Buoyancy and Archimedes’ Principle (4B) - Chem & Physics

  1. What is the equilibrium force balance for a floating object (neglecting surface tension)?
    FB=WF_B=W. At equilibrium, the buoyant force upward equals the object's weight downward for a floating object.
  2. What is the buoyant force on a fully submerged object of volume VV in a fluid of density ρ\rho?
    FB=ρVgF_B=\rho V g. Buoyant force equals the weight of displaced fluid, calculated as fluid density times object volume times gravity.
  3. What is the volume displaced by an object that is fully submerged in a fluid?
    Vdisp=VobjV_{\text{disp}}=V_{\text{obj}}. For fully submerged objects, the displaced volume equals the entire object volume.
  4. What is the formula for the weight of a displaced fluid volume VdispV_{\text{disp}}?
    Wdisp=ρfluidVdispgW_{\text{disp}}=\rho_{\text{fluid}}V_{\text{disp}}g. Weight equals mass times gravity, where mass is the product of fluid density and displaced volume.
  5. An object has ρobj=800 kg/m3\rho_{\text{obj}}=800\,\text{kg/m}^3 in water. What fraction of its volume is submerged when floating?
    0.800.80. Submerged fraction equals object density divided by water density for floating objects.
  6. A 1.0 kg1.0\,\text{kg} object experiences FB=3 NF_B=3\,\text{N}. What is its apparent weight in the fluid using g=10 m/s2g=10\,\text{m/s}^2?
    7 N7\,\text{N}. Apparent weight equals actual weight minus buoyant force, reducing effective downward force.
  7. A cube of volume 1.0×10−3 m31.0\times10^{-3}\,\text{m}^3 floats in oil with ρ=800 kg/m3\rho=800\,\text{kg/m}^3. What is its maximum mass?
    0.80 kg0.80\,\text{kg}. Maximum mass for floating occurs when object density equals oil density, so mass is oil density times volume.
  8. What is the formula for buoyant force on a fully submerged object in a fluid?
    FB=ρfluidVdispgF_B=\rho_{\text{fluid}}V_{\text{disp}}g. Archimedes' principle states that the buoyant force equals the weight of the fluid displaced by the submerged volume.
  9. What is the formula for the pressure difference across a vertical height hh in a static fluid?
    ΔP=ρgh\Delta P=\rho gh. Pressure increases linearly with depth due to the weight of the overlying fluid column.
  10. What is the condition for neutral buoyancy (neither rising nor sinking) in a fluid?
    ρobj=ρfluid\rho_{\text{obj}}=\rho_{\text{fluid}}. Neutral buoyancy occurs when the object's density matches the fluid's, balancing buoyant force and weight.
  11. Identify the correct unit for buoyant force in SI base units.
    N=kg⋅m⋅s−2\text{N}=\text{kg}\cdot\text{m}\cdot\text{s}^{-2}. Buoyant force, a force, has units of Newtons, equivalent to kg m s−2s^{-2} in SI base units.
  12. Which option is correct: buoyant force depends on object density or on fluid density (for fixed VdispV_{\text{disp}})?
    It depends on fluid density, not object density. Buoyant force arises from fluid pressure differences and scales with fluid density for constant displaced volume.
  13. Which statement best describes how buoyant force changes with depth in an incompressible fluid?
    It is independent of depth for fixed VdispV_{\text{disp}}. In incompressible fluids, buoyant force depends on displaced volume and fluid density, remaining constant with depth.
  14. Find the buoyant force on 2.0 L2.0\,\text{L} of displaced water using ρ=1000 kg/m3\rho=1000\,\text{kg/m}^3 and g=10 m/s2g=10\,\text{m/s}^2.
    20 N20\,\text{N}. Buoyant force equals the weight of displaced water, calculated as density times volume times gravity.
  15. A 1.0 kg1.0\,\text{kg} object displaces 5.0×10−4 m35.0\times10^{-4}\,\text{m}^3 of water. What is FBF_B using g=10 m/s2g=10\,\text{m/s}^2?
    5 N5\,\text{N}. Buoyant force depends on displaced water volume and water density, independent of object mass.
  16. Which condition determines whether an object sinks, in terms of average densities?
    Sinks if ρobj>ρfluid\rho_{\text{obj}}>\rho_{\text{fluid}}. An object sinks when its average density exceeds the fluid's, resulting in weight greater than maximum buoyant force.
  17. What is the volume displaced by an object that is floating (partially submerged)?
    Vdisp=VsubV_{\text{disp}}=V_{\text{sub}}. Displaced volume for floating objects is the submerged portion, balancing buoyant force with weight.
  18. What is the apparent weight of a fully submerged object in a fluid, in terms of WW and FBF_B?
    Wapp=W−FBW_{\text{app}}=W-F_B. Apparent weight is the actual weight reduced by the opposing buoyant force.
  19. What is the formula for hydrostatic pressure at depth hh below a fluid surface?
    P=P0+ρghP=P_0+\rho gh. Hydrostatic pressure adds the contribution from the fluid column to the surface pressure.
  20. What does Archimedes' principle state about the buoyant force on an object in a fluid?
    Buoyant force equals weight of displaced fluid. Archimedes' principle quantifies the upward force on an object as equal to the weight of the fluid it displaces.
  21. Which condition determines whether an object floats, in terms of average densities?
    Floats if ρobj<ρfluid\rho_{\text{obj}}<\rho_{\text{fluid}}. An object floats when its average density is less than the fluid's, causing buoyant force to exceed weight when partially submerged.
  22. What is the net force on a fully submerged object (positive upward) in terms of FBF_B and WW?
    Fnet=FB−WF_{\text{net}}=F_B-W. Net force is the difference between upward buoyant force and downward weight.
  23. An object floats in water with 60%60\% of its volume submerged. What is ρobj\rho_{\text{obj}}?
    600 kg/m3600\,\text{kg/m}^3. Object density is the submerged fraction times water density for floating equilibrium.
  24. A 0.50 m30.50\,\text{m}^3 object is fully submerged in a fluid with ρ=1200 kg/m3\rho=1200\,\text{kg/m}^3. Find FBF_B using g=10 m/s2g=10\,\text{m/s}^2.
    6000 N6000\,\text{N}. Buoyant force equals fluid density times submerged volume times gravity for fully submerged objects.
  25. What is the fraction of a floating object's volume that is submerged in a fluid?
    VsubVobj=ρobjρfluid\frac{V_{\text{sub}}}{V_{\text{obj}}}=\frac{\rho_{\text{obj}}}{\rho_{\text{fluid}}}. The submerged fraction equals the ratio of object density to fluid density for equilibrium in floating objects.

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