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Amino Acid Structure
Properties & \(\text{p}K_a\) Behavior

Explore the building blocks of proteins: how amino acids are structured, how their ionizable groups respond to pH, and why \(\text{p}K_a\) values matter in biochemistry.

Biochemistry

What Is an Amino Acid?

Amino acids are organic molecules that serve as the monomers of proteins. Every amino acid shares a common backbone but carries a unique side chain (R group) that determines its chemical personality.

\(C_\alpha\)
\(\text{NH}_3^+\)
Amino Group
\(\text{COO}^-\)
Carboxyl Group
\(H\)
\(R\)
Side Chain

The Zwitterion: A Molecular Dipole

At physiological pH (~7.4), amino acids exist as zwitterions: molecules with both a positive and a negative charge, yet an overall net charge of zero.

\(\text{NH}_3^+\)
Protonated (+) charge
\(C_\alpha\)
\(\text{COO}^-\)
Deprotonated (−) charge

Why Does \(\text{p}K_a\) Matter?

The \(\text{p}K_a\) of a group tells you the pH at which that group is 50% protonated and 50% deprotonated. It determines how an amino acid behaves as the pH changes.

Low \(\text{p}K_a\)
The group loses its proton easily: it is a stronger acid. Example: carboxyl group \(\text{p}K_a \approx 2\).
High \(\text{p}K_a\)
The group holds onto its proton tightly: it is a weaker acid. Example: amino group \(\text{p}K_a \approx 9\).

The Henderson-Hasselbalch Equation

This equation is the quantitative link between pH, \(\text{p}K_a\), and the ratio of protonated to deprotonated forms of an ionizable group:

1
When pH = \(\text{p}K_a\): the log term is 0 because \([\text{A}^-] = [\text{HA}]\). The group is exactly half-protonated.
2
When pH > \(\text{p}K_a\): \([\text{A}^-] > [\text{HA}]\). The deprotonated form dominates.
3
When pH < \(\text{p}K_a\): \([\text{HA}] > [\text{A}^-]\). The protonated form dominates.

Titration Curve of Glycine

pH
Equivalents of \(OH^-\) added
0 2 4 6 8 10 12 0 0.5 1.0 1.5 2.0
\(\text{p}K_{a1} = 2.34\)
\(\text{p}K_{a2} = 9.60\)
pI = 5.97

\(\text{p}K_{a1}\) vs \(\text{p}K_{a2}\) vs \(\text{p}K_{aR}\)

\(\text{p}K_{a1}\) \(\text{p}K_{a2}\) \(\text{p}K_{aR}\)
Group \(-\text{COOH}\) \(-\text{NH}_3^+\) R group
Typical Range 1.8 − 2.5 8.8 − 10.5 3.7 − 12.5
Loses Proton First (lowest pH) Second Varies by residue
Present in All amino acids All amino acids Only 7 of 20

The Ionizable Side Chains

Acidic
Asp (\(\text{p}K_{aR} \approx 3.7\))
Glu (\(\text{p}K_{aR} \approx 4.1\))
Negative at pH 7
Basic
Lys (\(\text{p}K_{aR} \approx 10.5\))
Arg (\(\text{p}K_{aR} \approx 12.5\))
Positive at pH 7
Special
His (\(\text{p}K_{aR} \approx 6.0\))
Cys (\(\text{p}K_{aR} \approx 8.3\))
Tyr (\(\text{p}K_{aR} \approx 10.1\))

Calculating the Isoelectric Point (pI)

The isoelectric point (pI) is the pH at which the amino acid carries zero net charge. At the pI, the molecule will not migrate in an electric field.

1
Nonpolar / polar (no ionizable R): Average the two backbone \(\text{p}K_a\) values: $$\text{pI} = \frac{\text{p}K_{a1} + \text{p}K_{a2}}{2}$$
2
Acidic R group (Asp, Glu): Average the two lowest \(\text{p}K_a\) values: $$\text{pI} = \frac{\text{p}K_{a1} + \text{p}K_{aR}}{2}$$
3
Basic R group (Lys, Arg, His): Average the two highest \(\text{p}K_a\) values: $$\text{pI} = \frac{\text{p}K_{a2} + \text{p}K_{aR}}{2}$$

How to Determine Net Charge at Any pH

1
List all ionizable groups and their \(\text{p}K_a\) values: \(\alpha\)-COOH, \(\alpha\text{-NH}_3^+\), and R group (if applicable).
2
Compare each \(\text{p}K_a\) to the pH. If \(\text{pH} > \text{p}K_a\), the group has lost its proton (deprotonated). If \(\text{pH} < \text{p}K_a\), the group retains its proton (protonated).
3
Assign charges: deprotonated COOH → \(COO^-\) (−1), protonated \(\text{NH}_2 \rightarrow \text{NH}_3^+\) (+1). Sum all charges.
4
Add up the charges from every group to find the net charge on the entire molecule.

