HSPT Math • Mathematics

Apply Statistics Concepts — Calculate mean, median, and probability.

Master the essentials of averages, middle values, and chance to ace the HSPT math section.

HSPT emblem with a school, checked assessment, and reasoning brain
Inside this lesson 10 sections 5 questions 7 figures

SECTION 1

Historical Context & Motivation

People have always wanted to make sense of numbers. Imagine a farmer thousands of years ago wondering, "What is a typical harvest?" or a sailor asking, "What are the chances of a storm today?" These are statistics questions! Statistics is the branch of math that helps us collect, organize, and understand data.

Over centuries, mathematicians developed tools like the mean (average), median (middle value), and probability (chance of something happening). Let's see how these ideas grew over time.

3000 BCE • Ancient Record-Keeping

Egyptians and Babylonians kept records of crop harvests and populations. They used simple averages to plan for the future.

1654 • Birth of Probability

French mathematicians Blaise Pascal and Pierre de Fermat exchanged letters about gambling problems. Their work launched the formal study of probability.

1713 • Law of Large Numbers

Jacob Bernoulli published a book proving that the more data you collect, the closer your results get to the true probability. This made statistics reliable.

1900s • Statistics Goes Mainstream

Governments and businesses began using mean, median, and probability for everything from census data to weather forecasts and medical research.

Today, these tools show up everywhere — from your favorite sports stats to predicting the weather. On the HSPT, you will need to calculate the mean and median of a data set and find the probability of an event. Let's learn how!

SECTION 2

Core Principles & Definitions

Before we start calculating, let's nail down the key vocabulary. These three concepts are the building blocks of statistics on the HSPT.

1

Mean (Average)

The mean is the sum of all values divided by how many values there are. It tells you the "fair share" if everything were split equally.
2

Median (Middle Value)

The median is the middle number when you list values in order from least to greatest. If there are two middle numbers, you average them.
3

Probability (Chance)

The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. It is always between 0 and 1 (or 0% and 100%).
4

Data Set

A data set is simply a collection of numbers or values. For example, test scores {85, 90, 78, 92, 88} form a data set of five values.
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KEY TAKEAWAY

Think of the mean like splitting a pizza equally among friends — everyone gets the same amount. The median is like lining up your class by height and finding the person in the exact middle. And probability is like asking, "If I grab one candy from a bag without looking, what are the chances it's my favorite flavor?"

SECTION 3

Visual Explanation

The diagram below shows a small data set and walks you through finding the mean and median step by step. Study the arrows and labels to see how each calculation works.

Finding Mean & Median of a Data SetData Set: { 4, 7, 2, 9, 3 }MEAN (Average)Step 1: Add all values4 + 7 + 2 + 9 + 3 = 25Step 2: Divide by count (5 values)25 ÷ 5 = 5Mean = 5MEDIAN (Middle Value)Step 1: Order least to greatest2, 3, 4, 7, 9Step 2: Find the middle number2 3 4 7 9Median = 4WHAT IF THERE IS AN EVEN NUMBER OF VALUES?Example: { 2, 3, 7, 9 } → ordered: 2, 3, 7, 9Two middle numbers: 3 and 7Median = (3 + 7) ÷ 2 = 10 ÷ 2 = 5Average the two middles!
The cyan box shows how the mean is found by adding and dividing. The violet box shows how the median is found by ordering and picking the middle value. The pink box explains the even-count case.

Notice that the mean (5) and median (4) are different numbers. That is perfectly normal! The mean gets pulled by very high or very low values, while the median stays right in the center.

SECTION 4

Mathematical Framework

Let's look at the formulas you need. Don't worry — they are simpler than they look! We will break each one down.

MEAN FORMULA

Mean=(Sumofallvalues)÷(Numberofvalues)Mean = (Sum of all values) ÷ (Number of values)

Add up every number in the data set. Then divide by how many numbers there are. For example, if your data set is {10, 20, 30}, the mean = (10 + 20 + 30) ÷ 3 = 60 ÷ 3 = 20.

MEDIAN RULE

Oddcount→middlevalue∣Evencount→averageoftwomiddlevaluesOdd count → middle value | Even count → average of two middle values

First, put all numbers in order from least to greatest. If you have an odd number of values, the median is the single middle number. If you have an even number of values, find the two middle numbers and take their mean.

