AP Physics 2 • Waves, Sound, and Physical Optics

Periodic Waves

Understanding how repeating disturbances transfer energy through media without transporting matter.

An atom with wave and electric energy symbols.
Inside this lesson 10 sections 5 questions 9 figures

SECTION 1

Historical Context & Motivation

The study of periodic waves has deep roots in humanity's effort to understand how energy propagates through space without the bulk motion of matter. Ancient Greek thinkers, including Pythagoras, recognized that musical pitch was tied to the vibration of strings, but a rigorous mathematical framework would take centuries to develop. The transition from qualitative descriptions of sound and water waves to the precise, quantitative wave equations we use today represents one of the great triumphs of classical physics, and its consequences extend far beyond acoustics—into optics, electromagnetism, and even quantum mechanics.

~500 BCE • Pythagorean Harmonics

Pythagoras and his followers discovered that harmonious musical intervals correspond to simple ratios of string lengths, establishing the first quantitative link between wave properties and perceived phenomena.

1678 • Huygens' Wave Theory

Christiaan Huygens proposed that light propagates as a wave, introducing the principle that every point on a wavefront acts as a source of secondary wavelets—a framework later essential for understanding diffraction and interference of periodic waves.

1746 • d'Alembert's Wave Equation

Jean le Rond d'Alembert derived the one-dimensional wave equation, providing the first partial-differential-equation description of how periodic disturbances evolve in time and space along a vibrating string.

1864 • Maxwell's Electromagnetic Waves

James Clerk Maxwell unified electricity and magnetism, predicting that oscillating electric and magnetic fields propagate as periodic transverse waves at the speed of light—bridging mechanics and optics under one theory.

1887 • Hertz Confirms EM Waves

Heinrich Hertz experimentally generated and detected electromagnetic waves, confirming Maxwell's prediction and demonstrating that periodic wave phenomena extend beyond mechanical media to the electromagnetic spectrum.

These developments converged around a central question that remains at the heart of AP Physics 2: How do we describe, predict, and manipulate the behavior of disturbances that repeat in both time and space? Answering this question requires a precise mathematical vocabulary—wavelength, frequency, amplitude, period, and wave speed—and an understanding of how these quantities interrelate. The concepts you learn here underpin everything from understanding sound in a concert hall to analyzing the electromagnetic radiation that carries information through fiber optic cables.

SECTION 2

Core Principles & Definitions

A periodic wave is a disturbance that repeats itself at regular intervals in both time and space. Unlike a single pulse, which passes through a medium once, a periodic wave is generated by a source that oscillates continuously, producing a pattern that can be described by a fixed set of parameters. The medium through which the wave travels—air, water, a stretched string—oscillates locally, but the medium itself does not travel with the wave; instead, energy and momentum are transported while the medium particles return to their equilibrium positions. Understanding the following foundational concepts is essential before we develop the mathematical framework.

1

Wavelength (λ)

The spatial distance over which the wave pattern repeats—measured from crest to crest, trough to trough, or any two successive points in phase. SI unit: meters (m).
2

Frequency (f)

The number of complete oscillation cycles passing a fixed point per unit time. SI unit: hertz (Hz), where 1 Hz = 1 cycle per second. Frequency is determined by the source.
3

Period (T)

The time for one complete cycle of the wave to pass a given point. It is the temporal reciprocal of frequency: T = 1/f. SI unit: seconds (s).
4

Amplitude (A)

The maximum displacement of the medium from its equilibrium position. Amplitude is directly related to the energy carried by the wave—doubling the amplitude quadruples the energy per unit length.
5

Wave Speed (v)

The speed at which a crest (or any fixed phase point) propagates through the medium. Determined by the medium's properties—not by frequency or amplitude. Related to λ and f by v = λf.
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KEY TAKEAWAY

Think of a periodic wave like a stadium "wave" at a sporting event. Each spectator (the medium) stands and sits in place—no one moves around the stadium—yet the pattern of standing clearly travels around the arena. The speed of the wave depends on how quickly each person reacts (the medium's properties), while the frequency depends on how often the crowd decides to initiate a new cycle (the source). Energy and pattern travel; the medium does not.

