IBEW: Electrical Training Alliance Aptitude Test • Algebra & Functions

Multiply Factored Expressions — Identify products from factored forms.

Learn to recognize and expand factored algebraic expressions into their fully multiplied products.

IBEW aptitude test emblem with an energized plug, circuit board, and trade wrench
Inside this lesson 10 sections 5 questions 9 figures

SECTION 1

Historical Context & Motivation

The ability to move between factored form and expanded (product) form of algebraic expressions is one of the most fundamental skills in algebra. This concept dates back to ancient civilizations that needed systematic methods for computing areas, volumes, and material quantities — the same kinds of calculations that electricians, plumbers, and construction professionals rely on every day. When you see an expression like (x + 3)(x − 5) and recognize it equals x² − 2x − 15, you are performing a task whose roots stretch back thousands of years.

~1800 BCE • Babylonian Area Calculations

Babylonian scribes computed areas of fields using geometric methods equivalent to multiplying binomial-like expressions, recording results on clay tablets.

~300 BCE • Euclid's Geometric Algebra

Euclid's Elements formalized the distributive property geometrically, showing that a rectangle's area could be decomposed into sub-rectangles — the visual foundation of FOIL.

820 CE • Al-Khwarizmi's Al-Jabr

The Persian mathematician al-Khwarizmi published systematic methods for manipulating algebraic expressions, giving us the word "algebra" itself from al-jabr (restoration).

1631 • Modern Symbolic Notation

Thomas Harriot and others popularized using letters and symbols like × and parentheses, making factored and expanded forms easy to write and manipulate on paper.

On the IBEW Electrical Training Alliance Aptitude Test, you will encounter questions that present an expression in factored form and ask you to identify its expanded product, or vice versa. The central question this lesson addresses is straightforward: given two or more factors, how do you systematically multiply them to produce the correct polynomial product? Mastering this skill is essential not only for the aptitude test but also for practical tasks like calculating circuit loads, conduit lengths, and material estimates in the electrical trade.

SECTION 2

Core Principles & Definitions

Before diving into techniques, let's establish the foundational vocabulary and principles that govern multiplying factored expressions. A factor is any quantity being multiplied by another quantity. A product is the result of that multiplication. When we write 3(x + 4), the number 3 and the binomial (x + 4) are both factors, and the expanded result 3x + 12 is the product. The process of going from factored form to product form relies on a single powerful rule: the distributive property.

1

Distributive Property

a(b + c) = ab + ac. Every term inside the parentheses gets multiplied by the term outside. This is the single rule that drives all factored-to-product conversions.
2

FOIL Method

For two binomials (a + b)(c + d), multiply First, Outer, Inner, Last terms. FOIL is a structured application of the distributive property specifically for binomial × binomial.
3

Combining Like Terms

After distributing, gather terms with identical variable parts (e.g., 3x and −5x combine to −2x). This step simplifies your raw product into its final, clean polynomial form.
4

Monomial × Polynomial

When one factor has only one term (a monomial), distribute it across every term in the other factor. Example: 5x(x² + 2x − 3) = 5x³ + 10x² − 15x.
5

Sign Handling

Positive × positive = positive. Negative × negative = positive. Positive × negative = negative. Tracking signs carefully through each multiplication is critical to accuracy.
✦

KEY TAKEAWAY

Think of the distributive property like wiring a junction box with multiple circuits. Each incoming wire (term outside the parentheses) must connect to every outgoing wire (term inside the parentheses) — you cannot skip a connection. If you have two binomials, that means four connections total (FOIL). Miss one connection and the circuit is incomplete, just as missing one multiplication term gives you the wrong product.

SECTION 3

Visual Explanation — The Area Model

The most intuitive way to understand multiplying factored expressions is through the area model. Imagine you need to calculate the total area of a rectangular space whose sides are defined by algebraic expressions. The rectangle's width is (x + 3) and its length is (x + 5). By subdividing this rectangle into four smaller rectangles, you can compute each partial area and then sum them to find the total product.

Area Model: (x + 3)(x + 5)x · x = x²x · 3 = 3x5 · x = 5x5 · 3 = 15x3x5(x + 3) →(x + 5) ↑Product = x² + 3x + 5x + 15 = x² + 8x + 15
The area model partitions the product (x + 3)(x + 5) into four sub-areas: x² (First), 3x (Outer), 5x (Inner), and 15 (Last). Summing these gives the product x² + 8x + 15.

