General Chemistry 2 • Acids and Bases

Ka, Kb & pKa/pKb — Interpret acid/base strength using Ka, Kb, and pKa/pKb

Quantify acid and base strength through equilibrium constants and their logarithmic scales.

An atom with laboratory flask and electron orbit for General Chemistry 2
Inside this lesson 10 sections 5 questions 9 figures

SECTION 1

Historical Context & Motivation

The quest to quantify acid and base strength stretches back to the late nineteenth century, when chemists recognized that simply labeling a substance as an "acid" or a "base" was insufficient for predicting its behavior in solution. Early titration experiments demonstrated that acids of equal concentration could differ dramatically in their ability to conduct electricity, corrode metals, or shift indicator dyes—observations that demanded a numerical measure of intrinsic acid strength. The development of equilibrium constants for ionization reactions provided exactly that measure, transforming acid–base chemistry from a qualitative art into a rigorous, predictive science.

1884 • Arrhenius Theory of Ionization

Svante Arrhenius proposed that electrolytes dissociate into ions in aqueous solution, laying the groundwork for understanding that acids produce H⁺ and bases produce OH⁻ to varying degrees.

1907 • Ostwald's Dilution Law

Wilhelm Ostwald applied the law of mass action to weak electrolytes, deriving a relationship between the degree of dissociation, concentration, and what we now call the acid dissociation constant, Ka.

1909 • Sørensen Introduces the pH Scale

Søren Sørensen defined pH as the negative logarithm of the hydrogen ion concentration, providing a compact, logarithmic scale that would later inspire the analogous pKa and pKb scales.

1923 • Brønsted–Lowry Definition

Johannes Brønsted and Thomas Lowry independently redefined acids as proton donors and bases as proton acceptors, broadening the theoretical framework beyond aqueous solutions and solidifying the role of conjugate acid–base pairs.

1930s–Present • Systematic pKa Tables

Extensive compilations of pKa values were assembled for thousands of organic and inorganic compounds, becoming indispensable tools in pharmacology, biochemistry, and synthetic chemistry.

The central question these developments addressed is deceptively simple: How do we assign a single number that captures how readily an acid donates a proton—or a base accepts one—in aqueous equilibrium? The answer lies in the acid dissociation constant (Kₐ), the base dissociation constant (KbK_b), and their logarithmic counterparts pKa and pKb.

SECTION 2

Core Principles & Definitions

Before diving into calculations, it is essential to establish the conceptual framework connecting equilibrium constants to acid–base strength. Every weak acid or base establishes a dynamic equilibrium in water, and the position of that equilibrium—whether it favors products (ions) or reactants (undissociated molecules)—is what Ka and Kb quantify. The following core ideas underpin the entire discussion.

1

Kₐ — Acid Dissociation Constant

For a generic acid HA ⇌ H⁺ + A⁻, Ka = [H⁺][A⁻] / [HA]. A larger Kₐ means greater ionization and therefore a stronger acid.
2

Kb — Base Dissociation Constant

For a base B + H₂O ⇌ BH⁺ + OH⁻, Kb = [BH⁺][OH⁻] / [B]. A larger Kb signals a stronger base.
3

pKₐ & pKb — Logarithmic Scales

pKa = −log(Ka) and pKb = −log(Kb). The negative logarithm inverts the scale: a smaller pKₐ corresponds to a stronger acid.
4

Conjugate Pair Relationship

For any conjugate acid–base pair in water at 25 °C, Ka × Kb = Kw = 1.0 × 10⁻¹⁴, and pKa + pKb = 14.00. This linkage means knowing one constant immediately gives the other.
✦

KEY TAKEAWAY

Think of Ka as a report card for how willingly an acid "lets go" of its proton, much like a spring constant in mechanics quantifies how easily a spring extends under force. A stiff spring (large Ka) releases its stored energy readily; a weak spring (small Ka) resists. The pKa scale simply compresses these wildly different magnitudes into a human-friendly range, exactly as pH does for [H⁺].

