AP Physics 2 • Geometric Optics

Images Formed by Mirrors

How the geometry of reflection creates real and virtual images in flat, concave, and convex mirrors.

An atom with wave and electric energy symbols.
Inside this lesson 10 sections 5 questions 8 figures

SECTION 1

Historical Context & Motivation

Mirrors rank among humanity's oldest optical tools, and their history reveals an evolving understanding of how light interacts with reflective surfaces. Ancient civilizations used polished metals—bronze in Egypt, obsidian in Anatolia—long before anyone articulated a mathematical law of reflection. The Greeks, particularly Euclid around 300 BCE, first formalized the idea that the angle of incidence equals the angle of reflection, laying the groundwork for geometric optics. Yet it took many more centuries before scholars understood how curved mirrors could focus light and produce images at predictable locations.

~300 BCE • Euclid's Catoptrica

Euclid codifies the law of reflection and uses geometric ray-tracing to explain image formation in flat mirrors, establishing that the image appears as far behind the mirror as the object is in front.

~1000 CE • Ibn al-Haytham's Kitāb al-Manāẓir

Alhazen publishes his Book of Optics, rigorously analyzing curved mirror reflections, introducing the concept of a focal point, and employing experimental verification of ray diagrams.

1663 • Gregory's Reflecting Telescope

James Gregory designs the first practical reflecting telescope using a concave primary mirror, demonstrating the real-world application of image formation by curved mirrors.

1668 • Newton's Reflector

Isaac Newton builds the first successful reflecting telescope, using a concave mirror to eliminate chromatic aberration found in lens-based designs and cementing the importance of mirror optics in astronomy.

1932 • Modern Mirror Fabrication

Vacuum deposition of aluminum on glass enables mass production of high-quality mirrors, making precise curved mirrors accessible for scientific instruments, telescopes, and eventually everyday applications like vehicle side mirrors.

The central question that geometric optics answers is deceptively simple: given a mirror of known shape and an object at a known position, where does the image form, and what are its properties? Answering this question requires a systematic framework built on the law of reflection, ray-tracing techniques, and a concise algebraic relationship—the mirror equation. These tools allow physicists and engineers to predict whether an image will be real or virtual, upright or inverted, and magnified or diminished, all from the geometry of the mirror and the object's placement.

SECTION 2

Core Principles & Definitions

Image formation by mirrors rests on a small set of powerful ideas that apply uniformly to plane, concave, and convex mirrors. Before diving into ray diagrams and equations, it is essential to establish the vocabulary and sign conventions used throughout geometric optics. The AP Physics 2 exam uses the standard sign convention in which distances measured on the same side as the incoming light (the object side) are positive, and distances behind the mirror surface are negative. This convention keeps the mirror equation consistent across all mirror types.

1

Law of Reflection

The angle of incidence θi always equals the angle of reflection θr, measured from the normal to the surface at the point of incidence. This single principle governs every ray reflected by any mirror.
2

Real vs. Virtual Images

A real image forms where reflected rays actually converge; it can be projected onto a screen. A virtual image forms where reflected rays appear to diverge from; it cannot be captured on a screen but is visible to an observer looking into the mirror.
3

Focal Point & Focal Length

For a spherical mirror of radius of curvature R, the focal length f = R/2. Parallel rays converge at the focal point for concave mirrors and appear to diverge from it for convex mirrors.
4

Magnification

The lateral magnification m = −di / do gives both the size ratio and orientation. A positive m indicates an upright image; a negative m indicates an inverted image.
5

Principal Axis & Center of Curvature

The principal axis is the line through the center of curvature C and the vertex V of a curved mirror. All standard ray-tracing rules reference rays parallel to, through, or aimed at points along this axis.
✦

KEY TAKEAWAY

Think of a concave mirror as a satellite dish for light: it gathers parallel wavefronts and funnels them to a single focal point, much as a parabolic antenna focuses radio waves onto a receiver. A convex mirror does the opposite—it scatters incoming rays outward, like a traffic dome mirror that sacrifices magnification for a wider field of view. Whether light converges or diverges determines whether the image is real and projectable or virtual and visible only in the mirror.

