Quantum Theory and Wave–Particle Duality
AP Physics 2 · Flashcards · Application
AP PHYSICS 2 · FLASHCARDS
Card 1
of 7
0 got it
0 to review
Current
Got it
Still learning
Not seen
QUESTION
Convert
λ
=
450
nm
\lambda = 450 \text{ nm}
λ
=
450
nm
to energy of a photon.
QUESTION
Determine the frequency of a photon with energy
E
E
E
.
QUESTION
Find the energy of a photon with wavelength
λ
=
500
nm
\lambda = 500 \text{ nm}
λ
=
500
nm
.
Tap to flip before you grade
ANSWER
Use
E
=
h
c
λ
E = \frac{hc}{\lambda}
E
=
λ
h
c
. Substitute wavelength into energy-wavelength relationship.
Swipe → got it · swipe ← still learning
Got it
Still learning
Flip Card
Previous card
Next card