Change in Arithmetic and Geometric Sequences - AP Precalculus

  1. State the formula for the sum of the first nn terms of an arithmetic sequence.
    Sn=n2(a1+an)S_n = \frac{n}{2} (a_1 + a_n). Uses the average of first and last terms, multiplied by number of terms.
  2. What is the first term if a5=21a_{5} = 21 and d=5d = 5?
    11. From a5=a1+4d=21a_5 = a_1 + 4d = 21, solve: a1=21−4(5)=1a_1 = 21 - 4(5) = 1.
  3. Find the common difference: 7,10,13,16,...7, 10, 13, 16, \text{...}
    33. Subtract consecutive terms: 10−7=310 - 7 = 3.
  4. What type of sequence is an=5na_n = 5n?
    Arithmetic sequence. Linear form 5n5n indicates constant difference (here d=5d = 5).
  5. Find the number of terms in the geometric sequence: 1,3,9,...,811, 3, 9, \text{...}, 81
    55. Solve 81=1×3n−181 = 1 \times 3^{n-1} to find n=5n = 5.
  6. Identify the 4th term of the sequence: 3,9,27,...3, 9, 27, \text{...}
    8181. Common ratio is 33, so a4=3×34−1=3×27=81a_4 = 3 \times 3^{4-1} = 3 \times 27 = 81.
  7. Describe the sequence 7,21,63,...7, 21, 63, \text{...}
    Geometric sequence. Each term is multiplied by 33 (constant ratio).
  8. Which type of sequence is defined by an=3n+2a_n = 3n + 2?
    Arithmetic sequence. Linear form 3n+23n + 2 indicates constant difference between consecutive terms.
  9. Calculate the 7th term: 4,8,12,16,...4, 8, 12, 16, \text{...}
    2828. Common difference is 44, so a7=4+(7−1)×4=28a_7 = 4 + (7-1) \times 4 = 28.
  10. State the formula for the nnth term of a geometric sequence.
    an=a1×rn−1a_n = a_1 \times r^{n-1}. Start with first term a1a_1, then multiply by rr raised to (n−1)(n-1) power.
  11. Find the common ratio: 5,15,45,...5, 15, 45, \text{...}
    33. Divide consecutive terms: 15÷5=315 \div 5 = 3.
  12. If a1=2a_1 = 2 and r=4r = 4, what is the nnth term of the sequence?
    an=2×4n−1a_n = 2 \times 4^{n-1}. Substitute given values into the geometric sequence formula.
  13. State the formula for the nnth term of an arithmetic sequence.
    an=a1+(n−1)da_n = a_1 + (n-1)d. Start with first term a1a_1, then add (n−1)(n-1) times the common difference.
  14. Determine the 6th term: 1,4,7,10,...1, 4, 7, 10, \text{...}
    1616. Common difference is 33, so a6=1+(6−1)×3=16a_6 = 1 + (6-1) \times 3 = 16.
  15. What is a10a_{10} if a1=3a_1 = 3 and d=2d = 2 in an arithmetic sequence?
    2121. Use formula: a10=3+(10−1)×2=21a_{10} = 3 + (10-1) \times 2 = 21.
  16. Identify the 5th term of the sequence: 2,5,8,11,...2, 5, 8, 11, \text{...}
    1414. Common difference is 33, so a5=2+(5−1)×3=14a_5 = 2 + (5-1) \times 3 = 14.
  17. Find the sum of the first 4 terms: 2,6,18,...2, 6, 18, \text{...}
    8080. Sum the terms: 2+6+18+54=802 + 6 + 18 + 54 = 80.
  18. What is the common difference in an arithmetic sequence?
    The constant difference between consecutive terms. Each term is found by adding this same value to the previous term.
  19. Find the nnth term if a1=6a_1 = 6 and d=4d = 4.
    an=6+(n−1)×4a_n = 6 + (n-1) \times 4. Substitute given values into the arithmetic sequence formula.
  20. Describe the sequence 9,14,19,24,...9, 14, 19, 24, \text{...}
    Arithmetic sequence. Each term increases by 55 (constant difference).
  21. Identify the sequence: 5,9,13,17,...5, 9, 13, 17, \text{...}
    Arithmetic sequence. Each term adds 44 to the previous term (constant difference).
  22. What is the common ratio in a geometric sequence?
    The constant factor between consecutive terms. Each term is found by multiplying the previous term by this same value.
  23. What is the first term if a4=81a_{4} = 81 and r=3r = 3?
    33. From a4=a1×r3=81a_4 = a_1 \times r^3 = 81, solve: a1=81÷33=3a_1 = 81 \div 3^3 = 3.
  24. If a1=5a_1 = 5 and d=3d = 3, what is the nnth term of the sequence?
    an=5+(n−1)×3a_n = 5 + (n-1) \times 3. Substitute given values into the arithmetic sequence formula.
  25. Find the sum of the first 6 terms: 3,6,9,12,...3, 6, 9, 12, \text{...}
    6363. Sum formula: S6=62(3+18)=3×21=63S_6 = \frac{6}{2}(3 + 18) = 3 \times 21 = 63.
  26. What is the sum of the first 4 terms of the sequence: 2,4,8,16,...2, 4, 8, 16, \text{...}?
    3030. Add the terms: 2+4+8+16=302 + 4 + 8 + 16 = 30.
  27. What type of sequence is an=3×2na_n = 3 \times 2^n?
    Geometric sequence. Exponential form 3×2n3 \times 2^n indicates constant ratio (here r=2r = 2).
  28. What is the sum of the first 5 terms of the sequence: 1,3,5,7,...1, 3, 5, 7, \text{...}?
    2525. Add the terms: 1+3+5+7+9=251 + 3 + 5 + 7 + 9 = 25.
  29. Calculate the 5th term: 10,30,90,...10, 30, 90, \text{...}
    810810. Common ratio is 33, so a5=10×35−1=10×81=810a_5 = 10 \times 3^{5-1} = 10 \times 81 = 810.
  30. Determine the 3rd term: 8,24,72,...8, 24, 72, \text{...}
    7272. Given sequence shows a3=72a_3 = 72 directly from the pattern.
  31. Which type of sequence is defined by an=4×2n−1a_n = 4 \times 2^{n-1}?
    Geometric sequence. Exponential form 4×2n−14 \times 2^{n-1} indicates constant ratio between consecutive terms.
  32. State the formula for the sum of the first nn terms of a geometric sequence.
    Sn=a11−rn1−rS_n = a_1 \frac{1-r^n}{1-r}, r≠1r \neq 1. Uses first term times the finite geometric series formula when r≠1r \neq 1.
  33. Find the nnth term if a1=7a_1 = 7 and r=2r = 2.
    an=7×2n−1a_n = 7 \times 2^{n-1}. Substitute given values into the geometric sequence formula.
  34. Calculate the sum: 2,6,18,...,1622, 6, 18, \text{...}, 162
    242242. Use geometric sum formula with a1=2a_1 = 2, r=3r = 3, and n=5n = 5.
  35. Identify the sequence: 10,20,40,80,...10, 20, 40, 80, \text{...}
    Geometric sequence. Each term doubles the previous term (constant ratio of 22).
  36. How many terms are in the arithmetic sequence: 2,5,8,...,202, 5, 8, \text{...}, 20?
    77. Solve 20=2+(n−1)×320 = 2 + (n-1) \times 3 to find n=7n = 7.

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