Evaluate Wave and Particle Models - Physics

  1. What is the momentum of a photon in terms of energy in the particle model?
    p=Ecp=\frac{E}{c}. Relates photon momentum to energy using E=pcE=pc for massless particles.
  2. Which change increases photoelectron Kmax⁡K_{\max}: increasing light intensity or increasing frequency?
    Increasing frequency. Higher ff means more energy per photon after work function.
  3. Find Kmax⁡K_{\max} if hf=4.0 eVhf=4.0\,\text{eV} and ϕ=2.5 eV\phi=2.5\,\text{eV} in the photoelectric effect.
    Kmax⁡=1.5 eVK_{\max}=1.5\,\text{eV}. Subtracts work function from photon energy: 4.0−2.5=1.54.0-2.5=1.5 eV.
  4. Identify the correct model: Light transfers energy in discrete packets and ejects electrons instantly above f0f_0.
    Particle (photon) model. Instant emission and discrete energy packets indicate photons.
  5. Which model (wave or particle) directly explains the photoelectric effect?
    Particle (photon) model. Photons transfer discrete energy packets to electrons.
  6. What is the speed of electromagnetic waves in vacuum, cc, in terms of ff and λ\lambda?
    c=fλc=f\lambda. Wave equation relates speed to frequency and wavelength.
  7. What is the photon momentum formula in terms of wavelength λ\lambda?
    p=hλp=\frac{h}{\lambda}. de Broglie relation gives photon momentum from wavelength.
  8. Identify the correct statement: intensity changes photon energy or photon number per second?
    Intensity changes photon number per second. Higher intensity means more photons, not higher energy per photon.
  9. What is the photon energy formula written using wavelength instead of frequency?
    E=hcλE=\frac{hc}{\lambda}. Substitutes f=cλf=\frac{c}{\lambda} into E=hfE=hf to express energy in terms of wavelength.
  10. What is the photoelectric threshold condition for electron emission in terms of hfhf and ϕ\phi?
    Emission if hf≥ϕhf\ge\phi. Photon energy must exceed work function to eject electrons.
  11. Which model (wave or particle) best explains radiation pressure via momentum transfer?
    Particle (photon) model. Photons carry momentum p=E/cp=E/c that transfers on impact.
  12. Which model (wave or particle) best explains discrete atomic emission and absorption lines?
    Particle (photon) model. Photons with specific energies match discrete atomic energy level transitions.
  13. Which model (wave or particle) best explains interference and diffraction of light?
    Wave model. Waves can superpose and bend around obstacles, explaining these phenomena.
  14. What happens to photon energy when frequency increases, according to E=hfE=hf?
    Photon energy increases. Direct proportionality: doubling frequency doubles photon energy.
  15. What is the photon energy formula relating energy EE to frequency ff?
    E=hfE=hf. Planck's constant hh links photon energy to frequency.
  16. What is the momentum of a photon in terms of wavelength in the particle model?
    p=hλp=\frac{h}{\lambda}. de Broglie relation shows photons have momentum inversely proportional to wavelength.
  17. What is the stopping potential relation to maximum kinetic energy in the photoelectric effect?
    eVs=Kmax⁡eV_s=K_{\max}. Stopping voltage times electron charge equals maximum kinetic energy.
  18. Find photon energy for f=5.0×1014 Hzf=5.0\times10^{14}\,\text{Hz} using h=6.63×10−34 J⋅sh=6.63\times10^{-34}\,\text{J·s}.
    E=3.3×10−19 JE=3.3\times10^{-19}\,\text{J}. Multiplies Planck's constant by frequency: 6.63×10−34×5.0×10146.63\times10^{-34}\times^5.0\times10^{14}.
  19. What is the photoelectric threshold condition for emission using work function ϕ\phi?
    hf≥ϕhf\ge\phi. Photon energy must exceed work function to eject electrons from metal.
  20. What is the threshold frequency f0f_0 in terms of work function ϕ\phi?
    f0=ϕhf_0=\frac{\phi}{h}. Minimum frequency where photon energy equals work function.