SECTION 3

Ray Diagrams for Concave Mirrors

Ray diagrams are the single most important qualitative tool for understanding image formation. For a concave (converging) mirror, three principal rays originate from the tip of the object: (1) a ray parallel to the principal axis reflects through the focal point F, (2) a ray through the focal point reflects parallel to the axis, and (3) a ray through the center of curvature C reflects back on itself. The intersection of any two of these rays locates the tip of the image. The diagram below illustrates the case where the object is placed beyond the center of curvature, producing a real, inverted, and diminished image between F and C.

Concave Mirror — Object Beyond CMirrorVFCObjectRay 1: parallel → FRay 2: through F → ∥Ray 3: through C → backImage(real, inverted, diminished)do > R → Image between F and C
Three principal rays leave the tip of the object (cyan arrow). Ray 1 travels parallel to the axis and reflects through F. Ray 2 passes through F and reflects parallel. Ray 3 passes through C and reflects back on itself. The three reflected rays converge at the tip of the real image (orange arrow), which is inverted and smaller than the object.

The diagram encapsulates the most common AP exam scenario for concave mirrors. When the object distance do exceeds the radius of curvature R, reflected rays converge to form a real image between F and C. Moving the object closer to C causes the image to grow and recede; placing the object between F and C flips this relationship—the image appears beyond C, magnified and still inverted. The critical transition occurs when the object sits exactly at F: reflected rays emerge parallel and no image forms at a finite distance. Inside F, the concave mirror produces a virtual, upright, magnified image behind the mirror surface—exactly the configuration used in makeup and shaving mirrors.

A candle, screen with inverted candle projection, and concave mirror on an optical rail.A concave mirror forms a real image where reflected rays converge. When the object is inside the focal length, the reflected rays diverge and their backward extensions locate an upright virtual image.

Real image in a concave mirror. With focal length 20 cm, an object 30 cm in front of the mirror forms a real image 60 cm in front. A 5 cm object gives an inverted 10 cm image.With focal length 20 cm, an object 30 cm in front of the mirror forms a real image 60 cm in front. A 5 cm object gives an inverted 10 cm image.

Virtual image inside the focal length. An object 10 cm in front of a concave mirror with f = 20 cm has image distance −20 cm and magnification +2. Only backward extensions meet behind the mirror.An object 10 cm in front of a concave mirror with f = 20 cm has image distance −20 cm and magnification +2. Only backward extensions meet behind the mirror.

SECTION 4

Mathematical Framework

The quantitative analysis of image formation by spherical mirrors relies on two equations that the AP Physics 2 exam expects you to apply fluently. Both equations emerge from the geometry of similar triangles formed by the principal rays, the principal axis, and the mirror surface. Combined with a consistent sign convention, they predict every measurable property of the image.

MIRROR EQUATION

1/f=1/do+1/di1/f = 1/dₒ + 1/dᵢ

f = focal length (positive for concave, negative for convex); do = object distance (always positive for real objects); di = image distance (positive for real images in front of mirror, negative for virtual images behind mirror).

LATERAL MAGNIFICATION

m=hi/ho=−di/dom = hᵢ / hₒ = −dᵢ / dₒ

m = lateral magnification; hi = image height; ho = object height. |m| > 1 indicates enlargement; |m| < 1 indicates reduction. Positive m → upright image; negative m → inverted image.

FOCAL LENGTH–RADIUS RELATION

f=R/2f = R / 2

R = radius of curvature of the spherical mirror. This relationship holds in the paraxial approximation, where rays strike the mirror close to the principal axis. For a plane mirror, R → ∞ so f → ∞, and the mirror equation yields di = −do (virtual image at equal distance behind the mirror).

💡

Sign Convention Summary

On the AP exam, consistent sign usage prevents most errors. Remember: concave mirrors have positive f because their focal point is on the reflective (front) side. Convex mirrors have negative f because their focal point is behind the mirror. A positive di means the image is real (in front); a negative di means the image is virtual (behind).

