Weak Acid and Base Equilibria - AP Chemistry

  1. What is the pHpH of a neutral solution at 25o25^\text{o}C?
    pH=7pH = 7. Equal concentrations of H+H^+ and OH−OH^- at equilibrium.
  2. Identify the relationship between KwK_w, KaK_a, and KbK_b for conjugate acid-base pairs.
    Kw=Ka×KbK_w = K_a \times K_b. For conjugate acid-base pairs, their equilibrium constants multiply to give KwK_w.
  3. What is the expression for the equilibrium constant KbK_b of a weak base?
    Kb=[BH+][OH−][B]K_b = \frac{[\text{BH}^+][\text{OH}^-]}{[\text{B}]}. Shows equilibrium between weak base and its protonation products.
  4. What does a smaller KbK_b value indicate about the strength of a base?
    The base is weaker. Lower KbK_b means less dissociation and weaker base.
  5. What does a larger KaK_a value indicate about the strength of an acid?
    The acid is stronger. Higher KaK_a means greater dissociation and stronger acid.
  6. How do you find [OH−][OH^-] from pOHpOH?
    [OH−]=10−pOH[OH^-] = 10^{-pOH}. Inverse logarithm converts pOH back to concentration.
  7. What is the Bronsted-Lowry definition of a base?
    A base is a proton acceptor. Accepts protons from acids in chemical reactions.
  8. What is the general expression for the equilibrium constant KaK_a of a weak acid?
    Ka=[H+][A−][HA]K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}. Shows equilibrium between weak acid and its dissociation products.
  9. What is the expression for the percent ionization of a weak acid?
    Percent ionization = \frac{[\text{H}^+]}{[\text{HA}]_0} \times 100\text{%}. Ratio of ionized acid to initial concentration times 100%.
  10. What is the formula for the autoionization of water?
    2H2O⇌H3O++OH−2 \text{H}_2\text{O} \rightleftharpoons \text{H}_3\text{O}^+ + \text{OH}^-. Water molecules exchange protons to form ions.
  11. Calculate the pHpH for [OH−]=4×10−5[OH^-] = 4 \times 10^{-5} M.
    pH=9.6pH = 9.6. Find pOH=4.4pOH = 4.4, then pH=14−4.4=9.6pH = 14 - 4.4 = 9.6.
  12. Which is stronger: an acid with Ka=1.0×10−4K_a = 1.0 \times 10^{-4} or Ka=1.0×10−6K_a = 1.0 \times 10^{-6}?
    The acid with Ka=1.0×10−4K_a = 1.0 \times 10^{-4} is stronger. Larger KaK_a value indicates greater acid dissociation.
  13. What is the pHpH of a 0.010.01 M sulfuric acid solution assuming complete dissociation?
    pH=2pH = 2. Diprotic acid: [H+]=0.02[H^+] = 0.02 M, so pH=−log⁡(0.02)=2pH = -\log(0.02) = 2.
  14. What is the relationship between pHpH and pOHpOH at 25o25^\text{o}C?
    pH+pOH=14pH + pOH = 14. Sum of pH and pOH equals 14 at standard temperature.
  15. What is the value of KwK_w at 25o25^\text{o}C?
    Kw=1.0×10−14K_w = 1.0 \times 10^{-14}. Ion product of water at standard temperature.
  16. What is the effect of temperature on the value of KwK_w?
    KwK_w increases with temperature. Higher temperature increases water dissociation.
  17. What is the conjugate base of the bicarbonate ion, HCO3−HCO_3^{-}?
    CO32−CO_3^{2-}. Loses another proton to form carbonate ion.
  18. What is the conjugate acid of ammonia, NH₃?
    NH₄^+. Gains a proton to form the conjugate acid.
  19. Find the pKapK_a given Ka=1.8×10−5K_a = 1.8 \times 10^{-5}.
    pKa=4.74pK_a = 4.74. Use pKa=−log⁡(Ka)=−log⁡(1.8×10−5)=4.74pK_a = -\log(K_a) = -\log(1.8 \times 10^{-5}) = 4.74.
  20. Identify the Lewis definition of an acid.
    An acid is an electron pair acceptor. Accepts electron pairs from Lewis bases.
  21. How does pHpH change when a weak acid is diluted?
    pHpH increases slightly. Dilution reduces concentration but increases degree of ionization.
  22. Calculate the pOHpOH of a solution with [OH−]=2×10−3[OH^-] = 2 \times 10^{-3} M.
    pOH=2.7pOH = 2.7. Use pOH=−log⁡(2×10−3)=2.7pOH = -\log(2 \times 10^{-3}) = 2.7.
  23. How is pKbpK_b calculated from KbK_b?
    pKb=−log(Kb)pK_b = -\text{log}(K_b). Negative logarithm converts base constant to pK scale.
  24. Find KaK_a given pKa=4.76pK_a = 4.76.
    Ka=1.74×10−5K_a = 1.74 \times 10^{-5}. Use Ka=10−pKa=10−4.76=1.74×10−5K_a = 10^{-pK_a} = 10^{-4.76} = 1.74 \times 10^{-5}.
  25. Identify the effect of dilution on the pHpH of a weak acid solution.
    Dilution increases pHpH slightly. Equilibrium shifts right, increasing ionization and pH.
  26. How is [H+][H^+] calculated from pHpH?
    [H+]=10−pH[H^+] = 10^{-pH}. Inverse logarithm converts pH back to concentration.
  27. What is the pHpH of a 0.050.05 M hydrochloric acid solution?
    pH=1.3pH = 1.3. Strong acid completely dissociates: pH=−log⁡(0.05)=1.3pH = -\log(0.05) = 1.3.
  28. Determine the pKbpK_b given Kb=4.5×10−4K_b = 4.5 \times 10^{-4}.
    pKb=3.35pK_b = 3.35. Use pKb=−log⁡(4.5×10−4)=3.35pK_b = -\log(4.5 \times 10^{-4}) = 3.35.
  29. Determine the pHpH of a 0.10.1 M NaOH solution.
    pH=13pH = 13. Strong base: [OH−]=0.1[OH^-] = 0.1 M, so pOH=1pOH = 1, pH=13pH = 13.
  30. What does a pHpH greater than 77 indicate?
    The solution is basic. pH above 7 means hydroxide concentration exceeds hydronium.
  31. Determine the pHpH of a solution if [H+]=1×10−3[H^+] = 1 \times 10^{-3} M.
    pH=3pH = 3. Use pH=−log⁡(1×10−3)=3pH = -\log(1 \times 10^{-3}) = 3.
  32. State the formula for calculating pHpH from [H+][H^+] concentration.
    pH=−log([H+])pH = -\text{log}([H^+]). Negative logarithm converts concentration to pH scale.
  33. What is the relationship between pKapK_a and the strength of an acid?
    Lower pKapK_a means stronger acid. Lower pKapK_a corresponds to larger KaK_a and stronger acid.
  34. What is the conjugate base of acetic acid, CH₃COOH?
    CH₃COO⁻. Loses a proton to form the conjugate base.

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