Chi-Square Homogeneity or Independence (Setup) - AP Statistics

  1. Determine the test: Evaluating if gender is related to voting preference.
    Chi-Square Test of Independence. Tests if gender and voting preference are associated variables.
  2. What is the alternative hypothesis for a Chi-Square Test of Homogeneity?
    The distributions are different. Homogeneity tests check if categorical distributions vary across groups.
  3. What assumption does a Chi-Square test make about samples?
    Samples are randomly selected. Random sampling ensures independence and representative results.
  4. Calculate degrees of freedom for a 4x3 contingency table.
    (4−1)(3−1)=6(4-1)(3-1) = 6. Use the formula (r−1)(c−1)(r-1)(c-1) where r=4r=4 rows and c=3c=3 columns.
  5. Which test uses the contingency table to organize data?
    Both Chi-Square Tests. Both tests use contingency tables to organize observed frequencies.
  6. Which test checks if proportions differ across multiple populations?
    Chi-Square Test of Homogeneity. Homogeneity tests compare categorical proportions across multiple populations.
  7. What does a significant Chi-Square statistic indicate?
    Reject the null hypothesis. Significant results lead to rejecting the null hypothesis.
  8. What is the formula for the Chi-Square statistic?
    Chi-Square=(O−E)2E\text{Chi-Square} = \frac{(O-E)^2}{E} summed over all cells. Sum the squared standardized deviations across all contingency table cells.
  9. What is the null hypothesis for a Chi-Square Test of Independence?
    The variables are independent. For independence tests, we assume no relationship exists between variables.
  10. What is the degree of freedom formula for a Chi-Square Test of Independence?
    (r−1)(c−1)(r-1)(c-1), where rr is rows, cc is columns. Degrees of freedom account for constraints in the contingency table.
  11. What is the null hypothesis for a Chi-Square Test of Homogeneity?
    The distributions are the same. Assumes categorical distributions are identical across all groups.
  12. What type of test is the Chi-Square Test of Homogeneity?
    Non-parametric test. Non-parametric tests don't assume specific population distributions.
  13. Which test assesses if sample proportions are equal across groups?
    Chi-Square Test of Homogeneity. Homogeneity tests compare proportions of categorical outcomes across groups.
  14. What describes a contingency table with 3 rows and 2 columns?
    3x2 table. Describes the dimensions of a two-way frequency table.
  15. Calculate Chi-Square\text{Chi-Square}: O=10,E=8O=10, E=8 in one cell.
    (10−8)28=0.5\frac{(10-8)^2}{8} = 0.5. Apply the Chi-Square formula: (O−E)2/E(O-E)^2/E for this cell.
  16. What is the critical value for a Chi-Square test with 2 df at 0.05 significance?
    5.991. Standard critical value for 2 degrees of freedom at 5% significance level.
  17. Determine the test: Evaluating if study fields affect job types.
    Chi-Square Test of Independence. Tests association between study field and job type variables.
  18. Identify the test: Comparing categorical distributions across multiple groups.
    Chi-Square Test of Homogeneity. This test compares how categorical variables are distributed across groups.
  19. State the alternative hypothesis for a Chi-Square Test of Independence.
    The variables are dependent. Independence alternative hypothesis states variables are related or associated.
  20. Identify the test: Comparing response frequency across different age groups.
    Chi-Square Test of Homogeneity. Compares response distributions across different age group populations.
  21. Find the expected frequency: 6060 total, 1515 in row, 44 in column.
    E=(15×4)60=1E = \frac{(15 \times 4)}{60} = 1. Apply the expected frequency formula: row total × column total ÷ grand total.
  22. How are the observed frequencies denoted in Chi-Square tests?
    OO. O represents the actual counts observed in each cell.
  23. What is a common use of the Chi-Square Test of Independence?
    To assess relationships between categorical variables. Independence tests determine if categorical variables are associated.
  24. Which test applies when examining if two variables interact?
    Chi-Square Test of Independence. Independence tests examine relationships between two categorical variables.
  25. State the formula for the expected frequency in a contingency table cell.
    E=(row total×column total)grand totalE = \frac{(row\text{ }total \times column\text{ }total)}{grand\text{ }total}. Expected frequency equals the product of marginal totals divided by sample size.
  26. Identify the type of variable suitable for Chi-Square tests.
    Categorical variables. Chi-Square tests require qualitative data with distinct categories.
  27. Find expected frequency: 100100 total, 2525 in row, 1010 in column.
    E=(25×10)100=2.5E = \frac{(25 \times 10)}{100} = 2.5. Calculate using the standard expected frequency formula.
  28. What assumption must be met regarding expected frequencies for Chi-Square tests?
    Expected frequencies should be at least 5. This ensures the Chi-Square distribution approximation is valid.
  29. When is a Chi-Square test considered invalid?
    When expected frequencies are less than 5. Low expected frequencies violate the Chi-Square distribution assumption.
  30. What is the minimum sample size recommended for Chi-Square tests?
    No specific size, but expected counts > 5. Focus is on expected counts rather than total sample size.
  31. What is the general purpose of a Chi-Square test?
    To test the association between categorical variables. Chi-Square tests evaluate relationships and patterns in categorical data.
  32. What type of distribution is used in Chi-Square tests?
    Chi-Square distribution. Chi-Square distribution is the theoretical basis for these hypothesis tests.
  33. Identify the symbol commonly used for the Chi-Square statistic.
    Chi-Square\text{Chi-Square} or X2\text{X}^2. Both symbols represent the calculated test statistic in Chi-Square tests.
  34. Identify the test: Assessing relationship between two categorical variables.
    Chi-Square Test of Independence. This test determines if two categorical variables are associated.
  35. What is required for valid Chi-Square results concerning data collection?
    Random sampling. Random sampling ensures valid statistical inferences from Chi-Square tests.
  36. What condition must be met for Chi-Square tests regarding sample size?
    Expected frequencies must be at least 5. All expected frequencies must meet the minimum threshold of 5.
  37. What is the range of values for a Chi-Square statistic?
    0 to infinity\text{infinity}. Chi-Square statistics are always non-negative with no upper bound.
  38. What do you compare the Chi-Square statistic to for hypothesis testing?
    Chi-Square critical value. Compare calculated test statistic to tabled critical value for decision.

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