Inverse Trigonometric Functions - AP Precalculus

  1. What is the inverse of sin(θ)=x\text{sin}(\theta) = x?
    θ=arcsin(x)\theta = \text{arcsin}(x). Solving for θ\theta when sine equals xx.
  2. What is the range of the inverse sine function, arcsin(x)\text{arcsin}(x)?
    The range is [−π2,π2][-\frac{\text{π}}{2}, \frac{\text{π}}{2}]. Restricted to quadrants I and IV where sine is invertible.
  3. Find arccot(√3)\text{arccot}(\text{√3}).
    π6\frac{\text{π}}{6}. Since cot⁡(π6)=3\cot(\frac{\pi}{6}) = \sqrt{3}.
  4. What is arctan(√3)\text{arctan}(\text{√3})?
    π3\frac{\text{π}}{3}. Since tan⁡(π3)=3\tan(\frac{\pi}{3}) = \sqrt{3}.
  5. Find the value of arctan(−1)\text{arctan}(-1).
    −π4-\frac{\text{π}}{4}. Since tan⁡(−π4)=−1\tan(-\frac{\pi}{4}) = -1.
  6. Find arcsin(−√22)\text{arcsin}(-\frac{\text{√2}}{2}).
    −π4-\frac{\text{π}}{4}. Since sin⁡(−π4)=−22\sin(-\frac{\pi}{4}) = -\frac{\sqrt{2}}{2}.
  7. What is the inverse of tan(θ)=x\text{tan}(\theta) = x?
    θ=arctan(x)\theta = \text{arctan}(x). Solving for θ\theta when tangent equals xx.
  8. What is the range of the inverse cosecant function, arccsc(x)\text{arccsc}(x)?
    [−π2,0) or (0,π2][-\frac{\text{π}}{2}, 0) \text{ or } (0, \frac{\text{π}}{2}]. Excludes 0 where cosecant is undefined.
  9. Evaluate arccos(1)\text{arccos}(1).
    00. Since cos⁡(0)=1\cos(0) = 1.
  10. What is arccos(12)\text{arccos}(\frac{1}{2})?
    π3\frac{\text{π}}{3}. Since cos⁡(π3)=12\cos(\frac{\pi}{3}) = \frac{1}{2}.
  11. Find arccsc(√2)\text{arccsc}(\text{√2}).
    π4\frac{\text{π}}{4}. Since csc⁡(π4)=2\csc(\frac{\pi}{4}) = \sqrt{2}.
  12. Find arccos(−√32)\text{arccos}(-\frac{\text{√3}}{2}).
    5π6\frac{5\text{π}}{6}. Since cos⁡(5π6)=−32\cos(\frac{5\pi}{6}) = -\frac{\sqrt{3}}{2} in quadrant II.
  13. Evaluate arccot(−1)\text{arccot}(-1).
    3π4\frac{3\text{π}}{4}. Since cot⁡(3π4)=−1\cot(\frac{3\pi}{4}) = -1.
  14. What is the domain of the inverse cosine function, arccos(x)\text{arccos}(x)?
    The domain is [−1,1][-1, 1]. Cosine input values must be between -1 and 1.
  15. Evaluate arcsec(2)\text{arcsec}(2).
    π3\frac{\text{π}}{3}. Since sec⁡(π3)=2\sec(\frac{\pi}{3}) = 2.
  16. What is arcsec(1)\text{arcsec}(1)?
    00. Since sec⁡(0)=1\sec(0) = 1.
  17. Evaluate arcsec(−2)\text{arcsec}(-2).
    2π3\frac{2\text{π}}{3}. Since sec⁡(2π3)=−2\sec(\frac{2\pi}{3}) = -2 in quadrant II.
  18. What is arccot(0)\text{arccot}(0)?
    π2\frac{\text{π}}{2}. Since cot⁡(π2)=0\cot(\frac{\pi}{2}) = 0.
  19. What is the value of arccos(0)\text{arccos}(0)?
    π2\frac{\text{π}}{2}. Since cos⁡(π2)=0\cos(\frac{\pi}{2}) = 0.
