Applying Density in Modeling Situations - Geometry

  1. Which unit best matches volume density: kg/m2\text{kg/m}^2 or kg/m3\text{kg/m}^3?
    kg/m3\text{kg/m}^3. Volume density has cubic units in the denominator.
  2. What total population QQ corresponds to 35 people/mi235\text{ people/mi}^2 over 8 mi28\text{ mi}^2?
    280 people280\text{ people}. Q=DA=35×8=280Q = DA = 35 × 8 = 280 people.
  3. Identify the correct density unit: "g/cm2^2" or "g/cm3^3" for volume density.
    "g/cm3^3". Volume density requires cubic units in the denominator.
  4. What is the volume density if 300300 units fill a cylinder of volume 60(ft)360 (\text{ft})^3?
    5(units/ft)35 (\text{units/ft})^3. Density = 30060=5\frac{300}{60} = 5 units per cubic foot.
  5. Which expression correctly converts 3 BTU/ft33\text{ BTU/ft}^3 to BTU per in3\text{in}^3?
    31728 BTU/in3\frac{3}{1728}\text{ BTU/in}^3. Convert using 1 ft3=1728 in31 \text{ ft}^3 = 1728 \text{ in}^3.
  6. What is the area density if 450450 trees occupy 9 acres9\text{ acres}?
    50 trees/acre50\text{ trees/acre}. Density = 4509=50\frac{450}{9} = 50 trees per acre.
  7. If a map scale factor is k=2k=2, how does a fixed total QQ affect area density?
    Density becomes 14\frac{1}{4} of the original. Area scales by 22=42^2 = 4, so density is divided by 4.
  8. Identify the correct density unit: "g/cm2^2" or "g/cm3^3" for area density.
    "g/cm2^2". Area density requires square units in the denominator.
  9. A room has 9600 BTU9600\text{ BTU} in 320 ft3320\text{ ft}^3. What is the energy density?
    30 BTU/ft330\text{ BTU/ft}^3. Density = 9600320=30\frac{9600}{320} = 30 BTU per cubic foot.
  10. What is the formula for total amount QQ given volume density DD and volume VV?
    Q=DVQ=DV. Multiply density by volume to get total amount.
  11. What is 3 BTU/ft33\text{ BTU/ft}^3 expressed in BTU per in3\text{in}^3?
    1576 BTU/in3\frac{1}{576}\text{ BTU/in}^3. 31728=1576\frac{3}{1728} = \frac{1}{576} BTU per cubic inch.
  12. What is the area of a triangle with base 10 m10\text{ m} and height 6 m6\text{ m}?
    30 m230\text{ m}^2. Area = 12×10×6=30\frac{1}{2} × 10 × 6 = 30 square meters.
  13. Find and correct the unit error: area density written as people/mi3\text{people/mi}^3.
    Correct unit: people/mi2\text{people/mi}^2. Area density needs square units, not cubic units.
  14. What is the area of a rectangle with sides 8 m8\text{ m} and 3 m3\text{ m}?
    24 m224\text{ m}^2. Area = length × width = 8×38 × 3.
  15. A city has 80 people/mi280\text{ people/mi}^2. How many people are in 0.5 mi20.5\text{ mi}^2?
    40 people40\text{ people}. Q=DA=80×0.5=40Q = DA = 80 × 0.5 = 40 people.
  16. What volume VV is needed for 900 BTU900\text{ BTU} at 15 BTU/ft315\text{ BTU/ft}^3?
    60 ft360\text{ ft}^3. V=QD=90015=60V = \frac{Q}{D} = \frac{900}{15} = 60 cubic feet.
  17. A plot has density 4 plants/m24\text{ plants/m}^2. How many plants are in 15 m215\text{ m}^2?
    60 plants60\text{ plants}. Q=DA=4×15=60Q = DA = 4 × 15 = 60 plants.
  18. What unit type should area density have (in terms of powers of length)?
    Units of the form quantitylength2\frac{\text{quantity}}{\text{length}^2}. Area has square units, so density uses length squared in denominator.
  19. What is 2 people/ft22\text{ people/ft}^2 expressed in people per in2\text{in}^2?
    172 people/in2\frac{1}{72}\text{ people/in}^2. 2144=172\frac{2}{144} = \frac{1}{72} people per square inch.
