Amino Acid Structure and Classification (1A) - Bio & Biochem

  1. A short peptide is placed in a solution at pH 2.0. Consider a residue with a side chain containing a carboxyl group (–CH2_2–COOH) in addition to the backbone carboxyl. Which statement is most consistent with the side-chain charge of that residue at pH 2.0? General amino acid: H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-}
    Answer: The side chain is predominantly protonated and neutral This question tests the understanding of amino acid structure and classification, specifically the protonation states of acidic side chains at low pH. Amino acids with carboxyl side chains, like aspartate, have pKa values around 4, meaning they are protonated and neutral below this pH, while deprotonated and charged above it. In this peptide at pH 2.0, the side chain carboxyl (–CH₂–COOH) is below its pKa, favoring protonation. Thus, it is predominantly protonated and neutral (choice B), as the acidic group retains its hydrogen, yielding zero charge. Choice A fails by claiming deprotonation and negative charge, a misconception ignoring that pH < pKa promotes protonation for acids. To verify, use the Henderson-Hasselbalch equation to estimate protonated fraction. This concept extends to predicting peptide behavior in acidic cellular compartments.
  2. A soluble cytosolic protein is engineered to increase stability by strengthening its hydrophobic core. One candidate substitution introduces an amino acid with R=CH3R = \text{CH}_3. The backbone is H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-} at pH 7.4. Which outcome is most consistent with this residue's classification in a folded, water-soluble protein?
    Answer: It is nonpolar and more likely to be buried in the interior This question tests amino acid classification and its impact on protein stability through core interactions. Side chains classify amino acids as nonpolar (hydrophobic), promoting burial in protein interiors to enhance stability. The substitution introduces R = CH₃, alanine, a nonpolar residue. This nonpolar nature makes it more likely buried, strengthening the hydrophobic core for stability. Suggesting it is basic and solvent-exposed errs by ignoring the methyl group's lack of charge, misclassifying nonpolar as charged. Verify by assessing if the side chain is small and aliphatic without polar atoms. Such classifications guide engineering efforts to optimize protein folding and thermostability.
  3. In a refolding assay, a 110-aa cytosolic enzyme is denatured in 6 M urea and then rapidly diluted into pH 7.4 buffer. A single-site variant shows decreased refolding yield but unchanged catalytic residues. The mutation replaces a residue located in a buried helical segment (solvent-inaccessible by protease protection). Which substitution is most consistent with disrupting the protein interior primarily by introducing an unfavorable side chain at pH 7.4?
    Answer: Leu Asp This question tests understanding of amino acid classification and how side chain properties affect protein folding. Amino acids are classified by their side chain properties: hydrophobic (nonpolar), hydrophilic (polar/charged), and special cases. The question describes a buried helical segment that becomes disrupted when leucine (Leu), a hydrophobic amino acid, is replaced. Since the residue is buried and the protein is at pH 7.4, introducing a charged residue like aspartate (Asp, negatively charged at pH 7.4) would be highly unfavorable in the hydrophobic core. The other options (Val, Phe, Ile) are all hydrophobic amino acids like Leu, so these substitutions would maintain the hydrophobic character needed for the buried position. A key principle is that charged residues are energetically costly to bury in protein interiors due to the lack of water for solvation.
  4. A cytosolic enzyme contains a catalytic nucleophile that attacks a carbonyl substrate. Activity drops when this residue is replaced by one lacking a side-chain hydroxyl group but remaining uncharged at pH 7.4. Which substitution is most consistent with removing the nucleophilic hydroxyl while keeping the side chain non-ionizable under these conditions?
    Answer: Ser Ala This question tests understanding of amino acid functional groups and their role in catalysis. Amino acids with nucleophilic side chains can attack electrophilic centers like carbonyls, with serine's hydroxyl group being a common catalytic nucleophile. Replacing serine (Ser) with alanine (Ala) removes the hydroxyl group while maintaining a small, uncharged side chain at pH 7.4. Alanine has only a methyl group, eliminating nucleophilic capability. Option A (Ser→Thr) maintains a hydroxyl group, option B (Ser→Asp) introduces a carboxylate that could act as a nucleophile, and option D (Ser→Lys) adds an amino group that can be nucleophilic. The key concept is that nucleophilic catalysis requires electron-rich groups like hydroxyl, thiol, or amino groups. Alanine lacks any such groups, having only a simple alkyl side chain, explaining the loss of activity.
  5. A protein's 280 nm absorbance comes mainly from which side chains?
    Answer: Trp and Tyr Aromatic side chains absorb UV light at 280 nm, and tryptophan and tyrosine have the strong conjugated ring systems that dominate. The most tempting wrong pick is phenylalanine and histidine, but phenylalanine absorbs weakly around 280 and histidine's imidazole ring absorbs much lower, so neither contributes significantly.
