Torque - AP Physics 1

  1. State the effect on torque if θ\theta changes from 90∘90^\circ to 0∘0^\circ.
    Torque decreases to zero. Maximum torque at 90°90° reduces to zero at 0°0°.
  2. What happens to torque if the angle is decreased from 90∘90^\circ?
    Torque decreases. Smaller angles reduce sin⁡(θ)\sin(\theta), decreasing rotational effect.
  3. Calculate torque for r=3r=3 m, F=10F=10 N, θ=60∘\theta=60^\circ.
    τ=25.98\tau = 25.98 Nm. τ=3×10×sin⁡(60°)=30×0.866=25.98\tau = 3 \times 10 \times \sin(60°) = 30 \times 0.866 = 25.98 Nm.
  4. What is the effect of perpendicular force application on torque?
    Maximizes torque. Perpendicular application gives sin⁡(90°)=1\sin(90°) = 1, the maximum value.
  5. Which direction is positive torque conventionally?
    Counterclockwise. Standard physics convention for positive rotational direction.
  6. Identify the unit of torque in the SI system.
    Newton-meter (Nm). Force times distance gives units of energy per radian.
  7. Choose the result when a force acts at the pivot point.
    Torque is zero. At the pivot point, the lever arm distance r=0r = 0.
  8. What is the effect of negative torque on rotation?
    Causes clockwise rotation. Negative torque produces rotation opposite to positive direction.
  9. State the torque if F=8F=8 N, r=0.5r=0.5 m, and θ=90∘\theta=90^\circ.
    τ=4\tau = 4 Nm. τ=8×0.5×sin⁡(90°)=8×0.5×1=4\tau = 8 \times 0.5 \times \sin(90°) = 8 \times 0.5 \times 1 = 4 Nm.
  10. Identify the symbol for torque in equations.
    τ\tau. Greek letter tau is the standard physics symbol for torque.
  11. What does rr represent in the torque formula?
    Distance from pivot point to force application. The lever arm length determines how much turning advantage you have.
  12. Find the torque for r=2r=2 m, F=5F=5 N, θ=30∘\theta=30^\circ.
    τ=5\tau = 5 Nm. τ=2×5×sin⁡(30°)=2×5×0.5=5\tau = 2 \times 5 \times \sin(30°) = 2 \times 5 \times 0.5 = 5 Nm.
  13. When is the torque zero?
    When θ=0∘\theta = 0^\circ or sin⁡(θ)=0\sin(\theta) = 0. Force parallel to lever arm produces no rotational effect.
  14. What is the torque if F=0F=0?
    Zero. No force means no rotational effect can be produced.
  15. Identify the direction of torque for negative angle.
    Clockwise. Negative angles conventionally indicate clockwise rotation direction.
  16. State the effect of doubling rr on torque if FF and θ\theta are constant.
    Torque doubles. Torque is directly proportional to lever arm length.
  17. What happens to torque if the force increases?
    Torque increases. Torque is directly proportional to applied force magnitude.
  18. State the effect on torque if the force is perpendicular to the lever arm.
    Torque is maximized. Perpendicular force gives sin⁡(90°)=1\sin(90°) = 1, the maximum torque.
  19. What is the formula for torque?
    τ=r⋅F⋅sin⁡(θ)\tau = r \cdot F \cdot \sin(\theta). Fundamental formula where all three factors determine rotational effect.
  20. Which quantity is vector: force, mass, or torque?
    Torque. Torque has both magnitude and direction, making it a vector.
  21. What is the net torque if equal and opposite torques are applied?
    Zero. Equal magnitude opposite torques cancel each other out.
  22. What is the torque if r=0r=0?
    Zero. No lever arm means no rotational advantage or effect.
  23. Calculate torque for r=1.5r=1.5 m, F=20F=20 N, θ=45∘\theta=45^\circ.
    τ=21.21\tau = 21.21 Nm. τ=1.5×20×sin⁡(45°)=30×0.707=21.21\tau = 1.5 \times 20 \times \sin(45°) = 30 \times 0.707 = 21.21 Nm.
  24. Choose the effect of increasing rr on torque.
    Torque increases. Torque is directly proportional to lever arm distance.
  25. State the right-hand rule in torque context.
    Curl fingers in rotation direction; thumb points in torque direction. Standard method to determine torque vector direction in 3D.
  26. What is the torque direction for a positive angle?
    Counterclockwise. Positive angles correspond to counterclockwise rotation by convention.
  27. Identify the factor that does not affect torque.
    Mass of the object. Mass affects weight but not the geometric torque relationship.
  28. What does FF represent in the torque formula?
    Magnitude of the force applied. The force magnitude directly affects the rotational strength.
  29. Find the angle for zero torque if r=4r=4 m and F=7F=7 N.
    θ=0∘\theta = 0^\circ or 180∘180^\circ. When force is parallel to lever arm, sin⁡(θ)=0\sin(\theta) = 0.
  30. Find the net torque: τ1=5\tau_1=5 Nm, τ2=−3\tau_2=-3 Nm.
    τnet=2\tau_{net} = 2 Nm. Vector addition: 5+(−3)=25 + (-3) = 2 Nm in positive direction.
  31. What does τ\tau represent in the torque formula?
    Torque. Greek letter tau represents the rotational moment or turning effect.
  32. What does θ\theta represent in the torque formula?
    Angle between force and lever arm. This angle determines the effective component of force causing rotation.
  33. Calculate the torque if r=2r=2 m, F=10F=10 N, θ=0∘\theta=0^\circ.
    τ=0\tau = 0 Nm. sin⁡(0°)=0\sin(0°) = 0, so torque equals zero regardless of rr and FF.
  34. Find torque: r=3r=3 m, F=15F=15 N, θ=90∘\theta=90^\circ.
    τ=45\tau = 45 Nm. τ=3×15×sin⁡(90°)=3×15×1=45\tau = 3 \times 15 \times \sin(90°) = 3 \times 15 \times 1 = 45 Nm.
  35. Find the lever arm if torque is 2020 Nm and force is 55 N.
    r=4r = 4 m. From τ=rFsin⁡(θ)\tau = rF\sin(\theta), assuming θ=90°\theta = 90°: r=τ/F=20/5=4r = \tau/F = 20/5 = 4 m.
  36. Calculate torque: r=1r=1 m, F=10F=10 N, θ=45∘\theta=45^\circ.
    τ=7.07\tau = 7.07 Nm. τ=1×10×sin⁡(45°)=10×0.707=7.07\tau = 1 \times 10 \times \sin(45°) = 10 \times 0.707 = 7.07 Nm.
  37. State the relationship between torque and rotational equilibrium.
    Net torque must be zero. No net torque means no angular acceleration occurs.
  38. What effect does increasing θ\theta to 90∘90^\circ have on torque?
    Torque increases. Approaching 90∘90^\circ increases sin⁡(θ)\sin(\theta) toward its maximum value.
  39. State the condition for maximum torque.
    θ=90∘\theta = 90^\circ or sin⁡(θ)=1\sin(\theta) = 1. Perpendicular force application maximizes the rotational effect.

Study these flashcards