Implicitly Defined Functions - AP Precalculus

  1. How is implicit differentiation used in related rates?
    To relate rates of change of different variables. Connects how variables change with respect to time.
  2. Identify the term to differentiate implicitly: x2+xy+y=1x^2 + xy + y = 1.
    xyxy. The product term requires the product rule for differentiation.
  3. Differentiate x2y+y3=7x^2y + y^3 = 7 implicitly.
    2xy+x2dydx+3y2dydx=02xy + x^2 \frac{dy}{dx} + 3y^2 \frac{dy}{dx} = 0. Apply the product rule and chain rule to each term.
  4. What does it mean to implicitly differentiate y2=4xy^2 = 4x?
    Find dydx\frac{dy}{dx} for y2=4xy^2 = 4x. Apply chain rule to find the derivative relationship.
  5. Differentiate implicitly x3+y3=3xyx^3 + y^3 = 3xy.
    3x2+3y2dydx=3y+3xdydx3x^2 + 3y^2 \frac{dy}{dx} = 3y + 3x \frac{dy}{dx}. Apply chain rule to y3y^3 and product rule to 3xy3xy.
  6. What is the chain rule for implicit differentiation?
    Differentiate both sides with respect to xx, apply dydx\frac{dy}{dx} to yy terms. Treat yy as a function of xx when differentiating.
  7. Differentiate x2−2xy+y2=0x^2 - 2xy + y^2 = 0 implicitly.
    2x−2y−2xdydx+2ydydx=02x - 2y - 2x \frac{dy}{dx} + 2y \frac{dy}{dx} = 0. Use product rule on −2xy-2xy and chain rule on y2y^2.
  8. Find dy/dxdy/dx for x3+y3=6xyx^3 + y^3 = 6xy.
    2y−3x23y2−2x\frac{2y - 3x^2}{3y^2 - 2x}. Use implicit differentiation on both sides of the equation.
  9. Find the implicit derivative for x3+3xy+y3=0x^3 + 3xy + y^3 = 0.
    3x2+3y+3xdydx+3y2dydx=03x^2 + 3y + 3x \frac{dy}{dx} + 3y^2 \frac{dy}{dx} = 0. Use product rule on 3xy3xy and chain rule on cubic terms.
  10. Differentiate x2+y=2xyx^2 + y = 2xy implicitly.
    2x+dydx=2y+2xdydx2x + \frac{dy}{dx} = 2y + 2x \frac{dy}{dx}. Differentiate each term and apply product rule to 2xy2xy.
  11. Find dy/dxdy/dx for the equation x2y+y2=10x^2y + y^2 = 10.
    −2xy+2yx2+2y-\frac{2xy + 2y}{x^2 + 2y}. Use product rule and solve for dydx\frac{dy}{dx}.
  12. What is the implicit derivative for x2+y2=25x^2 + y^2 = 25?
    2x+2ydydx=02x + 2y \frac{dy}{dx} = 0. Standard circle equation differentiated implicitly.
  13. What does it mean to differentiate implicitly?
    Differentiate an equation involving multiple variables. Take derivatives without solving for one variable first.
  14. Find dy/dxdy/dx for x2+y2=4xyx^2 + y^2 = 4xy.
    2x−4y2y−4x\frac{2x - 4y}{2y - 4x}. Rearrange after differentiating to solve for dydx\frac{dy}{dx}.
  15. Differentiate x2+2xy+y2=0x^2 + 2xy + y^2 = 0 implicitly.
    2x+2y+2xdydx+2ydydx=02x + 2y + 2x \frac{dy}{dx} + 2y \frac{dy}{dx} = 0. Perfect square form requires product rule on 2xy2xy.
  16. What is the implicit derivative of ex+ey=1e^x + e^y = 1?
    ex+eydydx=0e^x + e^y \frac{dy}{dx} = 0. Apply chain rule to eye^y term only.
  17. What is the implicit differentiation of x+y=xyx + y = xy?
    1+dydx=y+xdydx1 + \frac{dy}{dx} = y + x \frac{dy}{dx}. Apply product rule to xyxy term on right side.
