AP Chemistry • Chemical Reactions

Introduction to Acid-Base Reactions

Explore how proton transfer and electron-pair donation govern acid-base chemistry across three foundational models.

AP Chemistry illustration with a laboratory flask, atom, and microscope
Inside this lesson 10 sections 5 questions 9 figures

SECTION 1

Historical Context & Motivation

The study of acids and bases is one of the oldest threads in the history of chemistry, stretching back to the alchemists who classified substances by taste, corrosiveness, and their ability to change the color of plant-derived indicators. For centuries, practitioners recognized that certain substances—vinegar, citrus juice, mineral spirits—shared a sour taste and reacted vigorously with metals, while others—lye, slaked lime, wood ash—felt slippery and neutralized the sour agents. Despite this practical knowledge, a coherent theoretical framework did not emerge until the late nineteenth century, when rapid advances in electrochemistry and atomic theory finally supplied the tools needed to explain acid-base behavior at the molecular level.

1661 • Boyle's Indicator Tests

Robert Boyle systematically described acids as substances that dissolve many other materials, turn litmus red, and lose their acidity when mixed with alkaline substances—laying the empirical groundwork for acid-base classification.

1884 • Arrhenius Dissociation Theory

Svante Arrhenius proposed that acids produce H⁺ ions and bases produce OH⁻ ions in aqueous solution, earning him the 1903 Nobel Prize and establishing the first quantitative model of acid-base chemistry.

1923 • Brønsted–Lowry Proton-Transfer Model

Johannes Brønsted and Thomas Lowry independently defined acids as proton donors and bases as proton acceptors, extending acid-base theory beyond aqueous solutions to any solvent system.

1923 • Lewis Electron-Pair Model

Gilbert N. Lewis broadened the definition further: a Lewis acid accepts an electron pair, and a Lewis base donates one, unifying coordination chemistry and organic reaction mechanisms under the acid-base umbrella.

1909 • Sørensen's pH Scale

Søren Sørensen introduced the pH scale as a convenient measure of hydrogen-ion activity, transforming how chemists communicate and compare the acidity of solutions in research and industry.

Each successive model addressed limitations of its predecessors: Arrhenius could not explain why ammonia (NH₃) acts as a base even though it contains no OH⁻; Brønsted–Lowry handled that case but could not account for reactions lacking proton transfer, such as BF₃ accepting a lone pair from NH₃. The central question this lesson addresses is: How do we identify, classify, and predict the products of acid-base reactions using these three complementary models?

SECTION 2

Core Principles & Definitions

Understanding acid-base reactions requires fluency with three models, each of which captures a different slice of chemical reality. On the AP Chemistry exam, you are expected to apply all three, choosing whichever model best illuminates a given reaction. The following grid summarizes the foundational ideas; mastering these definitions is the prerequisite for every calculation and prediction that follows.

1

Arrhenius Model

An Arrhenius acid dissociates in water to produce H⁺ (or H₃O⁺) ions; an Arrhenius base dissociates to produce OH⁻ ions. This model is limited to aqueous solutions.
2

Brønsted–Lowry Model

A Brønsted–Lowry acid donates a proton (H⁺) to another species; a Brønsted–Lowry base accepts a proton. This model introduces the concept of conjugate acid-base pairs.
3

Lewis Model

A Lewis acid accepts an electron pair; a Lewis base donates an electron pair. This is the most general definition and encompasses all Brønsted–Lowry reactions.
4

Conjugate Pairs

When a Brønsted–Lowry acid donates a proton it becomes its conjugate base; when a base accepts a proton it becomes its conjugate acid. Every proton-transfer reaction contains two conjugate pairs.
5

Amphoteric / Amphiprotic Species

Certain substances such as water (H₂O) and the bicarbonate ion (HCO₃⁻) can act as either acids or bases depending on the reaction partner. These are termed amphiprotic species.
✦

KEY TAKEAWAY

Think of the three acid-base models as progressively wider-angle camera lenses. The Arrhenius lens is a narrow zoom that captures only aqueous H⁺/OH⁻ chemistry. The Brønsted–Lowry lens zooms out to see proton transfers in any solvent. The Lewis lens is the widest panoramic shot, capturing every reaction in which an electron pair is shared with an electron-deficient species. Each lens is 'correct'—you simply choose the one that shows the most useful detail for a given problem.

