AP Physics C Electricity and Magnetism Quiz
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ELECTROMAGNETIC INDUCTION
Question 1
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A transformer has
N
p
=
200
N_p=200
N
p
=
200
,
N
s
=
800
N_s=800
N
s
=
800
, and
V
p
=
24
V
rms
V_p=24\ \text{V}_{\text{rms}}
V
p
=
24
V
rms
; calculate induced secondary voltage magnitude.
A
96
V
rms
96\ \text{V}_{\text{rms}}
96
V
rms
using
V
s
=
V
p
(
N
s
/
N
p
)
=
24
(
800
/
200
)
V_s=V_p(N_s/N_p)=24(800/200)
V
s
=
V
p
(
N
s
/
N
p
)
=
24
(
800/200
)
for an ideal transformer.
B
6.0
V
rms
6.0\ \text{V}_{\text{rms}}
6.0
V
rms
using
V
s
=
V
p
(
N
p
/
N
s
)
V_s=V_p(N_p/N_s)
V
s
=
V
p
(
N
p
/
N
s
)
, inverting the turns ratio by mistake.
C
9.6
V
rms
9.6\ \text{V}_{\text{rms}}
9.6
V
rms
from
24
(
80
/
200
)
24(80/200)
24
(
80/200
)
, dropping a zero in
N
s
N_s
N
s
during substitution.
D
96
A
96\ \text{A}
96
A
found from
V
p
(
N
s
/
N
p
)
V_p(N_s/N_p)
V
p
(
N
s
/
N
p
)
, giving current units instead of induced voltage units.
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