Applying Laws of Sines and Cosines - Geometry

  1. Identify the correct first step to solve SSASSA data: use Law of Sines to find an angle or Law of Cosines to find a side?
    Use Law of Sines to find an angle. With two sides and non-included angle, find the angle opposite the known side.
  2. What is the circumradius form of the Law of Sines relating aa and sin⁡A\sin A?
    asin⁡A=2R\frac{a}{\sin A}=2R. Relates any side-angle pair to twice the circumradius RR.
  3. What is the full circumradius form of the Law of Sines for triangle ABCABC?
    asin⁡A=bsin⁡B=csin⁡C=2R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R. Extended Law of Sines including the circumradius relationship.
  4. Identify the missing step: If sin⁡A=asin⁡Bb\sin A=\frac{a\sin B}{b}, what must be checked before taking A=arcsin⁡(⋅)A=\arcsin(\cdot)?
    Check for a second solution 180∘−A180^\circ-A (ambiguous case). Must check if 180°−A180° - A also creates a valid triangle solution.
  5. Which method should you use first for SSSSSS data: Law of Sines or Law of Cosines?
    Law of Cosines. Three sides require Law of Cosines to find any angle.
  6. Find KK if a=10a=10, b=6b=6, and included angle C=30∘C=30^\circ.
    K=12⋅10⋅6sin⁡30∘K=\frac{1}{2}\cdot 10\cdot 6\sin 30^\circ. Apply area formula with sides aa, bb and included angle CC.
  7. What is the Law of Cosines formula for side cc in triangle ABCABC?
    c2=a2+b2−2abcos⁡Cc^2=a^2+b^2-2ab\cos C. Relates side cc to the other two sides and the cosine of opposite angle CC.
  8. Which method should you use first for ASAASA data: Law of Sines or Law of Cosines?
    Law of Sines. Two angles and one side can use Law of Sines directly.
  9. What is the Pythagorean Theorem statement that the Law of Cosines generalizes?
    a2=b2+c2a^2=b^2+c^2 when A=90∘A=90^\circ. The Pythagorean Theorem is a special case when one angle is 90°90°.
  10. What is the possible second angle in the SSASSA ambiguous case if one solution has angle AA?
    180∘−A180^\circ-A. Sine is positive in quadrants I and II, creating two possible angles.
  11. Which method should you use first for SASSAS data: Law of Sines or Law of Cosines?
    Law of Cosines. Two sides and included angle require Law of Cosines first.
  12. Which triangle data type is typically solved first using the Law of Cosines: SSSSSS or AASAAS?
    SSSSSS. Three sides require Law of Cosines to find any angle.
  13. Find CC in degrees if cos⁡C=0\cos C=0.
    C=90∘C=90^\circ. Cosine equals zero when the angle is 90°90°.
  14. What is the condition for exactly one right triangle in SSASSA when AA is acute and a=bsin⁡Aa=b\sin A?
    One triangle (right). When a=bsin⁡Aa = b\sin A, the triangle forms exactly one right triangle.
  15. What is the Law of Cosines formula for side bb in triangle ABCABC?
    b2=a2+c2−2accos⁡Bb^2=a^2+c^2-2ac\cos B. Relates side bb to the other two sides and the cosine of opposite angle BB.
  16. What is the condition for no triangle in SSASSA when AA is obtuse and a≤ba\le b?
    No triangle. Obtuse angle requires its opposite side to be the longest.
  17. What is the sine definition used in a Law of Cosines proof for angle AA in the same setup with opposite height hh and hypotenuse cc?
    sin⁡A=hc\sin A=\frac{h}{c}. Opposite side hh over hypotenuse cc defines sine of angle AA.
  18. What is the height relation used in a common proof of the Law of Sines when dropping altitude hh to side cc from CC?
    h=bsin⁡A=asin⁡Bh=b\sin A=a\sin B. Altitude creates two right triangles with the same height from vertex CC.
  19. Find cc using the Law of Sines if C=60∘C=60^\circ, A=45∘A=45^\circ, and a=8a=8.
    c=8⋅sin⁡60∘sin⁡45∘c=8\cdot\frac{\sin 60^\circ}{\sin 45^\circ}. Apply csin⁡C=asin⁡A\frac{c}{\sin C} = \frac{a}{\sin A} and solve for cc.
