Calculus 2 Quiz
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APPLICATIONS OF INTEGRATION
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A particle moves with acceleration a(t)=6t−12a(t) = 6t - 12 m/s² starting from rest at the origin. The particle's kinetic energy is given by KE=12mv2KE = \frac{1}{2}mv^2 where m=2m = 2 kg. At what time does the particle first return to having zero kinetic energy after t=0t = 0?
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