Derive Equations of Ellipses and Parabolas - Geometry

  1. What are the vertices of a vertical hyperbola centered at (h,k)(h,k)?
    (h, k±a)(h,\,k\pm a). Vertices are the endpoints of the transverse axis, aa units from center.
  2. Find the center if the foci are (−2,5)(-2,5) and (8,5)(8,5).
    (3, 5)(3,\,5). The center is the midpoint: (−2+82,5+52)=(3,5)\left(\frac{-2+8}{2}, \frac{5+5}{2}\right) = (3,5).
  3. What are the foci of a horizontal ellipse centered at (h,k)(h,k)?
    (h±c, k)(h\pm c,\,k). Horizontal ellipses have foci along the xx-axis, displaced cc units from center.
  4. What are the vertices of a horizontal hyperbola centered at (h,k)(h,k)?
    (h±a, k)(h\pm a,\,k). Vertices are the endpoints of the transverse axis, aa units from center.
  5. Find ee for a hyperbola with a=5a=5 and c=13c=13.
    e=135e=\frac{13}{5}. Eccentricity: e=ca=135e = \frac{c}{a} = \frac{13}{5}.
  6. What is the equation of the hyperbola with foci (0,±6)(0, \pm 6) and constant difference 44?
    y24−x232=1\frac{y^2}{4}-\frac{x^2}{32}=1. Vertical hyperbola: a=2a = 2, c=6c = 6, so b2=36−4=32b^2 = 36 - 4 = 32.
  7. What is the locus definition of an ellipse using foci F1,F2F_1,F_2 and constant 2a2a?
    d(P,F1)+d(P,F2)=2ad(P,F_1)+d(P,F_2)=2a. The sum of distances from any point on an ellipse to both foci equals 2a2a.
  8. What is the equation of the hyperbola with foci (−2,1)(-2,1) and (6,1)(6,1) and constant difference 66?
    (x−2)29−(y−1)27=1\frac{(x-2)^2}{9}-\frac{(y-1)^2}{7}=1. Center (2,1)(2,1), c=4c = 4, a=3a = 3, horizontal, so b2=16−9=7b^2 = 16 - 9 = 7.
  9. What is the standard form of a horizontal ellipse centered at (h,k)(h,k) with a>ba>b?
    (x−h)2a2+(y−k)2b2=1\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1. For horizontal ellipses, aa (semi-major axis) goes under the xx-term when a>ba>b.
  10. For a hyperbola centered at $ (h,k) $, how do you find the center from foci $ (x1x_1,y1y_1) $ and $ (x2x_2,y2y_2) $?
    (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right). The center is the midpoint of the two foci.
  11. What is the equation of the hyperbola with foci (0,±6)(0,\pm 6) and constant difference 44?
    y24−x232=1\frac{y^2}{4}-\frac{x^2}{32}=1. Vertical hyperbola: a=2a = 2, c=6c = 6, so b2=36−4=32b^2 = 36 - 4 = 32.
  12. What are the foci of a vertical hyperbola centered at (h,k)(h,k)?
    (h, k±c)(h,\,k\pm c). Vertical hyperbolas have foci along the yy-axis, displaced cc units from center.
  13. What are the vertices of a vertical ellipse centered at (h,k)(h,k)?
    (h, k±a)(h,\,k\pm a). Vertices are the endpoints of the major axis, aa units from center.
  14. What is the equation of the ellipse with foci (−1,2)(-1,2) and (7,2)(7,2) and constant sum 1414?
    (x−3)249+(y−2)233=1\frac{(x-3)^2}{49}+\frac{(y-2)^2}{33}=1. Center (3,2)(3,2), c=4c = 4, a=7a = 7, horizontal, so b2=49−16=33b^2 = 49 - 16 = 33.
  15. For an ellipse centered at (h,k)(h,k), how do you find the center from foci (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?
    (x1+x22, y1+y22)\left(\frac{x_1+x_2}{2},\,\frac{y_1+y_2}{2}\right). The center is the midpoint of the two foci.
  16. What is the standard form of a horizontal hyperbola centered at $ (h,k) $?
    (x−h)2a2−(y−k)2b2=1\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1. Horizontal hyperbolas have the positive term with xx and negative term with yy.
  17. What is the standard form of a vertical ellipse centered at (h,k)(h,k) with a>ba>b?
    (x−h)2b2+(y−k)2a2=1\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1. For vertical ellipses, aa (semi-major axis) goes under the yy-term when a>ba>b.
  18. Which equation matches a horizontal hyperbola with center (h,k)(h,k), a=3a=3, and b=4b=4?
    (x−h)29−(y−k)216=1\frac{(x-h)^2}{9}-\frac{(y-k)^2}{16}=1. Horizontal hyperbola with a2=9a^2 = 9 and b2=16b^2 = 16.
  19. What is the distance formula between (x,y)(x,y) and (h,k)(h,k) in the plane?
    d=(x−h)2+(y−k)2d=\sqrt{(x-h)^2+(y-k)^2}. The Euclidean distance formula derived from the Pythagorean theorem.