The area model is particularly useful for tradespeople because it mirrors real-world layout calculations. When you frame a wall opening that is (x + 3) feet wide and (x + 5) feet tall, the total area is indeed the sum of those four partial areas. The diagram above shows that the cyan region represents x × x = x², the violet region represents x × 3 = 3x, the pink region represents 5 × x = 5x, and the amber region represents 5 × 3 = 15. Adding these four areas together produces the final product: x² + 8x + 15.

SECTION 4

Mathematical Framework

All factored-to-product conversions rest on a small set of algebraic identities and properties. The following equations formalize the patterns you will use repeatedly on the aptitude test and in field calculations.

DISTRIBUTIVE PROPERTY

a(b+c)=ab+aca(b + c) = ab + ac

Where a is any monomial factor and (b + c) is a polynomial factor. Each term inside the parentheses is multiplied by a.

BINOMIAL × BINOMIAL (FOIL)

(a+b)(c+d)=ac+ad+bc+bd(a + b)(c + d) = ac + ad + bc + bd

F = First (ac), O = Outer (ad), I = Inner (bc), L = Last (bd). After expanding, combine like terms to simplify.

DIFFERENCE OF SQUARES

(a+b)(a−b)=a2−b2(a + b)(a − b) = a² − b²

A special product where the middle terms cancel. The outer product (−ab) and inner product (+ab) sum to zero, leaving only the difference of the squares.

PERFECT SQUARE TRINOMIAL

(a+b)2=a2+2ab+b2(a + b)² = a² + 2ab + b²

Squaring a binomial always produces three terms. The middle term is exactly twice the product of the two terms in the binomial. Similarly, (a − b)² = a² − 2ab + b².

These four formulas cover the vast majority of factored expressions you will encounter on the IBEW aptitude test. The distributive property is the universal engine; FOIL, the difference of squares, and the perfect square trinomial are all specific applications of distribution applied to particular factor structures. Recognizing which pattern applies to a given problem allows you to expand quickly and accurately, saving valuable time on a timed exam.

SECTION 5

Detailed Breakdown — Recognizing Factored Forms

A key skill on the aptitude test is rapid pattern recognition. When you see a factored expression, you should immediately classify it so you can apply the correct expansion technique. The diagram below maps the main categories of factored expressions you will encounter and shows the product each one produces.

Classification of Factored ExpressionsFactored ExpressionMonomial × PolyBinomial × BinomialSpecial Products3x(x² + 2x − 4)= 3x³ + 6x² − 12xGeneral FOIL(x+2)(x+7)= x²+9x+14With Coefficients(2x−1)(3x+4)= 6x²+5x−4Diff. of Squares(x+6)(x−6)= x²−36Perfect Square(x+4)²= x²+8x+16Quick Identification Checklist✓ One factor is a single term? → Distribute the monomial✓ Two binomials, different terms? → Use FOIL (4 products)✓ Sum × Difference of same terms? → Difference of squares (a² − b²)✓ Same binomial squared? → Perfect square trinomial (a² ± 2ab + b²)
Decision tree for classifying factored expressions. Start at the top, determine your factor types, then follow the branch to the correct expansion technique.
Factored FormPattern NameExpanded ProductKey Clue
4(x + 7)Monomial distribution4x + 28Single term outside parentheses
(x + 2)(x + 9)FOIL (general)x² + 11x + 18Two different binomials, leading coeff. = 1
(3x − 2)(x + 5)FOIL (with coefficients)3x² + 13x − 10Leading coefficients ≠ 1
(x + 8)(x − 8)Difference of squaresx² − 64Same terms, opposite signs
(x − 5)²Perfect square trinomialx² − 10x + 25Binomial squared

Common factored forms and their expanded products

SECTION 6

Worked Example

Let's walk through a complete example of the type you might see on the IBEW aptitude test. Suppose you need to find the product of (2x − 3)(4x + 5). This is a binomial × binomial with leading coefficients, so we will apply the FOIL method carefully, paying close attention to signs.