SECTION 5

Image Characteristics by Mirror Type

A thorough understanding of image formation requires knowing how image properties change as the object moves relative to the mirror. The three mirror types—plane, concave, and convex—each have distinct behaviors. A plane mirror always produces a virtual, upright, same-size image (m = +1) located as far behind the surface as the object is in front. A convex mirror always produces a virtual, upright, diminished image regardless of object position, which is why it is used as a wide-angle security or vehicle mirror. The concave mirror is the richest case: its image properties depend critically on where the object is placed relative to F and C.

Object Position (Concave)Image LocationImage TypeSize / Orientation
do > R (beyond C)Between F and CRealDiminished, Inverted
do = R (at C)At CRealSame size, Inverted
f < do < R (between F and C)Beyond CRealMagnified, Inverted
do = f (at F)At infinity (no finite image)——
do < f (inside F)Behind mirrorVirtualMagnified, Upright

Summary of concave mirror image properties as a function of object position

Convex Mirror — Image Always Virtual, Upright, DiminishedMirrorVF(behind mirror)C(behind mirror)ObjectRay 1: ∥ → divergesas if from FRay 2: aimed at F→ reflects ∥Image(virtual, upright, diminished)Behind mirror
For a convex mirror, C and F lie behind the reflective surface (shaded region). Ray 1 arrives parallel to the axis and reflects as though it diverged from the virtual focal point F. Ray 2 aims toward F but reflects parallel. The extensions of the reflected rays converge behind the mirror, locating the virtual, upright, diminished image (orange arrow).
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AP Exam Tip

A frequent free-response task asks you to draw a ray diagram and then confirm your result with the mirror equation. Always draw at least two principal rays; the third serves as a self-check. Label F, C, V, the object, and the image clearly. State whether the image is real or virtual, upright or inverted, and magnified or diminished—these three descriptors are worth separate rubric points.

SECTION 6

Worked Example

Concave Mirror: Finding Image Position and Characteristics

  1. 1

    Step 1 — Identify Given Values

    A concave mirror has a radius of curvature R = 40.0 cm. An object 5.0 cm tall is placed 30.0 cm in front of the mirror. We need to find the image distance di, the magnification m, and the image height hi.
    R = 40.0 cm → f = R/2 = 20.0 cm; do = 30.0 cm; ho = 5.0 cm
  2. 2

    Step 2 — Apply the Mirror Equation

    Using 1/f = 1/do + 1/di, we rearrange: 1/di = 1/f − 1/do = 1/20.0 − 1/30.0 = (3 − 2)/60 = 1/60.
    di = +60.0 cm (positive → real image, in front of mirror)
  3. 3

    Step 3 — Calculate Magnification

    m = −di / do = −60.0 / 30.0 = −2.0.
    m = −2.0 (negative → inverted; |m| = 2 → magnified by factor of 2)
  4. 4

    Step 4 — Find Image Height

    hi = m × ho = (−2.0)(5.0 cm) = −10.0 cm.
    hi = −10.0 cm (the negative sign confirms the image is inverted)
  5. 5

    Step 5 — Interpret the Result

    The object was between F (20 cm) and C (40 cm). The image forms at 60.0 cm in front of the mirror—beyond C. It is real (di > 0), inverted (m < 0), and magnified (|m| > 1). This matches the third row of the classification table in Section 5, confirming our calculation.
    Real, inverted, magnified image at 60.0 cm, height 10.0 cm

SECTION 7

Comparing Mirror Types: Strengths & Limitations

Each mirror type has practical advantages and disadvantages that explain its real-world applications. The AP Physics 2 curriculum expects you to connect these properties to everyday and scientific contexts, from telescopes and solar furnaces to security mirrors and automobile side mirrors.

