Electric Flux
AP Physics C Electricity and Magnetism · Flashcards · Application
AP PHYSICS C ELECTRICITY AND MAGNETISM · FLASHCARDS
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QUESTION
How does electric flux change if the field direction is reversed?
QUESTION
How does the electric flux through a closed surface change if its size is increased?
QUESTION
Find the electric flux:
E
=
10
N/C
\boldsymbol{E} = 10 \text{ N/C}
E
=
10
N/C
,
A
=
1
m
2
A = 1 \text{ m}^2
A
=
1
m
2
,
θ
=
45
°
\theta = 45°
θ
=
45°
.
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ANSWER
Electric flux =
7.07
N m
2
/
C
7.07 \text{ N m}^2/\text{C}
7.07
N m
2
/
C
. Using
Φ
=
10
×
1
×
cos
(
45
°
)
=
10
×
2
2
≈
7.07
\Phi = 10 \times 1 \times \cos(45°) = 10 \times \frac{\sqrt{2}}{2} \approx 7.07
Φ
=
10
×
1
×
cos
(
45°
)
=
10
×
2
2
≈
7.07
.
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