  20. What is the definition of volume density in a modeling situation?
    Amount per unit volume, such as quantityunit3\frac{\text{quantity}}{\text{unit}^3}. Ratio of total quantity to the volume it occupies.
  21. Find AA if Q=500Q=500 and D=25D=25 in D=QAD=\frac{Q}{A}.
    2020. A=QD=50025=20A = \frac{Q}{D} = \frac{500}{25} = 20.
  22. What is the formula for total amount QQ given area density DD and area AA?
    Q=DAQ=DA. Multiply density by area to get total amount.
  23. Identify the correct interpretation of D=QVD=\frac{Q}{V} in words.
    Density equals amount per unit volume. Formula represents quantity divided by volume.
  24. Identify the density if Q=72Q=72 and A=9A=9: what is DD in D=QAD=\frac{Q}{A}?
    88. D=729=8D = \frac{72}{9} = 8 units per area.
  25. What is the volume density if 300300 units fill a cylinder of volume 60 ft360\text{ ft}^3?
    5 units/ft35\text{ units/ft}^3. Density = 30060=5\frac{300}{60} = 5 units per cubic foot.
  26. What is the area density if 150150 fish are in a pond of area 30m230\text{m}^2?
    5fish/m25\text{fish/m}^2. Density = 15030=5\frac{150}{30} = 5 fish per square meter.
  27. What is the volume of a cylinder with r=2 ftr=2\text{ ft} and h=5 fth=5\text{ ft} using π≈3\pi\approx 3?
    60 ft360\text{ ft}^3. Volume = πr2h=3×4×5=60\pi r^2 h = 3 × 4 × 5 = 60 cubic feet.
  28. A park has 300300 visitors over 12 ha12 \text{ ha}. What is the visitor density?
    25 visitors/ha25 \text{ visitors/ha}. Density = 30012=25\frac{300}{12} = 25 visitors per hectare.
  29. If a solid is scaled by factor kk, how does its volume scale?
    Volume scales by k3k^3. Linear scaling factor kk gives volume scaling k3k^3.
  30. Identify the missing variable: Q=DVQ=DV solves for what when you compute QD\frac{Q}{D}?
    VV. Rearranging Q=DVQ = DV gives V=QDV = \frac{Q}{D}.
  31. What is the definition of area density in a modeling situation?
    Amount per unit area, such as quantityunit2\frac{\text{quantity}}{\text{unit}^2}. Ratio of total quantity to the area it occupies.
  32. Which unit best matches area density: kg/m2\text{kg/m}^2 or kg/m3\text{kg/m}^3?
    kg/m2\text{kg/m}^2. Area density has square units in the denominator.
  33. What is the volume of a rectangular prism 2 m×3 m×4 m2\text{ m}\times 3\text{ m}\times 4\text{ m}?
    24 m324\text{ m}^3. Volume = length × width × height = 2×3×42 × 3 × 4.
  34. If a model is scaled by k=3k=3 with fixed total QQ, how does volume density change?
    Density becomes 127\frac{1}{27} of the original. Volume scales by 33=273^3 = 27, so density is divided by 27.
  35. Find and correct the unit error: area density written as people/mi3\text{people/mi}^3.
    Correct unit: people/mi2\text{people/mi}^2. Area density needs square units, not cubic units.
  36. Identify the density if Q=84Q=84 and V=7V=7: what is DD in D=QVD=\frac{Q}{V}?
    1212. D=847=12D = \frac{84}{7} = 12 units per volume.
  37. A fuel has 25 BTU/ft325\text{ BTU/ft}^3. How many BTU are in 2 ft32\text{ ft}^3?
    50 BTU50\text{ BTU}. Q=DV=25×2=50Q = DV = 25 × 2 = 50 BTU.
  38. What is the area density if 120120 people live in 3 mi23\text{ mi}^2?
    40 people/mi240\text{ people/mi}^2. Density = 1203=40\frac{120}{3} = 40 people per square mile.
  39. What area AA is needed for 240240 people at 30 people/mi230\text{ people/mi}^2?
    8 mi28\text{ mi}^2. A=QD=24030=8A = \frac{Q}{D} = \frac{240}{30} = 8 square miles.
