Simple Functional Relationships - ISEE Upper Level Quantitative Reasoning

  1. A swimmer completes 4 laps every 10 minutes. Based on this relationship, how does output laps change if input minutes doubles?​​
    Answer: Laps double This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a swimmer completing 4 laps every 10 minutes, with input as minutes and output as laps. Choice B is correct because it accurately follows the function rule of proportional rate, so doubling minutes doubles the laps. Choice C is incorrect because it assumes laps increase by 4, which is a common mistake when adding the base amount instead of scaling proportionally. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  2. A snack costs $2 per bag plus a $1 fee. How would output cost change if input bags increases by 3?​​
    Answer: It increases by $6 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a snack costing $2 per bag plus a $1 fee, with input as bags and output as cost. Choice D is correct because it accurately follows the function rule, showing that an increase of 3 bags leads to 3 * 2 = $6 increase in cost. Choice C is incorrect because it assumes $3, which is a common mistake when using the fee instead of the per-bag cost. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  3. A gym charges a $15 membership plus $3 per visit. Which rule gives output cost CC from input visits vv?​​
    Answer: C=3v+15C=3v+15 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a gym charging a $15 membership plus $3 per visit, with input as visits and output as cost. Choice A is correct because it accurately follows the function rule C = 3v + 15, combining fixed and variable costs. Choice B is incorrect because it assumes C = 15v + 3, which is a common mistake when swapping coefficients in linear equations. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  4. A function m(n)m(n) gives the number of minutes it takes to complete nn problems, where m(n)=3n+5m(n) = 3n + 5. If it takes 26 minutes to complete a certain number of problems, how long would it take to complete twice as many problems?
    Answer: 47 minutes When you encounter a function problem like this, you're working with input-output relationships where you need to find unknown values and then apply the function again. First, let's find how many problems were completed in 26 minutes. Since m(n)=3n+5m(n) = 3n + 5 and we know m(n)=26m(n) = 26, we can set up the equation: 26=3n+526 = 3n + 5. Solving for nn: subtract 5 from both sides to get 21=3n21 = 3n, then divide by 3 to find n=7n = 7 problems. Now we need the time for twice as many problems: 2×7=142 \times 7 = 14 problems. Using our function: m(14)=3(14)+5=42+5=47m(14) = 3(14) + 5 = 42 + 5 = 47 minutes. Looking at the wrong answers: Choice B (52 minutes) likely comes from incorrectly calculating m(14)m(14) as 3(14)+103(14) + 10 instead of 3(14)+53(14) + 5. Choice C (57 minutes) might result from doubling the original 26 minutes and adding 5, which misunderstands how the function works. Choice D (62 minutes) could come from thinking you simply double 26 minutes and add 10, again missing the actual function relationship. The correct answer is A) 47 minutes. Strategy tip: In function problems, always work systematically: first solve for the unknown input value, then apply the function to your new input. Don't try to shortcut by manipulating the output directly—functions don't work that way. Always go back to the original function with your new input value.
  5. The cost function C(n)=25n+150C(n) = 25n + 150 gives the total cost (in dollars) to produce nn items. If the cost increased by $200 when production increased from nn items to n+kn + k items, what is the value of kk?
    Answer: 8 items When you encounter a linear cost function like C(n)=25n+150C(n) = 25n + 150, you're working with a situation where costs change at a constant rate. The coefficient of nn (which is 25) tells you the cost per additional item produced. To find kk, you need to set up an equation comparing the costs at two production levels. The cost at nn items is C(n)=25n+150C(n) = 25n + 150, and the cost at n+kn + k items is C(n+k)=25(n+k)+150=25n+25k+150C(n + k) = 25(n + k) + 150 = 25n + 25k + 150. Since the cost increased by $200, you can write: C(n+k)−C(n)=200C(n + k) - C(n) = 200 (25n+25k+150)−(25n+150)=200(25n + 25k + 150) - (25n + 150) = 200 25k=20025k = 200 k=8k = 8 Choice A (6 items) would result in a cost increase of 25×6=15025 \times 6 = 150 dollars, which is too small. Choice C (10 items) would give 25×10=25025 \times 10 = 250 dollars, and choice D (12 items) would give 25×12=30025 \times 12 = 300 dollars—both are too large. Only choice B (8 items) produces the required $200 increase: 25×8=20025 \times 8 = 200. Study tip: In linear cost functions, the coefficient of the variable always represents the per-unit cost. When you see questions about cost increases, multiply this per-unit rate by the change in quantity. This pattern appears frequently on quantitative reasoning sections.
