Calculus 1 Quiz
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LIMITS & CONTINUITY
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Let f(x)=1x−2f(x) = \frac{1}{x-2}. The Intermediate Value Theorem states that for a continuous function on [a,b][a, b], the function takes on every value between f(a)f(a) and f(b)f(b). Since f(1)=−1f(1)=-1 and f(3)=1f(3)=1, why does the theorem not guarantee a root cc in (1,3)(1,3) where f(c)=0f(c)=0?
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