Example: Glycine at pH 1

Glycine has \(\text{p}K_{a1} = 2.34\) (COOH) and \(\text{p}K_{a2} = 9.60\) (\(\text{NH}_3^+\)). What is its charge at pH 1?

pH 1
\(\text{p}K_{a1} = 2.34\)
COOH
\(\text{p}K_{a2} = 9.60\)
\(\text{NH}_3^+\)
pH < both pKa values

Example: Glycine at pH 6

Same glycine: \(\text{p}K_{a1} = 2.34\), \(\text{p}K_{a2} = 9.60\). Now the pH is between the two \(\text{p}K_a\) values.

pH 6
\(\text{p}K_{a1} = 2.34\)
COOH
\(\text{p}K_{a2} = 9.60\)
\(\text{NH}_3^+\)
Between pKa\(_1\) and pKa\(_2\)

Example: Aspartate at pH 7

Aspartate has three ionizable groups: \(\text{p}K_{a1} = 2.1\) (COOH), \(\text{p}K_{aR} = 3.9\) (side chain COOH), \(\text{p}K_{a2} = 9.8\) (\(\text{NH}_3^+\)).

pH 7
\(\text{p}K_{a1} = 2.1\)
\(\alpha\text{-COOH}\)
\(\text{p}K_{aR} = 3.9\)
R-COOH
\(\text{p}K_{a2} = 9.8\)
\(\text{NH}_3^+\)

Classifying by Side Chain Properties

Nonpolar
Hydrophobic: Ala, Val, Leu, Ile, Pro, Phe, Trp, Met, Gly. Found in protein interiors.
Polar Uncharged
Hydrophilic: Ser, Thr, Asn, Gln. Form H-bonds but carry no charge at pH 7.
Negatively Charged
Asp (−), Glu (−). Acidic side chains are deprotonated at pH 7.
Positively Charged
Lys (+), Arg (+), His (+/0). Basic side chains are protonated at pH 7.

Common Mistakes to Avoid

✕ Confusing pH > pKa Direction
When pH > pKa the group is deprotonated, not protonated. Many students reverse this critical rule.
✕ Wrong pKa Pair for pI
For acidic amino acids, average the two lowest pKa values. For basic, average the two highest. Do not always use pKa\(_1\) and pKa\(_2\).
✕ Forgetting the R Group
Seven amino acids have ionizable R groups. Ignoring the third pKa leads to wrong net charges and wrong pI calculations.

Summary: Key Amino Acids & Their \(\text{p}K_a\) Values

Amino Acid \(\text{p}K_{a1}\) \(\text{p}K_{aR}\) \(\text{p}K_{a2}\) pI
Glycine2.34—9.605.97
Alanine2.35—9.876.11
Aspartate2.103.869.822.98
Glutamate2.104.079.473.08
Histidine1.776.109.187.64
Lysine2.1810.538.959.74
Arginine2.0112.489.0410.76

Question 1 of 5

At physiological pH (7.4), what is the net charge on glycine (\(\text{p}K_{a1} = 2.34\), \(\text{p}K_{a2} = 9.60\))?

Question 2 of 5

Which amino acid has a side chain \(\text{p}K_a\) near physiological pH, making it an effective proton shuttle in enzyme active sites?

Question 3 of 5

What is the isoelectric point (pI) of aspartate given \(\text{p}K_{a1} = 2.1\), \(\text{p}K_{aR} = 3.9\), \(\text{p}K_{a2} = 9.8\)?

Question 4 of 5

At pH 11, what is the net charge on lysine (\(\text{p}K_{a1} = 2.2\), \(\text{p}K_{a2} = 9.0\), \(\text{p}K_{aR} = 10.5\))?

Question 5 of 5

According to the Henderson-Hasselbalch equation, when \(\text{pH} = \text{p}K_a\), what is the ratio of \([\text{A}^-]\) to \([\text{HA}]\)?