Math 3 Quiz
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ALGEBRA & FUNCTIONS
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When solving x2−9=x−3, a student squares both sides to get x2−9=(x−3)2, which simplifies to x2−9=x2−6x+9, leading to x=3. However, substituting x=3 into the original equation yields 0=0, which seems to confirm the solution, yet further analysis reveals an issue. What subtle problem explains why x=3 might be considered extraneous?
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