SECTION 3

Anatomy of a Periodic Wave

Transverse Periodic Wave — Displacement vs. PositionEquilibriumx (m)y (m)λ (wavelength)A(amplitude)CrestTroughNodeDirection of wave propagation →Medium particles oscillateperpendicular to propagation↕ oscillation
A snapshot of a transverse periodic wave. The cyan curve shows displacement y as a function of position x at a single instant. The violet brackets mark one wavelength λ, the pink lines indicate the amplitude A, and the amber and red dots mark a crest and trough, respectively.

The diagram above captures a spatial snapshot of a transverse periodic wave—a graph of displacement versus position at one instant of time. Notice that the wave pattern is perfectly repetitive: each wavelength contains one complete crest-to-trough cycle. The crest is the point of maximum positive displacement, the trough is the point of maximum negative displacement, and the nodes are the equilibrium-crossing points. In a transverse wave, the oscillation of the medium is perpendicular to the direction of wave propagation, as indicated by the orange arrows. For a longitudinal wave (such as sound in air), the oscillation would instead be parallel to the direction of travel—we will compare these two types in Section 5.

💡

AP Exam Tip

The AP Physics 2 exam frequently asks you to distinguish between a displacement-versus-position graph (spatial snapshot) and a displacement-versus-time graph (temporal record at one location). Be sure to read axis labels carefully—the wavelength λ is read from the x-axis of a y vs. x graph, while the period T is read from the t-axis of a y vs. t graph.

SECTION 4

Mathematical Framework

The behavior of periodic waves is governed by a small set of interconnected equations. Mastering these relationships—and understanding which variables are set by the source and which are determined by the medium—is essential for solving AP Physics 2 problems efficiently.

WAVE SPEED EQUATION

v=λfv = λf

v = wave speed (m/s), λ = wavelength (m), f = frequency (Hz). This is the most fundamental relationship: wave speed equals wavelength times frequency. Because v depends on the medium and f depends on the source, wavelength adjusts when a wave enters a new medium.

PERIOD–FREQUENCY RELATION

T=1/fT = 1 / f

T = period (s), f = frequency (Hz). Period and frequency are reciprocals—a wave with a high frequency completes cycles quickly and therefore has a short period.

WAVE SPEED FROM PERIOD

v=λ/Tv = λ / T

An equivalent form obtained by substituting f = 1/T into v = λf. Useful when the period (rather than frequency) is the given quantity.

SINUSOIDAL WAVE FUNCTION

y(x,t)=Asin(2π(x/λ−t/T))y(x, t) = A sin(2π(x/λ − t/T))

A = amplitude, λ = wavelength, T = period. This function gives the displacement y of the medium at position x and time t for a wave traveling in the +x direction. The argument of the sine function is the phase of the wave. While AP Physics 2 is algebra-based and rarely requires you to evaluate this function numerically, understanding its structure clarifies why crests, troughs, and nodes appear where they do.

A critical conceptual point: frequency is set by the source, and wave speed is set by the medium. When a periodic wave crosses a boundary between two media (for example, light entering glass from air), the frequency remains constant, the speed changes, and the wavelength must adjust accordingly. This principle is the foundation of refraction. Furthermore, the energy carried by a mechanical wave is proportional to the square of the amplitude and the square of the frequency: E ∝ A²f². Doubling the amplitude quadruples the energy transport rate, which is why high-amplitude waves—such as tsunamis—carry enormous destructive energy.

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KEY TAKEAWAY

Think of v = λf as the wave analogue of the simple relationship distance = speed × time. Just as a car traveling at a fixed speed covers a certain distance each second, a wave traveling at speed v covers one wavelength λ in each period T = 1/f. The medium dictates the speed limit, and the source dictates how often new crests are produced—wavelength is simply whatever fills the gap.

SECTION 5

Transverse vs. Longitudinal Waves

Periodic waves are classified by the relationship between the direction of the medium's oscillation and the direction of wave propagation. In a transverse wave, the medium oscillates perpendicular to the wave's direction of travel—examples include waves on a string, surface water waves (approximately), and electromagnetic waves. In a longitudinal wave, the medium oscillates parallel to the direction of propagation. Sound waves in air, where air molecules oscillate back and forth along the direction the sound travels, are the classic example. Some waves, such as surface waves on deep water, exhibit both transverse and longitudinal components simultaneously.