  6. The graph shown represents a function f(x)f(x). Based on the graph, what is the value of f(f(2))f(f(2))?
    Answer: 1 From the graph, f(2)=3f(2) = 3. Then f(f(2))=f(3)=1f(f(2)) = f(3) = 1.
  7. A plant grows 2 cm each week from 10 cm. How would the output height change if input weeks increases by 4?​​
    Answer: It increases by 8 cm This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a plant growing 2 cm each week from an initial 10 cm, with input as weeks and output as height. Choice C is correct because it accurately follows the function rule, showing that an increase of 4 weeks leads to 4 * 2 = 8 cm growth. Choice B is incorrect because it assumes 4 cm, which is a common mistake when using the weekly rate without multiplying by the change in input. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  8. A town's population increases by 200 each year from 5,000. What conclusion best describes input year to output population?​​
    Answer: Output increases by 200 yearly This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a town's population starting at 5,000 and increasing by 200 each year, with input as years and output as population. Choice A is correct because it accurately follows the function rule of linear growth, describing a constant annual increase of 200. Choice B is incorrect because it assumes exponential doubling, which is a common mistake when confusing linear and exponential relationships. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  9. A savings account starts with $100 and earns $5 each year. What is the output after 6 years?​​
    Answer: 130130 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a savings account starting at $100 and earning $5 each year, with input as years and output as total amount. Choice C is correct because it accurately follows the function rule of initial amount plus annual earnings, calculating 100 + 5*6 = 130 after 6 years. Choice B is incorrect because it assumes 100 + 5*5 = 125, which is a common mistake when off-by-one in counting years. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  10. A runner's distance follows input minutes tt to output miles dd: 5→0.5, 10→1.0, 15→1.5. Which rule matches?​​
    Answer: d=t10d=\frac{t}{10} This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by input minutes t to output miles d: 5→0.5, 10→1.0, 15→1.5. Choice A is correct because it accurately follows the function rule d = t/10, matching the proportional pattern. Choice B is incorrect because it assumes d = 10t, which is a common mistake when inverting the rate in proportional relationships. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  11. A taxi fare follows input miles mm to output cost cc: 1→7, 2→9, 3→11. Which function rule is correct?​​
    Answer: c=2m+5c=2m+5 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by input miles m to output cost c: 1→7, 2→9, 3→11. Choice A is correct because it accurately follows the function rule c = 2m + 5, matching the linear pattern with a slope of 2 and intercept of 5. Choice B is incorrect because it assumes c = 5m + 2, which is a common mistake when reversing the coefficients in the equation. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  12. The temperature TT (in degrees Fahrenheit) hh hours after midnight is given by T(h)=−2h2+8h+50T(h) = -2h^2 + 8h + 50 for 0≤h≤60 \leq h \leq 6. At what time does the temperature reach its maximum value?
    Answer: 2:00 AM (h = 2) When you encounter a quadratic function representing a real-world situation like temperature over time, you're looking for the maximum or minimum value. Since this function has a negative coefficient for the h2h^2 term (−2-2), the parabola opens downward, meaning it has a maximum point at its vertex. To find when the temperature reaches its maximum, you need to locate the vertex of the parabola T(h)=−2h2+8h+50T(h) = -2h^2 + 8h + 50. For any quadratic in the form f(x)=ax2+bx+cf(x) = ax^2 + bx + c, the x-coordinate of the vertex is x=−b2ax = -\frac{b}{2a}. Here, a=−2a = -2 and b=8b = 8, so: h=−82(−2)=−8−4=2h = -\frac{8}{2(-2)} = -\frac{8}{-4} = 2 This means the maximum temperature occurs at h=2h = 2, which is 2:00 AM, making choice B correct. Let's examine why the other options are wrong. Choice A (h=1h = 1) gives T(1)=−2(1)2+8(1)+50=56°FT(1) = -2(1)^2 + 8(1) + 50 = 56°F. Choice C (h=3h = 3) gives T(3)=−2(9)+24+50=56°FT(3) = -2(9) + 24 + 50 = 56°F. Choice D (h=4h = 4) gives T(4)=−2(16)+32+50=50°FT(4) = -2(16) + 32 + 50 = 50°F. Notice that choices A and C give the same temperature because they're equidistant from the vertex, while D gives an even lower temperature as you move further from the maximum. Remember: for quadratic word problems involving maximization or minimization, always identify whether the parabola opens up or down, then use the vertex formula x=−b2ax = -\frac{b}{2a} to find the optimal point.
  13. If g(x)=x2−6x+8g(x) = x^2 - 6x + 8 and g(m)=g(n)g(m) = g(n) where m<nm < n, what is the relationship between mm and nn?