SECTION 3

Visual Explanation — Strength Scale Diagram

Acid & Base Strength: Kₐ, pKₐ, and the Conjugate RelationshippKₐ Scale (Acid Strength)−10−251016STRONG ACIDWEAK ACIDHClpKₐ ≈ −7H₃PO₄pKₐ = 2.15CH₃COOHpKₐ = 4.76NH₄⁺pKₐ = 9.25H₂OpKₐ = 15.7Conjugate Pair Link: pKₐ + pKb = 14CH₃COOHpKₐ = 4.76⇌CH₃COO⁻pKb = 9.244.76 + 9.24 = 14.00Stronger acid → weaker conjugate base (higher pK)b↑ Kₐ means ↓ pKₐ means ↑ pKb of conjugate means ↓ Kb of conjugate
The upper gradient bar maps common species along the pKa axis: red (strong acid, low pKa) to green (very weak acid, high pKa). The lower section illustrates the conjugate pair linkage between acetic acid (pKa = 4.76) and the acetate ion (pKb = 9.24), summing to 14.

The diagram above encapsulates two crucial ideas simultaneously. First, the pKₐ scale is inversely related to acid strength: moving left (lower pKa) means a more extensively ionized—and therefore stronger—acid. Hydrochloric acid, with a pKa around −7, ionizes essentially completely, whereas water, at pKa ≈ 15.7, barely donates a proton at all. Second, each conjugate acid–base pair is tethered by the constraint pKa + pKb = 14. A strong acid necessarily has a weak conjugate base, and vice versa; the product Ka × Kb is always anchored to Kw.

SECTION 4

Mathematical Framework

The quantitative backbone of acid–base equilibrium rests on a handful of interrelated equations. Mastery of these equations, and especially the ability to convert fluidly among Ka, pKa, Kb, and pKb, is essential for buffer calculations, titration curve analysis, and predicting the direction of proton transfer reactions.

ACID DISSOCIATION CONSTANT

Ka=[H3O+][A−]/[HA]Kₐ = [H₃O⁺][A⁻] / [HA]

For the equilibrium HA + H₂O ⇌ H₃O⁺ + A⁻. Water is the solvent and is excluded from the expression by convention. All concentrations are molar equilibrium concentrations (mol L⁻¹).

BASE DISSOCIATION CONSTANT

Kb=[BH+][OH−]/[B]Kb = [BH⁺][OH⁻] / [B]

For the equilibrium B + H₂O ⇌ BH⁺ + OH⁻. Applies to molecular bases like NH₃ and to conjugate bases such as CH₃COO⁻.

pK DEFINITIONS

pKa=−log10(Ka)pKb=−log10(Kb)pKₐ = −log₁₀(Kₐ) pKb = −log₁₀(Kb)

Because K values span many orders of magnitude (10⁻⁵⁰ to 10¹⁰ and beyond), the logarithmic pK scale compresses this range. A one-unit change in pK corresponds to a tenfold change in K.

CONJUGATE PAIR IDENTITY

Ka×Kb=Kw=1.0×10−14⟹pKa+pKb=14.00(at25°C)Kₐ × Kb = Kw = 1.0 × 10⁻¹⁴ ⟹ pKₐ + pKb = 14.00 (at 25 °C)

This relationship is derived by adding the ionization reaction of the acid HA with the ionization reaction of its conjugate base A⁻. The net reaction is the autoionization of water, so the equilibrium constants multiply to give Kw. On the logarithmic scale, multiplication becomes addition, hence pKa + pKb = pKw = 14.00.

⚠

Inverse Relationship Reminder

Because of the negative sign in the p-function, the relationships between K and pK are inverse: large Ka → small pKa → stronger acid. Similarly, large Kb → small pKb → stronger base. Misinterpreting this inversion is the most common source of errors on exams.

SECTION 5

Classifying Acid & Base Strength

Acid–base strength is not a binary strong-or-weak label; it exists on a continuum. However, for practical purposes, chemists group species into categories based on the magnitude of their dissociation constants. The table below summarizes these categories with representative examples, their Ka or Kb values, and the corresponding pK values.