Transverse vs. Longitudinal Periodic WavesTRANSVERSE WAVEeq.Oscillation ↕Propagation →LONGITUDINAL WAVECompr.Raref.CRCRλOscillation ↔Propagation →
Upper panel: A transverse wave with oscillation perpendicular to propagation. Lower panel: A longitudinal wave showing alternating compressions (C) and rarefactions (R), with one wavelength λ spanning from one compression to the next.
PropertyTransverse WaveLongitudinal Wave
Oscillation directionPerpendicular to propagationParallel to propagation
Key featuresCrests and troughsCompressions and rarefactions
Can travel inSolids, surfaces, vacuum (EM waves)Solids, liquids, gases
Polarizable?Yes—oscillation can be restricted to one planeNo—oscillation is along a single axis
Common examplesLight, waves on a string, S-wavesSound in air, P-waves, ultrasound

Comparison of transverse and longitudinal periodic waves

An important point for AP Physics 2: electromagnetic waves are transverse and can propagate through a vacuum, unlike mechanical waves which require a material medium. Sound, by contrast, is longitudinal and cannot travel through empty space. The fact that transverse waves can be polarized while longitudinal waves cannot is a direct consequence of the geometry of oscillation, and this distinction plays a central role when you study polarization in the optics portion of the course.

SECTION 6

Worked Example

Let's work through a multi-part problem that integrates the core equations and conceptual reasoning needed for the AP exam.

Sound Wave Crossing Media Boundaries

  1. 1

    Step 1 — Read the Problem

    A tuning fork vibrating at 440 Hz produces a sound wave in air where the speed of sound is 343 m/s. The sound then enters water, where the speed of sound is 1480 m/s. Determine (a) the wavelength in air, (b) the wavelength in water, and (c) explain why the frequency does not change when the wave crosses the boundary.
  2. 2

    Step 2 — Identify Given Values

    f = 440 Hz (set by the source, constant across both media). vair = 343 m/s. vwater = 1480 m/s.
  3. 3

    Step 3 — Solve for Wavelength in Air

    Using v = λf → λair = vair / f = 343 m/s ÷ 440 Hz
    λ_air = 0.780 m
  4. 4

    Step 4 — Solve for Wavelength in Water

    The frequency remains 440 Hz. λwater = vwater / f = 1480 m/s ÷ 440 Hz
    λ_water = 3.36 m
  5. 5

    Step 5 — Explain Constant Frequency

    At the air-water boundary, the wave arriving from air drives oscillations in the water at the same rate it arrives—every crest in air produces a crest in water. If the frequency changed at the boundary, wave crests would either pile up or disappear at the interface, violating conservation of energy and creating a physical discontinuity. Therefore, frequency is preserved across boundaries, and the wavelength adjusts to accommodate the new wave speed in the second medium.
  6. 6

    Step 6 — Check Reasonableness

    The wave speed in water is about 4.3 times that in air (1480/343 ≈ 4.31), and the ratio of wavelengths is also 3.36/0.780 ≈ 4.31. This consistent ratio confirms our calculation and reinforces that λ ∝ v when f is constant.

SECTION 7

Source vs. Medium: What Controls What

One of the most common sources of confusion on the AP exam is determining which wave properties are intrinsic to the source and which are determined by the medium. The table below clarifies these relationships and their implications.

Wave PropertyDetermined ByChanges at a Boundary?Physical Reason
Frequency (f)SourceNoBoundary continuity: crests arrive and depart at the same rate
Wave speed (v)MediumYesSpeed depends on density, elasticity, temperature, etc.
Wavelength (λ)Both (v/f)YesAdjusts so that v = λf remains satisfied with constant f
Amplitude (A)Source + mediumYesEnergy partition at boundary; absorption and damping in medium
Period (T)SourceNoT = 1/f; since f is preserved, T is also preserved

Summary of which wave properties change when a periodic wave crosses into a new medium

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KEY TAKEAWAY

Imagine a factory (the source) producing items on a conveyor belt at a fixed rate (frequency). When the belt transitions from a slow section (one medium) to a fast section (another medium), the items spread farther apart (longer wavelength) because they're being carried faster—but the factory still outputs them at the same rate. The production rate (frequency) never changes; only the spacing (wavelength) adjusts.

T 10 N,μ0.010 kg/m givesv 31.62 m/s;20/40 Hz givesλ1.581/0.791 m.At fixed tension and linear density, the wave speed stays constant while a higher drive frequency shortens wavelength.

