Equivalent Representations of Trigonometric Functions - AP Precalculus

  1. State the identity for 1+tan⁡2(θ)1 + \tan^2(\theta).
    1+tan⁡2(θ)=sec⁡2(θ)1 + \tan^2(\theta) = \sec^2(\theta). Pythagorean identity involving tangent and secant.
  2. Find the value of tan⁡(π4)\tan(\frac{\pi}{4}).
    tan⁡(π4)=1\tan(\frac{\pi}{4}) = 1. At 45°, tangent equals 1 since opposite equals adjacent.
  3. Identify the period of tan⁡(θ)\tan(\theta).
    The period of tan⁡(θ)\tan(\theta) is π\pi. Tangent completes one cycle every π\pi radians.
  4. Express tan⁡(π2−θ)\tan(\frac{\pi}{2} - \theta) using a co-function identity.
    tan⁡(π2−θ)=cot⁡(θ)\tan(\frac{\pi}{2} - \theta) = \cot(\theta). Co-function identity: tangent of complementary angle equals cotangent.
  5. What is the reciprocal identity for secant?
    sec⁡(θ)=1cos⁡(θ)\sec(\theta) = \frac{1}{\cos(\theta)}. Secant is the reciprocal of cosine.
  6. Find the value of sin⁡(0)\sin(0).
    sin⁡(0)=0\sin(0) = 0. At zero radians, sine equals zero.
  7. Which quadrant is cos⁡(θ)>0\cos(\theta) > 0 and sin⁡(θ)<0\sin(\theta) < 0?
    Quadrant IV. In Quadrant IV, cosine is positive and sine is negative.
  8. Express cosine in terms of sine for an angle θ\theta.
    cos⁡(θ)=sin⁡(π2−θ)\cos(\theta) = \sin(\frac{\pi}{2} - \theta). Co-function identity relating cosine and sine.
  9. Convert radians to degrees for π3\frac{\pi}{3}.
    π3\frac{\pi}{3} radians = 60∘60^\circ. Multiply by 180π\frac{180}{\pi} to convert radians to degrees.
  10. Express sin⁡(θ+π)\sin(\theta + \pi) using an identity.
    sin⁡(θ+π)=−sin⁡(θ)\sin(\theta + \pi) = -\sin(\theta). Adding π\pi to angle negates sine value.
  11. Convert degrees to radians for 180∘180^\circ.
    180∘180^\circ = π\pi radians. Multiply by π180\frac{\pi}{180} to convert degrees to radians.
  12. Express tan⁡(−θ)\tan(-\theta) using an identity.
    tan⁡(−θ)=−tan⁡(θ)\tan(-\theta) = -\tan(\theta). Tangent is an odd function, so tan⁡(−x)=−tan⁡(x)\tan(-x) = -\tan(x).
  13. Find the value of csc⁡(π2)\csc(\frac{\pi}{2}).
    csc⁡(π2)=1\csc(\frac{\pi}{2}) = 1. Since sin⁡(π2)=1\sin(\frac{\pi}{2}) = 1, its reciprocal is 1.
  14. Express cos⁡(π2−θ)\cos(\frac{\pi}{2} - \theta) using a co-function identity.
    cos⁡(π2−θ)=sin⁡(θ)\cos(\frac{\pi}{2} - \theta) = \sin(\theta). Co-function identity: cosine of complementary angle equals sine.
  15. What is the reciprocal identity for cosecant?
    csc⁡(θ)=1sin⁡(θ)\csc(\theta) = \frac{1}{\sin(\theta)}. Cosecant is the reciprocal of sine.
  16. Find the value of cos⁡(π)\cos(\pi).
    cos⁡(π)=−1\cos(\pi) = -1. At π\pi radians (180°), cosine equals -1.
  17. Express cos⁡(θ+π)\cos(\theta + \pi) using an identity.
    cos⁡(θ+π)=−cos⁡(θ)\cos(\theta + \pi) = -\cos(\theta). Adding π\pi to angle negates cosine value.
  18. State the identity for 1+cot⁡2(θ)1 + \cot^2(\theta).
    1+cot⁡2(θ)=csc⁡2(θ)1 + \cot^2(\theta) = \csc^2(\theta). Pythagorean identity involving cotangent and cosecant.
  19. What is the reciprocal identity for cotangent?
    cot⁡(θ)=1tan⁡(θ)\cot(\theta) = \frac{1}{\tan(\theta)}. Cotangent is the reciprocal of tangent.
