IB Mathematics Analysis and Approaches Quiz
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FUNCTIONS
Question 1
of 19
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Let
f
(
x
)
=
x
+
3
f(x) = x+3
f
(
x
)
=
x
+
3
and
g
(
x
)
=
1
x
−
1
g(x) = \frac{1}{x-1}
g
(
x
)
=
x
−
1
1
. The function
h
h
h
is defined as
h
(
x
)
=
(
f
∘
g
)
(
x
)
h(x) = (f \circ g)(x)
h
(
x
)
=
(
f
∘
g
)
(
x
)
. Find the inverse function
h
−
1
(
x
)
h^{-1}(x)
h
−
1
(
x
)
.
A
h
−
1
(
x
)
=
1
x
−
3
h^{-1}(x) = \frac{1}{x-3}
h
−
1
(
x
)
=
x
−
3
1
B
h
−
1
(
x
)
=
1
x
+
3
h^{-1}(x) = \frac{1}{x+3}
h
−
1
(
x
)
=
x
+
3
1
C
h
−
1
(
x
)
=
1
+
1
x
+
3
h^{-1}(x) = 1 + \frac{1}{x+3}
h
−
1
(
x
)
=
1
+
x
+
3
1
D
h
−
1
(
x
)
=
1
+
1
x
−
3
h^{-1}(x) = 1 + \frac{1}{x-3}
h
−
1
(
x
)
=
1
+
x
−
3
1
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