PROBABILITY FORMULA

P(event)=(Numberoffavorableoutcomes)÷(Totalnumberofpossibleoutcomes)P(event) = (Number of favorable outcomes) ÷ (Total number of possible outcomes)

P(event) means "the probability of the event." Favorable outcomes are the outcomes you want. Total outcomes are all the outcomes that could happen. The answer is always between 0 (impossible) and 1 (certain).

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Quick Tip

You can express probability as a fraction, a decimal, or a percent. For instance, 1/4 = 0.25 = 25%. The HSPT may ask for any of these forms.

SECTION 5

Probability in Action

Probability becomes easier to understand when you can see it. The diagram below shows a bag of colored marbles and how to calculate the probability of drawing each color.

Probability — Marble Bag ExampleA bag has 10 marbles: 4 Red, 3 Blue, 2 Green, 1 YellowTHE BAGProbability CalculationsP(Red) = 4 ÷ 10 =2/540%P(Blue) = 3 ÷ 10 =3/1030%P(Green) = 2 ÷ 10 =1/520%P(Yellow) = 1 ÷ 10 =1/1010%Total: 4+3+2+1 = 10 ÷ 10 =1All probabilities add up to 1 (100%)!Key Rule: All individual probabilities must add up to exactly 1 (or 100%).
The marble bag diagram shows how to use the probability formula for each color. Notice that all the probabilities add up to 1, meaning one of the outcomes must happen.

Red marbles are the most common, so red has the highest probability. Yellow has only one marble, so it has the lowest probability. This makes sense — you are more likely to grab a color when there are more of that color in the bag!

Probability Scale

0 (Impossible) 1 (Certain)
0 (0%)0.5 (50%)1 (100%)

SECTION 6

Worked Example

Let's solve a full problem like one you might see on the HSPT. We will find the mean, median, and a probability — all in one scenario.

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Problem

A student scored the following points in six basketball games: 12, 8, 15, 10, 8, 19. (a) What is the mean score? (b) What is the median score? (c) If one game is chosen at random, what is the probability the student scored more than 12 points?

Part (a): Finding the Mean

  1. 1

    Step 1 — Add All Scores

    Add up all six scores: 12 + 8 + 15 + 10 + 8 + 19 = 72.
    Sum = 72
  2. 2

    Step 2 — Divide by the Number of Games

    There are 6 games total. Divide the sum by 6: 72 ÷ 6 = 12.
    Mean = 12 points

Part (b): Finding the Median

  1. 1

    Step 1 — Order the Scores from Least to Greatest

    Put the scores in order: 8, 8, 10, 12, 15, 19.
  2. 2

    Step 2 — Find the Middle

    There are 6 values (an even number). The two middle values are the 3rd and 4th numbers: 10 and 12.
  3. 3

    Step 3 — Average the Two Middle Values

    (10 + 12) ÷ 2 = 22 ÷ 2 = 11.
    Median = 11 points

Part (c): Finding the Probability

  1. 1

    Step 1 — Count Favorable Outcomes

    We want scores greater than 12. Look at the scores: 8, 8, 10, 12, 15, 19. Only 15 and 19 are greater than 12. That gives us 2 favorable outcomes.
  2. 2

    Step 2 — Count Total Outcomes

    There are 6 games total, so there are 6 possible outcomes.
  3. 3

    Step 3 — Apply the Probability Formula

    P(score > 12) = 2 ÷ 6 = 1/3 ≈ 0.333 ≈ 33.3%.
    Probability = 1/3

SECTION 7

Mean vs. Median — When to Use Each

Both the mean and median describe the "center" of a data set, but they behave differently. Understanding their strengths and weaknesses will help you answer tricky HSPT questions.

FeatureMeanMedian
What it measuresThe "fair share" or balance point of all valuesThe exact middle value when data is in order
Affected by outliers?Yes — one very high or low value can pull it a lotNo — it stays in the middle no matter what
Best when…Data is evenly spread with no extreme valuesData has very high or very low values (outliers)
Example useAverage test score in a classTypical home price in a neighborhood (a few mansions don't skew it)

Comparison of mean and median

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KEY TAKEAWAY

Imagine five friends have $10 each, but then one friend suddenly gets $1,000. The mean jumps to $208, which doesn't describe the typical friend at all. But the median stays at $10 — much more useful! When you see a weird, extreme value, the median is usually the better measure.