    Answer: m+n=6m + n = 6 because the axis of symmetry is at x=3x = 3 When you see a quadratic function where two different inputs produce the same output, you're dealing with the symmetry property of parabolas. Since g(m)=g(n)g(m) = g(n) with m<nm < n, the points (m,g(m))(m, g(m)) and (n,g(n))(n, g(n)) are reflections of each other across the parabola's axis of symmetry. For any quadratic ax2+bx+cax^2 + bx + c, the axis of symmetry occurs at x=−b2ax = -\frac{b}{2a}. In g(x)=x2−6x+8g(x) = x^2 - 6x + 8, we have a=1a = 1 and b=−6b = -6, so the axis of symmetry is at x=−(−6)2(1)=3x = -\frac{(-6)}{2(1)} = 3. Since mm and nn are equidistant from this axis of symmetry, the midpoint between them must be 3. This means m+n2=3\frac{m + n}{2} = 3, so m+n=6m + n = 6. Choice A incorrectly states that m+n=3m + n = 3. While it correctly identifies the axis of symmetry at x=3x = 3, it confuses this value with the sum of the two x-coordinates. Choice C suggests m+n=8m + n = 8 based on the constant term. The constant term tells us where the parabola crosses the y-axis, but has no direct relationship to points with equal y-values. Choice D claims m⋅n=8m \cdot n = 8 because of the constant term. Again, the constant term doesn't determine the product of symmetric x-coordinates. Remember: when two x-values produce the same y-value in a quadratic function, their average equals the x-coordinate of the axis of symmetry. This symmetry property is crucial for solving quadratic equations and understanding parabola behavior.
  14. The table shows values of a linear function g(x)g(x). What is the value of g(8)g(8)?
    Answer: 24 A linear function changes by the same amount for each step in xx. From the table, g(0)=8g(0) = 8 and g(3)=14g(3) = 14, so the slope is 14−83−0=2\frac{14 - 8}{3 - 0} = 2. The function is g(x)=2x+8g(x) = 2x + 8, and the other rows agree: g(5)=18g(5) = 18 and g(7)=22g(7) = 22. Then g(8)=2(8)+8=16+8=24g(8) = 2(8) + 8 = 16 + 8 = 24 Equivalently, g(8)g(8) is one step past g(7)=22g(7) = 22, so it is 22+2=2422 + 2 = 24. The value 22 is g(7)g(7), the last value in the table, not g(8)g(8). The value 26 comes from an addition slip in 16+816 + 8 or from adding an extra step of 2. The value 28 adds 6 to 22, as if xx went up by 3. Tip: check your rule against every row of the table, then extend it one step at a time.
  15. A car travels at constant speed. Input-output pairs are shown: t→dt\to d: 1→45, 2→90, 3→135. Which rule matches?​​
    Answer: d=45td=45t This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by input-output pairs for time t to distance d: 1→45, 2→90, 3→135. Choice B is correct because it accurately follows the function rule d = 45t, which matches the proportional pattern in the data. Choice A is incorrect because it assumes d = 45 + t, which is a common mistake when misinterpreting constant rate as addition. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  16. A function p(t)p(t) represents the profit (in dollars) from selling tt items, where p(t)=15t−200p(t) = 15t - 200. How many items must be sold for the profit to equal $100?
    Answer: 20 items When you encounter a function problem asking for a specific output value, you're solving an equation by substituting the given information and solving for the unknown variable. Here, you need to find how many items (tt) must be sold for the profit to equal $100. Set up the equation by substituting the desired profit into the function: p(t)=15t−200=100p(t) = 15t - 200 = 100. Now solve for tt: 15t−200=10015t - 200 = 100 15t=100+20015t = 100 + 200 15t=30015t = 300 t=20t = 20 Therefore, 20 items must be sold to achieve a profit of $100, making (B) correct. Let's examine why the other choices are wrong. Choice (A) 18 items would give p(18)=15(18)−200=270−200=70p(18) = 15(18) - 200 = 270 - 200 = 70, which is $30 short of the target. Choice (C) 22 items would yield p(22)=15(22)−200=330−200=130p(22) = 15(22) - 200 = 330 - 200 = 130, which exceeds the target by $30. Choice (D) 24 items would produce p(24)=15(24)−200=360−200=160p(24) = 15(24) - 200 = 360 - 200 = 160, overshooting by $60. Notice that these incorrect answers are evenly spaced around the correct answer, which is a common pattern in multiple-choice tests. When solving function problems, always substitute your answer back into the original equation to verify it produces the desired result. This quick check can catch arithmetic errors and confirm you've found the right solution.
