Differential Equations Quiz
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FIRST-ORDER DIFFERENTIAL EQUATIONS
Question 1
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Consider the initial value problem given by
y
′
=
y
x
2
+
1
y' = \frac{y}{x^2 + 1}
y
′
=
x
2
+
1
y
with the initial condition
y
(
0
)
=
−
2
y(0) = -2
y
(
0
)
=
−
2
. What is the value of
y
(
1
)
y(1)
y
(
1
)
?
A
−
2
e
π
/
4
-2e^{\pi/4}
−
2
e
π
/4
B
2
e
π
/
4
2e^{\pi/4}
2
e
π
/4
C
−
e
π
/
4
/
2
-e^{\pi/4}/2
−
e
π
/4
/2
D
−
2
+
π
/
4
-2 + \pi/4
−
2
+
π
/4
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