SECTION 8

Connecting to More Advanced Ideas

The mean, median, and basic probability you learn now are the foundation for bigger topics in high school math and beyond. Here is a preview of where these ideas lead.

What You Know NowWhere It Leads
Mean (average)Weighted averages — some values count more than others, like final exams vs. homework
MedianQuartiles and box plots — splitting data into four equal groups to see spread
Basic probability (one event)Compound probability — finding the chance of two or more events happening together
Counting outcomesPermutations and combinations — advanced counting when order matters or doesn't

From HSPT basics to high school statistics

You don't need to know these advanced topics for the HSPT, but it's cool to know that everything you learn here is a stepping stone. Master the basics and you will be ready for whatever comes next!

SECTION 9

Practice Problems

Try these five problems on your own. They start easy and get harder. After each question, check the answer to see if you are on the right track.

Question 1: CONCEPTUAL

True or false: The median of a data set always equals the mean of that data set. Explain your answer.
Show answer
False. The mean and median are two different measures. They can be equal (for example, in the set {3, 5, 7}, both the mean and median are 5), but they don't have to be. In the set {1, 2, 10}, the median is 2 while the mean is about 4.33. The mean gets pulled by the extreme value 10, but the median stays in the middle.

Question 2: BASIC CALCULATION

Find the mean and median of this data set: {14, 20, 11, 17, 23}.
Show answer
To find the mean, add all values: 14 + 20 + 11 + 17 + 23 = 85. Then divide by 5: 85 ÷ 5 = 17. For the median, first put the values in order: 11, 14, 17, 20, 23. The middle value (3rd out of 5) is 17. In this case, the mean and median happen to be the same!

Question 3: INTERMEDIATE

A spinner has 8 equal sections numbered 1 through 8. What is the probability of spinning a number greater than 5? Express your answer as a fraction and a percent.
Show answer
The numbers greater than 5 are 6, 7, and 8. That gives us 3 favorable outcomes out of 8 total outcomes. Using the probability formula: P(>5) = 3 ÷ 8 = 3/8. To convert to a percent: 3 ÷ 8 = 0.375 = 37.5%. So you have a little more than a one-in-three chance of landing on a number greater than 5.

Question 4: APPLIED

Maria's math test scores are 88, 76, 92, and 84. She has one more test. What score does she need on the 5th test so that her mean score is exactly 85?
Show answer
If the mean of 5 tests must be 85, then the total of all 5 scores must be 85 × 5 = 425. Maria's first four scores add up to 88 + 76 + 92 + 84 = 340. She needs 425 − 340 = 85 on her 5th test. This problem uses the mean formula in reverse: instead of dividing to find the mean, we multiply the desired mean by the count and work backward to find the missing value.

Question 5: CRITICAL THINKING

A class of 7 students has quiz scores with a median of 80. A new student joins the class and scores 95. Could the median of all 8 scores go down? Explain your reasoning.
Show answer
No, the median cannot go down. Here's why: with 7 students, the median is the 4th score (when ordered). With 8 students, the median becomes the average of the 4th and 5th scores. Adding a score of 95 at the top does not change any value below it. The 4th score stays the same or shifts up, and the new 5th score is either the old 4th or something higher. So the new median is either the same as before (80) or higher — it cannot decrease. This shows an important property: adding a value above the median can only push the median up or leave it the same.

SUMMARY

Lesson Summary

Summary

In this lesson you learned three powerful statistics tools. The mean is found by adding all values and dividing by the count — it tells you the "fair share." The median is the middle value of an ordered data set; when there is an even number of values, you average the two middle ones. The probability of an event equals favorable outcomes divided by total outcomes, and it is always between 0 (impossible) and 1 (certain).

Remember that the mean is sensitive to outliers while the median resists them. On the HSPT, always read carefully to know which measure the question asks for. For probability, be sure to count favorable and total outcomes accurately, and simplify your fraction when possible. Master these three skills and you'll be ready for every statistics question on test day!

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