Business Calculus Quiz
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Question 1
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A biochemical reaction follows the model
C
(
t
)
=
C
0
e
−
k
t
+
A
k
(
1
−
e
−
k
t
)
C(t) = C_0 e^{-kt} + \frac{A}{k}(1 - e^{-kt})
C
(
t
)
=
C
0
e
−
k
t
+
k
A
(
1
−
e
−
k
t
)
, where
C
0
=
100
C_0 = 100
C
0
=
100
,
A
=
20
A = 20
A
=
20
, and
k
=
0.5
k = 0.5
k
=
0.5
. What is the rate of change of concentration at
t
=
2
t = 2
t
=
2
?
A
−
40
e
−
1
+
10
(
1
−
e
−
1
)
-40e^{-1} + 10(1 - e^{-1})
−
40
e
−
1
+
10
(
1
−
e
−
1
)
B
−
50
e
−
1
+
10
e
−
1
=
−
40
e
−
1
-50e^{-1} + 10e^{-1} = -40e^{-1}
−
50
e
−
1
+
10
e
−
1
=
−
40
e
−
1
C
−
50
e
−
1
+
20
e
−
1
=
−
30
e
−
1
-50e^{-1} + 20e^{-1} = -30e^{-1}
−
50
e
−
1
+
20
e
−
1
=
−
30
e
−
1
D
−
100
e
−
1
+
40
e
−
1
=
−
60
e
−
1
-100e^{-1} + 40e^{-1} = -60e^{-1}
−
100
e
−
1
+
40
e
−
1
=
−
60
e
−
1
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