SECTION 3

Visual Explanation — Proton Transfer in Action

The diagram below illustrates the Brønsted–Lowry proton-transfer reaction between hydrochloric acid (HCl) and water (H₂O). Follow the curved arrow to trace how the proton migrates from the acid to the base, generating the conjugate acid (H₃O⁺) and the conjugate base (Cl⁻). This simple one-directional proton transfer is characteristic of strong acids, which ionize completely in aqueous solution.

Brønsted–Lowry Proton Transfer: HCl + H₂O → H₃O⁺ + Cl⁻HClBrønsted–LowryACID (proton donor)H₂OBrønsted–LowryBASE (proton acceptor)H⁺ transfer⟶Cl⁻ConjugateBASEH₃O⁺ConjugateACIDConjugate PairsHCl / Cl⁻Pair 1H₂O / H₃O⁺Pair 2Stronger acid → weakerconjugate base
The curved pink arrow traces the proton (H⁺) as it transfers from HCl (the Brønsted–Lowry acid, shown in cyan) to H₂O (the Brønsted–Lowry base, shown in violet). The products form two conjugate pairs listed in the legend on the right.

Notice how the diagram encodes two conjugate pairs. HCl and Cl⁻ form the first conjugate acid-base pair: HCl loses a proton to become its conjugate base Cl⁻. Similarly, H₂O and H₃O⁺ form the second pair: water accepts a proton to become its conjugate acid, the hydronium ion. A general rule on the AP exam is that the stronger an acid, the weaker its conjugate base—and vice versa. Since HCl is a strong acid that ionizes completely in water, Cl⁻ is an extremely weak conjugate base with negligible tendency to re-accept a proton.

SECTION 4

Mathematical Framework — pH, KaK_a, and KbK_b

Quantifying acid-base chemistry requires several interrelated equations. The pH scale compresses the enormous range of hydrogen-ion concentrations (from roughly 10 M in concentrated acid down to 10⁻¹⁵ M in concentrated base) into a manageable logarithmic scale. The equilibrium constants Ka and Kb quantify the extent to which weak acids and bases ionize, while the autoionization constant of water, Kw, links these quantities together.

DEFINITION OF pH

pH=−log10[H3O+]pH = −log₁₀[H₃O⁺]

where [H₃O⁺] is the molar concentration of hydronium ions in solution. A pH of 7.00 at 25 °C is neutral; values below 7 are acidic, values above 7 are basic.

AUTOIONIZATION OF WATER

Kw=[H3O+][OH−]=1.0×10−14(at25°C)Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴ (at 25 °C)

This relationship holds in every aqueous solution. Because Kw is constant at a given temperature, knowing [H₃O⁺] immediately determines [OH⁻], and vice versa.

ACID IONIZATION CONSTANT

Ka=[H3O+][A−]/[HA]Ka = [H₃O⁺][A⁻] / [HA]

For a generic weak acid HA that donates a proton to water: HA + H₂O ⇌ H₃O⁺ + A⁻. A larger Ka indicates a stronger acid (greater degree of ionization).

CONJUGATE Ka–Kb RELATIONSHIP

Ka×Kb=Kw=1.0×10−14(at25°C)Ka × Kb = Kw = 1.0 × 10⁻¹⁴ (at 25 °C)

For any conjugate acid-base pair, the product of Ka for the acid form and Kb for the base form equals Kw. This allows conversion between acid and base strength for conjugate pairs.

💡

AP Exam Tip

The College Board commonly tests whether students can connect Ka to molecular structure. Factors such as bond polarity, atomic radius of the atom bonded to the acidic hydrogen, resonance stabilization of the conjugate base, and inductive effects all influence Ka. Be prepared to rank acid strength using these structural arguments.

SECTION 5

Classifying Acid-Base Reactions

Acid-base reactions can be organized into several categories that recur throughout AP Chemistry: neutralization reactions, reactions of acids with metals, reactions of acids or bases with water (ionization), and reactions involving Lewis acid-base adduct formation. The pH scale provides a convenient visual framework for comparing the relative positions of common substances, and the classification table below groups reaction types by their net ionic equations and expected products.