SECTION 8

Connections to Superposition and Beyond

Periodic waves are the building blocks for nearly every phenomenon you will encounter in the rest of AP Physics 2's wave unit. When two or more periodic waves overlap in the same region of space, they obey the superposition principle: the resultant displacement at any point is the algebraic sum of the individual displacements. This principle leads directly to interference, standing waves, beats, and diffraction—all of which are tested on the AP exam. Fourier's theorem, while beyond the algebra-based syllabus, tells us that any complex periodic waveform can be decomposed into a sum of simple sinusoidal waves, further underscoring the centrality of the sinusoidal model developed in this lesson.

ConceptThis Lesson (Periodic Waves)Advanced Extensions
Single wave descriptionv = λf; sinusoidal shape; amplitude, periodFull wave equation ∂²y/∂t² = v²∂²y/∂x²
Two waves overlappingSuperposition principle; constructive/destructive interferenceStanding wave patterns; beats; Fourier synthesis
Wave at a boundaryFrequency preserved; λ adjusts; partial reflectionSnell's law; impedance matching; transmission coefficients
Energy transportEnergy ∝ A²; waves carry energy without net mass transportIntensity (power/area); inverse-square law; Poynting vector
Wave typeTransverse vs. longitudinal classificationPolarization; electromagnetic wave structure (E ⊥ B ⊥ v)

How periodic wave concepts extend to advanced topics in the AP Physics 2 curriculum

As you proceed through the waves unit, remember that every interference pattern, every standing wave resonance, and every diffraction effect builds directly on the properties of the periodic waves you have studied here. The mathematical simplicity of v = λf belies the extraordinary range of physical phenomena it governs—from the harmonics of a guitar string to the colors in a thin film of soap.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

A periodic sound wave travels from air into a denser medium where the speed of sound is higher. Which of the following correctly describes the changes to the wave's frequency and wavelength upon entering the new medium?
  • A. Frequency increases; wavelength stays the same
  • B. Frequency stays the same; wavelength increases
  • C. Frequency decreases; wavelength increases
  • D. Frequency stays the same; wavelength decreases
Show answer (B)
The correct answer is B. Frequency is determined by the source and is preserved when a wave crosses a boundary—this eliminates choices A and C. Since v = λf and the speed increases while frequency remains constant, the wavelength must increase (λ = v/f). Choice D incorrectly states the wavelength decreases, which would only occur if the wave speed decreased. Choice A incorrectly suggests frequency changes, violating boundary continuity.

Question 2: BASIC CALCULATION

A periodic wave on a string has a wavelength of 0.50 m and a frequency of 120 Hz. What is the wave speed on the string?
  • A. 24 m/s
  • B. 60 m/s
  • C. 240 m/s
  • D. 0.0042 m/s
Show answer (B)
The correct answer is B. Applying v = λf: v = (0.50 m)(120 Hz) = 60 m/s. Choice A (24 m/s) may result from an arithmetic error or incorrect formula manipulation. Choice C (240 m/s) comes from mistakenly dividing f by λ and then scaling incorrectly. Choice D (0.0042 m/s) results from computing λ/f instead of λ × f. Always verify units: meters × (1/seconds) = meters/second.

Question 3: INTERMEDIATE

A student observes that a periodic wave on a spring completes 15 full cycles in 3.0 seconds. The distance between the first and fourth crests is measured to be 0.90 m. What is the speed of the wave?
  • A. 0.30 m/s
  • B. 1.5 m/s
  • C. 4.5 m/s
  • D. 2.25 m/s
Show answer (B)
The correct answer is B. First, find frequency: f = 15 cycles / 3.0 s = 5.0 Hz. The distance from the 1st to the 4th crest spans 3 wavelengths (not 4), so λ = 0.90 m / 3 = 0.30 m. Then v = λf = (0.30 m)(5.0 Hz) = 1.5 m/s. Choice A (0.30 m/s) confuses wavelength with speed. Choice C (4.5 m/s) incorrectly uses 0.90 m as the wavelength (failing to divide by 3). Choice D (2.25 m/s) likely uses 0.90 m / 2 = 0.45 m for λ, wrongly counting only 2 wavelengths between 4 crests.