Expand (2x − 3)(4x + 5)

  1. 1

    Step 1 — Identify the Structure

    We have two binomial factors: (2x − 3) and (4x + 5). Since both have two terms and one has a leading coefficient of 2 and the other 4, this is a general FOIL problem. Label the terms: a = 2x, b = −3, c = 4x, d = 5.
    Pattern: (a + b)(c + d) → FOIL
  2. 2

    Step 2 — First: Multiply First Terms

    Multiply the first term of each binomial: (2x)(4x) = 8x². When multiplying monomials, multiply the coefficients (2 × 4 = 8) and add the exponents of x (1 + 1 = 2).
    F = 8x²
  3. 3

    Step 3 — Outer: Multiply Outer Terms

    Multiply the outermost terms: (2x)(5) = 10x. The outer terms are the first term of the first binomial and the last term of the second binomial.
    O = 10x
  4. 4

    Step 4 — Inner: Multiply Inner Terms

    Multiply the innermost terms: (−3)(4x) = −12x. Note the negative sign carries through from the −3 in the first binomial.
    I = −12x
  5. 5

    Step 5 — Last: Multiply Last Terms

    Multiply the last term of each binomial: (−3)(5) = −15. A negative times a positive yields a negative result.
    L = −15
  6. 6

    Step 6 — Combine Like Terms

    Sum all four products: 8x² + 10x + (−12x) + (−15). The like terms 10x and −12x combine: 10x − 12x = −2x. The final expanded product is:
    (2x − 3)(4x + 5) = 8x² − 2x − 15
💡

Sign-Check Tip

On a timed test, the most common error is dropping a negative sign during the Inner or Last multiplication. After you finish FOIL, do a quick sign audit: count how many negative terms appeared in your original factors and verify that the signs in your product are consistent. In the example above, the −3 should produce exactly two negative partial products (Inner and Last), which it does.

SECTION 7

Comparing Expansion Methods

Several methods exist for expanding factored expressions, and each has its strengths depending on the situation. On the aptitude test, choosing the right method can save you significant time. Below is a practical comparison of the main approaches.

MethodBest Used WhenStrengthsLimitations
Simple DistributionOne factor is a monomial (e.g., 5x × polynomial)Fastest method; minimal steps; hard to make errorsOnly works with monomial × polynomial
FOILTwo binomials of any formOrganized; mnemonic makes it memorable; systematicOnly works for exactly two binomials; doesn't extend to trinomials
Area Model / GridAny polynomial × polynomial, especially larger productsVisual and organized; scales to trinomial × trinomial; reduces missed termsTakes more space and time to draw
Special Product PatternsDifference of squares, perfect square trinomialsExtremely fast; skip FOIL entirely; instant recognitionMust correctly identify the pattern; misidentification leads to errors

Comparison of factored expression expansion methods

✦

KEY TAKEAWAY

Think of these methods like tools in your electrician's pouch. A lineman's pliers and a wire stripper both cut wire, but you pick the right tool for the job. Simple distribution is your screwdriver — fast and universal for straightforward tasks. FOIL is your multi-tool — structured and reliable for the most common binomial problems. Special product patterns are your power tool — blazingly fast when the conditions are right, but you need to verify the fit before pulling the trigger.

SECTION 8

Connection to Advanced Applications

Multiplying factored expressions is a gateway to more advanced algebraic reasoning. On the IBEW aptitude test, some questions may combine this skill with other concepts — for example, requiring you to multiply factors and then evaluate the resulting polynomial at a specific value, or to compare two factored expressions by expanding both and simplifying. Understanding the forward connections helps you anticipate and prepare for harder questions.

This Lesson (Foundational)Advanced Extension
Multiply two binomials using FOILMultiply three or more binomials by chaining: expand two, then multiply the result by the third
Recognize difference of squaresFactor higher-degree differences: a⁴ − b⁴ = (a² + b²)(a² − b²)
Expand and simplify a productSolve quadratic equations by setting the expanded product equal to zero and factoring back
Compute areas using algebraic dimensionsCalculate electrical load formulas involving Power = Voltage × Current where variables have algebraic expressions

From factored-expression multiplication to advanced algebra

In the electrical trade, these algebraic skills translate directly into practical calculations. For instance, the power equation P = V × I can involve expressions where voltage and current are defined in terms of resistances, impedances, and source values — all of which may appear in factored form. The ability to expand and simplify such expressions efficiently is not just a test skill; it is a trade skill that supports safe, accurate electrical work in the field.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

