Change in Arithmetic and Geometric Sequences - AP Precalculus

  1. A savings account grows geometrically with a1=500a_1=500 and r=1.10r=1.10: 500; 550; 605. Based on the sequence, what is a6a_6?
    Answer: 805.26805.26 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 500, growing by a ratio of 1.10 each term (10% growth). Choice A is correct because it accurately applies the geometric sequence formula: a₆ = a₁ × r⁵ = 500 × (1.10)⁵ = 500 × 1.61051 = 805.26. Choice B (732.05) is incorrect due to using the wrong power of r, a common mistake when students miscalculate compound growth. To help students: Remember that for the nth term, use rn−1r^{n-1}. Practice with a calculator to ensure accuracy with decimal powers.
  2. A salary follows an arithmetic sequence with a1=50,000a_1=50{,}000 and d=2,000d=2{,}000: 50,000; 52,000; 54,000. Based on the sequence, what is the nnth term ana_n?
    Answer: an=50,000+2,000(n−1)a_n=50{,}000+2{,}000(n-1) This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, changing by a difference of 2,000 each term. Choice C is correct because it accurately applies the arithmetic sequence formula ana_n = a1a_1 + d(n-1), giving ana_n = 50,000 + 2,000(n-1). Choice A is incorrect due to using n instead of (n-1), a common mistake when students forget that the first term already includes a1a_1. To help students: Practice identifying the correct formula structure for arithmetic sequences. Emphasize that (n-1) represents the number of times we add the common difference, starting from the first term.
  3. Bacteria doubles hourly in a geometric sequence with a1=200a_1=200 and r=2r=2: 200; 400; 800. Using the given terms, what is the nnth term of the sequence?
    Answer: an=200⋅2n−1a_n=200\cdot 2^{n-1} This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 200 bacteria, doubling each hour (ratio of 2). Choice B is correct because it accurately represents the geometric sequence formula: aₙ = a₁ × rn−1r^{n-1} = 200 × 2n−12^{n-1}. Choice C (200 × 2ⁿ) is incorrect due to using n instead of (n-1) as the exponent, a common mistake when students forget that the first term uses r⁰. To help students: Remember that geometric sequences use rn−1r^{n-1} because the first term has no multiplication by r. Practice writing out the first few terms to verify the formula pattern.
  4. A city's population declines geometrically with a1=100,000a_1=100{,}000 and r=0.98r=0.98: 100,000; 98,000; 96,040. Based on the sequence, how does the sequence change from term 1 to term 4?
    Answer: Decreases by 5,880.805{,}880.80 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 100,000, declining by a ratio of 0.98 each term. Choice A is correct because it accurately calculates the change from term 1 to term 4: a4a_4 = 100,000 × 0.9830.98^3 = 94,119.20, giving a decrease of 100,000 - 94,119.20 = 5,880.80. Choice B is incorrect due to assuming a linear decrease of 2,000 per term, a common mistake when students confuse geometric and arithmetic sequences. To help students: Practice distinguishing between multiplicative and additive changes. Emphasize that geometric sequences with r < 1 show decreasing changes between consecutive terms.
  5. A city's population declines geometrically with a1=100,000a_1=100{,}000 and r=0.95r=0.95: 100,000; 95,000; 90,250. Using the given terms, what is a5a_5?
    Answer: 81,450.6381{,}450.63 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 100,000, changing by a ratio of 0.95 each term (representing a 5% decline). Choice A is correct because it accurately applies the geometric sequence formula: a₅ = a₁ × r⁴ = 100,000 × (0.95)⁴ = 100,000 × 0.81450625 = 81,450.63. Choice C (77,378.09) is incorrect due to using r⁵ instead of r⁴, a common mistake when students confuse the term number with the exponent. To help students: Remember that for the nth term, use rn−1r^{n-1} as the exponent. Practice calculating several terms to build confidence with the pattern.
  6. Bacteria doubles hourly in a geometric sequence with a1=50a_1=50 and r=2r=2: 50; 100; 200. Using the given terms, how does the sequence change from term 3 to term 6?
    Answer: Increases by 1,4001{,}400 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50 bacteria, doubling each hour. Choice A is correct because it accurately calculates the change: a3a_3 = 200 and a6a_6 = 50 × 252^5 = 50 × 32 = 1,600, giving an increase of 1,600 - 200 = 1,400. Choice B is incorrect with only 200, likely confusing the value of a3a_3 with the change between terms. To help students: Practice finding specific terms before calculating differences. Emphasize the importance of reading carefully to identify which terms are being compared.
  7. A city's population declines geometrically with a1=80,000a_1=80{,}000 and r=0.90r=0.90: 80,000; 72,000; 64,800. Using the given terms, determine the sum of the first 4 terms.
    Answer: 275,120275{,}120 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 80,000, declining by a ratio of 0.90 each term. Choice A is correct because it accurately calculates the sum: a₁ = 80,000, a₂ = 72,000, a₃ = 64,800, a₄ = 58,320, giving a sum of 275,120. Choice C (268,920) is incorrect due to calculation errors in finding individual terms, a common mistake when students rush through geometric calculations. To help students: Calculate each term carefully before summing. For geometric series, you can also use the formula SnS_n = a₁(1-rⁿ)/(1-r) as a check.