  20. Find RR if a=12a=12 and A=30∘A=30^\circ using asin⁡A=2R\frac{a}{\sin A}=2R.
    R=122sin⁡30∘R=\frac{12}{2\sin 30^\circ}. Use circumradius formula R=a2sin⁡AR = \frac{a}{2\sin A}.
  21. What is the Law of Cosines formula for side aa in triangle ABCABC?
    a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A. Relates side aa to the other two sides and the cosine of opposite angle AA.
  22. What is the ambiguous case associated with the Law of Sines called?
    SSASSA ambiguous case. Two sides and non-included angle can create zero, one, or two triangles.
  23. Find cc with the Law of Cosines if a=5a=5, b=12b=12, and C=90∘C=90^\circ.
    c=52+122c=\sqrt{5^2+12^2}. When C=90°C = 90°, Law of Cosines reduces to Pythagorean Theorem.
  24. What is the condition for exactly one triangle in SSASSA when AA is obtuse and a>ba>b?
    One triangle. Obtuse angle with longer opposite side creates exactly one triangle.
  25. Identify the correct formula to find an angle from three sides aa, bb, cc (choose the one for CC).
    C=arccos⁡(a2+b2−c22ab)C=\arccos\left(\frac{a^2+b^2-c^2}{2ab}\right). Inverse cosine of the rearranged Law of Cosines expression.
  26. Find BB if A=40∘A=40^\circ and C=65∘C=65^\circ in triangle ABCABC.
    B=75∘B=75^\circ. Angles in a triangle sum to 180°180°: B=180°−40°−65°B = 180° - 40° - 65°.
  27. Which triangle data type is typically solved first using the Law of Cosines: SASSAS or ASAASA?
    SASSAS. Two sides and included angle require Law of Cosines to find the third side.
  28. What equality follows immediately from bsin⁡A=asin⁡Bb\sin A=a\sin B in a Law of Sines proof?
    asin⁡A=bsin⁡B\frac{a}{\sin A}=\frac{b}{\sin B}. Dividing both sides by sin⁡Asin⁡B\sin A \sin B yields the Law of Sines ratio.
  29. What is the cosine definition used in a Law of Cosines proof for angle AA in a right triangle with adjacent xx and hypotenuse cc?
    cos⁡A=xc\cos A=\frac{x}{c}. Adjacent side xx over hypotenuse cc defines cosine of angle AA.
  30. What is the condition for no triangle in SSASSA when given AA acute, opposite side aa, adjacent side bb, and a<bsin⁡Aa<b\sin A?
    No triangle. When a<bsin⁡Aa < b\sin A, the given side is too short to reach the base.
  31. What is the rearranged Law of Cosines expression for cos⁡C\cos C?
    cos⁡C=a2+b2−c22ab\cos C=\frac{a^2+b^2-c^2}{2ab}. Isolates cos⁡C\cos C by rearranging the Law of Cosines formula.
  32. Find and correct the mismatch: asin⁡B=bsin⁡A\frac{a}{\sin B}=\frac{b}{\sin A} in triangle ABCABC.
    Correct: asin⁡A=bsin⁡B\frac{a}{\sin A}=\frac{b}{\sin B}. Sides must pair with their opposite angles in the Law of Sines.
  33. What is the Law of Sines for triangle ABCABC with sides aa, bb, cc opposite AA, BB, CC?
    asin⁡A=bsin⁡B=csin⁡C\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}. Each side divided by its opposite angle's sine equals the same ratio.
  34. What is the area formula using two sides and the included angle, suitable with SASSAS data?
    K=12bcsin⁡AK=\frac{1}{2}bc\sin A. Uses two sides and their included angle to find triangle area.
  35. What is the condition for exactly one triangle in SSASSA when AA is acute and a≥ba\ge b?
    One triangle. When the known side is longest, only one triangle is possible.
  36. What is the rearranged Law of Cosines expression for cos⁡B\cos B?
    cos⁡B=a2+c2−b22ac\cos B=\frac{a^2+c^2-b^2}{2ac}. Isolates cos⁡B\cos B by rearranging the Law of Cosines formula.
  37. Which triangle data type is always solvable using the Law of Sines without ambiguity: ASAASA, AASAAS, SASSAS, or SSSSSS?
    ASAASA or AASAAS. Both cases provide two angles and one side, giving unique solutions.
