Coordinate Geometry and Graph Interpretation - Quantitative Reasoning

  1. What is the vertex of the parabola y=(x−2)2−9y=(x-2)^2-9?
    (2,−9)(2,-9). Vertex form y=a(x−h)2+ky=a(x-h)^2+k identifies vertex at (h,k)=(2,−9)(h,k)=(2,-9).
  2. What is the slope formula for the line through points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?
    m=y2−y1x2−x1m=\frac{y_2-y_1}{x_2-x_1}. Calculates the rate of change as the difference in yy-coordinates divided by the difference in xx-coordinates.
  3. Identify the axis of symmetry of the parabola y=(x+5)2+1y=(x+5)^2+1.
    x=−5x=-5. In vertex form y=(x−h)2+ky=(x-h)^2+k, axis of symmetry is x=h=−5x=h=-5.
  4. What does it mean graphically if a function is increasing on an interval?
    As xx increases, yy increases (positive slope trend). The graph rises from left to right, reflecting a positive derivative.
  5. Identify the yy-intercept of the line 2x−3y=122x-3y=12.
    (0,−4)(0,-4). Set x=0x=0 in 2(0)−3y=122(0)-3y=12 to solve −3y=12-3y=12, so y=−4y=-4.
  6. What is the condition on slopes m1m_1 and m2m_2 for two nonvertical lines to be perpendicular?
    m1m2=−1m_1m_2=-1. The product of slopes equals −1-1 for lines forming right angles.
  7. What is the midpoint formula for the segment with endpoints (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?
    (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right). Averages the xx- and yy-coordinates to find the central point of the segment.
  8. Which option is the slope of a line perpendicular to y=−14x+7y=-\frac{1}{4}x+7?
    44. Perpendicular slope is the negative reciprocal of −14-\frac{1}{4}, which is 44.
  9. Identify the distance between points (0,0)(0,0) and (3,4)(3,4).
    55. Distance formula gives (3−0)2+(4−0)2=25=5\sqrt{(3-0)^2+(4-0)^2}=\sqrt{25}=5.
  10. Identify the slope of the line passing through (2,3)(2,3) and (6,11)(6,11).
    22. Apply slope formula: 11−36−2=84=2\frac{11-3}{6-2}=\frac{8}{4}=2.
  11. What is the slope-intercept form of a line with slope mm and yy-intercept bb?
    y=mx+by=mx+b. Describes the line with its slope and the point where it crosses the yy-axis.
  12. What is the slope of any vertical line in the coordinate plane?
    Undefined. Infinite slope due to zero change in xx, causing division by zero in the formula.
  13. What is the equation of a line with slope mm passing through (x1,y1)(x_1,y_1) (point-slope form)?
    y−y1=m(x−x1)y-y_1=m(x-x_1). Expresses the linear relationship using a known point and the constant rate of change.
  14. Identify the equation of the line parallel to y=23x−1y=\frac{2}{3}x-1 passing through (0,5)(0,5).
    y=23x+5y=\frac{2}{3}x+5. Parallel lines share slope 23\frac{2}{3}, and (0,5)(0,5) gives yy-intercept 55.
  15. What is the condition on slopes m1m_1 and m2m_2 for two nonvertical lines to be parallel?
    m1=m2m_1=m_2. Equal slopes ensure the lines maintain constant distance and never intersect.
  16. What is the distance formula between points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) in the coordinate plane?
    d=(x2−x1)2+(y2−y1)2d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Derives from the Pythagorean theorem applied to the horizontal and vertical distances between points.
  17. What does it mean graphically if a function is decreasing on an interval?
    As xx increases, yy decreases (negative slope trend). The graph falls from left to right, reflecting a negative derivative.
  18. What is the slope of any horizontal line in the coordinate plane?
    00. No vertical change occurs as xx varies, resulting in zero rise over run.
  19. Identify the xx-intercept of the line 2x−3y=122x-3y=12.
    (6,0)(6,0). Set y=0y=0 in 2x−3(0)=122x-3(0)=12 to solve 2x=122x=12, so x=6x=6.
  20. What is the equation of the line with slope 33 passing through (1,−2)(1,-2)?
    y=3x−5y=3x-5. Point-slope form y+2=3(x−1)y+2=3(x-1) simplifies to slope-intercept form.
  21. Identify the midpoint of the segment with endpoints (−4,7)(-4,7) and (2,−1)(2,-1).
    (−1,3)(-1,3). Midpoint formula yields (−4+22,7+(−1)2)=(−1,3)\left(\frac{-4+2}{2}, \frac{7+(-1)}{2}\right)=(-1,3).
  22. What are the xx- and yy-intercepts of the line in standard form Ax+By=CAx+By=C?
    x-int=CA, y-int=CBx\text{-int}=\frac{C}{A},\ y\text{-int}=\frac{C}{B}. Solve for intercepts by setting y=0y=0 for xx and x=0x=0 for yy.

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