  20. What is the domain of the inverse secant function, arcsec(x)\text{arcsec}(x)?
    (−∞,−1] or [1,∞)(-\text{∞}, -1] \text{ or } [1, \text{∞}). Secant undefined where cosine equals zero.
  21. Find the value of arcsin(0)\text{arcsin}(0).
    00. Since sin⁡(0)=0\sin(0) = 0.
  22. Evaluate arccsc(−2)\text{arccsc}(-2).
    −π6-\frac{\text{π}}{6}. Since csc⁡(−π6)=−2\csc(-\frac{\pi}{6}) = -2.
  23. What is the range of the inverse tangent function, arctan(x)\text{arctan}(x)?
    The range is (−π2,π2)(-\frac{\text{π}}{2}, \frac{\text{π}}{2}). Asymptotic limits as x approaches ±∞±∞.
  24. Evaluate arctan(1)\text{arctan}(1).
    π4\frac{\text{π}}{4}. Since tan⁡(π4)=1\tan(\frac{\pi}{4}) = 1.
  25. Identify the principal value of arccos(−1)\text{arccos}(-1).
    π\text{π}. Since cos⁡(π)=−1\cos(\pi) = -1.
  26. Find arcsin(√32)\text{arcsin}(\frac{\text{√3}}{2}).
    π3\frac{\text{π}}{3}. Since sin⁡(π3)=32\sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2}.
  27. Evaluate arctan(0)\text{arctan}(0).
    00. Since tan⁡(0)=0\tan(0) = 0.
  28. What is the range of the inverse cotangent function, arccot(x)\text{arccot}(x)?
    (0,π)(0, \text{π}). Full range from 0 to π\pi for all real inputs.
  29. What is the domain of the inverse cotangent function, arccot(x)\text{arccot}(x)?
    (−∞,∞)(-\text{∞}, \text{∞}). Cotangent is defined for all real numbers.
  30. Identify the principal value of arcsin(−1)\text{arcsin}(-1).
    −π2-\frac{\text{π}}{2}. Since sin⁡(−π2)=−1\sin(-\frac{\pi}{2}) = -1.
  31. Find arccos(−32)\text{arccos}(-\frac{\sqrt{3}}{2}).
    5π6\frac{5\pi}{6}. Since cos⁡(5π6)=−32\cos(\frac{5\pi}{6}) = -\frac{\sqrt{3}}{2} in quadrant II.
  32. What is the principal value of arccsc(−1)\text{arccsc}(-1)?
    −π2-\frac{\text{π}}{2}. Since csc⁡(−π2)=−1\csc(-\frac{\pi}{2}) = -1.
  33. What is the principal value of arcsec(−1)\text{arcsec}(-1)?
    π\text{π}. Since sec⁡(π)=−1\sec(\pi) = -1.
  34. What is the principal value of arccsc(1)\text{arccsc}(1)?
    π2\frac{\text{π}}{2}. Since csc⁡(π2)=1\csc(\frac{\pi}{2}) = 1.
  35. What is the inverse of cos(θ)=x\text{cos}(\theta) = x?
    θ=arccos(x)\theta = \text{arccos}(x). Solving for θ\theta when cosine equals xx.
  36. What is arcsin(12)\text{arcsin}(\frac{1}{2})?
    π6\frac{\text{π}}{6}. Since sin⁡(π6)=12\sin(\frac{\pi}{6}) = \frac{1}{2}.
  37. Evaluate arccos(−12)\text{arccos}(-\frac{1}{2}).
    2π3\frac{2\text{π}}{3}. Since cos⁡(2π3)=−12\cos(\frac{2\pi}{3}) = -\frac{1}{2} in quadrant II.
  38. Find arcsin(−12)\text{arcsin}(-\frac{1}{2}).
    −π6-\frac{\text{π}}{6}. Since sin⁡(−π6)=−12\sin(-\frac{\pi}{6}) = -\frac{1}{2}.

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