  20. Find b2b^2 for a hyperbola if a=9a=9 and c=15c=15.
    b2=144b^2=144. Using c2=a2+b2c^2 = a^2 + b^2: b2=225−81=144b^2 = 225 - 81 = 144.
  21. Find ee for an ellipse with a=10a=10 and c=6c=6.
    e=35e=\frac{3}{5}. Eccentricity: e=ca=610=35e = \frac{c}{a} = \frac{6}{10} = \frac{3}{5}.
  22. What is the equation of the hyperbola with center (0,0)(0,0), foci (0,±13)(0,\pm 13), and constant difference 1010?
    y225−x2144=1\frac{y^2}{25}-\frac{x^2}{144}=1. Vertical hyperbola: a=5a = 5, c=13c = 13, so b2=169−25=144b^2 = 169 - 25 = 144.
  23. Identify the error: Using c2=a2+b2c^2=a^2+b^2 for an ellipse. What is the correct relation?
    Correct: c2=a2−b2c^2=a^2-b^2. Ellipses use subtraction: c2=a2−b2c^2 = a^2 - b^2 since c<ac < a.
  24. Find the vertices of the ellipse with foci (±3,0)(\pm 3,0) and constant sum 1010.
    (±5, 0)(\pm 5,\,0). From constant sum 10: a=5a = 5, so vertices are at (±5,0)(\pm 5, 0).
  25. What are the foci of a horizontal hyperbola centered at (h,k)(h,k)?
    (h±c, k)(h\pm c,\,k). Horizontal hyperbolas have foci along the xx-axis, displaced cc units from center.
  26. Identify the error: Using c2=a2−b2c^2=a^2-b^2 for a hyperbola. What is the correct relation?
    Correct: c2=a2+b2c^2=a^2+b^2. Hyperbolas use addition: c2=a2+b2c^2 = a^2 + b^2 since c>ac > a.
  27. Identify the value of aa for a hyperbola if the constant difference of distances is 1010.
    a=5a=5. The constant difference 2a=102a = 10, so a=5a = 5.
  28. Find cc for an ellipse if a=13a=13 and b=5b=5.
    c=12c=12. Using c2=a2−b2c^2 = a^2 - b^2: c2=169−25=144c^2 = 169 - 25 = 144, so c=12c = 12.
  29. For a hyperbola centered at (h,k)(h,k), how do you find the center from foci (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?
    (x1+x22, y1+y22)\left(\frac{x_1+x_2}{2},\,\frac{y_1+y_2}{2}\right). The center is the midpoint of the two foci.
  30. What is the standard form of a vertical hyperbola centered at (h,k)(h,k)?
    (y−k)2a2−(x−h)2b2=1\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1. Vertical hyperbolas have the positive term with yy and negative term with xx.
  31. What is the eccentricity formula for an ellipse or hyperbola in terms of aa and cc?
    e=cae=\frac{c}{a}. Eccentricity measures how elongated the conic is relative to a circle.
  32. What is the asymptote form for a vertical hyperbola (y−k)2a2−(x−h)2b2=1\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1?
    y−k=±ab(x−h)y-k=\pm \frac{a}{b}(x-h). For vertical hyperbolas, slopes are ±ab\pm \frac{a}{b}.
  33. What is the equation of the ellipse with center (0,0)(0,0), foci (±3,0)(\pm 3,0), and constant sum 1010?
    x225+y216=1\frac{x^2}{25}+\frac{y^2}{16}=1. Horizontal ellipse: a=5a = 5, c=3c = 3, so b2=25−9=16b^2 = 25 - 9 = 16.
  34. Which equation matches a vertical ellipse with center (h,k)(h,k), a=7a=7, and b=2b=2?
    (x−h)24+(y−k)249=1\frac{(x-h)^2}{4}+\frac{(y-k)^2}{49}=1. Vertical ellipse with a2=49a^2 = 49 and b2=4b^2 = 4.
  35. What is the equation of the hyperbola with center (0,0)(0,0), foci (±5,0)(\pm 5,0), and constant difference 66?
    x29−y216=1\frac{x^2}{9}-\frac{y^2}{16}=1. Horizontal hyperbola: a=3a = 3, c=5c = 5, so b2=25−9=16b^2 = 25 - 9 = 16.
  36. Find b2b^2 for an ellipse if a=10a=10 and c=6c=6.
    b2=64b^2=64. Using c2=a2−b2c^2 = a^2 - b^2: b2=100−36=64b^2 = 100 - 36 = 64.
  37. For a hyperbola, what relationship connects aa, bb, and focal distance cc?
    c2=a2+b2c^2=a^2+b^2. For hyperbolas, c>ac>a so c2=a2+b2c^2 = a^2 + b^2 where cc is the focal distance.
  38. Identify the transverse axis orientation if the foci are (h±c,k)(h\pm c,k).
    Horizontal. Foci with same yy-coordinate indicate horizontal transverse axis.