  6. An enzyme's substrate-binding pocket is lined by residues that stabilize a negatively charged ligand via electrostatic attraction at pH 7.4. Which amino acid side chain is most consistent with this function?
    Answer: R=(CH2)4-NH3+R = (\text{CH}_2)_4\text{-NH}_3^+ (basic) This question tests amino acid classifications for electrostatic roles in substrate binding. Basic side chains carry positive charge at pH 7, attracting negative ligands. The function requires stabilizing a negative ligand, best matched by basic residues. The side chain R = (CH₂)₄-NH₃⁺ (lysine) provides positive charge for electrostatic attraction. Choosing a nonpolar like R = CH₃ fails, lacking charge for interaction, confusing hydrophobicity with basicity. Check side chain pKa to ensure protonation at pH 7. This applies to designing binding pockets in enzymes.
  7. A peptide is synthesized with an N-terminus and C-terminus free (not blocked). It contains a single histidine side chain in an otherwise nonpolar sequence. During ion-exchange chromatography at pH 5.5, the peptide binds more strongly to a cation-exchange resin than at pH 8.0. Which conclusion about the histidine side chain is most consistent with this behavior?
    Answer: His is more protonated (positively charged) at pH 5.5 than at pH 8.0 This question tests understanding of amino acid ionization states and their pH-dependent behavior. Amino acids with ionizable side chains change their charge state depending on pH relative to their pKa values. Histidine has a side chain pKa around 6.0, making it unique among amino acids as it can be protonated or deprotonated near physiological pH. At pH 5.5 (below the pKa), the histidine side chain will be predominantly protonated and positively charged, causing stronger binding to the negatively charged cation-exchange resin. At pH 8.0 (above the pKa), histidine is mostly deprotonated and neutral, resulting in weaker binding. Option B incorrectly states histidine becomes negatively charged, but the imidazole side chain only loses a proton to become neutral, not negative. Remember that for ionizable groups: pH < pKa means protonated form predominates, pH > pKa means deprotonated form predominates.
  8. An enzyme active site requires a nucleophilic side chain that is typically uncharged at pH 7 and can form hydrogen bonds. Which side chain best matches this requirement?
    Answer: R=CH2-OHR = \text{CH}_2\text{-OH} This question tests amino acid classifications for nucleophilic and hydrogen-bonding roles in active sites. Polar uncharged side chains like hydroxyl are nucleophilic and uncharged at pH 7. The requirement matches a neutral nucleophile capable of H-bonding. R = CH₂-OH (serine) fits, providing OH for nucleophilicity and bonds. Selecting charged R = CH₂-CH₂-COO⁻ (glutamate) fails, as it's anionic, not uncharged. Verify by ensuring no net charge and presence of heteroatoms. This is common in serine proteases and enzyme mechanisms.
  9. A substitution is introduced into an enzyme's core: R=CH2-COO−R = \text{CH}_2\text{-COO}^-. The enzyme is assayed at pH 7.4 and shows reduced stability. Which rationale is most consistent with amino acid classification and typical core environments?
    Answer: A charged acidic side chain in the hydrophobic core is energetically unfavorable This question tests stability impacts of charged residues in protein cores. Acidic charges in hydrophobic cores are unfavorable without partners. Substituting core R = CH₂-COO⁻ (aspartate) reduces stability due to unsolvated charge. This energetic penalty arises from desolvation in nonpolar environment. Suggesting nonpolar disruption via H-bond loss fails, as nonpolar fits cores better. Assess core hydrophobicity: charges destabilize unless bridged. Cores exclude charged residues to maintain folding.
  10. A soluble enzyme is mutated at a buried position from R=CH3R = \text{CH}_3 to R = \text{CH}_2\text{-OH. No other changes are made. Which effect on folding is most consistent with amino acid classification and the hydrophobic effect?
    Answer: Introduction of a polar group in the core, potentially destabilizing folding This question tests effects of amino acid classification changes on protein core stability. Polar side chains in hydrophobic cores disrupt folding by preferring solvent. Mutating buried R = CH₃ (alanine, nonpolar) to CH₂-OH (serine, polar) introduces a polar group, potentially destabilizing. This arises from the hydrophobic effect favoring nonpolar burial. Claiming increased hydrophobic packing errs, as OH adds polarity, not hydrophobicity. Check by comparing side chain polarity before/after mutation. Core mutations often impact enzyme stability and function.
  11. A researcher designs a short peptide to bind a negatively charged DNA backbone via electrostatic attraction at pH 7.4. Which amino acid is most likely to be enriched in the binding region due to a positively charged side chain at this pH?
