Coordinate Geometry and Distance - Quantitative Reasoning

  1. What is the distance between (−1,−2)(-1,-2) and (2,2)(2,2)?
    55. Distance formula results in sqrt(2−(−1))2+(2−(−2))2=sqrt9+16=5sqrt{(2-(-1))^2+(2-(-2))^2}=sqrt{9+16}=5.
  2. What is the midpoint of the segment joining (−3,5)(-3,5) and (1,−1)(1,-1)?
    (−1,2)\left(-1,2\right). Midpoint formula: left(\frac{-3+1}{2},\frac{5+(-1)}{2}\right)=(-1,2).
  3. What is the distance between (1,2)(1,2) and (4,6)(4,6)?
    55. Distance formula gives sqrt(4−1)2+(6−2)2=sqrt9+16=5sqrt{(4-1)^2+(6-2)^2}=sqrt{9+16}=5.
  4. State the formula for the midpoint of the segment joining (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2).
    (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right). Averages the x-coordinates and y-coordinates separately to find the central point of the line segment.
  5. What is the equation of the circle with center (0,0)(0,0) and radius rr?
    x2+y2=r2x^2+y^2=r^2. Special case of the circle equation when the center is at the origin, using distance from (0,0)(0,0).
  6. What is the distance from (4,−3)(4,-3) to the origin (0,0)(0,0)?
    55. Distance to origin: sqrt(4−0)2+(−3−0)2=sqrt16+9=5sqrt{(4-0)^2+(-3-0)^2}=sqrt{16+9}=5.
  7. Identify the condition for points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) to be exactly rr units apart.
    (x2−x1)2+(y2−y1)2=r2(x_2-x_1)^2+(y_2-y_1)^2=r^2. Sets the squared distance equal to r2r^2 to define points exactly rr units apart without needing the square root.
  8. What is the distance between (5,−1)(5,-1) and (5,6)(5,6)?
    77. Vertical line segment with Deltax=0Delta x=0 and Deltay=7Delta y=7, so distance equals ∣6−(−1)∣|6-(-1)|.
  9. What is the distance between (2,3)(2,3) and (8,3)(8,3)?
    66. Horizontal line segment with Deltax=6Delta x=6 and Deltay=0Delta y=0, so distance equals ∣8−2∣|8-2|.
  10. What is the equation of the circle with center (h,k)(h,k) and radius rr?
    (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2. Represents all points (x,y)(x,y) at distance rr from center (h,k)(h,k) using the distance formula squared.
  11. State the formula for the distance from the origin (0,0)(0,0) to a point (x,y)(x,y).
    x2+y2\sqrt{x^2+y^2}. Applies the distance formula with (x1,y1)=(0,0)(x_1,y_1)=(0,0), yielding the magnitude of the position vector from the origin.
  12. What is the distance from (x1,y1)(x_1,y_1) to (x1,y2)(x_1,y_2) (same xx-coordinate)?
    ∣y2−y1∣|y_2-y_1|. With identical x-coordinates, the distance simplifies to the absolute difference in y-coordinates, as the horizontal change is zero.
  13. What is the distance from point (x0,y0)(x_0,y_0) to the horizontal line y=cy=c?
    ∣y0−c∣|y_0-c|. Vertical distance between the point's y-coordinate and the line y=cy=c uses the absolute difference.
  14. State the distance formula between two points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) in the coordinate plane.
    d=(x2−x1)2+(y2−y1)2d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Derived from the Pythagorean theorem, calculating the hypotenuse of the right triangle formed by the horizontal and vertical differences in coordinates.
  15. What is the midpoint of the segment joining (2,7)(2,7) and (6,1)(6,1)?
    (4,4)\left(4,4\right). Midpoint formula: left(\frac{2+6}{2},\frac{7+1}{2}\right)=(4,4).
  16. What is the squared distance between (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) (no square root)?
    (x2−x1)2+(y2−y1)2(x_2-x_1)^2+(y_2-y_1)^2. Squares the differences in coordinates to compute distance squared, avoiding the square root for comparisons or equations.
  17. What is the distance between (−2,1)(-2,1) and (1,5)(1,5)?
    55. Distance formula yields sqrt(1−(−2))2+(5−1)2=sqrt9+16=5sqrt{(1-(-2))^2+(5-1)^2}=sqrt{9+16}=5.
  18. What is the distance from (x1,y1)(x_1,y_1) to (x2,y1)(x_2,y_1) (same yy-coordinate)?
    ∣x2−x1∣|x_2-x_1|. With identical y-coordinates, the distance simplifies to the absolute difference in x-coordinates, as the vertical change is zero.
  19. What is the distance from (x,y)(x,y) to the xx-axis?
    ∣y∣|y|. Vertical distance from any point on the line y=yy=y to y=0y=0 is the absolute value of the y-coordinate.
  20. What is the length of the diagonal of a rectangle with corners (0,0)(0,0) and (6,8)(6,8)?
    1010. Diagonal length is the distance between opposite corners: sqrt(6−0)2+(8−0)2=sqrt36+64=10sqrt{(6-0)^2+(8-0)^2}=sqrt{36+64}=10.
  21. What is the distance from (x,y)(x,y) to the yy-axis?
    ∣x∣|x|. Horizontal distance from any point on the line x=xx=x to x=0x=0 is the absolute value of the x-coordinate.
  22. What is the distance between (0,0)(0,0) and (3,4)(3,4)?
    55. Applies the distance formula: sqrt(3−0)2+(4−0)2=sqrt9+16=sqrt25=5sqrt{(3-0)^2+(4-0)^2}=sqrt{9+16}=sqrt{25}=5.
  23. What is the distance from point (x0,y0)(x_0,y_0) to the vertical line x=cx=c?
    ∣x0−c∣|x_0-c|. Horizontal distance between the point's x-coordinate and the line x=cx=c uses the absolute difference.

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