  39. What is the equation of the ellipse with foci (±2,0)(\pm 2,0) and constant sum 1212?
    x236+y232=1\frac{x^2}{36}+\frac{y^2}{32}=1. Horizontal ellipse: a=6a = 6, c=2c = 2, so b2=36−4=32b^2 = 36 - 4 = 32.
  40. What is the equation of the hyperbola with foci $ (5,-4) $ and $ (5,8) $ and constant difference $ 8 $?
    (y−2)216−(x−5)220=1\frac{(y-2)^2}{16}-\frac{(x-5)^2}{20}=1. Center $ (5,2) $, $ c = 6 $, $ a = 4 $, vertical, so $ b2b^2 = 36 - 16 = 20 $.
  41. Find the center if the foci are (4,−7)(4,-7) and (4,9)(4,9).
    (4, 1)(4,\,1). The center is the midpoint: (4+42,−7+92)=(4,1)\left(\frac{4+4}{2}, \frac{-7+9}{2}\right) = (4,1).
  42. What is the equation of the ellipse with foci (4,−3)(4,-3) and (4,9)(4,9) and constant sum 2020?
    (x−4)264+(y−3)2100=1\frac{(x-4)^2}{64}+\frac{(y-3)^2}{100}=1. Center (4,3)(4,3), c=6c = 6, a=10a = 10, vertical, so b2=100−36=64b^2 = 100 - 36 = 64.
  43. For an ellipse, what inequality must hold between 2a2a and the distance between the foci 2c2c?
    2a>2c2a>2c. For an ellipse to exist, the sum must exceed the distance between foci.
  44. For an ellipse, what relationship connects aa, bb, and focal distance cc?
    c2=a2−b2c^2=a^2-b^2. For ellipses, c<ac<a so c2=a2−b2c^2 = a^2 - b^2 where cc is the focal distance.
  45. What is the equation of the ellipse with center (0,0)(0,0), foci (0,±4)(0,\pm 4), and constant sum 1414?
    x233+y249=1\frac{x^2}{33}+\frac{y^2}{49}=1. Vertical ellipse: a=7a = 7, c=4c = 4, so b2=49−16=33b^2 = 49 - 16 = 33.
  46. For a hyperbola, what inequality must hold between 2a2a and the distance between the foci 2c2c?
    2a<2c2a<2c. For a hyperbola to exist, the difference must be less than the distance between foci.
  47. Find cc if the foci of a horizontal conic are (h−6,k)(h-6,k) and (h+6,k)(h+6,k).
    c=6c=6. The distance from center to each focus is c=6c = 6.
  48. Identify the value of aa for an ellipse if the constant sum of distances is 1414.
    a=7a=7. The constant sum 2a=142a = 14, so a=7a = 7.
  49. What is the locus definition of a hyperbola using foci F1,F2F_1,F_2 and constant 2a2a?
    ∣d(P,F1)−d(P,F2)∣=2a|d(P,F_1)-d(P,F_2)|=2a. The absolute difference of distances from any point on a hyperbola to both foci equals 2a2a.
  50. What condition on eccentricity ee indicates a hyperbola?
    e>1e>1. Hyperbolas have eccentricity greater than 1.
  51. What condition on eccentricity ee indicates an ellipse (not a circle)?
    0<e<10<e<1. Ellipses have eccentricity between 0 and 1 (circle has e=0e = 0).
  52. Identify the transverse axis orientation if the foci are (h,k±c)(h,k\pm c).
    Vertical. Foci with same xx-coordinate indicate vertical transverse axis.
  53. What is the asymptote form for a horizontal hyperbola (x−h)2a2−(y−k)2b2=1\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1?
    y−k=±ba(x−h)y-k=\pm \frac{b}{a}(x-h). For horizontal hyperbolas, slopes are ±ba\pm \frac{b}{a}.
  54. What is the equation of the hyperbola with foci (5,−4)(5,-4) and (5,8)(5,8) and constant difference 88?
    (y−2)216−(x−5)220=1\frac{(y-2)^2}{16}-\frac{(x-5)^2}{20}=1. Center (5,2)(5,2), c=6c = 6, a=4a = 4, vertical, so b2=36−16=20b^2 = 36 - 16 = 20.
  55. Find cc for a hyperbola if a=8a=8 and b=6b=6.
    c=10c=10. Using c2=a2+b2c^2 = a^2 + b^2: c2=64+36=100c^2 = 64 + 36 = 100, so c=10c = 10.
  56. What are the vertices of a horizontal ellipse centered at (h,k)(h,k)?
    (h±a, k)(h\pm a,\,k). Vertices are the endpoints of the major axis, aa units from center.
  57. What are the foci of a vertical ellipse centered at (h,k)(h,k)?
    (h, k±c)(h,\,k\pm c). Vertical ellipses have foci along the yy-axis, displaced cc units from center.
  58. Find the vertices of the hyperbola with foci (0,±13)(0,\pm 13) and constant difference 1010.
    (0, ±5)(0,\,\pm 5). From constant difference 10: a=5a = 5, so vertices are at (0,±5)(0, \pm 5).

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