  20. Convert cos⁡(θ)\cos(\theta) to terms of secant.
    cos⁡(θ)=1sec⁡(θ)\cos(\theta) = \frac{1}{\sec(\theta)}. Reciprocal identity relating cosine and secant.
  21. Convert sin⁡(θ)\sin(\theta) to terms of cosecant.
    sin⁡(θ)=1csc⁡(θ)\sin(\theta) = \frac{1}{\csc(\theta)}. Reciprocal identity relating sine and cosecant.
  22. Express tangent in terms of sine and cosine for an angle θ\theta.
    tan⁡(θ)=sin⁡(θ)cos⁡(θ)\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}. Quotient identity expressing tangent in terms of sine and cosine.
  23. Express tan⁡(2θ)\tan(2\theta) using a double angle identity.
    tan⁡(2θ)=2tan⁡(θ)1−tan⁡2(θ)\tan(2\theta) = \frac{2\tan(\theta)}{1 - \tan^2(\theta)}. Double angle identity for tangent function.
  24. Find the value of sec⁡(0)\sec(0).
    sec⁡(0)=1\sec(0) = 1. Since cos⁡(0)=1\cos(0) = 1, its reciprocal is 1.
  25. What is the sine of an angle expressed as a ratio in a right triangle?
    Sine = oppositehypotenuse\frac{\text{opposite}}{\text{hypotenuse}}. Basic right triangle definition for sine function.
  26. Express cos⁡(−θ)\cos(-\theta) using an identity.
    cos⁡(−θ)=cos⁡(θ)\cos(-\theta) = \cos(\theta). Cosine is an even function, so cos⁡(−x)=cos⁡(x)\cos(-x) = \cos(x).
  27. Express sin⁡(π2−θ)\sin(\frac{\pi}{2} - \theta) using a co-function identity.
    sin⁡(π2−θ)=cos⁡(θ)\sin(\frac{\pi}{2} - \theta) = \cos(\theta). Co-function identity: sine of complementary angle equals cosine.
  28. Find the value of cot⁡(π4)\cot(\frac{\pi}{4}).
    cot⁡(π4)=1\cot(\frac{\pi}{4}) = 1. Since tan⁡(π4)=1\tan(\frac{\pi}{4}) = 1, its reciprocal is 1.
  29. Identify the period of sin⁡(θ)\sin(\theta).
    The period of sin⁡(θ)\sin(\theta) is 2π2\pi. Sine completes one cycle every 2π2\pi radians.
  30. What is the cosine of an angle expressed as a ratio in a right triangle?
    Cosine = adjacenthypotenuse\frac{\text{adjacent}}{\text{hypotenuse}}. Basic right triangle definition for cosine function.
  31. Express sine in terms of cosine for an angle θ\theta.
    sin⁡(θ)=cos⁡(π2−θ)\sin(\theta) = \cos(\frac{\pi}{2} - \theta). Co-function identity relating sine and cosine.
  32. Which quadrant is sin⁡(θ)>0\sin(\theta) > 0 and cos⁡(θ)<0\cos(\theta) < 0?
    Quadrant II. In Quadrant II, sine is positive and cosine is negative.
  33. Express cos⁡(2θ)\cos(2\theta) using a double angle identity.
    cos⁡(2θ)=cos⁡2(θ)−sin⁡2(θ)\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta). Double angle identity for cosine function.
  34. Convert tan⁡(θ)\tan(\theta) to terms of cotangent.
    tan⁡(θ)=1cot⁡(θ)\tan(\theta) = \frac{1}{\cot(\theta)}. Reciprocal identity relating tangent and cotangent.
  35. Express sin⁡(2θ)\sin(2\theta) using a double angle identity.
    sin⁡(2θ)=2sin⁡(θ)cos⁡(θ)\sin(2\theta) = 2\sin(\theta)\cos(\theta). Double angle identity for sine function.
  36. What is the identity for sin⁡2(θ)+cos⁡2(θ)\sin^2(\theta) + \cos^2(\theta)?
    sin⁡2(θ)+cos⁡2(θ)=1\sin^2(\theta) + \cos^2(\theta) = 1. Pythagorean identity, fundamental trigonometric relationship.
  37. What is the tangent of an angle expressed as a ratio in a right triangle?
    Tangent = oppositeadjacent\frac{\text{opposite}}{\text{adjacent}}. Basic right triangle definition for tangent function.
  38. Express sin⁡(−θ)\sin(-\theta) using an identity.
    sin⁡(−θ)=−sin⁡(θ)\sin(-\theta) = -\sin(\theta). Sine is an odd function, so sin⁡(−x)=−sin⁡(x)\sin(-x) = -\sin(x).

Study these flashcards