  8. A salary follows an arithmetic sequence with a1=30,000a_1=30{,}000 and d=1,000d=1{,}000: 30,000; 31,000; 32,000. Based on the sequence, calculate the total change after 10 terms.
    Answer: 9,0009{,}000 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 30,000, changing by a difference of 1,000 each term. Choice A is correct because the total change after 10 terms means finding the difference between a₁₀ and a₁: a₁₀ = 30,000 + 9(1,000) = 39,000, so the change is 39,000 - 30,000 = 9,000. Choice B (10,000) is incorrect due to confusing the number of terms with the number of differences, a common mistake when students forget that reaching the 10th term requires only 9 steps. To help students: Remember that the change from term 1 to term n involves (n-1) differences. Draw out the first few terms to visualize the pattern.
  9. A salary follows an arithmetic sequence with a1=30,000a_1=30{,}000 and d=1,000d=1{,}000: 30,000; 31,000; 32,000. Based on the sequence, how does the sequence change from term 2 to term 8?
    Answer: Increases by 6,0006{,}000 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 30,000, increasing by 1,000 each term. Choice B is correct because in an arithmetic sequence, the change from term 2 to term 8 is 6 times the common difference: 6 × 1,000 = 6,000. Choice C is incorrect with 7,000, likely from counting 7 steps instead of 6, a common mistake when students include both endpoints. To help students: Practice counting the number of steps between terms carefully. Emphasize that from term 2 to term 8, there are exactly 6 steps (8 - 2 = 6).
  10. A salary follows an arithmetic sequence with a1=50,000a_1=50{,}000 and d=2,000d=2{,}000: 50,000; 52,000; 54,000. Based on the sequence, determine the sum of the first 5 terms.
    Answer: 270,000270{,}000 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, changing by a difference of 2,000 each term. Choice B is correct because it accurately applies the arithmetic series formula: S₅ = 5/2 × (2a₁ + 4d) = 5/2 × (100,000 + 8,000) = 5/2 × 108,000 = 270,000. Choice A (260,000) is incorrect due to miscalculating the sum formula, a common mistake when students forget to properly apply the arithmetic series formula. To help students: Practice using the sum formula SnS_n = n/2 × (2a₁ + (n-1)d) systematically. Emphasize verifying calculations by adding the first few terms manually as a check.
  11. A city's population declines geometrically with a1=50,000a_1=50{,}000 and r=0.95r=0.95: 50,000; 47,500; 45,125. Based on the sequence, what is the nnth term ana_n?
    Answer: an=50,000(0.95)n−1a_n=50{,}000(0.95)^{n-1} This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 50,000, declining by a ratio of 0.95 each term. Choice B is correct because it accurately applies the geometric sequence formula ana_n = a1a_1 × rn−1r^{n-1}, giving ana_n = 50,000(0.95)n−1(0.95)^{n-1}. Choice A is incorrect due to treating this as an arithmetic sequence with a difference of 0.95, a common mistake when students see a decimal and assume subtraction. To help students: Practice identifying sequence types from the given terms. Emphasize that ratios less than 1 still indicate geometric sequences, not arithmetic ones.
  12. Bacteria doubles hourly in a geometric sequence with a1=200a_1=200 and r=2r=2: 200; 400; 800. Using the given terms, what is a7a_7?
    Answer: 12,80012{,}800 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 200 bacteria, doubling (ratio of 2) each hour. Choice A is correct because it accurately applies the geometric sequence formula ana_n = a1a_1 × rn−1r^{n-1}, giving a7a_7 = 200 × 262^6 = 200 × 64 = 12,800. Choice B is incorrect due to calculating 252^5 instead of 262^6, a common mistake when students forget that the exponent is (n-1). To help students: Practice counting the number of multiplications needed to reach the nth term. Emphasize that for the 7th term, we multiply by r exactly 6 times.
  13. A savings account grows geometrically with a1=1,000a_1=1{,}000 and r=1.05r=1.05: 1,000; 1,050; 1,102.50. Using the given terms, what is a5a_5?
    Answer: 1,215.511{,}215.51 This question tests understanding of changes in arithmetic and geometric sequences, crucial for AP Precalculus. Arithmetic sequences change by a fixed difference, while geometric sequences change by a fixed ratio. In this scenario, the sequence starts with 1,000, changing by a ratio of 1.05 each term. Choice A is correct because it accurately applies the geometric sequence formula ana_n = a1a_1 × rn−1r^{n-1}, giving a5a_5 = 1,000 × 1.0541.05^4 = 1,000 × 1.21550625 = 1,215.51. Choice C is incorrect due to multiplying by 10, likely from misreading the decimal point, a common mistake when students rush calculations. To help students: Practice careful calculation with geometric sequences, especially with decimal ratios. Emphasize checking that answers are reasonable given the growth rate.

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