Rates of Change in Polar Functions - AP Precalculus

  1. What is the formula for dxdθ\frac{dx}{d\theta} when r=sin⁡(θ)r = \sin(\theta)?
    dxdθ=cos⁡(θ)cos⁡(θ)−sin⁡2(θ)\frac{dx}{d\theta} = \cos(\theta)\cos(\theta) - \sin^2(\theta). Substitute r=sin⁡(θ)r = \sin(\theta) and drdθ=cos⁡(θ)\frac{dr}{d\theta} = \cos(\theta) into formula.
  2. Find dydθ\frac{dy}{d\theta} for r(θ)=θ2r(\theta) = \theta^2.
    dydθ=2θsin⁡(θ)+θ2cos⁡(θ)\frac{dy}{d\theta} = 2\theta \sin(\theta) + \theta^2 \cos(\theta). Substitute r=θ2r = \theta^2 and drdθ=2θ\frac{dr}{d\theta} = 2\theta into the formula.
  3. What is the polar equation of a cardioid?
    r=a(1+cos⁡(θ))r = a(1 + \cos(\theta)). Heart-shaped curve with cusp at the origin.
  4. Find dydθ\frac{dy}{d\theta} for r(θ)=1+cos⁡(θ)r(\theta) = 1 + \cos(\theta).
    dydθ=cos⁡(θ)+sin⁡(θ)\frac{dy}{d\theta} = \cos(\theta) + \sin(\theta). Apply product rule with r=1+cos⁡(θ)r = 1 + \cos(\theta) and drdθ=−sin⁡(θ)\frac{dr}{d\theta} = -\sin(\theta).
  5. What is the formula for the derivative of r(θ)r(\theta) with respect to θ\theta?
    drdθ\frac{dr}{d\theta}. Standard notation for the derivative of polar radius function.
  6. Find dydx\frac{dy}{dx} for r(θ)=1+sin⁡(θ)r(\theta) = 1 + \sin(\theta) at θ=π2\theta = \frac{\pi}{2}.
    00. Horizontal tangent occurs when dydθ=0\frac{dy}{d\theta} = 0 at this angle.
  7. Find dxdθ\frac{dx}{d\theta} for r(θ)=θ2r(\theta) = \theta^2.
    dxdθ=2θcos⁡(θ)−θ2sin⁡(θ)\frac{dx}{d\theta} = 2\theta \cos(\theta) - \theta^2 \sin(\theta). Substitute r=θ2r = \theta^2 and drdθ=2θ\frac{dr}{d\theta} = 2\theta into the formula.
  8. What is the polar equation for a line through the origin at an angle α\alpha?
    θ=α\theta = \alpha. Constant angle creates a ray from the origin.
  9. What is the formula for the instantaneous rate of change of rr?
    drdθ\frac{dr}{d\theta}. Represents the instantaneous rate of change of radius with angle.
  10. What is the formula for the rate of change of xx with respect to θ\theta?
    dxdθ=drdθcos⁡(θ)−rsin⁡(θ)\frac{dx}{d\theta} = \frac{dr}{d\theta} \cos(\theta) - r \sin(\theta). Product rule applied to x=rcos⁡(θ)x = r\cos(\theta) with respect to θ\theta.
  11. Find dxdθ\frac{dx}{d\theta} for r(θ)=1+cos⁡(θ)r(\theta) = 1 + \cos(\theta).
    dxdθ=−sin⁡2(θ)\frac{dx}{d\theta} = -\sin^2(\theta). Apply product rule with r=1+cos⁡(θ)r = 1 + \cos(\theta) and drdθ=−sin⁡(θ)\frac{dr}{d\theta} = -\sin(\theta).
  12. What is the derivative of r=aθ+br = a\theta + b with respect to θ\theta?
    drdθ=a\frac{dr}{d\theta} = a. Derivative of linear function is the coefficient of θ\theta.
  13. Find drdθ\frac{dr}{d\theta} for r(θ)=3cos⁡(2θ)r(\theta) = 3\cos(2\theta).
    drdθ=−6sin⁡(2θ)\frac{dr}{d\theta} = -6\sin(2\theta). Chain rule: derivative of 3cos⁡(2θ)3\cos(2\theta) is −6sin⁡(2θ)-6\sin(2\theta).
  14. Find the derivative drdθ\frac{dr}{d\theta} for r=3θ2r = 3\theta^2.
    drdθ=6θ\frac{dr}{d\theta} = 6\theta. Power rule: derivative of 3θ23\theta^2 is 6θ6\theta.
  15. Convert the polar function r=3sin⁡(θ)r = 3\sin(\theta) to Cartesian coordinates.
    x2+(y−32)2=(32)2x^2 + (y - \frac{3}{2})^2 = (\frac{3}{2})^2. Circle with center (0,32)(0, \frac{3}{2}) and radius 32\frac{3}{2}.
