Linear and Quadratic Rates of Change - AP Precalculus

  1. What is the instantaneous rate of change of f(x)=2x2f(x) = 2x^2 at x=−1x = -1?
    -4. Find f′(x)=4xf'(x) = 4x, then evaluate at x=−1x = -1.
  2. State the formula for finding the slope of a secant line over [a,b][a, b].
    f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}. Same formula as average rate of change between two points.
  3. State the formula for the derivative of f(x)=ax2+bx+cf(x) = ax^2 + bx + c.
    2ax+b2ax + b. General form of derivative for quadratic functions.
  4. What is the instantaneous rate of change of f(x)=x3f(x) = x^3 at x=1x = 1?
    3. Find f′(x)=3x2f'(x) = 3x^2, then evaluate at x=1x = 1.
  5. Find the average rate of change of f(x)=x2+2x−1f(x) = x^2 + 2x - 1 over [2,4][2, 4].
    8. Calculate f(4)−f(2)4−2=23−72=8\frac{f(4) - f(2)}{4 - 2} = \frac{23 - 7}{2} = 8.
  6. State the formula for finding the slope of a secant line over $ [a, b] $.
    f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}. Same formula as average rate of change between two points.
  7. Find the slope of the tangent line to f(x)=x2−5x+6f(x) = x^2 - 5x + 6 at x=3x = 3.
    1. Find f′(x)=2x−5f'(x) = 2x - 5, then substitute x=3x = 3.
  8. Find the slope of the tangent line to f(x)=4x2−xf(x) = 4x^2 - x at x=1x = 1.
    7. Find f′(x)=8x−1f'(x) = 8x - 1, then evaluate at x=1x = 1.
  9. Identify the expression for the derivative of f(x)=x3−2xf(x) = x^3 - 2x.
    3x2−23x^2 - 2. Apply power rule to each term: (x3)′=3x2(x^3)' = 3x^2 and (2x)′=2(2x)' = 2.
  10. State the formula for the derivative of f(x)=3x2+4x+5f(x) = 3x^2 + 4x + 5.
    6x+46x + 4. Differentiate each term using power rule and sum rule.
  11. Find the average rate of change of f(x)=x2+4xf(x) = x^2 + 4x over [3,6][3, 6].
    13. Calculate f(6)−f(3)6−3=60−213=13\frac{f(6) - f(3)}{6 - 3} = \frac{60 - 21}{3} = 13.
  12. Identify the derivative of f(x)=2x3−x2+4f(x) = 2x^3 - x^2 + 4.
    6x2−2x6x^2 - 2x. Apply power rule: (2x3)′=6x2(2x^3)' = 6x^2 and (−x2)′=−2x(-x^2)' = -2x.
  13. Identify the instantaneous rate of change of f(x)=x3−3x2f(x) = x^3 - 3x^2 at x=2x = 2.
    0. Find f′(x)=3x2−6xf'(x) = 3x^2 - 6x, then substitute x=2x = 2.
  14. State the derivative of f(x)=x2+5x−3f(x) = x^2 + 5x - 3.
    2x+52x + 5. Differentiate each term using power rule and constant rule.
  15. Find the slope of the tangent line to f(x)=x2+3xf(x) = x^2 + 3x at x=2x = 2.
    7. Find f′(x)=2x+3f'(x) = 2x + 3, then substitute x=2x = 2.
  16. What is the derivative of f(x)=3x2+2x+1f(x) = 3x^2 + 2x + 1?
    6x+26x + 2. Apply power rule: (xn)′=nxn−1(x^n)' = nx^{n-1} and sum rule.
  17. What is the derivative of f(x)=−x2+3xf(x) = -x^2 + 3x?
    −2x+3-2x + 3. Apply power rule and sum rule to find the derivative.
