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Coordinate Geometry
and Distance

Master the coordinate plane, the distance formula, and the midpoint formula: essential tools for GRE Quantitative success.

GRE Quantitative

The Coordinate Plane

Every point in the plane is described by an ordered pair \((x, y)\). The horizontal axis is the \(x\)-axis, and the vertical axis is the \(y\)-axis. They intersect at the origin \((0, 0)\).

x y (0, 0) Quadrant I Quadrant II Quadrant III Quadrant IV (+, +) (−, +) (−, −) (+, −)

Quadrant Sign Rules

Quadrant I
\(x > 0,\ y > 0\)
Quadrant II
\(x < 0,\ y > 0\)
Quadrant III
\(x < 0,\ y < 0\)
Quadrant IV
\(x > 0,\ y < 0\)

Why Coordinate Geometry Matters

Coordinate geometry converts geometric relationships into algebra. On the GRE, you will use it to find distances, midpoints, slopes, and to verify whether shapes have specific properties.

1
Distance: How far apart are two points?
2
Midpoint: Where is the center between two points?
3
Slope: How steep is the line connecting them?

The Distance Formula

For two points \(A(x_1, y_1)\) and \(B(x_2, y_2)\):

A(1, 2) B(5, 8) Δx = 4 Δy = 6 d

The Midpoint Formula

The midpoint \(M\) of a segment joining \(A(x_1, y_1)\) and \(B(x_2, y_2)\):

A(2, 3) B(8, 9) M(5, 6)

Distance vs. Midpoint

Distance Midpoint
Returns A number (length) A point (coordinates)
Operation Subtract, square, add, root Add, then divide by 2
Based on Pythagorean Theorem Arithmetic Mean
GRE Cue "How far," "length of" "Center," "halfway," "bisects"

How to Apply the Formulas

1
Identify the two points. Label them \((x_1, y_1)\) and \((x_2, y_2)\).
2
Decide the formula. "How far" → distance. "Center" → midpoint.
3
Substitute carefully. Watch minus signs: \((x_2 - x_1)^2\) is always non-negative.
4
Simplify the radical. On the GRE, simplify \(\sqrt{50}\) to \(5\sqrt{2}\), etc.
5
Check reasonableness. Sketch a quick diagram: does the answer make sense?

Example 1: Distance Between Two Points

Find the distance between \(P(-3, 4)\) and \(Q(5, -2)\).

P(−3, 4) Q(5, −2) Δx = 8 Δy = 6 d = 10

Example 2: Finding the Midpoint

Find the midpoint of the segment from \(A(-6, 2)\) to \(B(4, 8)\).

A(−6, 2) B(4, 8) M(−1, 5)

Example 3: Finding an Endpoint

The midpoint of segment \(\overline{AB}\) is \(M(3, 7)\). If \(A = (1, 4)\), find \(B\).

1
Set up the midpoint equation: \(\frac{1 + x_2}{2} = 3\) and \(\frac{4 + y_2}{2} = 7\).
2
Solve for \(x_2\): \(1 + x_2 = 6\), so \(x_2 = 5\).
3
Solve for \(y_2\): \(4 + y_2 = 14\), so \(y_2 = 10\).

Special Cases: Horizontal and Vertical

Horizontal Segment
Same \(y\)-coordinates: distance is simply \(|x_2 - x_1|\). No square root needed.
Vertical Segment
Same \(x\)-coordinates: distance is simply \(|y_2 - y_1|\). No square root needed.
(1, 5) (7, 5) d = 6 (3, 9) (3, 0) d = 9

Using Distance to Find Area

On the GRE, you may be asked for the area of a triangle or rectangle given coordinates. Use the distance formula to find side lengths, then apply the appropriate area formula.

A(1, 1) B(1, 7) C(9, 1) 6 8 10

Common Mistakes

✕ Forgetting to Square
Writing \(\sqrt{(x_2-x_1) + (y_2-y_1)}\) instead of \(\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\).
✕ Sign Errors
Subtracting \((-3) - 5\) as \(2\) instead of \(-8\). Watch negative coordinates.
✕ Mixing Up Formulas
Using subtraction in the midpoint formula or addition in the distance formula.

Formula Summary

Concept Formula Result Type
Distance \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\) A number
Midpoint \(\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\) A point
Horizontal distance \(|x_2 - x_1|\) A number
Vertical distance \(|y_2 - y_1|\) A number
Reverse midpoint \(x_2 = 2M_x - x_1\) A coordinate

Question 1 of 5

What is the distance between the points \((2, -1)\) and \((-4, 7)\)?

Question 2 of 5

What is the midpoint of the segment joining \((-2, 6)\) and \((8, -4)\)?

Question 3 of 5

The midpoint of \(\overline{PQ}\) is \(M(4, 3)\). If \(P = (1, -2)\), what are the coordinates of \(Q\)?

Question 4 of 5

A triangle has vertices at \((0, 0)\), \((6, 0)\), and \((6, 8)\). What is the length of the hypotenuse?

Question 5 of 5

Point \(A\) is at \((-3, 5)\) and point \(B\) is at \((9, 5)\). What is the distance from \(A\) to \(B\)?