The pH Scale — Common Substances01234567891011121314ACIDICNEUTRALBASICHCl (1 M)pH ≈ 0LemonpH ≈ 2VinegarpH ≈ 3Pure WaterpH = 7.0Baking SodapH ≈ 9AmmoniapH ≈ 12NaOH (1 M)pH ≈ 14Acid-Base Reaction CategoriesStrong acid + Strong base → Salt + Water (neutralization)Weak acid + Water ⇌ Conjugate base + H₃O⁺ (partial ionization)Weak base + Water ⇌ Conjugate acid + OH⁻ (partial ionization)Lewis acid + Lewis base → Adduct (coordinate bond formation)
The gradient bar maps pH 0 (strongly acidic, red) through pH 7 (neutral, green) to pH 14 (strongly basic, violet). Common substances are marked at their approximate pH values. The summary box lists the four major categories of acid-base reactions encountered in AP Chemistry.
Reaction TypeGeneral EquationExample
NeutralizationHA + BOH → BA + H₂OHCl + NaOH → NaCl + H₂O
Weak acid ionizationHA + H₂O ⇌ A⁻ + H₃O⁺CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
Weak base ionizationB + H₂O ⇌ BH⁺ + OH⁻NH₃ + H₂O ⇌ NH₄⁺ + OH⁻
Lewis adduct formationA + :B → A–BBF₃ + NH₃ → F₃B–NH₃

Major acid-base reaction types tested on the AP Chemistry exam

SECTION 6

Worked Example — Finding pH of a Weak Acid

The following worked example walks through the calculation of the pH of a 0.10 M acetic acid (CH₃COOH) solution given Ka = 1.8 × 10⁻⁵. This is a canonical AP Chemistry problem that tests your ability to set up an ICE table, make the standard simplifying approximation, and verify its validity.

Calculate the pH of 0.10 M CH₃COOH (Ka = 1.8 × 10⁻⁵)

  1. 1

    Step 1 — Write the equilibrium expression

    The ionization equilibrium is CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺. The equilibrium expression is Ka = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]. Water does not appear because it is the solvent.
  2. 2

    Step 2 — Set up the ICE table

    Let x = [H₃O⁺] at equilibrium. Initial: [CH₃COOH] = 0.10 M, [CH₃COO⁻] = 0, [H₃O⁺] ≈ 0. Change: −x, +x, +x. Equilibrium: (0.10 − x), x, x.
  3. 3

    Step 3 — Substitute and apply the 5% approximation

    Substituting into the Ka expression: 1.8 × 10⁻⁵ = x² / (0.10 − x). Because Ka is small relative to the initial concentration, assume x ≪ 0.10 so that 0.10 − x ≈ 0.10. This gives x² = 1.8 × 10⁻⁶.
  4. 4

    Step 4 — Solve for x

    x = √(1.8 × 10⁻⁶) = 1.34 × 10⁻³ M. Verification: (1.34 × 10⁻³ / 0.10) × 100% = 1.34%, which is well under 5%, confirming the approximation is valid.
    [H₃O⁺] = 1.34 × 10⁻³ M
  5. 5

    Step 5 — Calculate pH

    pH = −log₁₀(1.34 × 10⁻³) = −(−2.87) = 2.87. The solution is moderately acidic, consistent with the weak-acid character of acetic acid.
    pH = 2.87
⚠

When the 5% Rule Fails

If x exceeds 5% of the initial concentration, do not discard it. Instead, use the quadratic formula to solve x² + Kax − KaC₀ = 0, where C₀ is the initial acid concentration. On the AP exam with a calculator, this is entirely feasible.

SECTION 7

Comparing the Three Acid-Base Models

Each acid-base model has particular strengths and limitations. On the AP Chemistry exam, selecting the appropriate model is itself a tested skill—questions may ask you to identify which definition best explains a given reaction. The table below provides a side-by-side comparison across several dimensions of applicability.

FeatureArrheniusBrønsted–LowryLewis
Acid definitionProduces H⁺ in waterDonates a protonAccepts an electron pair
Base definitionProduces OH⁻ in waterAccepts a protonDonates an electron pair
Solvent requirementAqueous onlyAny solvent or gas phaseAny phase
Conjugate pairs?Not explicitlyYes—central conceptNot typically used
Explains NH₃ as a base?No (no OH⁻ in formula)Yes (accepts H⁺)Yes (donates lone pair)
Explains BF₃ + NH₃?NoNo (no proton transferred)Yes (electron-pair donation)
Best use on AP examSimple neutralization in waterProton-transfer equilibria, buffers, titrationsCoordination compounds, organic mechanisms, metal-ion hydration

Side-by-side comparison of the three acid-base models

✦

KEY TAKEAWAY

Think of the three models like diagnostic tools in a hospital. The Arrhenius model is a basic thermometer—quick and useful for routine checks but limited in what it can detect. The Brønsted–Lowry model is an X-ray machine—it reveals internal structure (conjugate pairs) invisible to the simpler tool. The Lewis model is an MRI scanner—the most powerful and general, able to diagnose conditions the other instruments miss entirely. A skilled chemist, like a skilled physician, chooses the right tool for the problem at hand.