  18. Identify the average rate of change of f(x)=3x−4f(x) = 3x - 4 over [2,5][2, 5].
    3. Linear functions have constant rate equal to the coefficient of xx.
  19. Identify the average rate of change of f(x)=2x+3f(x) = 2x + 3 over [1,4][1, 4].
    2. Linear functions have constant slope, which equals the coefficient of xx.
  20. Identify the average rate of change of f(x)=−x2+4f(x) = -x^2 + 4 over [0,2][0, 2].
    -2. Calculate f(2)−f(0)2−0=0−42=−2\frac{f(2) - f(0)}{2 - 0} = \frac{0 - 4}{2} = -2.
  21. State the relationship between secant and tangent lines in context of rates of change.
    Secant: average rate, Tangent: instantaneous rate. Secant connects two points; tangent touches at one point.
  22. Identify the instantaneous rate of change of f(x)=x2f(x) = x^2 at x=3x = 3.
    6. Find f′(x)=2xf'(x) = 2x, then evaluate at x=3x = 3.
  23. Identify the slope of the tangent line to f(x)=x3−3xf(x) = x^3 - 3x at x=1x = 1.
    0. Find f′(x)=3x2−3f'(x) = 3x^2 - 3, then evaluate at x=1x = 1.
  24. What is the average rate of change of f(x)=4x−7f(x) = 4x - 7 over [0,2][0, 2]?
    44. Linear functions have constant rate of change equal to the slope.
  25. What is the instantaneous rate of change of f(x)=x2+2xf(x) = x^2 + 2x at x=0x = 0?
    2. Find f′(x)=2x+2f'(x) = 2x + 2, then substitute x=0x = 0.
  26. What is the derivative of f(x)=x2−4x+2f(x) = x^2 - 4x + 2?
    2x−42x - 4. Apply power rule and linear term differentiation.
  27. What is the instantaneous rate of change of f(x)=3x2−5xf(x) = 3x^2 - 5x at x=4x = 4?
    19. Find f′(x)=6x−5f'(x) = 6x - 5, then evaluate at x=4x = 4.
  28. Find the average rate of change of f(x)=5x2+2xf(x) = 5x^2 + 2x over [1,3][1, 3].
    22. Calculate f(3)−f(1)3−1=51−72=22\frac{f(3) - f(1)}{3 - 1} = \frac{51 - 7}{2} = 22.
  29. What is the derivative of f(x)=5x2−3x+1f(x) = 5x^2 - 3x + 1?
    10x−310x - 3. Differentiate using power rule on each term.
  30. What is the instantaneous rate of change of f(x)=x2−xf(x) = x^2 - x at x=0x = 0?
    -1. Find f′(x)=2x−1f'(x) = 2x - 1, then substitute x=0x = 0.
  31. Identify the average rate of change of f(x)=6x−x2f(x) = 6x - x^2 over [0,3][0, 3].
    3. Calculate f(3)−f(0)3−0=9−03=3\frac{f(3) - f(0)}{3 - 0} = \frac{9 - 0}{3} = 3.
  32. What is the average rate of change of f(x)=−x2+2xf(x) = -x^2 + 2x over [1,5][1, 5]?
    -4. Calculate f(5)−f(1)5−1=−15−14=−4\frac{f(5) - f(1)}{5 - 1} = \frac{-15 - 1}{4} = -4.
  33. What is the formula for the average rate of change of a function f(x)f(x) over [a,b][a, b]?
    f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}. This is the slope formula for secant lines connecting two points.
  34. What is the instantaneous rate of change of f(x)=4x2f(x) = 4x^2 at x=2x = 2?
    16. Find f′(x)=8xf'(x) = 8x, then evaluate at x=2x = 2.
  35. What is the derivative of f(x)=7x2f(x) = 7x^2?
    14x14x. Use power rule on 7x27x^2 to get 7⋅2x=14x7 \cdot 2x = 14x.
  36. State the formula for the instantaneous rate of change of f(x)f(x) at x=ax = a.
    f′(a)f'(a). The derivative gives the instantaneous rate of change at any point.
  37. What is the average rate of change of f(x)=x2f(x) = x^2 over [1,3][1, 3]?
    4. Calculate f(3)−f(1)3−1=9−12=4\frac{f(3) - f(1)}{3 - 1} = \frac{9 - 1}{2} = 4.

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