IB Mathematics Analysis and Approaches Quiz
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CALCULUS
Question 1
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Using the substitution
u
=
e
x
u = e^x
u
=
e
x
, find
∫
e
x
e
2
x
−
3
e
x
+
2
d
x
\int \frac{e^x}{e^{2x} - 3e^x + 2} dx
∫
e
2
x
−
3
e
x
+
2
e
x
d
x
.
A
ln
∣
e
x
−
1
e
x
−
2
∣
+
C
\ln|\frac{e^x-1}{e^x-2}| + C
ln
∣
e
x
−
2
e
x
−
1
∣
+
C
B
ln
∣
e
x
−
2
e
x
−
1
∣
+
C
\ln|\frac{e^x-2}{e^x-1}| + C
ln
∣
e
x
−
1
e
x
−
2
∣
+
C
C
ln
∣
e
2
x
−
3
e
x
+
2
∣
+
C
\ln|e^{2x} - 3e^x + 2| + C
ln
∣
e
2
x
−
3
e
x
+
2∣
+
C
D
arctan
(
e
x
−
3
/
2
)
+
C
\arctan(e^x - 3/2) + C
arctan
(
e
x
−
3/2
)
+
C
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