Math 2 Quiz
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ALGEBRA & FUNCTIONS
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A particle moves along a path where its vertical position yy (in meters) is given by y(t)=t2−6t+13y(t) = t^2 - 6t + 13 and its horizontal position follows x(t)=2t+1x(t) = 2t + 1, where tt is time in seconds. At what horizontal position will the particle reach its minimum vertical position?
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