SpeciesTypeKₐ or KbpKₐ or pKbClassification
HClAcid≈ 10⁷≈ −7Strong acid
H₃PO₄ (1st)Acid7.1 × 10⁻³2.15Moderately weak
CH₃COOHAcid1.8 × 10⁻⁵4.76Weak acid
HCNAcid6.2 × 10⁻¹⁰9.21Very weak acid
NaOHBaseComplete dissociationN/AStrong base
NH₃BaseKb = 1.8 × 10⁻⁵pKb = 4.74Weak base

Representative acids and bases ranked by dissociation constant

Converting Among Kₐ, pKₐ, Kb, and pKbKₐlarge → strong acidpKₐsmall → strong acidpKbpKb = 14 − pKₐKblarge → strong base−log14 − pKₐ10^(−pKb)10^(−pKₐ)14 − pKb−logKₐ × Kb = KwKw / Kₐ = Kb
A conversion roadmap showing the four quantities Ka, pKa, pKb, and Kb connected by logarithmic and complementary relationships. Downward arrows apply −log, upward arrows apply 10 raised to the negative power, and the dashed arcs show the Kw relationship linking conjugate partners directly.

This conversion roadmap is your most practical tool for exam problems. Given any one of the four quantities, you can navigate to any other. For example, starting from Ka = 1.8 × 10⁻⁵ for acetic acid: take −log to get pKa = 4.74, subtract from 14 to get pKb = 9.26 for the acetate ion, then compute Kb = 10⁻⁹·²⁶ = 5.6 × 10⁻¹⁰. Alternatively, you can jump directly using Kb = Kw / Ka.

SECTION 6

Worked Example

Consider the following problem: Hydrofluoric acid (HF) has Ka = 6.8 × 10⁻⁴ at 25 °C. Determine its pKa, and then find Kb and pKb for its conjugate base, the fluoride ion (F⁻). Finally, compare HF's acid strength to that of acetic acid (Ka = 1.8 × 10⁻⁵).

From Kₐ of HF to Full Conjugate Pair Analysis

  1. 1

    Step 1 — Calculate pKₐ of HF

    Apply the definition pKa = −log(Ka). Substituting: pKa = −log(6.8 × 10⁻⁴). Break this into −[log(6.8) + log(10⁻⁴)] = −[0.833 + (−4)] = −0.833 + 4.
    pKₐ(HF) = 3.17
  2. 2

    Step 2 — Find pKb of F⁻

    Use the conjugate pair identity: pKa + pKb = 14.00. Rearranging: pKb = 14.00 − 3.17.
    pKb(F⁻) = 10.83
  3. 3

    Step 3 — Calculate Kb of F⁻

    Convert from pKb back to Kb: Kb = 10⁻ᵖᴷᵇ = 10⁻¹⁰·⁸³. Using a calculator: 10⁻¹⁰·⁸³ = 10⁻¹¹ × 10⁰·¹⁷ = 1.48 × 10⁻¹¹. As a check, verify Ka × Kb = (6.8 × 10⁻⁴)(1.48 × 10⁻¹¹) ≈ 1.0 × 10⁻¹⁴ = Kw. ✓
    Kb(F⁻) = 1.5 × 10⁻¹¹
  4. 4

    Step 4 — Compare HF to CH₃COOH

    Acetic acid has Ka = 1.8 × 10⁻⁵ (pKa = 4.74). HF has Ka = 6.8 × 10⁻⁴ (pKa = 3.17). Since 6.8 × 10⁻⁴ > 1.8 × 10⁻⁵ (or equivalently, 3.17 < 4.74), HF is the stronger acid. It ionizes roughly 38 times more extensively than acetic acid at the same concentration.
    HF is a stronger acid than CH₃COOH (lower pKₐ, higher Kₐ)

SECTION 7

Strengths & Limitations of Ka / pKa

While Ka and pKa are indispensable tools, they are not without caveats. Understanding when these quantities apply—and when they may mislead—is critical to using them correctly in advanced contexts such as biochemistry and organic synthesis.