  16. Identify the formula for dydx\frac{dy}{dx} in polar coordinates.
    dydx=dydθdxdθ\frac{dy}{dx} = \frac{\frac{dy}{d\theta}}{\frac{dx}{d\theta}}. Chain rule connecting Cartesian and polar derivatives.
  17. What is the formula for dydθ\frac{dy}{d\theta} when r=sin⁡(θ)r = \sin(\theta)?
    dydθ=cos⁡2(θ)+sin⁡(θ)cos⁡(θ)\frac{dy}{d\theta} = \cos^2(\theta) + \sin(\theta)\cos(\theta). Substitute r=sin⁡(θ)r = \sin(\theta) and drdθ=cos⁡(θ)\frac{dr}{d\theta} = \cos(\theta) into formula.
  18. What is the formula for arc length LL of a polar curve r(θ)r(\theta)?
    L=∫ab(drdθ)2+r2 dθL = \int_{a}^{b} \sqrt{(\frac{dr}{d\theta})^2 + r^2} \, d\theta. Integrates the speed element in polar coordinates over the interval.
  19. What is the formula for the derivative of y=rsin⁡(θ)y = r\sin(\theta) with respect to θ\theta?
    dydθ=drdθsin⁡(θ)+rcos⁡(θ)\frac{dy}{d\theta} = \frac{dr}{d\theta}\sin(\theta) + r\cos(\theta). Product rule applied to the Cartesian conversion formula.
  20. What is the polar equation of a rose curve with 4 petals?
    r=acos⁡(2θ)r = a\cos(2\theta). Four-petaled rose has period π\pi in the cosine function.
  21. What is the polar equation for a spiral of Archimedes?
    r=aθr = a\theta. Linear relationship between radius and angle creates uniform spiral.
  22. What is the formula for the rate of change of yy with respect to θ\theta?
    dydθ=drdθsin⁡(θ)+rcos⁡(θ)\frac{dy}{d\theta} = \frac{dr}{d\theta} \sin(\theta) + r \cos(\theta). Product rule applied to y=rsin⁡(θ)y = r\sin(\theta) with respect to θ\theta.
  23. What is the polar equation for an exponential spiral?
    r=aebθr = ae^{b\theta}. Exponential growth pattern with constant aa and growth rate bb.
  24. Determine dydx\frac{dy}{dx} for r(θ)=2sin⁡(θ)r(\theta) = 2\sin(\theta) at θ=π2\theta = \frac{\pi}{2}.
    Undefined. Vertical tangent occurs when dxdθ=0\frac{dx}{d\theta} = 0 but dydθ≠0\frac{dy}{d\theta} \neq 0.
  25. Identify the formula for dxdθ\frac{dx}{d\theta} in polar coordinates.
    dxdθ=drdθcos⁡(θ)−rsin⁡(θ)\frac{dx}{d\theta} = \frac{dr}{d\theta} \cos(\theta) - r \sin(\theta). Standard formula for horizontal rate of change in polar coordinates.
  26. Identify the formula for dydθ\frac{dy}{d\theta} in polar coordinates.
    dydθ=drdθsin⁡(θ)+rcos⁡(θ)\frac{dy}{d\theta} = \frac{dr}{d\theta} \sin(\theta) + r \cos(\theta). Standard formula for vertical rate of change in polar coordinates.
  27. What is the polar equation for a circle centered at the origin with radius 2?
    r=2r = 2. Constant radius distance from origin defines a circle.
  28. What is the general polar form of an ellipse?
    r=ed1+ecos⁡(θ)r = \frac{ed}{1 + e\cos(\theta)}. Standard form where ee is eccentricity and dd is directrix distance.
  29. What is the polar equation for a lemniscate?
    r2=a2cos⁡(2θ)r^2 = a^2\cos(2\theta). Figure-eight curve with equation involving cos⁡(2θ)\cos(2\theta).
  30. What is the formula for the derivative of x=rcos⁡(θ)x = r\cos(\theta) with respect to θ\theta?
    dxdθ=drdθcos⁡(θ)−rsin⁡(θ)\frac{dx}{d\theta} = \frac{dr}{d\theta}\cos(\theta) - r\sin(\theta). Product rule applied to the Cartesian conversion formula.
  31. Find drdθ\frac{dr}{d\theta} for r(θ)=2θ+sin⁡(θ)r(\theta) = 2\theta + \sin(\theta).
    drdθ=2+cos⁡(θ)\frac{dr}{d\theta} = 2 + \cos(\theta). Derivative of each term: 22 from 2θ2\theta and cos⁡(θ)\cos(\theta) from sin⁡(θ)\sin(\theta).
  32. What is the polar equation for a limaçon with inner loop?
    r=a+bcos⁡(θ)r = a + b\cos(\theta), ∣a∣<∣b∣|a| < |b|. When ∣a∣<∣b∣|a| < |b|, the curve creates an inner loop.

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