nm, giving the stated energy.
  13. State the critical angle formula for total internal reflection from n1n_1 to n2n_2 with n1>n2n_1>n_2.
    sin⁡θc=n2n1\sin\theta_c = \frac{n_2}{n_1}. The critical angle occurs when the refracted angle is 90 degrees, leading to total internal reflection for larger incident angles.
  14. Identify the wavelength of a 5.0×1014 Hz5.0\times 10^{14}\ \text{Hz} photon in vacuum using c=3.0×108 m/sc=3.0\times 10^8\ \text{m/s}.
    λ=6.0×10−7 m\lambda = 6.0\times 10^{-7}\ \text{m}. Wavelength is calculated as speed of light divided by frequency, yielding the given value.
  15. Identify the formula for the momentum of a photon in terms of wavelength.
    p=hλp = \frac{h}{\lambda}. Photon momentum arises from wave-particle duality, equaling Planck's constant divided by wavelength.
  16. What is the intensity trend with distance for a point light source in free space?
    I∝1r2I \propto \frac{1}{r^2}. Intensity follows the inverse square law as power spreads over the surface area of an expanding sphere.
  17. What happens to photon energy when wavelength decreases?
    Photon energy increases because E∝1λE \propto \frac{1}{\lambda}. Photon energy is inversely proportional to wavelength, so decreasing wavelength increases energy.
  18. What is the work function relationship for photoelectric emission in terms of threshold frequency?
    ϕ=hf0\phi = hf_0. The work function equals the energy of photons at the threshold frequency for electron emission.
  19. What is the photon momentum in terms of energy for light in vacuum?
    p=Ecp = \frac{E}{c}. For photons, relativistic energy-momentum relation simplifies to momentum as energy divided by speed of light.
  20. State the formula for photon energy in terms of frequency.
    E=hfE = hf. Photon energy is directly proportional to its frequency, with Planck's constant as the proportionality factor.
  21. What is hchc in convenient units for spectroscopy calculations?
    hc≈1240 eV⋅nmhc \approx 1240\ \text{eV}\cdot\text{nm}. This product enables straightforward computation of photon energy in electronvolts from wavelength in nanometers.
  22. Identify the frequency of 600 nm600\ \text{nm} light in vacuum using c=3.0×108 m/sc=3.0\times 10^8\ \text{m/s}.
    f=5.0×1014 Hzf = 5.0\times 10^{14}\ \text{Hz}. Frequency is determined by dividing speed of light by wavelength, resulting in the specified value.
  23. What type of wave is electromagnetic radiation in terms of field orientation and direction of travel?
    A transverse wave; E⃗\vec{E} and B⃗\vec{B} are perpendicular to propagation. Electromagnetic waves are transverse because the electric and magnetic fields oscillate perpendicular to the direction of wave propagation.
  24. State Snell's law relating incident and refracted angles and refractive indices.
    n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1 = n_2\sin\theta_2. Snell's law governs refraction by equating the products of refractive indices and sines of angles across an interface.
  25. What is the relationship between frequency and wavelength for light in a fixed medium?
    f∝1λf \propto \frac{1}{\lambda} because v=λfv = \lambda f with fixed vv. With constant wave speed in a medium, frequency and wavelength maintain an inverse proportionality.

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