AP Chemistry Quiz
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For the reaction X+Y→ZX + Y \rightarrow Z, the experimentally determined rate law is Rate = k[X]2k[X]^2.
An experiment is performed with [X]=0.40M[X] = 0.40 M and [Y]=0.40M[Y] = 0.40 M. A second experiment is performed with [X]=0.40M[X] = 0.40 M and [Y]=0.80M[Y] = 0.80 M. How will the initial rate of the second experiment compare to the first?
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