SECTION 8

Connections to Advanced Acid-Base Theory

The introductory treatment of acid-base reactions presented here forms the launchpad for several more advanced topics you will encounter later in the AP Chemistry curriculum and in university-level courses. Buffer systems, titration curves, polyprotic acid equilibria, and the Henderson–Hasselbalch equation all build directly on the Ka and conjugate-pair logic introduced in this lesson. Furthermore, Lewis acid-base theory extends seamlessly into transition-metal coordination chemistry, where metal cations act as Lewis acids and ligands serve as Lewis bases. Understanding acid-base reactions also connects to thermodynamics through ΔG° = −RT ln K, linking equilibrium constants to free energy.

This Lesson (Introductory)Advanced Extension
Ka for monoprotic acidsStepwise Ka1, Ka2, Ka3 for polyprotic acids (H₃PO₄, H₂SO₄)
pH of a single weak acidHenderson–Hasselbalch equation for buffer pH: pH = pKa + log([A⁻]/[HA])
Neutralization as a categoryFull titration curve analysis: equivalence point, half-equivalence point, indicator selection
Lewis acid-base definitionsCrystal-field theory, spectrochemical series, and ligand-field splitting in coordination compounds
Qualitative strength rankingQuantitative structure–acidity relationships: bond enthalpy, electronegativity, resonance, inductive effects

From introductory acid-base chemistry to advanced topics

As you progress through the AP Chemistry curriculum, keep returning to the core logic of this lesson: every acid-base reaction involves a transfer—whether of a proton or an electron pair—and every equilibrium expression encodes the relative strengths of the acid and base involved. This framework does not change; it simply grows richer as the systems you study become more complex.

SECTION 9

Practice Problems

Question 1: CONCEPTUAL

In the reaction NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq), which species acts as a Brønsted–Lowry acid?
  • A. NH₃
  • B. H₂O
  • C. NH₄⁺
  • D. OH⁻
Show answer (B)
B is correct. A Brønsted–Lowry acid is defined as a proton donor. In this reaction, H₂O donates a proton (H⁺) to NH₃, forming OH⁻ (its conjugate base) and NH₄⁺. A is incorrect because NH₃ accepts a proton, making it the Brønsted–Lowry base. C is incorrect because NH₄⁺ is a product (the conjugate acid of NH₃), not a reactant acting as the acid. D is incorrect because OH⁻ is the conjugate base of water, a product of the reaction, not the proton donor.

Question 2: BASIC CALCULATION

What is the pH of a 0.0025 M solution of HNO₃, a strong acid that ionizes completely in water?
  • A. 2.60
  • B. 3.40
  • C. 11.40
  • D. 2.00
Show answer (A)
A is correct. Since HNO₃ is a strong acid, it ionizes completely: [H₃O⁺] = 0.0025 M = 2.5 × 10⁻³ M. pH = −log(2.5 × 10⁻³) = −(log 2.5 + log 10⁻³) = −(0.40 + (−3)) = 2.60. B is incorrect — this would correspond to [H₃O⁺] ≈ 4.0 × 10⁻⁴ M, a misapplication of the logarithm. C is incorrect — 11.40 would be the pOH, not the pH; this error arises from confusing −log[OH⁻] with −log[H₃O⁺]. D is incorrect — pH = 2.00 would require [H₃O⁺] = 0.010 M, four times the actual concentration.

Question 3: INTERMEDIATE

Hypochlorous acid (HOCl) has Ka = 2.9 × 10⁻⁸. What is the Kb of its conjugate base, OCl⁻?
  • A. 2.9 × 10⁻⁶
  • B. 1.0 × 10⁻¹⁴
  • C. 7.5 × 10⁻²²
  • D. 3.4 × 10⁻⁷
Show answer (D)
D is correct. For any conjugate acid-base pair, Ka × Kb = Kw = 1.0 × 10⁻¹⁴ at 25 °C. Therefore Kb = (1.0 × 10⁻¹⁴) / (2.9 × 10⁻⁸) = 3.4 × 10⁻⁷. A is incorrect — dividing incorrectly or using the wrong relationship. B is incorrect — this is Kw itself, not the ratio. C is incorrect — this results from multiplying Ka × Kw instead of dividing.