  17. Temperature converts by input CC to output FF using F=95C+32F=\frac{9}{5}C+32. How does FF change when CC increases by 5?​​
    Answer: It increases by 9 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by the temperature conversion formula F = (9/5)C + 32, with input as Celsius and output as Fahrenheit. Choice B is correct because it accurately follows the function rule, showing that an increase of 5 in C leads to an increase of (9/5)*5 = 9 in F. Choice A is incorrect because it assumes the increase is just 5, which is a common mistake when ignoring the multiplication factor in linear conversions. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.
  18. If u(x)=3x+7u(x) = 3x + 7 and u−1u^{-1} represents the inverse function of uu, what is u−1(16)u^{-1}(16)?
    Answer: 3 When you encounter inverse functions, remember that if f(a)=bf(a) = b, then f−1(b)=af^{-1}(b) = a. This means the inverse function "undoes" what the original function does. To find u−1(16)u^{-1}(16), you need to determine what input value makes u(x)=16u(x) = 16. Set up the equation: 3x+7=163x + 7 = 16. Solving for xx: subtract 7 from both sides to get 3x=93x = 9, then divide by 3 to get x=3x = 3. Since u(3)=16u(3) = 16, we know that u−1(16)=3u^{-1}(16) = 3. You can verify this by checking: u(3)=3(3)+7=9+7=16u(3) = 3(3) + 7 = 9 + 7 = 16 ✓ Looking at the wrong answers: Choice B (4) would mean u(4)=16u(4) = 16, but u(4)=3(4)+7=19u(4) = 3(4) + 7 = 19. Choice C (5) would mean u(5)=16u(5) = 16, but u(5)=3(5)+7=22u(5) = 3(5) + 7 = 22. Choice D (6) would mean u(6)=16u(6) = 16, but u(6)=3(6)+7=25u(6) = 3(6) + 7 = 25. These are all too large because students might mistakenly try to substitute these values into the original function rather than solving the inverse relationship. Study tip: For inverse function problems, always ask yourself "what input gives me this output?" rather than plugging the given number directly into the original function. Set up an equation where the function equals your target value, then solve for the input.
  19. Given that r(x)=2x−1r(x) = 2x - 1 and s(x)=x2+3s(x) = x^2 + 3, what is the value of r(s(2))r(s(2))?
    Answer: 13 This question tests function composition, where you evaluate one function and use that result as the input for another function. When you see r(s(2))r(s(2)), you're working from the inside out - first find s(2)s(2), then use that result as the input for function rr. Start by evaluating the inner function s(2)s(2). Since s(x)=x2+3s(x) = x^2 + 3, substitute x=2x = 2: s(2)=22+3=4+3=7s(2) = 2^2 + 3 = 4 + 3 = 7. Now you need to find r(7)r(7) since r(s(2))=r(7)r(s(2)) = r(7). Using r(x)=2x−1r(x) = 2x - 1, substitute x=7x = 7: r(7)=2(7)−1=14−1=13r(7) = 2(7) - 1 = 14 - 1 = 13. Choice A (13) is correct - this follows the proper inside-out evaluation process. Choice B (15) likely comes from incorrectly calculating r(7)=2(7)+1r(7) = 2(7) + 1 instead of 2(7)−12(7) - 1, mixing up the sign. Choice C (17) could result from evaluating r(2)+s(2)=3+14=17r(2) + s(2) = 3 + 14 = 17, misunderstanding composition as addition of separate function values. Choice D (19) might come from calculating s(2)⋅r(2)+1=7⋅3+1−1=19s(2) \cdot r(2) + 1 = 7 \cdot 3 + 1 - 1 = 19, confusing composition with multiplication. For function composition problems, always work inside-out and substitute carefully. Write down each step: identify the inner function, evaluate it completely, then use that result as input for the outer function. This methodical approach prevents the sign errors and operational mix-ups that create these wrong answer choices.
  20. A store gives 10% off a $50 item. If input is discount rate, output is final price, what is the output?​​
    Answer: 4545 This question tests ISEE Upper Level quantitative reasoning skills, specifically interpreting simple functional relationships. A functional relationship describes how one quantity changes in response to another, often represented using a rule, table, or graph. In this question, the relationship is illustrated by a store giving 10% off a $50 item, with input as discount rate and output as final price. Choice C is correct because it accurately follows the function rule of final price = 50 * (1 - 0.10) = 45. Choice B is incorrect because it assumes 40, which is a common mistake when calculating 20% off instead of 10%. To help students: Teach them to carefully analyze the given data and check if their interpretation aligns with the rule. Practice identifying and correcting common errors like misreading tables or graphs. Encourage using estimation to verify the plausibility of their answers.

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