StrengthLimitation
Provides a single, temperature-specific number for comparing acid strength across different species.Values are temperature-dependent; tabulated values at 25 °C may not apply at physiological (37 °C) or industrial temperatures.
The pK scale compresses enormous ranges into manageable integers, simplifying mental estimates.pK values assume dilute aqueous solution and ideal behavior; concentrated solutions or mixed solvents can shift apparent pKa significantly.
The conjugate pair identity (Ka × Kb = Kw) links acid and base strength elegantly.For polyprotic acids, each ionization has its own Ka (Ka1, Ka2, …), and ignoring successive constants leads to errors.
Widely tabulated for thousands of organic and inorganic species, enabling rapid look-up and prediction.Ka alone does not determine solution pH—concentration, buffering effects, and common ions must also be considered.

Strengths and limitations of the Kₐ/pKₐ framework

✦

KEY TAKEAWAY

Ka is analogous to a material's tensile strength in engineering: it tells you the intrinsic property of the substance, but the actual performance in a system also depends on the load (concentration), environment (solvent, temperature), and constraints (buffers, competing equilibria). Always pair your knowledge of Ka with an understanding of the conditions in which the acid or base operates.

SECTION 8

Connection to Advanced Theory

The Ka/pKa framework taught in general chemistry is the launching point for several powerful extensions. In physical chemistry and biochemistry, thermodynamic activities replace concentrations, activity coefficients correct for non-ideal behavior, and the temperature dependence of Ka is quantified through the van 't Hoff equation. These refinements become indispensable when working with ionic strength effects in biological fluids or industrial processes at elevated temperatures.

General Chemistry ApproachAdvanced / Physical Chemistry Approach
Kₐ expressed using molar concentrations [HA], [H⁺], [A⁻]Thermodynamic Kₐ° uses activities: aH₃O⁺ · aA⁻ / aHA, correcting for ion–ion interactions
pKₐ + pKb = 14.00 (exact at 25 °C)pKₐ + pKb = pKw, where pKw varies with temperature (e.g., pKw = 13.02 at 50 °C)
Strength compared by magnitude of Kₐ or position on pKₐ scaleHammett σ constants and linear free-energy relationships (LFERs) predict how substituents shift pKₐ quantitatively
Single Kₐ per ionizable protonMicroscopic pKₐ values distinguish individual protonation sites in polyprotic or zwitterionic molecules (e.g., amino acids)

General chemistry vs. advanced treatment of acid dissociation constants

As you advance, you will also encounter the Henderson–Hasselbalch equation (pH = pKa + log([A⁻]/[HA])), which directly employs pKa to predict buffer pH. This equation underpins buffer design in biochemistry—selecting a buffer whose pKa is within ±1 unit of the desired pH ensures maximum buffering capacity. The foundations you have built here are therefore not merely academic; they are the quantitative language spoken in every wet laboratory on Earth.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

Benzoic acid has pKa = 4.20, and phenol has pKa = 9.95. Without performing any calculations, which is the stronger acid, and what does this imply about the basicity of their conjugate bases?
Show answer
Benzoic acid is the stronger acid because it has the lower pKa (4.20 < 9.95), meaning its Ka is larger and it ionizes more extensively. Because pKa + pKb = 14, the conjugate base of benzoic acid (benzoate, pKb = 9.80) is a weaker base than phenoxide (pKb = 4.05). A stronger acid always produces a weaker conjugate base.

Question 2: BASIC CALCULATION

Nitrous acid (HNO₂) has Ka = 4.5 × 10⁻⁴. Calculate its pKa and determine Kb for its conjugate base, NO₂⁻.
Show answer
pKa = −log(4.5 × 10⁻⁴) = −[log(4.5) + (−4)] = −0.653 + 4 = 3.35. For the conjugate base NO₂⁻, Kb = Kw / Ka = (1.0 × 10⁻¹⁴) / (4.5 × 10⁻⁴) = 2.2 × 10⁻¹¹. Equivalently, pKb = 14.00 − 3.35 = 10.65, and Kb = 10⁻¹⁰·⁶⁵ = 2.2 × 10⁻¹¹.