Explain in your own words why (x + 4)(x − 4) produces a binomial (two-term) result rather than a trinomial (three-term) result. What happens to the middle terms?
Show answer
When you apply FOIL to (x + 4)(x − 4), the four partial products are: x², −4x, +4x, and −16. The middle terms −4x and +4x are additive inverses — they sum to zero and cancel completely. This leaves only x² − 16, a two-term expression called a difference of squares. This cancellation occurs whenever two binomials share the same terms but have opposite signs on the second term, because the Outer and Inner products will always be equal in magnitude but opposite in sign.

Question 2: BASIC CALCULATION

Expand the expression 6x(2x² − 3x + 5) and write the result in standard form.
Show answer
Distribute 6x to each term inside the parentheses: 6x × 2x² = 12x³, 6x × (−3x) = −18x², and 6x × 5 = 30x. The expanded product in standard form (descending powers of x) is 12x³ − 18x² + 30x. Note that when multiplying monomials, you multiply the coefficients and add the exponents on x.

Question 3: INTERMEDIATE

Find the product of (3x + 7)(2x − 5). Show all four FOIL partial products before combining like terms.
Show answer
Apply FOIL: First = (3x)(2x) = 6x², Outer = (3x)(−5) = −15x, Inner = (7)(2x) = 14x, Last = (7)(−5) = −35. Before combining: 6x² − 15x + 14x − 35. Combining like terms: −15x + 14x = −x. The final product is 6x² − x − 35. This problem tests your ability to handle leading coefficients greater than 1 and to track negative signs through the Outer and Last multiplications.

Question 4: APPLIED

An electrician is calculating the area of a rectangular cable tray cover. The width of the cover is (x + 8) inches and the length is (x + 12) inches. Write an expression for the area in expanded form. If x = 6 inches, what is the numerical area?
Show answer
Area = length × width = (x + 8)(x + 12). Using FOIL: First = x², Outer = 12x, Inner = 8x, Last = 96. Combining like terms: x² + 20x + 96. To find the numerical area when x = 6, substitute: (6)² + 20(6) + 96 = 36 + 120 + 96 = 252 square inches. You can verify by computing the dimensions directly: width = 6 + 8 = 14 inches, length = 6 + 12 = 18 inches, and 14 × 18 = 252 square inches.

Question 5: CRITICAL THINKING

A student claims that (2x + 3)² = 4x² + 9. Identify the error, provide the correct expansion, and explain a general rule for avoiding this mistake when squaring any binomial.
Show answer
The student's error is omitting the middle term. Squaring a binomial means multiplying it by itself: (2x + 3)² = (2x + 3)(2x + 3). Applying FOIL: First = 4x², Outer = 6x, Inner = 6x, Last = 9. Combining like terms: 4x² + 12x + 9. The student forgot the 2ab term (here, 2 × 2x × 3 = 12x). The general rule is (a + b)² = a² + 2ab + b² — never simply a² + b². When squaring a binomial, always remember the middle term equals twice the product of the two terms. This is one of the most common algebraic errors, and recognizing it can save you points on the aptitude test.

SUMMARY

Lesson Summary

Summary

Multiplying factored expressions means converting from factored form to expanded product form using the distributive property. For a monomial times a polynomial, distribute the monomial to every term. For two binomials, use FOIL (First, Outer, Inner, Last) to generate four partial products, then combine like terms. Recognize special patterns — the difference of squares (a + b)(a − b) = a² − b² and the perfect square trinomial (a + b)² = a² + 2ab + b² — for instant expansion without full FOIL.

On the IBEW Electrical Training Alliance Aptitude Test, always begin by classifying the factored expression: is it monomial × polynomial, general binomial × binomial, or a recognizable special product? Apply the appropriate method, track signs carefully through every multiplication step, and verify your answer by checking that like terms have been properly combined. Use the area model as a visual check whenever you are unsure. These skills form the foundation for solving equations, simplifying complex formulas, and performing real-world trade calculations involving algebraic dimensions.

Varsity Tutors • IBEW: Electrical Training Alliance Aptitude Test • Multiply Factored Expressions — Identify products from factored forms.