Question 4: APPLIED

4 pts
A chemist prepares a 0.20 M solution of formic acid (HCOOH, Ka = 1.8 × 10⁻⁴). (a) Write the equilibrium expression for the ionization of formic acid in water. (b) Using an ICE table and the small-x approximation, calculate [H₃O⁺] at equilibrium. (c) Calculate the pH of the solution. (d) Determine the percent ionization and state whether the 5% approximation is valid.
Show answer
Rubric (4 points): Point 1 (part a): Correct equilibrium expression: Ka = [HCOO⁻][H₃O⁺] / [HCOOH] = 1.8 × 10⁻⁴. Water is omitted from the expression because it is the solvent. Point 2 (part b): Correct ICE setup and calculation. Let x = [H₃O⁺] produced at equilibrium. Initial: [HCOOH] = 0.20 M, [HCOO⁻] = 0, [H₃O⁺] = 0. Change: −x, +x, +x. Equilibrium: (0.20 − x), x, x. Substituting into the Ka expression: 1.8 × 10⁻⁴ = x² / (0.20 − x). Applying the small-x approximation (assume x ≪ 0.20): 1.8 × 10⁻⁴ ≈ x² / 0.20. Solving: x² = 3.6 × 10⁻⁵, so x = 6.0 × 10⁻³ M. Point 3 (part c): pH = −log(6.0 × 10⁻³) = −log(6.0) + −log(10⁻³) = −0.778 + 3 = 2.22. Point 4 (part d): Percent ionization = (6.0 × 10⁻³ / 0.20) × 100% = 3.0%. Since 3.0% < 5%, the small-x approximation is valid.

Question 5: CRITICAL THINKING

4 pts
A student measures the pH of four 0.10 M solutions and records the following data: Solution A: pH = 1.0 Solution B: pH = 2.9 Solution C: pH = 7.0 Solution D: pH = 11.1 (a) Identify which solution most likely contains a strong acid. Justify your answer using the data. (b) Calculate [H₃O⁺] for Solution B and determine whether the solute in Solution B is a strong or weak acid. Explain your reasoning. (c) Solution D is a 0.10 M solution of a weak base. Calculate [OH⁻] for this solution. (d) The student claims that the Kb of the weak base in Solution D can be determined from the data. Calculate Kb and comment on whether this base is relatively strong or weak among weak bases.
Show answer
Rubric (4 points): Point 1 (part a): Solution A (pH = 1.0) is the strong acid. For a 0.10 M strong monoprotic acid, complete ionization gives [H₃O⁺] = 0.10 M, and pH = −log(0.10) = 1.0, which matches exactly. A weak acid at the same concentration would have a higher pH. Point 2 (part b): [H₃O⁺] = 10⁻²·⁹ = 1.26 × 10⁻³ M. Since the initial concentration is 0.10 M but only 1.26 × 10⁻³ M ionized (1.26% ionization), the acid is weak—a strong acid would ionize completely and produce [H₃O⁺] = 0.10 M. Point 3 (part c): pOH = 14.00 − 11.1 = 2.9, so [OH⁻] = 10⁻²·⁹ = 1.26 × 10⁻³ M. Point 4 (part d): Using the ICE approach: Kb = [BH⁺][OH⁻] / [B] = (1.26 × 10⁻³)² / (0.10 − 1.26 × 10⁻³) ≈ (1.59 × 10⁻⁶) / 0.099 = 1.6 × 10⁻⁵. This Kb is comparable to that of ammonia (1.8 × 10⁻⁵), indicating the base is moderately weak—stronger than most amine bases but far from fully ionized.

SUMMARY

Lesson Summary

Summary

Acid-base chemistry rests on three progressively inclusive models. The Arrhenius model defines acids as H⁺ producers and bases as OH⁻ producers in aqueous solution. The Brønsted–Lowry model generalizes these roles to proton donors (acids) and proton acceptors (bases) in any solvent, introducing the crucial concept of conjugate acid-base pairs. The Lewis model is the broadest, defining acids as electron-pair acceptors and bases as electron-pair donors, which encompasses every Brønsted–Lowry reaction and extends to coordination chemistry and organic mechanisms.

Quantitatively, the pH scale (pH = −log[H₃O⁺]) condenses hydrogen-ion concentrations into a manageable range. The autoionization constant Kw = 1.0 × 10⁻¹⁴ at 25 °C links [H₃O⁺] and [OH⁻] in every aqueous solution. For weak acids and bases, Ka and Kb quantify ionization strength and obey the relationship Ka × Kb = Kw for every conjugate pair. These tools—model identification, equilibrium expressions, ICE tables, and the 5% approximation—form the foundation for buffer chemistry, titration analysis, and advanced equilibrium problems on the AP Chemistry exam.

Varsity Tutors • AP Chemistry • Introduction to Acid-Base Reactions