PropertyPlane MirrorConcave MirrorConvex Mirror
Image typeAlways virtualReal or virtual (depends on do)Always virtual
OrientationUpright (laterally reversed)Inverted (real) or upright (virtual)Always upright
Magnificationm = +1 always|m| can be < 1, = 1, or > 10 < m < 1 always
Focal lengthf → ∞f > 0 (positive)f < 0 (negative)
Common applicationsBathroom mirrors, periscopesTelescopes, headlights, solar furnaces, shaving/makeup mirrorsPassenger side mirrors, store security mirrors, ATM cameras
Key limitationCannot project real images; no magnificationSpherical aberration for large apertures; image properties change with doImage always smaller than object; cannot form real images

Comprehensive comparison of the three mirror types tested on AP Physics 2

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KEY TAKEAWAY

Mirror selection in engineering follows the same logic as choosing between a telephoto lens and a wide-angle lens in photography. A concave mirror acts like a telephoto—it narrows the field of view but can magnify and project. A convex mirror acts like a wide-angle—it captures more of the scene at the cost of making everything appear smaller. The application dictates which trade-off is acceptable.

SECTION 8

Connection to Lenses & Advanced Optics

The mirror equation is not an isolated result—it has a direct counterpart in the thin lens equation, which takes the identical algebraic form 1/f = 1/do + 1/di. The analogy between converging lenses and concave mirrors (both have positive f), and between diverging lenses and convex mirrors (both have negative f), runs deep. Mastering the sign conventions and ray-tracing techniques for mirrors provides a transferable framework that applies immediately when the AP Physics 2 curriculum moves to refraction and lenses.

FeatureMirrors (Reflection)Thin Lenses (Refraction)
Governing equation1/f = 1/do + 1/di1/f = 1/do + 1/di
Converging elementConcave mirror (f > 0)Converging (convex) lens (f > 0)
Diverging elementConvex mirror (f < 0)Diverging (concave) lens (f < 0)
Image sideSame side as object for real imagesOpposite side from object for real images
Chromatic aberrationNone (reflection is independent of wavelength)Present (index of refraction depends on wavelength)
Spherical aberrationPresent for large-aperture spherical mirrorsPresent for large-aperture spherical lenses

Mirrors vs. thin lenses: structural parallels and key differences

At a more advanced level, the paraxial approximation underlying the mirror equation breaks down for rays far from the principal axis, leading to spherical aberration—marginal rays focus at a different point than paraxial rays. Parabolic mirrors eliminate this defect entirely, which is why modern telescopes (such as the 6.5-meter primary mirror of the James Webb Space Telescope) use paraboloidal surfaces. While parabolic mirror geometry goes beyond AP Physics 2, understanding why the approximation works—and where it fails—deepens your appreciation for the elegance and limitations of the algebraic model.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

A student places an object at the focal point of a concave mirror. Which of the following best describes the image formed?
  • A. A real, inverted image forms at the center of curvature.
  • B. A virtual, upright, magnified image forms behind the mirror.
  • C. No image forms at a finite distance because reflected rays are parallel.
  • D. A real, inverted image of the same size forms at the focal point.
Show answer (C)
When the object is at the focal point of a concave mirror (do = f), the mirror equation gives 1/di = 1/f − 1/f = 0, so di → ∞. Physically, rays from the focal point reflect parallel to the principal axis and never converge at a finite location. Choice A is wrong because a same-size real image at C only occurs when the object is at C (do = R = 2f). Choice B describes the case when the object is inside the focal point (do < f). Choice D incorrectly implies that the image and object coincide at F, which would violate the mirror equation.

Question 2: BASIC CALCULATION

A convex mirror has a focal length of −15 cm. An object is placed 30 cm in front of the mirror. What is the image distance di?
  • A. −10 cm
  • B. +10 cm
  • C. −30 cm
  • D. +30 cm
Show answer (A)
Using the mirror equation: 1/di = 1/f − 1/do = 1/(−15) − 1/30 = −2/30 − 1/30 = −3/30 = −1/10. Therefore di = −10 cm. The negative sign confirms a virtual image located behind the mirror, which is consistent with convex mirror behavior. Choice B (+10 cm) is wrong because convex mirrors never produce real images (positive di). Choice C (−30 cm) would imply |di| = do, which only occurs for plane mirrors. Choice D (+30 cm) results from a sign error in the calculation.