    Answer: Arginine This question tests understanding of amino acid charge states and electrostatic interactions. DNA has a negatively charged sugar-phosphate backbone due to phosphate groups, requiring positively charged amino acids for electrostatic attraction. Arginine (choice A) has a guanidinium side chain with a pKa around 12.5, ensuring it remains positively charged at pH 7.4. Glutamine (B) is polar but uncharged, tyrosine (C) has a phenolic hydroxyl that remains uncharged at pH 7.4 (pKa ~10), and alanine (D) is nonpolar with no ionizable groups. Along with lysine, arginine is one of only two amino acids that carry positive charge at physiological pH, making them essential for binding negatively charged molecules like DNA. The high pKa of arginine's side chain ensures it maintains its positive charge across a wide pH range, making it particularly effective for stable electrostatic interactions.
  12. An enzyme active site requires a side chain that can act as a general base near physiological pH by accepting a proton, yet can also be neutral in other microenvironments. Which amino acid is most consistent with this role based on side-chain structure and ionization behavior? General amino acid: H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-}
    Answer: Histidine This question tests the understanding of amino acid structure and classification, focusing on side chain pKa and catalytic roles in enzymes. Amino acids differ in side chain functional groups, with some like histidine having imidazoles that can act as acids or bases due to pKa near 6, enabling proton acceptance or donation at physiological pH. The enzyme active site needs a side chain that functions as a general base by accepting protons yet remains neutral in certain contexts, pointing to histidine's versatility. Histidine (choice C) aligns because its imidazole can deprotonate to accept protons and toggle states based on microenvironment. Aspartate (choice B) fails as its low pKa (~4) keeps it mostly deprotonated and anionic, unsuitable for neutral states, reflecting a misconception about pKa ranges for bases. A useful check is comparing side chain pKa to physiological pH for ionization potential. This clarifies histidine's common role in catalytic triads across enzymes.
  13. A peptide (10 residues) is analyzed by isoelectric focusing. At pH 3.0 the peptide migrates toward the cathode, but at pH 10.0 it migrates toward the anode. The investigator suspects a single side chain with a pKaK_a near physiological pH contributes substantially to the charge change. Which residue is most consistent with this behavior based on its side-chain functional group?
    Answer: Histidine (imidazole side chain) This question tests understanding of amino acid ionization states and their pH-dependent behavior. Amino acids have characteristic pKa values for their ionizable groups: carboxyl groups (~2-4), amino groups (~9-10), and certain side chains. At pH 3.0, the peptide migrates toward the cathode (negative electrode), indicating a net positive charge, while at pH 10.0 it migrates toward the anode (positive electrode), indicating a net negative charge. Histidine (choice A) has an imidazole side chain with a pKa around 6.0, meaning it transitions from protonated (positive) to deprotonated (neutral) near physiological pH. Leucine (B) has no ionizable side chain, aspartate (C) has a carboxylate with pKa ~3.8 that would already be deprotonated at pH 3, and lysine (D) has a primary amine with pKa ~10.5 that would remain protonated even at pH 10. The dramatic charge change between pH 3 and 10 is best explained by histidine's unique pKa near the middle of this range.
  14. A peptide is synthesized with one residue whose side chain is R=HR = \text{H} (the backbone is H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-} at neutral pH). Which classification is most consistent with this residue and its typical role in folded proteins?
    Answer: Nonpolar; often tolerated in both surface and interior due to minimal side chain This question tests classification of glycine and its protein roles. With R = H, glycine is nonpolar due to minimal, non-polar side chain. It's tolerated in both surface and interior positions owing to flexibility. This small size allows versatile placement without steric issues. Claiming acidic misidentifies H as carboxylate, ignoring actual structure. Confirm by noting lack of functional groups in R. Glycine's nonpolarity aids tight packing in proteins.
  15. A researcher compares two peptides that differ at one position: one has an R-group of –CH2_2–OH and the other has –CH2_2–CH2_2–S–CH3_3. In an aqueous buffer at pH 7.4, which conclusion about that position is most consistent with amino acid classification? General amino acid: H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-}
    Answer: The –CH2_2–OH residue is polar uncharged and can hydrogen bond with water This question tests the understanding of amino acid structure and classification, comparing polar and nonpolar side chains in aqueous environments. Amino acids are categorized by side chain properties, with polar uncharged like serine (–CH₂–OH) forming hydrogen bonds with water for solvent exposure, while nonpolar like methionine (–CH₂–CH₂–S–CH₃) prefer burial. The peptides differ at a position with these R-groups in pH 7.4 buffer, affecting solvation. Choice C correctly states the –CH₂–OH (serine) is polar uncharged and H-bonds with water, aligning with its classification. Choice B fails by calling the thioether (methionine) polar and exposed, a misconception as methionine is nonpolar despite sulfur. Assess by reviewing standard classifications and hydropathy. This clarifies how side chains dictate protein surface properties.
  16. A soluble protein is engineered to include a surface-exposed patch that binds a positively charged ligand. Binding increases when the patch is enriched in residues that are negatively charged at pH 7.4. Which amino acid is most consistent with strengthening this interaction via its side-chain charge at pH 7.4?