  38. Find aa using the Law of Sines if A=30∘A=30^\circ, B=45∘B=45^\circ, and b=10b=10.
    a=10⋅sin⁡30∘sin⁡45∘a=10\cdot\frac{\sin 30^\circ}{\sin 45^\circ}. Apply asin⁡A=bsin⁡B\frac{a}{\sin A} = \frac{b}{\sin B} and solve for aa.
  39. What is the rearranged Law of Cosines expression for cos⁡A\cos A?
    cos⁡A=b2+c2−a22bc\cos A=\frac{b^2+c^2-a^2}{2bc}. Isolates cos⁡A\cos A by rearranging the Law of Cosines formula.
  40. Find bb using the Law of Sines if A=35∘A=35^\circ, B=70∘B=70^\circ, and a=4a=4.
    b=4⋅sin⁡70∘sin⁡35∘b=4\cdot\frac{\sin 70^\circ}{\sin 35^\circ}. Apply bsin⁡B=asin⁡A\frac{b}{\sin B} = \frac{a}{\sin A} and solve for bb.
  41. What is the area formula KK in terms of aa, cc, and included angle BB?
    K=12acsin⁡BK=\frac{1}{2}ac\sin B. Area formula using sides aa, cc and their included angle BB.
  42. Find a2a^2 using the Law of Cosines if b=3b=3, c=4c=4, and A=120∘A=120^\circ.
    a2=32+42−2⋅3⋅4cos⁡120∘a^2=3^2+4^2-2\cdot 3\cdot 4\cos 120^\circ. Apply Law of Cosines with cos⁡120°=−12\cos 120° = -\frac{1}{2}.
  43. Find aa with the Law of Cosines if b=7b=7, c=9c=9, and A=60∘A=60^\circ.
    a=72+92−2⋅7⋅9cos⁡60∘a=\sqrt{7^2+9^2-2\cdot 7\cdot 9\cos 60^\circ}. Apply Law of Cosines with known sides bb, cc and included angle AA.
  44. What is the condition for two triangles in SSASSA when AA is acute and bsin⁡A<a<bb\sin A<a<b?
    Two triangles. The intermediate range creates two possible triangles (ambiguous case).
  45. Identify the correct statement for side-angle correspondence in triangle ABCABC.
    a↔Aa\leftrightarrow A, b↔Bb\leftrightarrow B, c↔Cc\leftrightarrow C. Standard notation: lowercase sides opposite uppercase angles.
  46. What is the area formula KK in terms of aa, bb, and included angle CC?
    K=12absin⁡CK=\frac{1}{2}ab\sin C. Area formula using sides aa, bb and their included angle CC.
  47. What does the Law of Cosines become when A=180∘A=180^\circ in a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A?
    a2=(b+c)2a^2=(b+c)^2. When cos⁡180°=−1\cos 180° = -1, the formula becomes a2=b2+c2+2bc=(b+c)2a^2 = b^2 + c^2 + 2bc = (b+c)^2.
  48. Find sin⁡B\sin B if a=9a=9, A=50∘A=50^\circ, and b=12b=12 using the Law of Sines.
    sin⁡B=12sin⁡50∘9\sin B=\frac{12\sin 50^\circ}{9}. Apply sin⁡Bb=sin⁡Aa\frac{\sin B}{b} = \frac{\sin A}{a} and solve for sin⁡B\sin B.
  49. What does the Law of Cosines become when A=0∘A=0^\circ in the expression a2=b2+c2−2bccos⁡Aa^2=b^2+c^2-2bc\cos A?
    a2=(b−c)2a^2=(b-c)^2. When cos⁡0°=1\cos 0° = 1, the formula becomes a2=b2+c2−2bc=(b−c)2a^2 = b^2 + c^2 - 2bc = (b-c)^2.
  50. What does the Law of Cosines simplify to when A=90∘A=90^\circ?
    a2=b2+c2a^2=b^2+c^2. When cos⁡90°=0\cos 90° = 0, the −2bccos⁡A-2bc\cos A term vanishes.
  51. What is the Law of Sines proportion to solve for AA given aa, bb, and BB?
    sin⁡A=asin⁡Bb\sin A=\frac{a\sin B}{b}. Rearranged Law of Sines to isolate sin⁡A\sin A.
  52. Find cos⁡C\cos C if a=6a=6, b=8b=8, and c=10c=10.
    cos⁡C=62+82−1022⋅6⋅8\cos C=\frac{6^2+8^2-10^2}{2\cdot 6\cdot 8}. Apply rearranged Law of Cosines to find cos⁡C\cos C from three sides.

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