Question 3: INTERMEDIATE

A concave mirror has a radius of curvature of 50 cm. An object is placed 15 cm from the mirror. What is the magnification of the image?
  • A. −2.5
  • B. +2.5
  • C. +0.40
  • D. −0.60
Show answer (B)
First, f = R/2 = 25 cm. Since do = 15 cm < f = 25 cm, the object is inside the focal point, so we expect a virtual, upright, magnified image. Applying the mirror equation: 1/di = 1/f − 1/do = 1/25 − 1/15 = (3 − 5)/75 = −2/75, giving di = −37.5 cm. The negative sign confirms the image is virtual (behind the mirror). Then m = −di/do = −(−37.5)/15 = +2.5. The positive magnification confirms the image is upright, and |m| > 1 confirms it is magnified. The correct answer is B (+2.5). Choice A is wrong because a negative magnification would mean an inverted image, inconsistent with the object being inside F. Choice C would indicate a diminished image, and Choice D gives both the wrong sign and magnitude.

Question 4: APPLIED

5 pts
A student wants to experimentally determine the focal length of an unknown concave mirror using a lit candle, a screen, and a meter stick. (a) Describe a procedure the student should follow to collect sufficient data to determine f. Include what measurements to take and how to vary conditions. (b) Describe how the student should analyze the data to determine f, including what graph to plot and how f is obtained from the graph. (c) Identify one source of systematic error and explain its effect on the measured value of f.
Show answer
Rubric (5 points): Point 1 — Procedure description: Place the concave mirror at one end of the meter stick. Position the candle at various known object distances do (all greater than f). For each do, move the screen until a sharp image forms, then record di. Collect at least 5 data pairs. Point 2 — Sufficient variation: Object distances should span a wide range (e.g., from just beyond f to several times f) to improve the reliability of the graphical analysis. Point 3 — Graphical analysis: Plot 1/di (y-axis) vs. 1/do (x-axis). The mirror equation predicts a linear relationship: 1/di = 1/f − 1/do. The slope should be −1 and the y-intercept equals 1/f, so f = 1/(y-intercept). Alternatively, either axis intercept gives 1/f. Point 4 — Extraction of f: Draw a best-fit line through the data. Read the y-intercept (or x-intercept); take its reciprocal to obtain f. Point 5 — Systematic error: If the student measures distances from the front surface of the mirror rather than from the reflecting surface (which is slightly recessed), all do and di values will be systematically too large, causing the computed f to be larger than the true value.

Question 5: CRITICAL THINKING

4 pts
A concave mirror of focal length f forms a real image of an object. The object is then moved so that its distance from the mirror is reduced by half (from 2f to f). Using the mirror equation, explain mathematically what happens to the image distance. Then discuss the physical implication: does a real image still exist? If not, describe what an observer looking into the mirror would see and why.
Show answer
Rubric (4 points): Point 1 — Initial calculation: When do = 2f: 1/di = 1/f − 1/(2f) = 1/(2f), so di = 2f. The image is real, same size (m = −1), and located at the center of curvature. Point 2 — Final calculation: When do = f: 1/di = 1/f − 1/f = 0, so di → ∞. No finite image location exists. Point 3 — Physical interpretation: When the object is exactly at the focal point, reflected rays emerge parallel to the principal axis and never converge. No real image can be projected on a screen. Point 4 — Observer experience: An observer looking into the mirror from a distance would see no clearly focused image. If the object moves even slightly inside f, the mirror equation yields a negative di, producing a virtual, upright, magnified image behind the mirror. The focal point is thus the boundary between real and virtual image formation for a concave mirror—a critical transition tested frequently on the AP exam.

SUMMARY

Summary

Summary

Image formation by mirrors is governed by the law of reflection and analyzed using ray diagrams and the mirror equation (1/f = 1/do + 1/di). Plane mirrors produce virtual, upright, same-size images. Concave mirrors (f > 0) produce real or virtual images depending on whether the object lies outside or inside the focal point. Convex mirrors (f < 0) always produce virtual, upright, diminished images.

The magnification equation m = −di/do encodes both size ratio and orientation in a single signed quantity. Master the sign conventions (positive f and di on the reflective side; negative behind) and the three principal rays for ray diagrams, and you will be prepared for both the qualitative and quantitative mirror questions that appear on the AP Physics 2 exam.

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