    Answer: Glu This question tests understanding of amino acid charge states and electrostatic interactions. Amino acids are classified by their side chain properties at physiological pH, with some carrying formal charges that enable ionic interactions. To bind a positively charged ligand, the protein surface needs negatively charged residues at pH 7.4. Glutamate (Glu) has a carboxyl side chain with pKa ~4.2, making it deprotonated and negatively charged at pH 7.4, perfect for attracting positive charges. Glutamine (Gln) is the amide form and remains uncharged, lysine (Lys) is positively charged and would repel the ligand, and leucine (Leu) is hydrophobic and uncharged. The principle of complementary electrostatics drives this interaction: opposite charges attract. A useful mnemonic is that at physiological pH, Asp and Glu are negative (acidic), Lys and Arg are positive (basic), while most others are neutral.
  17. A membrane protein segment is reconstituted into lipid vesicles. A single residue in the middle of a transmembrane helix is mutated, and the mutant shows reduced insertion efficiency into the hydrophobic bilayer core. Which replacement is most consistent with introducing an energetically unfavorable polar/charged group into the bilayer interior? General amino acid: H3N+−CH(R)−COO−\mathrm{H_3N^+-CH(R)-COO^-}
    Answer: Leucine →\rightarrow Aspartate This question tests the understanding of amino acid structure and classification, emphasizing the role of side chain polarity in membrane protein insertion. Amino acids are grouped by side chain hydrophobicity, with nonpolar residues favoring the lipid bilayer core, while polar or charged ones incur energetic penalties in hydrophobic environments. Here, a mutation in a transmembrane helix reduces insertion efficiency into lipid vesicles by introducing a polar or charged group into the bilayer interior. Leucine to aspartate (choice A) fits because leucine is nonpolar, but aspartate's carboxyl group is charged and polar, making insertion unfavorable. In contrast, isoleucine to valine (choice B) fails as both are nonpolar aliphatics, not introducing polarity, stemming from a misconception that all substitutions disrupt membranes equally. To check, evaluate side chain hydropathy scores for membrane compatibility. This highlights how charged residues in transmembrane segments can cause misfolding or retention in aqueous phases.
  18. During translation, a nascent polypeptide emerges into the aqueous cytosol. A single amino acid in the sequence is predicted to form a salt bridge with a neighboring acidic residue, stabilizing a local fold. Which amino acid is most consistent with providing the positively charged side chain needed for this salt bridge at pH 7.4?
    Answer: Arg This question tests understanding of amino acid charge states and salt bridge formation. Amino acids capable of ionic interactions have charged side chains at physiological pH, with salt bridges forming between oppositely charged residues. To form a salt bridge with an acidic residue (negative charge), a basic amino acid with a positive charge is needed at pH 7.4. Arginine (Arg) has a guanidinium side chain with pKa ~12.5, ensuring it remains positively charged at pH 7.4 to pair with the negative charge. Valine (Val) is hydrophobic and uncharged, glycine (Gly) lacks a side chain beyond hydrogen, and asparagine (Asn) has a polar but uncharged amide group. The principle of salt bridge formation requires complementary charges: acidic residues (Asp/Glu) pair with basic residues (Lys/Arg). Arginine's high pKa makes it reliably positive at physiological pH, enabling stable electrostatic interactions that can stabilize protein folds.
  19. Raising pH from 7 to 11 disrupts a salt bridge. Which pair is responsible?
    Answer: Lys and Asp A salt bridge needs opposite charges. At pH 7 Lys is protonated and positive while Asp is deprotonated and negative, so they attract. Raising pH to 11 crosses Lys's side-chain pKa near 10.5, so Lys loses its proton and becomes neutral; Asp stays negative and the bridge breaks. Arg and Glu is tempting, but Arg's pKa is about 12.5, so it remains protonated and charged even at pH 11.
  20. A researcher mutates a protein to introduce a new salt bridge on the surface at pH 7.4. They place R=CH2-COO−R = \text{CH}_2\text{-COO}^- at one site. Which residue at a nearby site is most consistent with forming the intended ionic interaction?
    Answer: R=(CH2)4-NH3+R = (\text{CH}_2)_4\text{-NH}_3^+ This question tests amino acid classifications for forming ionic interactions like salt bridges. Basic residues pair with acidic ones via opposite charges at pH 7. With an acidic R = CH₂-COO⁻ placed, a nearby basic residue forms the salt bridge. R = (CH₂)₄-NH₃⁺ (lysine) provides the positive charge for ionic attraction. Selecting an acidic like R = CH₂-CH₂-COO⁻ would repel, missing the need for charge opposition. Confirm by matching classifications: acidic negative, basic positive. Salt bridges stabilize protein surfaces and are pH-sensitive.

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