Question 3: INTERMEDIATE

Methylamine (CH₃NH₂) has Kb = 4.4 × 10⁻⁴. Calculate the pKa of its conjugate acid, CH₃NH₃⁺. Is CH₃NH₃⁺ a stronger or weaker acid than NH₄⁺ (pKa = 9.25)?
Show answer
First, find pKb = −log(4.4 × 10⁻⁴) = −[0.643 + (−4)] = 3.36. Then pKa of CH₃NH₃⁺ = 14.00 − 3.36 = 10.64. Comparing to NH₄⁺ (pKa = 9.25): since 10.64 > 9.25, CH₃NH₃⁺ has a higher pKa and is therefore a weaker acid than NH₄⁺. This makes chemical sense because the electron-donating methyl group stabilizes the positive charge on nitrogen, making CH₃NH₃⁺ less inclined to donate a proton.

Question 4: APPLIED

A biochemist needs a buffer at pH 7.4 (physiological pH). She is choosing between two buffer systems: imidazole (pKa of conjugate acid = 6.99) and Tris (pKa of conjugate acid = 8.07). Which buffer is better suited, and why? Use the relationship between pKa and optimal buffering pH in your reasoning.
Show answer
A buffer is most effective when pH ≈ pKa, because the Henderson–Hasselbalch equation shows that the ratio [A⁻]/[HA] is closest to 1 (equal concentrations of acid and conjugate base). For imidazole, |7.4 − 6.99| = 0.41 units; for Tris, |7.4 − 8.07| = 0.67 units. Imidazole's pKa is closer to the target pH, so it will provide greater buffering capacity at pH 7.4. Both fall within the generally accepted ±1 pK unit range, but imidazole is the superior choice for maintaining physiological pH under acid or base load.

Question 5: CRITICAL THINKING

Glycine (H₂N−CH₂−COOH) is a diprotic amino acid with pKa1 = 2.34 (carboxyl group) and pKa2 = 9.60 (ammonium group). At physiological pH (7.4), which protonation states predominate? Calculate Kb for the carboxylate group (−COO⁻) acting as a base, and explain why the zwitterionic form dominates at pH 7.4.
Show answer
At pH 7.4, we compare with each pKa. Since 7.4 ≫ pKa1 (2.34), the carboxyl group is fully deprotonated (−COO⁻). Since 7.4 < pKa2 (9.60), the amino group is predominantly protonated (−NH₃⁺). The dominant species is therefore the zwitterion ⁺H₃N−CH₂−COO⁻, carrying both a positive and a negative charge with zero net charge. For the carboxylate acting as a base: pKb = 14.00 − 2.34 = 11.66, so Kb = 10⁻¹¹·⁶⁶ = 2.2 × 10⁻¹². This very small Kb confirms the carboxylate is an extremely weak base—consistent with it being the conjugate of a moderately strong acid (pKa = 2.34). The zwitterionic form dominates because the pH sits between the two pKa values, ensuring one group has lost its proton while the other retains it.

SUMMARY

Lesson Summary

Summary

The acid dissociation constant Kₐ quantifies the extent to which an acid ionizes in water: a larger Kₐ indicates a stronger acid. Its logarithmic counterpart, pKₐ = −log(Kₐ), inverts the scale so that a smaller pKₐ corresponds to a stronger acid. The analogous quantities for bases are Kb and pKb, where larger Kb (smaller pKb) means a stronger base.

Every conjugate acid–base pair is linked by the fundamental identity Kₐ × Kb = Kw = 1.0 × 10⁻¹⁴, or equivalently pKₐ + pKb = 14 at 25 °C. This means a strong acid necessarily has a weak conjugate base, and vice versa. Mastery of the conversion roadmap (Kₐ ↔ pKₐ ↔ pKb ↔ Kb) enables you to navigate buffer calculations, titration curves, and proton-transfer predictions with confidence.

Varsity Tutors • General Chemistry 2 • Ka, Kb & pKa/pKb