IB Mathematics Analysis and Approaches Quiz
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GEOMETRY AND TRIGONOMETRY
Question 1
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Assuming
sin
(
θ
)
+
cos
(
θ
)
≠
0
\sin(\theta) + \cos(\theta) \neq 0
sin
(
θ
)
+
cos
(
θ
)
=
0
, the expression
sin
3
(
θ
)
+
cos
3
(
θ
)
sin
(
θ
)
+
cos
(
θ
)
\frac{\sin^3(\theta) + \cos^3(\theta)}{\sin(\theta) + \cos(\theta)}
s
i
n
(
θ
)
+
c
o
s
(
θ
)
s
i
n
3
(
θ
)
+
c
o
s
3
(
θ
)
simplifies to:
A
1
B
1
−
sin
(
θ
)
cos
(
θ
)
1 - \sin(\theta)\cos(\theta)
1
−
sin
(
θ
)
cos
(
θ
)
C
1
+
sin
(
θ
)
cos
(
θ
)
1 + \sin(\theta)\cos(\theta)
1
+
sin
(
θ
)
cos
(
θ
)
D
1
−
2
sin
(
θ
)
cos
(
θ
)
1 - 2\sin(\theta)\cos(\theta)
1
−
2
sin
(
θ
)
cos
(
θ
)
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A
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C
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