  21. Which model (wave or particle) best explains the photoelectric effect observations?
    Particle (photon) model. Photons explain instant emission and frequency threshold, not wave intensity.
  22. What is the work function relation to threshold frequency f0f_0?
    ϕ=hf0\phi=hf_0. Work function equals minimum photon energy for emission.
  23. Choose the outcome: If f<f0f<f_0, what is the photoelectric emission result regardless of intensity?
    No electrons are emitted. Below threshold frequency, photons lack energy to overcome ϕ\phi.
  24. What is the photon energy formula in the particle model of electromagnetic radiation?
    E=hfE=hf. Planck's equation shows energy is quantized in packets proportional to frequency.
  25. Which model (wave or particle) directly explains interference and diffraction of light?
    Wave model. Waves superpose to create interference patterns.
  26. Find the photon energy for f=6.0×1014 Hzf=6.0\times10^{14}\ \text{Hz} using h=6.63×10−34 J⋅sh=6.63\times10^{-34}\ \text{J·s}.
    E≈4.0×10−19 JE\approx^4.0\times10^{-19}\ \text{J}. E=hf=(6.63×10−34)(6.0×1014)≈4.0×10−19E=hf=(6.63\times10^{-34})(6.0\times10^{14})\approx^4.0\times10^{-19} J.
  27. Which option best supports the photon model: emission occurs with no time delay above f0f_0?
    Particle (photon) model. Instant emission above threshold supports photon model over wave buildup.
  28. What is the maximum kinetic energy of photoelectrons in terms of ff and ϕ\phi?
    Kmax⁡=hf−ϕK_{\max}=hf-\phi. Excess photon energy beyond work function becomes electron kinetic energy.
  29. Identify the correct model: A double-slit pattern of bright and dark fringes is observed for light.
    Wave model. Interference fringes result from wave superposition.
  30. Identify the model best supported by polarization of light (wave or particle).
    Wave model (transverse wave). Only transverse waves can be polarized by filtering.
  31. What is the maximum kinetic energy of photoelectrons in the photoelectric effect?
    Kmax⁡=hf−ϕK_{\max}=hf-\phi. Excess photon energy becomes electron kinetic energy.
  32. Which change increases the photoelectric current (number of emitted electrons): higher intensity or higher frequency (above f0f_0)?
    Higher intensity. More photons (intensity) means more electrons if f>f0f>f_0.
  33. What is the wave-model relation between wave speed, frequency, and wavelength for EM radiation?
    c=fλc=f\lambda. Fundamental wave equation relating speed, frequency, and wavelength.
  34. Which model (wave or particle) explains Compton scattering as a wavelength increase after scattering?
    Particle (photon) model. Photon-electron collision transfers momentum and energy.
  35. Choose the correct model for Compton scattering (X-ray wavelength increases after scattering).
    Particle (photon) model. X-ray photons transfer momentum to electrons, losing energy and increasing λ\lambda.
  36. Find λ\lambda for f=6.0×1014 Hzf=6.0\times10^{14}\,\text{Hz} using c=3.0×108 m/sc=3.0\times10^8\,\text{m/s}.
    λ=5.0×10−7 m\lambda=5.0\times10^{-7}\,\text{m}. Uses λ=cf=3.0×1086.0×1014\lambda=\frac{c}{f}=\frac{3.0\times10^8}{6.0\times10^{14}}.
  37. What happens to wavelength when frequency increases, using c=fλc=f\lambda?
    Wavelength decreases. Since cc is constant, ff and λ\lambda are inversely proportional.
  38. Find the photon wavelength for f=5.0×1014 Hzf=5.0\times10^{14}\ \text{Hz} using c=3.0×108 m/sc=3.0\times10^8\ \text{m/s}.
    λ=6.0×10−7 m\lambda=6.0\times10^{-7}\ \text{m}. λ=c/f=(3.0×108)/(5.0×1014)=6.0×10−7\lambda=c/f=(3.0\times10^8)/(5.0\times10^{14})=6.0\times10^{-7} m.

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