Question 4: APPLIED

4 pts
Design an experiment to determine the speed of a periodic transverse wave on a string. You have access to a mechanical vibrator with adjustable frequency (1–100 Hz), a string of known linear mass density, a pulley, a set of hanging masses, a meter stick, and a stopwatch. (a) Describe a procedure to collect the data necessary to determine the wave speed. (b) State what measurements you would record and how you would use them to calculate wave speed. (c) Describe how you would reduce experimental uncertainty in your measurement of wavelength. (d) Explain one source of systematic error and how it might affect your results.
Show answer
Point 1 (Procedure – 1 pt): Attach the string to the vibrator, run it over the pulley, and hang a mass to provide tension. Set the vibrator to a known frequency and adjust until a clear standing wave pattern with well-defined nodes forms. A standing wave is used because it allows precise measurement of wavelength. Point 2 (Measurements and calculation – 1 pt): Measure the distance between adjacent nodes using the meter stick; this distance equals λ/2, so multiply by 2 to get the wavelength. Record the vibrator frequency f. Calculate wave speed as v = λf. Alternatively, measure the distance spanning several node-to-node intervals and divide to get a more precise λ/2. Point 3 (Reducing uncertainty – 1 pt): Measure the distance across multiple half-wavelengths (e.g., from the 1st node to the 6th node, spanning 5 half-wavelengths) and divide by the number of intervals. This averages out the uncertainty in identifying individual node positions and reduces random measurement error. Point 4 (Systematic error – 1 pt): A systematic error could arise from the vibrator attachment point not being an exact node, causing the effective vibrating length to be slightly longer or shorter than measured. This would systematically bias the wavelength measurement and therefore the calculated wave speed. Another valid example: string sagging under gravity changes the effective tension, making the actual tension slightly non-uniform along the string.

Question 5: CRITICAL THINKING

4 pts
A student claims: "If I double the frequency of a wave source, the wave speed on the same string must also double." Evaluate this claim. In your response: (a) State whether the claim is correct or incorrect and justify your reasoning using v = λf and the properties that determine wave speed on a string. (b) Explain what actually happens to the wavelength when the frequency is doubled on the same string. (c) Describe a scenario in which doubling the frequency of the source would result in a wave with a different speed, and explain why. (d) A second student suggests that increasing the amplitude of the wave would increase its speed. Evaluate this claim as well.
Show answer
Point 1 (Evaluate claim – 1 pt): The claim is incorrect. The speed of a wave on a string is determined by the medium's properties: v = √(FTF_T/μ), where FTF_T is the tension and μ is the linear mass density. Changing the source frequency does not alter the tension or mass density, so the wave speed remains unchanged. Point 2 (Wavelength change – 1 pt): Since v = λf and v is constant for the same string under the same tension, doubling f requires that λ be halved. The wavelength decreases by a factor of 2 so that the product λf remains equal to the unchanged wave speed. Point 3 (Scenario for different speed – 1 pt): If the wave source sends a signal from one medium into a different medium—for example, sound from air into water—the speed changes because the medium changes, not because of the frequency. Alternatively, if the student simultaneously doubled the frequency and increased the string tension (e.g., by adding mass to the hanging weight), the speed would increase due to the tension change, not the frequency change. The key distinction is that it is the medium's properties, not the source's frequency, that govern speed. Point 4 (Amplitude claim – 1 pt): The second student's claim is also incorrect for linear (small-amplitude) waves. Wave speed on a string depends on tension and linear mass density, not amplitude. Amplitude affects the energy transported by the wave (energy ∝ A²), but not the propagation speed. In extreme cases of very large amplitude, nonlinear effects can cause slight speed dependence on amplitude, but within the AP Physics 2 framework, speed is independent of amplitude.

SUMMARY

Periodic Waves — Summary

Summary

A periodic wave is a repeating disturbance characterized by five essential parameters: wavelength (λ), frequency (f), period (T = 1/f), amplitude (A), and wave speed (v). These are linked by the universal wave equation v = λf. Waves transport energy and momentum without net displacement of the medium. Transverse waves oscillate perpendicular to propagation (light, string waves), while longitudinal waves oscillate parallel to it (sound in air).

At a boundary between media, frequency is preserved (set by the source), wave speed changes (set by the medium), and wavelength adjusts to satisfy v = λf. Energy carried by a wave scales with the square of both amplitude and frequency. These foundational principles underpin every subsequent topic in the AP Physics 2 waves unit: superposition, interference, standing waves, diffraction, and refraction all depend on the behavior of periodic waves.

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