  40. What is the formula for density using area AA and total amount QQ?
    D=QAD=\frac{Q}{A}. Density equals quantity divided by area.
  41. What total energy QQ corresponds to 12 BTU/ft312\text{ BTU/ft}^3 in 50 ft350\text{ ft}^3?
    600 BTU600\text{ BTU}. Q=DV=12×50=600Q = DV = 12 × 50 = 600 BTU.
  42. What is the volume density if 18 g18\text{ g} of material fills 6 cm36\text{ cm}^3?
    3 g/cm33\text{ g/cm}^3. Density = 186=3\frac{18}{6} = 3 grams per cubic centimeter.
  43. Which expression correctly converts 2 people/ft22\text{ people/ft}^2 to people per in2\text{in}^2?
    2144 people/in2\frac{2}{144}\text{ people/in}^2. Convert using 1 ft2=144 in21 \text{ ft}^2 = 144 \text{ in}^2.
  44. Find and correct the unit error: volume density written as BTU/ft2\text{BTU/ft}^2.
    Correct unit: BTU/ft3\text{BTU/ft}^3. Volume density needs cubic units, not square units.
  45. If a region is scaled by factor kk, how does its area scale?
    Area scales by k2k^2. Linear scaling factor kk gives area scaling k2k^2.
  46. What is the volume density if 600 BTU600\text{ BTU} are in 30 ft330\text{ ft}^3?
    20 BTU/ft320\text{ BTU/ft}^3. Density = 60030=20\frac{600}{30} = 20 BTU per cubic foot.
  47. A container has density 7 mg/cm37\text{ mg/cm}^3. How many mg are in 10 cm310\text{ cm}^3?
    70 mg70\text{ mg}. Q=DV=7×10=70Q = DV = 7 × 10 = 70 milligrams.
  48. What does the unit "persons per square mile" represent in modeling?
    Area density: persons per mi2\text{mi}^2. Population distributed over square miles measures area density.
  49. What happens to area density if the same total QQ is spread over 22 times the area?
    It is divided by 22. Same quantity over double area gives half density.
  50. Find VV if Q=144Q=144 and D=6D=6 in D=QVD=\frac{Q}{V}.
    2424. V=QD=1446=24V = \frac{Q}{D} = \frac{144}{6} = 24.
  51. What happens to volume density if the same total QQ is spread over 33 times the volume?
    It is divided by 33. Same quantity over triple volume gives one-third density.
  52. What unit type should volume density have (in terms of powers of length)?
    Units of the form quantitylength3\frac{\text{quantity}}{\text{length}^3}. Volume has cubic units, so density uses length cubed in denominator.
  53. What is the formula for density using volume VV and total amount QQ?
    D=QVD=\frac{Q}{V}. Density equals quantity divided by volume.
  54. A park has 300300 visitors over 12 ha12\text{ ha}. What is the visitor density?
    25 visitors/ha25\text{ visitors/ha}. Density = 30012=25\frac{300}{12} = 25 visitors per hectare.
  55. What is 2 people/ft22\text{ people/ft}^2 expressed in people per in2\text{in}^2?
    172 people/in2\frac{1}{72}\text{ people/in}^2. 2144=172\frac{2}{144} = \frac{1}{72} people per square inch.
  56. Which expression correctly converts 2 people/ft22\text{ people/ft}^2 to people per in2\text{in}^2?
    2144 people/in2\frac{2}{144}\text{ people/in}^2. Convert using 1 ft2=144 in21 \text{ ft}^2 = 144 \text{ in}^2.
  57. What does the unit "BTU per cubic foot" represent in modeling?
    Volume density: BTU per ft3\text{ft}^3. Energy distributed over cubic feet measures volume density.
  58. Identify the correct interpretation of D=QAD=\frac{Q}{A} in words.
    Density equals amount per unit area. Formula represents quantity divided by area.
  59. Identify the missing variable: Q=DAQ=DA solves for what when you compute QD\frac{Q}{D}?
    AA. Rearranging Q=DAQ = DA gives A=QDA = \frac{Q}{D}.
  60. What is the area density if 150150 fish are in a pond of area 30 m230\text{ m}^2?
    5 fish/m25\text{ fish/m}^2. Density = 15030=5\frac{150}{30} = 5 fish per square meter.

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