  18. Differentiate xy=4xy = 4 implicitly.
    y+xdydx=0y + x \frac{dy}{dx} = 0. Apply the product rule to the xyxy term.
  19. Differentiate sin(xy)=1sin(xy) = 1 implicitly.
    cos(xy)(y+xdydx)=0cos(xy)(y + x \frac{dy}{dx}) = 0. Apply chain rule to sin⁡(xy)\sin(xy) using product rule inside.
  20. What is the implicit derivative of x2+2y2=1x^2 + 2y^2 = 1?
    2x+4ydydx=02x + 4y \frac{dy}{dx} = 0. Chain rule applies to 2y22y^2 with coefficient 4.
  21. What is an implicitly defined function?
    A function defined by an equation not solved for one variable. The equation contains both variables without solving for one.
  22. How do you solve for dy/dxdy/dx in an implicit equation?
    Use implicit differentiation, solve for dydx\frac{dy}{dx}. Collect terms with dydx\frac{dy}{dx} and factor them out.
  23. How do you differentiate xy=9xy = 9 implicitly?
    y+xdydx=0y + x \frac{dy}{dx} = 0. Standard product rule application to xyxy.
  24. What is the result of implicit differentiation for y2−x2=1y^2 - x^2 = 1?
    2ydydx−2x=02y \frac{dy}{dx} - 2x = 0. Differentiate each term using appropriate rules.
  25. Differentiate x2+y2=9x^2 + y^2 = 9 implicitly.
    2x+2ydydx=02x + 2y \frac{dy}{dx} = 0. Basic circle equation requiring chain rule for y2y^2.
  26. Find the implicit derivative for x2+3xy+2y2=0x^2 + 3xy + 2y^2 = 0.
    2x+3y+3xdydx+4ydydx=02x + 3y + 3x \frac{dy}{dx} + 4y \frac{dy}{dx} = 0. Mixed terms require product rule and chain rule.
  27. What is the chain rule in terms of implicit differentiation?
    Use dydx\frac{dy}{dx} for terms of yy when differentiating with respect to xx. Apply dydx\frac{dy}{dx} to all yy terms when differentiating.
  28. Identify the implicit differentiation of x3=y3x^3 = y^3.
    3x2=3y2dydx3x^2 = 3y^2 \frac{dy}{dx}. Equal powers differentiate to proportional expressions.
  29. What is the derivative of yy with respect to xx for x2+y2=1x^2 + y^2 = 1?
    −xy-\frac{x}{y}. Apply implicit differentiation to the circle equation.
  30. Differentiate 3x+4y=123x + 4y = 12 implicitly.
    3+4dydx=03 + 4\frac{dy}{dx} = 0. Simple linear equation with constant coefficients.
  31. Differentiate x2y−y=3x^2y - y = 3 implicitly.
    2xy+x2dydx−dydx=02xy + x^2 \frac{dy}{dx} - \frac{dy}{dx} = 0. Use product rule on x2yx^2y and chain rule on yy.
  32. Find the implicit derivative of x2+xy+y2=7x^2 + xy + y^2 = 7.
    2x+y+xdydx+2ydydx=02x + y + x \frac{dy}{dx} + 2y \frac{dy}{dx} = 0. Use product rule on xyxy and chain rule on y2y^2.
  33. What is the implicit derivative of ex+y=5e^x + y = 5?
    ex+dydx=0e^x + \frac{dy}{dx} = 0. Simple linear equation with exponential and linear terms.
  34. Differentiate sin(x)+cos(y)=1sin(x) + cos(y) = 1 implicitly.
    cos(x)−sin(y)dydx=0cos(x) - sin(y) \frac{dy}{dx} = 0. Apply chain rule to trigonometric functions of xx and yy.
  35. Identify the implicit function in x2+y2=1x^2 + y^2 = 1.
    x2+y2=1x^2 + y^2 = 1. The entire equation is implicit as written.

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