Enzyme Kinetics and Regulation (1A) - Bio & Biochem
- Which option describes a feedback inhibitor in a metabolic pathway?
- End product inhibits an earlier enzyme, often the first committed step. Feedback inhibition regulates pathways by allosterically inhibiting upstream enzymes to prevent overproduction of end products.
- State the relationship between , , and total enzyme .
- . V_max scales with total enzyme concentration, as k_cat is the turnover rate per enzyme molecule at saturation.
- What is the definition of the turnover number ?
- Catalytic cycles per enzyme per second at saturation. k_cat quantifies an enzyme's efficiency by measuring product formation rate per active site when fully saturated.
- What change in and is caused by pure noncompetitive inhibition?
- decreases; unchanged. Noncompetitive inhibitors bind elsewhere, reducing effective enzyme concentration and thus V_max, without altering Km.
- Identify where an uncompetitive inhibitor binds relative to substrate binding.
- Only to the complex (not to free enzyme). Uncompetitive inhibition requires substrate-bound enzyme, forming a dead-end complex that lowers apparent Km and V_max.
- State the Michaelisnten equation for initial velocity .
- . The equation describes hyperbolic kinetics, where velocity approaches V_max as [S] increases, based on enzyme-substrate binding equilibrium.
- What is the approximate rate when ?
- . Enzyme saturation at high [S] limits the rate to V_max, independent of further increases in substrate concentration.
- In a Lineweavernten plot, what is the -intercept equal to?
- . The y-intercept in the Lineweaver-Burk plot corresponds to infinite [S], where velocity equals V_max.
- What is the defining feature of irreversible inhibition in enzyme kinetics?
- Covalent or extremely tight binding permanently inactivates enzyme. Irreversible inhibitors form stable bonds with the enzyme, reducing active enzyme concentration permanently.
- What is the approximate rate law when ?
- . This linear approximation derives from the Michaelis-Menten equation when [S] is much less than Km, simplifying to a first-order rate.
- What is the definition of in Michaelis–Menten kinetics?
- Maximum initial rate at saturating . V_max is achieved when all enzyme active sites are saturated with substrate, reflecting the enzyme's maximum catalytic capacity.
- Which inhibition type is best overcome by increasing (substrate concentration)?
- Competitive inhibition. Increasing [S] can outcompete competitive inhibitors for the active site, restoring V_max unlike other inhibition types.
- What is the definition of in Michaelis–Menten kinetics?
- Substrate concentration where . Km represents enzyme-substrate affinity, as it is the [S] at which half-maximal velocity is achieved in the Michaelis-Menten model.
- What change in and is caused by uncompetitive inhibition?
- decreases; decreases. Uncompetitive inhibitors bind only to ES complex, decreasing both Km and V_max by stabilizing the complex.
- What does a Hill coefficient indicate about substrate binding?
- Positive cooperativity. A Hill coefficient greater than 1 signifies enhanced binding affinity after initial substrate attachment in multimeric enzymes.
- What is catalytic efficiency, and how is it written mathematically?
- . Catalytic efficiency measures how well an enzyme converts substrate to product at low [S], combining turnover and affinity.
- What is the key kinetic hallmark of allosteric enzymes versus Michaelisnten enzymes?
- Sigmoidal versus (cooperativity). Allosteric enzymes exhibit cooperative binding, yielding a sigmoidal curve unlike the hyperbolic Michaelis-Menten kinetics.
- What is the effect of phosphorylation on enzyme activity in general terms?
- Covalent modification that can increase or decrease activity. Phosphorylation adds a phosphate group via kinases, modulating enzyme conformation to either activate or inhibit catalysis.
- In a Lineweavernten plot, what is the slope equal to?
- . The slope reflects the ratio of Km to V_max, indicating how quickly velocity approaches maximum as [S] increases.
- Which condition on makes the rate approximately zero-order in substrate?
- . At high [S] relative to Km, the enzyme is saturated, making velocity independent of [S] and zero-order in substrate.
- Identify where a competitive inhibitor binds relative to the substrate binding site.
- Active site (mutually exclusive with substrate). Competitive inhibitors mimic substrate structure, binding reversibly to the same site and preventing substrate access.
- What change in and is caused by competitive inhibition?
- increases; unchanged. Competitive inhibitors compete for the active site, increasing apparent Km but not affecting V_max at high [S].
- Which condition on makes the rate approximately first-order in substrate?
- . At low [S] relative to Km, velocity is directly proportional to [S], following first-order kinetics in the Michaelis-Menten approximation.
- In a Lineweavernten plot, what is the -intercept equal to?
- . The x-intercept occurs where 1/v = 0, solving to -1/Km in the Lineweaver-Burk equation.
- State the Lineweavernten (double-reciprocal) form of the Michaelisnten equation.
- . The double-reciprocal plot linearizes Michaelis-Menten kinetics, allowing determination of Km and V_max from slope and intercepts.