Representing and Analyzing SHM - AP Physics 1

  1. What is the role of damping in SHM?
    Damping reduces amplitude over time. Energy loss causes oscillation amplitude to decrease gradually.
  2. Find the displacement if A=2A = 2 m, ω=π\omega = \pi rad/s, t=1t = 1 s, ϕ=0\phi = 0.
    x(1)=0x(1) = 0. Use x(t)=Acos⁡(ωt)x(t) = A\cos(\omega t) with given values.
  3. Find the total mechanical energy in SHM.
    E=12kA2E = \frac{1}{2}kA^2. Total energy equals maximum potential energy at amplitude.
  4. Which graph represents displacement in SHM?
    A sine or cosine wave. Displacement varies sinusoidally with time in SHM.
  5. Calculate the frequency if T=0.25T = 0.25 s.
    f=4f = 4 Hz. Use f=1Tf = \frac{1}{T} to convert period to frequency.
  6. Calculate the period given f=5f = 5 Hz.
    T=0.2T = 0.2 s. Use T=1fT = \frac{1}{f} to find period from frequency.
  7. What is the kinetic energy at maximum displacement?
    Zero. At maximum displacement, all energy is potential, none kinetic.
  8. What is the maximum velocity formula in SHM?
    vmax=Aωv_{max} = A\omega. Occurs at equilibrium where all energy is kinetic.
  9. What is the phase relationship between velocity and acceleration in SHM?
    π\pi radians out of phase. Acceleration and velocity are opposite in phase.
  10. Name the energy types involved in SHM.
    Kinetic and potential energy. Energy continuously converts between these two forms during oscillation.
  11. What is the formula for angular frequency in SHM?
    ω=2πf\omega = 2\pi f. Angular frequency is 2π2\pi times the regular frequency.
  12. Explain the effect of mass on the period of a pendulum.
    Mass does not affect the period. Pendulum period depends only on length and gravity.
  13. Identify the point of maximum acceleration in SHM.
    At maximum displacement. Restoring force and acceleration are greatest at amplitude.
  14. Find the velocity formula for SHM at time tt.
    v(t)=−Aωsin⁡(ωt+ϕ)v(t) = -A\omega\sin(\omega t + \phi). Velocity is the time derivative of displacement function.
  15. What does the graph of velocity against time look like in SHM?
    A sine wave. Velocity varies sinusoidally, 90 degrees ahead of displacement.
  16. Define simple harmonic motion (SHM).
    Motion where acceleration is proportional to displacement and directed towards equilibrium. Restoring force follows F=−kxF = -kx, creating sinusoidal motion.
  17. What is the maximum acceleration formula in SHM?
    amax=Aω2a_{max} = A\omega^2. Occurs at maximum displacement where restoring force is greatest.
  18. State Hooke's Law.
    F=−kxF = -kx. Force is proportional to displacement with negative sign for restoring nature.
  19. Find the period of a pendulum with L=1L = 1 m and g=9.8g = 9.8 m/s².
    T≈2.01T \approx 2.01 s. Use pendulum formula with given values.
  20. Calculate the maximum speed if A=0.2A = 0.2 m and ω=5\omega = 5 rad/s.
    vmax=1v_{max} = 1 m/s. Maximum speed occurs at equilibrium position.
  21. Find the angular frequency if T=0.5T = 0.5 s.
    ω=4π\omega = 4\pi rad/s. Use ω=2πT\omega = \frac{2\pi}{T} to convert period to angular frequency.
  22. What is the potential energy formula in a spring system?
    U=12kx2U = \frac{1}{2}kx^2. Energy stored increases with square of displacement from equilibrium.
  23. Identify the relationship between frequency and period.
    f=1Tf = \frac{1}{T}. Frequency and period are reciprocals of each other.
  24. Find the velocity at equilibrium position in SHM.
    v=vmaxv = v_{max}. At equilibrium, all energy is kinetic, reaching maximum speed.
  25. What is resonance in the context of SHM?
    When driving frequency matches natural frequency, maximizing amplitude. External driving at natural frequency causes large amplitude oscillations.
  26. Find the displacement formula for SHM at time tt.
    x(t)=Acos⁡(ωt+ϕ)x(t) = A\cos(\omega t + \phi). General solution with amplitude, angular frequency, and phase constant.
  27. Define the amplitude of oscillation.
    The maximum displacement from equilibrium. Amplitude represents the extent or range of oscillation.
  28. How does amplitude affect the period in SHM?
    Amplitude does not affect the period. Period depends only on system parameters, not initial conditions.
  29. Identify a real-world example of SHM.
    A swinging pendulum. Pendulums exhibit simple harmonic motion for small angles.
  30. Determine the effect of length on the pendulum's period.
    Longer length increases period. Period increases with square root of length.
  31. Calculate potential energy at maximum displacement for k=10k = 10 N/m, A=0.5A = 0.5 m.
    U=1.25U = 1.25 J. Use U=12kA2U = \frac{1}{2}kA^2 at maximum displacement.
  32. State the relationship between energy and amplitude in SHM.
    Energy is proportional to the square of amplitude. From E=12kA2E = \frac{1}{2}kA^2, energy increases with A2A^2.
  33. What is the formula for the period of a mass-spring system?
    T=2πmkT = 2\pi \sqrt{\frac{m}{k}}. Period increases with mass and decreases with spring stiffness.
  34. What is the acceleration formula for SHM at time tt?
    a(t)=−Aω2cos⁡(ωt+ϕ)a(t) = -A\omega^2\cos(\omega t + \phi). Acceleration is the time derivative of velocity function.
  35. What is the displacement at t=0t = 0 if ϕ=0\phi = 0?
    x(0)=Ax(0) = A. At t=0t=0 with ϕ=0\phi=0, cos⁡(0)=1\cos(0) = 1, so displacement equals amplitude.
  36. Identify the phase difference between displacement and velocity in SHM.
    π2\frac{\pi}{2} radians. Velocity leads displacement by 90 degrees in phase.

Study these flashcards